The correct answer is option B which is P ( A|B) will be ( 4 / 9 ).
What is probability?Probability is defined as the ratio of the number of favorable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.
Given that:-
A locker combination consists of two nonzero digits, and each combination consists of different digits. Event A is defined as choosing an odd number as the first digit, and event B is defined as choosing an odd number as the second digit.The total sample will have 9 numbers
S = { 1,2,3,4,5,6,7,8,9} = 9
Even Number = { 2,4,6,8} = 4
Odd Number = { 1,3,5,7,9} = 5
P ( A ) = ( 4 / 9 )
P ( B ) = ( 5 / 9 )
The probability will be calculated as:-
P( A:B ) = [tex]\dfrac{P(A)\times P(B)}{P(B)}[/tex]
P( A:B ) =[tex]\dfrac{( 5/9 ) ( 4/9 )}{5 / 9 }[/tex]
P( A:B ) = 4 / 9
Therefore the correct answer is option B which is P ( A|B) will be ( 4 / 9 ).
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Step 1: –10 + 8x < 6x – 4
Step 2: –10 < –2x – 4
Step 3: –6 < –2x
Step 4: ________
What is the final step in solving the inequality –2(5 – 4x) < 6x – 4?
x < –3
x > –3
x < 3
x > 3
Answer:
x < 3
Step-by-step explanation:
The last step is to divide by -2. When you divide by a negative number you must reverse (flip) the inequality symbol.
-6 < -2x
-6/-2 > -2x/-2
3 > x
This is the same as
x < 3 (see the pointy side pointing at the x and the wide open side facing the 3)
What is the value of x?
Enter your answer in the box.
x =
Answer:
4
Step-by-step explanation:
In triangle JKL, the side opposite the 30 degree angle, JL, is half the length of the hypotenuse, KL. Thus, JL has a length of
[tex]4 \sqrt{2} [/tex]
In triangle JML, the hypotenuse is
[tex] \sqrt{2} [/tex]
times the length of the leg, meaning that x = 4
Without using the formula, work out the gradient of the graph shown.
Give your answer in its simplest form?
Answer:
Slope is 3/4
Step-by-step explanation:
Gradient means slope. So, to find the slope without using the formula, look at two points then count up until you're in line with the other point, then count right until you reach the other point. Remember it must be written as rise/run.
I hope this explanation makes sense!
The points I will use is (0,-2) and (4,1).
Slope is 3/4.
Hope this helps!
If not, I am sorry.
What is the decimal multiplier to increase by 93%?
Answer:
0.93
Step-by-step explanation:
Why might the t-test be more useful in actual practice when you are running statistics rather than a z-test? give an example of a situation where you might use each of these and label their pros and cons.
The t-test might be more useful in actual practice when standard deviation or variance is unknown.
What is a t-test?The t-test is used to determine how the averages of various data sets differ from one another.
When variance is not provided, the T-test, a particular kind of parametric test, is used to determine how the means of two sets of data differ from one another. When variance is provided, the Z-test indicates a hypothesis test that determines whether the means of two datasets differ from one another.
Example of t-test: If you flip a coin 1,000 times, for instance, you can discover that the outcome is distributed normally over all trials.
Example of z-test: We are conducting research using information gathered from cohorts of students who have taken Elementary Statistics in the past.
T-tests are typically more suitable when addressing issues with small sample sizes, whereas z-tests are suitable for large sample sizes.
Using the t-test for an ordinal variable, their frequency is not even close to a normal distribution, and the arithmetic mean offers an unsuitable measure of location.
Because we frequently don't know the population standard deviation, Z-Tests have this drawback.
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Work out m and c for the line:
y = 2 − 3 x
Answer:
m = -3
c = 2
Step-by-step explanation:
This equation is given in slope-intercept form. The general structure of these equations is:
y = mx + c
In this form, "m" represents the slope and "c" represents the y-intercept. As you have been given the entire equation, the only thing you have to do is rearrange the equation to find which values correspond with the variables.
y = 2 - 3x -----> y = -3x + 2
Therefore,
m = -3
c = 2
what are simultaneous equations
Answer:
Simultaneous equations are two or more algebraic equations that share variables e.g. x and y . They are called simultaneous equations because the equations are solved at the same time. Each of these equations on their own could have infinite possible solutions.
Willing to give brainlyest if you can aswer these for me ASAP
Answer:
65
Step-by-step explanation:
its simple math
Answer:
x+5=12. x = 7,
7x=21. x = 3,
b-2/3=5/6. b = 1.5,
3/4x=6x=8. x = 1/3,
45=3(x+1). x = 14,
22.5+1.5x. x = 15,
20+(5•9). $65
Step-by-step explanation:
jackie brought 9 plants
Answer:
t+s = 9
4t+9s=51
tulips and succulents combined is 9 plants
the amount of money they have combined is $51
4 apples and 3 pears=£2.70 2 apples and 5 pears =£2.40 how much does 1 apple cost and 1 pear
Answer:
The answer is 0.45 pounds for an apple and 0.3 pounds for a pear
Step-by-step explanation:
Answer:
Cost of each apple: [tex]0.45[/tex].
Cost of each pear: [tex]0.30[/tex].
Step-by-step explanation:
Let [tex]x[/tex] denote the cost of each apple. Let [tex]y[/tex] denote the cost of each pear.
The question states that the cost of [tex]4[/tex] apples and [tex]3[/tex] pears is [tex]2.70[/tex]. Thus:
[tex]4\, x + 3\, y = 2.70[/tex].
Likewise, since the cost of [tex]2[/tex] apples and [tex]5[/tex] pears is [tex]2.40[/tex]:
[tex]2\, x + 5\, y = 2.40[/tex].
Solve this system of equations for [tex]x[/tex] and [tex]y[/tex] to find the price of each fruit.
[tex]\left\lbrace \begin{aligned} & 4\, x + 3\, y = 2.70 \\ & 2\, x + 5\, y = 2.40\end{aligned}\right.[/tex].
Multiply both sides of the equation [tex]2\, x + 5\, y = 2.40[/tex] by [tex]2[/tex] to match the coefficient of [tex]x[/tex] in the first equation:
[tex]\left\lbrace \begin{aligned} & 4\, x + 3\, y = 2.70 \\ & (2\times 2)\, x + (2 \times 5)\, y = (2 \times 2.40)\end{aligned}\right.[/tex].
[tex]\left\lbrace \begin{aligned} & 4\, x + 3\, y = 2.70 \\ & 4\, x + 10\, y = 4.80 \end{aligned}\right.[/tex].
Substitute the first equation from the new equation to eliminate [tex]x[/tex] and solve for [tex]y[/tex]:
[tex]\begin{aligned}& 4\, x + 10\, y - (4\, x +3\, y) = 4.80 - 2.70\end{aligned}[/tex].
[tex]10\, y - 3\, y = 2.10[/tex].
[tex]7\, y = 2.10[/tex].
[tex]y = 0.30[/tex].
Substitute [tex]y = 0.30[/tex] into an equation from the original system to eliminate [tex]y[/tex] and solve for [tex]x[/tex].
[tex]2\, x + 5\, y = 2.40[/tex].
[tex]2\, x + 5 \times 0.30 = 2.40[/tex].
[tex]2\, x = 0.90[/tex].
[tex]x = 0.45[/tex].
Thus, [tex]x = 0.45[/tex] and [tex]y = 0.30[/tex].
In other words, the price of each apple would be [tex]0.45[/tex]. The price of each pear would be [tex]0.30[/tex].
what’s the inverse of f(x)=(x+3)^3-1
Answer:
cbrt(x+1)-3=y
Step-by-step explanation:
The inverse of a function is when the domain and range are swapped. So to find the inverse simply swap the x and y in the equation and then solve for y.
[tex]y = (x+3)^3-1\\x=(y+3)^3-1\\x+1=(y+3)^3\\\sqrt[3]{x+1}=y+3\\\sqrt[3]{x+1}-3=y[/tex]
Which ordered pair would form a proportional relationship with the point graphed below?
Answer:
(c) (-30, 10)
Step-by-step explanation:
Two points will be on the same graph of a proportional relationship if the ratio of values y/x is the same.
__
The given point (x, y) = (60, -20) has a ratio k = y/x = -20/60 = -1/3.
The offered points have y/x ratios ...
(a) 30/-10 = -3
(b) -15/30 = -1/2
(c) 10/-30 = -1/3 . . . . . . the point you are looking for is (-30, 10)
(d) -30/80 = -3/8
What is the solution set for -1<-2f+1<9? Please show work and chose a b c and d
The solution set is 1 ≥ f ≥ -4, and the correct number line is the one in option A.
How to find the solution set?
Here we have the inequality:
-1 ≤ -2f + 1 ≤ 9
To solve this, we need to isolate the "f" on the middle.
First, we can subtract 1 in both sides to get:
-2 ≤ -2f ≤ 8
Now we need to divide both sides by -2, remember that this will change the direction of the symbols:
-2/-2 ≥ f ≥ 8/-2
1 ≥ f ≥ -4
So we need to have a line that starts at -4 and ends at 1, the correct option is number line A.
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Question 8 of 10
What are the zeros of f(x) = x² − 8x + 16?
A. x= -4 and x = 4
B. x=-2 and x = 8
C. x = 4 only
D. x = -4 only
Answer:
c ×=4, only
Step-by-step explanation:
4*-8×+16=0
16-32=-16
-16=-16
Answer:
D. x=4 only
Step-by-step explanation:
You can solve using the quadratic equation which is [tex]x=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}[/tex]
where in this case a=1, b=-8, and c=16. But there is any easier way to solve the equation. You can solve by completing the square which consists of moving the constant to the right side and then adding [tex](\frac{b}{2})^2[/tex]. To both sides that way you can rewrite the left side as a perfect square binomial. This is because [tex](x+b)^2[/tex] will expand to [tex]x^2 + 2xb + b^2[/tex]. So when you add [tex](\frac{b}{2})^2[/tex] to both equations. You're able to rewrite the left side as [tex](x+(\frac{b}{2}))^2[/tex]. Because once you expand it out, it becomes [tex]x^2 + 2(\frac{b}{2})x + (\frac{b}{2})^2[/tex]. Which simplifies to [tex]x^2 + bx + (\frac{b}{2})^2[/tex] which is the original equation. In this case there is no need to move the constant, which in this case is 16, to the other side. Since if you calculate the value of (-8/2)^2 it's equal to 16! So this can already be written as a perfect square binomial.
So the equation becomes
[tex]0 = (x+\frac{b}{2})^2[/tex]
Plug values in
[tex]0 = (x+(-\frac{8}{2}))^2[/tex]
Simplify
[tex]0 = (x-4)^2[/tex]
Take the square root of both sides
[tex]0 = x-4[/tex]
Add 4 to both sides
[tex]4 = x[/tex]
Which series of transformations will not map figure Q onto itself?
O(x+2, y-2), reflection over y = x - 1
O(x-2, y + 2), reflection over y = x + 3
O(x+0y-4), reflection over y = x - 1
O(x-3, y-3), reflection over y = -x +1
Question 1 (Answered)
OF
Your question is incomplete. Below you will find the missing content.
Which series of transformations will not map figure H onto itself?
A. O(x+0, y-2), reflection over y = 1
B. O(x+2, y-0), reflection over x=3
C. O(x+3, y+3), reflection over y = -x +7
D. O(x-3, y-3), reflection over y = -x +2
The correct option is Option D: the series of transformation O(x-3, y-3), reflection over y = -x +2 will not map figure H onto itself.
Here given a square with its 4 vertices at coordinates (2,1), (1,2), (2,3) and (3,2).
By checking all the options
Option A:
1st transformation (x+0, y-2) will map 4 vertices of the square into points of coordinates such as
(2,1) → (2,-1)
(1,2) → (1,0)
(2,3) → (2,1)
(3,2) → (3,0)
next transformation which is the reflection over y=1 gives the coordinates (x,2-y)
(2,-1) → (2,3)
(1,0) → (1,2)
(2,1) → (2,1)
(3,0) → (3,2)
These new points are exactly the same as the vertices of the initial square.
Option B:
1st transformation (x+2, y-0) will map 4 vertices of the square into points of coordinates such as
(2,1) → (4,1)
(1,2) → (3,2)
(2,3) → (4,3)
(3,2) → (5,2)
next transformation which is the reflection over x=3 gives the coordinates (6-x,y)
(4,1) → (2,1)
(3,2) → (3,2)
(4,3) → (2,3)
(5,2) → (1,2)
These new points are exactly the same as the vertices of the initial square.
Option C:
1st transformation (x+3, y+3) will map 4 vertices of the square into points of coordinates such as
(2,1) → (5,4)
(1,2) → (4,5)
(2,3) → (5,6)
(3,2) → (6,5)
next transformation which is the reflection over y=-x+7 gives the coordinates such as
(5,4) → (3,2)
(4,5) → (2,3)
(5,6) → (1,2)
(6,5) → (2,1)
These new points are exactly the same as the vertices of the initial square.
Option D:
1st transformation (x-3, y-3) will map 4 vertices of the square into points of coordinates such as
(2,1) → (-1,-2)
(1,2) → (-2,-1)
(2,3) → (-1,0)
(3,2) → (0,-1)
next transformation which is the reflection over y=-x+2 gives the coordinates such as
(-1,-2) → (4,3)
(-2,-1) → (3,4)
(-1,0) → (2,3)
(0,-1) → (3,2)
These new points are not matching with the vertices of the initial square.
Therefore the correct option is Option D: O(x-3, y-3), reflection over y = -x +2 will not map figure H onto itself.
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how many feet? help me please
Answer:
[tex]\fbox {400.41 feet}[/tex]
Step-by-step explanation:
Here we need to take the tan ratio of the angle.
⇒ tan 4° = 28/x = 0.0699268119
⇒ x = 28/0.0699268119
⇒ x = 400.41 feet
question attached below
If the first inequality is written as:
3x ≤ -12
Then the correct option is D.
If it is written as it is in the problem, then neither of the graphs is the correct option.
How to solve the compound inequality?
Here we have the inequalities:
3x ≤ 12
2x + 3 > 11
(notice that in all the options, the first inequality has a negative sign, while in the two given inequalities there are no negative sign. This means that you will never get the correct answer if you use the given information, as the problem is incorrectly written).
First, we need to isolate x on both inequalities, we will get:
3x ≤ 12
x ≤ 12/3
x ≤ 4
(As you can see, because we don't have the negative sign, this inequality is different to all the ones in the options).
And for the other:
2x + 3 > 11
2x > 11 - 3
x > 8/2
x > 4
So neither of the options is actually correct.
If we instead write the first inequality as:
3x ≤ -12
We would solve this as:
x ≤ -4
And in that case, our two inequalities are:
x ≤ -4
x > 4
So the correct graph is graph D.
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Domain and range of f(x)=3x^2-9x+8
The range of the function lies between (0,8) to (1.5,1.25).
What are domain and range?Range and Domain. The range of values that we are permitted to enter into our function is known as the domain of a function. The x values for a function like f make up this set (x). A function's range is the collection of values it can take as input. After we enter an x value, the function outputs this sequence of values.
The given function is:-
f(x) = 3x² -9x + 8
The value of the range will be from (0,8) to ( 1.5,1.25). When we plot the graph of the function the value of the range lies between the points (0,8) to ( 1.5,1.25). The graph is attached with the answer.
The domain of the function will be all the values of the real numbers for the function ranges from ( 0, ∞ ).
Therefore the range of the function lies between (0,8) to (1.5,1.25).
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please help mee, (30 points will give brainliest!!!)
Answer:
-4
+3
12
-0.5, 12.25
x = -0.5
Step-by-step explanation:
The x intercepts are the values of x when y = 0 ie the roots of the equation
[tex]-x^2 -x +12 = 0[/tex]
or
[tex]x^2 + x - 12 = 0[/tex]
We can re-write the above as:
(x+4) (x-3) = 0
This gives the two roots as x = -4 and x = +3. Leftmost (smallest) root is -4 and rightmost(largest) root is +3
y intercept is when x = 0. Plugging into the original equation, y value at x = 0 is 12
Vertex x value is given by the formula -b/2a where a is the coefficient of x^2 and b the coefficient of x
Here a = -1, b= -1 so vertex x value = - (-1)/(-1).2 = - 1/2 = -0.5
Plugging this value of x into the original function gives the vertex y value
[tex]y = - (0.5^{2}) - (-0.5) + 12\\= -0.25 + 0.5 + 12 = 12.25[/tex]
The line of symmetry is the vertical line corresponding to the vertex x value so line of symmetry is at x = -0.5
The graph of the quadratic function shows these values
Helppp!!!
[tex] \dfrac{2}{15} \div \dfrac{20}{3} [/tex]
.........
[tex]{\huge \underline{{ \fbox \color{red}{A}}{\fbox \color{green}{n}}{\fbox \color{purple}{s}}{\fbox \color{brown}{w}}{\fbox \color{yellow}{e}}{\fbox \color{gray}{r } }}}[/tex]
[tex] \sf \dfrac{2}{15} \div \dfrac{3}{20} = \dfrac{2 \times 20}{15 \times 3} = \dfrac{40}{45} = \dfrac{8}{9} [/tex]
Answer :-
[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf \Rrightarrow \dfrac{8}{9} [/tex]
I hope I've helped : )
[tex]\dfrac{1}{50}[/tex]
Step-by-step explanation:1. We multiply.[tex] \cfrac{2}{15} \times \cfrac{3}{20} [/tex]
2. We join the fractions and put it only in 1.[tex] \cfrac{2 \times 3}{15 \times 20} [/tex]
3. We multiply the one above which is 2 × 3.[tex] \cfrac{6}{15 \times 20} [/tex]
4. Now we will multiply the below.[tex] \cfrac{6}{300} [/tex]
5. Now we simplify.[tex] \cfrac{1}{50} [/tex]
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Peter gave away 5/12 of his marbles and had 70 left how many marbles he had at first
Answer:
There were 120 marbles to start
Step-by-step explanation:
Let x be the number of marbles at the start
x* 5/12 = number of marbles given away
1 -5/12 = 7/12 = fraction of marbles left
x * 7/12 = number of marbles left
x * 7/12 = 70
Multiply each side by 12/7
x *7/12 * 12/7 = 70 * 12/7
x =120
There were 120 marbles to start
What is 2 2/3 - (-3 2/6) show your work
The value of the expression 2 2/3 - (-3 2/6) is 6
How to solve the expression?The expression is given as:
2 2/3 - (-3 2/6)
Open the bracket
2 2/3 + 3 2/6
Express as improper fractions
8/3 + 20/6
Rewrite as:
16/6 +20/6
Evaluate the sum
36/6
Evaluate the quotient
6
Hence, the value of 2 2/3 - (-3 2/6) is 6
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if y= 2f(g(x)), then d^2y/dx^2=
Use the chain rule to differentiate both sides of the given equation with respect to [tex]x[/tex] :
[tex]y = 2 f(g(x))[/tex]
[tex]\dfrac{dy}{dx} = y' = 2 f'(g(x)) g'(x)[/tex]
Differentiate again with the product and chain rules to get the second derivative :
[tex]\dfrac{d^2y}{dx^2} = y'' = \boxed{2 f'(g(x)) g''(x) + 2 f''(g(x)) g'(x)^2}[/tex]
(D)
the rock cycle is an explanation of the conservation of
A. Magma
B. Matter
C. Sediment
Answer:
B. Matter
Explanation:
When rocks break down and become smaller ex: mountains eventually becoming sand, the matter does not disappear or get destroyed, it becomes smaller particles, but the matter is always preserved.
Hope It Helps!!!
Answer:
matter
Step-by-step explanation:
The conservation of matter states that
matter is neither created nor endorsedHere big matters gets down into smaller pieces
but they are not destroyed
If the nth term of a sequence is 11n+2 what is the 12th term
Answer:
134
Step-by-step explanation:
the "nth" term of a sequence means that you can plug in the term number to get the term value
so, if
11n + 2 is the sequence
11(12) + 2 is the 12th term
132 + 2 is the 12th term
134 is the 12th term
By plugging in the term "place" (1st, 2nd, 3rd, 4th, etc.) for the variable "n", we get a term value.
hope this helps!!
The 12th term of the sequence is 133
How to determine the 12th term?The nth term is given as:
Tn = 11n + 1
The 12th term is calculated as:
T(12) = 11(12) + 1
Evaluate
T(12) = 133
Hence, the 12th term of the sequence is 133
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Evaluate the function: g(x) = -x +4 Find: g(b-3)
Answer:
g(b-3) = -b + 7
Step-by-step explanation:
Plug in the value (b-3) as x into the equation
g(b-3) = -(b-3) + 4
distribute the negative sign
g(b-3) = -b + 3 + 4
combine like terms
g(b-3) = -b + 7
The exterior of a solid cone is painted. The height of the cone is 11.4 centimeters, and the diameter of its opening is 5 centimeters.
What is the surface area of the solid cone requiring paint to the nearest square centimeter?
The surface area of the solid cone requiring paint rounded to the nearest whole number is ___________ square centimeters.
Answer:
111 cm^2
Step-by-step explanation:
h = 11.4
d = 5 so r (radius) = 2.5
Surface Area of a Cone Formula: πr^2 + πrs
s represents the slant height of the cone, lets represent this with a drawing.
We have the values of h and r, but we don't have the value of s, meaning we have to find it. We can do this by using pythagorean theorem.
a^2 + b^2 = c^2
These three values can come together to create a right triangle which we can seperate from the rest of the diagram, now we can find s.
s = √(11.4^2 + 2.5^2) so s = 11.67
now that we have all of the pieces, we can plug back into the original surface area formula. πr^2 + πrs
π(2.5^2) + π(2.5)(11.67) = 111.29 cm^2 or 111 cm^2
The surface area of the solid cone requiring paint will be 111 square cm.
What is the surface area of a cone?Let d be the diameter of the base circle, l be the slant height, and h be the height of the cone.
Then the lateral surface area of the cone will be
SA = πrl + πr²
Then the slant height is given as
l² = r² + h²
The exterior of a solid cone is painted. The height of the cone is 11.4 centimeters, and the diameter of its opening is 5 centimeters.
Then the radius of the base circle will be
r = 5 / 2
r = 2.5 cm
The length of the slant height will be
l² = 11.4² + 2.5²
l² = 136.21
l = 11.67
Then the surface area of the solid cone requiring paint will be
SA = π × 2.5 × 11.67 + π × 2.5²
SA = 29.18π + 6.25π
SA = 35.43π
SA = 111.3
SA ≈ 111 square cm
The surface area of the solid cone requiring paint will be 111 square cm.
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there were 3 parts to Ritas race she ran the first part which was 4/9 of the total distance, in 20 minutes she ran the second part which was 2/5 of the remaining distance, in 12 minutes. She finally ran the third part in 15 minutes at the speed of 300 meters per minute.
How long was the first part of the race? What was Ritas speed in that section of the race?
Answer:
3/5 .................................. 6/9
Step-by-s4tep explanation:
Answer:
300 meters per minute
Step-by-step explanation:
Step 1
Determine the fraction of the total distance for each part of the race.
Given:
1st part of race = 4/9 of total distance2nd part of race = 2/5 of remaining distance[tex]\begin{aligned} \implies \sf 2nd\:part & = \sf \dfrac{2}{5}\:of\:remaining\:distance\\ & = \sf \dfrac{2}{5} \times\left(1-\dfrac{4}{9}\right)\\& = \sf \dfrac{2}{9}\:of\:total\:distance\end{aligned}[/tex]
[tex]\begin{aligned}\implies \sf 3rd\:part & = \sf 1-1st\:part-2nd\:part\\& = \sf 1-\dfrac{4}{9}-\dfrac{2}{9}\\& = \sf \dfrac{1}{3}\:of\:total\:distance\end{aligned}[/tex]
Step 2
Determine the distance of the third part of the race.
Given:
time = 15 minutesspeed = 300 meters per minute[tex]\begin{aligned}\sf Distance & = \sf speed \times time\\& = \sf 300 \times 15\\& = \sf 4500 \:\:meters\end{aligned}[/tex]
Step 3
If the third part of the race (which is 1/3 of the total distance) is 4500m, then the distance of the whole race is:
[tex]\begin{aligned} \sf Total\:distance & = \sf 4500 \times 3\\& = \sf 13500\:meters \end{aligned}[/tex]
Step 4
Determine the distance of the 1st part of the race:
[tex]\begin{aligned}\sf Distance\:of\:1st\:part\:of\:race & = \sf \dfrac{4}{9} \:of\:total\:distance\\& = \sf \dfrac{4}{9} \times 13500\\& = \sf 6000\:meters \end{aligned}[/tex]
Step 5
Determine the speed of the 1st part of the race:
Given:
time = 20 minutesdistance = 6000 m[tex]\begin{aligned}\sf Speed\:of\:1st\:part\:of\:race & = \sf \dfrac{distance}{time}\\& = \sf \dfrac{6000}{20}\\ & = \sf 300\:meters\:per\:minute\end{aligned}[/tex]
[tex]\sf\large\green{\underbrace{\red{Befikra*}}}:[/tex].
The first term of an arithmetic sequence is 1 and the sum of the first four terms is 100. Find the first four terms
First term f = 1
If first four terms are f, f + d, f + 2d, f + 3d
f + f + d + f + 2d + f + 3d = 100
4f + 6d = 100 (divided by 2 , both sides )
2f + 3d = 50
2 + 3d = 50
3d = 50 – 2
3d = 48
d = 48/3
d = 16
The arithmetic sequence is 1, 17, 33, 49, ………….
Answer:
[tex]\sf\large\blue{\underbrace{\red{itz \: jass*}}}:[/tex]
Step-by-step explanation:
[tex]\sf\large\green{\underbrace{\red{hlo \: \: sat \: shri \: akal \: ji \: \: \: *}}}:[/tex]
Can someone help me please?
Answer:
C.
Step-by-step explanation:
The reds are counting up in whole numbers by one integer.
Hope this helps!
If not, I am sorry.
