A gardener pushes a shovel into the ground with a force of 75 N. The angle of the shovel to the ground is 80 degrees. What is the downward force of the shovel? A. 13.0 N B. 73.9 N C. 75.2 N D. 80.0 N

Answer:

B) The lighter gases boiled off of the protoplanets closest to the sun, leaving dust and metals behind to form the inner planets.

Explanation:

Inner planets are smaller and rockier than outer gas planets,outer planets are larger,because of their lower gravity they don't attract extreme amounts of gas in their planets.The four outer planets were so far from the Sun that its winds could not blow away their ice and gases

Answer:

The monkey will get hit by the dart. This is because when the dart is fired the force of gravity makes it fall from its original position. The monkey also has the same fall from the branches which means they will both be falling at the same gravitational rate.

This will eventually make the monkey to get hit by the dart.

Answer: Iron and steel are two separate metallic elements.

Explanation:

The following are the differences between magnetic properties of iron and steel.:

1. Iron get magnitized quickly under the influence of magnetic field whereas the steel magnitized slowly.

2. The iron looses its magnitism when magnetic field is removed but steel retains the magnitism for long when magnetic field is removed.

Answer:

A drunk driver's car travel 49.13 ft further than a sober driver's car, before it hits the brakes

Explanation:

Distance covered by the car after application of brakes, until it stops can be found by using 3rd equation of motion:

2as = Vf² - Vi²

s = (Vf² - Vi²)/2a

where,  

Vf = Final Velocity of Car = 0 mi/h

Vi = Initial Velocity of Car = 50 mi/h

a = deceleration of car  

s = distance covered

Vf, Vi and a for both drivers is same as per the question. Therefore, distance covered by both car after application of brakes will also be same.

So, the difference in distance covered occurs before application of brakes during response time. Since, the car is in uniform speed before applying brakes. Therefore, following equation shall be used:

s = vt

FOR SOBER DRIVER:

v = (50 mi/h)(1 h/ 3600 s)(5280 ft/mi) = 73.33 ft/s

t = 0.33 s

s = s₁

Therefore,

s₁ = (73.33 ft/s)(0.33 s)

s₁ = 24.2 ft

FOR DRUNK DRIVER:

v = (50 mi/h)(1 h/ 3600 s)(5280 ft/mi) = 73.33 ft/s

t = 1 s

s = s₂

Therefore,

s₂ = (73.33 ft/s)(1 s)

s₂ = 73.33 ft

Now, the distance traveled by drunk driver's car further than sober driver's car is given by:

ΔS = s₂ - s₁

ΔS = 73.33 ft - 24.2 ft

ΔS = 49.13 ft

Answer:

259.52N

Explanation:

Force initiated on a spring that causes an extension is related by the expression below;

F= K×e

Where F is the Force

K is the spring constant

e is the extension caused by the spring.

By change of subject formula for K;

K = F/e

Now F is the same as weight and is given by mass× acceleration. In this case acceleration is g=9.8m/s2; this is because the child's mass is going to be under the influence of gravity as it swings up the harness}

Hence W =7.15×9.8=70.07N

Hence K = 70.07/0.27 =259.5185N/m

=259.52N/m to 2 decimal place.

your answer is b to be presided

Answer:[tex]4\ m/s^2[/tex]

Explanation:

Given

mass of toy [tex]m=0.5\ kg[/tex]

Force by first dog [tex]F_1=140\ N[/tex]

Force by second dog is [tex]F_2=138\ N[/tex]

Net force on the dog is

[tex]F_{net}=F_1-F_2=140-138[/tex]

[tex]F_{net}=2\ N[/tex]

and [tex]F_{net}=ma[/tex]

[tex]a=\dfrac{F_{net}}{m}[/tex]

[tex]a=\dfrac{2}{0.5}[/tex]

[tex]a=4\ m/s^2[/tex]

So, horizontal acceleration of the toy is [tex]4\ m/s^2[/tex]

Answer:

Explanation:

2 )

power of an electric device = V² / R where V is volts and R is resistance

putting given data

power = 9²/ 5

= 16.2 J/s

energy produced in 7 minutes

= 16.2 x 7 x 60

= 6804J .

3 ) Power of an electrical device

= V² / R

= V X I where I  is current

= 4.5 x .5

= 2.25 W or J/s

4 )

energy used in 3 minutes with power of 2.25 W

= 2.25 x 3 x 60

= 405 J .

7 )

power of a electrical device

= V x I

IR x I  where R is resistance .

= I²R

putting given data

power = .005² x 50

= 1.25 x 10⁻³ W .

8 )

Energy used up by a 60 W bulb in 2.5 hours

= 60 x 2.5 x 60 x 60

= 5.4 x 10⁵ J .

Answer:

Explanation:

Given the equation modelled by the height of the train given as:

s(t) = 18t²-2t³ for for 0 ≤ t ≤ 9

a) Velocity is the rate of change of displacement.

Velocity = dS(t)/dt

V = dS(t)/dt = 36t - 6t² miles

Velocity at t = 3hrs is determiner by substituting t = 3 into the velocity function.

V = 36(3) -6(3)²

V= 108 - 72

Velocity = 36mi/hr

b) for Velocity at time = 7hrs

V(7) = 36(7) - 6(7)²

V(7) = 252 - 294

V(7) = -42mi/hr

The velocity at t = 7hrs is -42mi/hr

c) Acceleration is the rate of change of velocity.

a(t) = dV(t)/dt

Given v(t) = 36t - 6t²

a(t) = 36 - 12t

Acceleration at t=1 is given as:

a(1) = 36 -12(1)

a(1) = 24mi/hr²

Answer:

C

Explanation:

Researches have shown that Optimism may lead to the advancement of a balanced lifestyle and proactive behavior, cognitive responses combined with improved resilience and problem solving abilities and a more successful processing of negative input will make a huge difference to mental and physical well-being.

So, Students who participated in an optimism workshop had fewer episodes of depression, fewer health problems and had fewer episodes of anxiety.So, the correct answer is C.

The answer is All Of These

Answer:

The current is  [tex]I = 0.4595 \ A[/tex]

Explanation:

From the question we are told that

    The length of the wire is  [tex]L = 64.7 \ cm = 0.647 \ m[/tex]

    The magnetic field is  [tex]B = 0.370 \ T[/tex]

      The magnetic force is  [tex]F = 0.110 \ N[/tex]

Generally the magnetic force exerted by the field is mathematically represented as

      [tex]F = IL B sin \theta[/tex]

Making I the subject we have

      [tex]I = \frac{F}{LB \ sin\theta}[/tex]

The angle here is  90° since the wire is perpendicular  to the direction of the magnetic field

      Substituting values

     [tex]I = \frac{0.110}{ (0.370) * 0.647 \ sin(90)}[/tex]

   [tex]I = 0.4595 \ A[/tex]

Answer:

Electron cloud model describes the region in an atom which negatively charged and which has probability to find an electron. according to this model, an electron can move closer or away from the nucleus that is it can be inside the nucleus but according to Bohr's model, an electron is always at a fixed distance from the nucleus. Thus, it is the limitation of the electron cloud model but still it is a widely accepted model.

Answer:

Beta Particle

Explanation:

The beta particle decay completes the following reaction,

¹⁴C₆   ⇒ ¹⁴N₇ + Beta particle

Therefore the answer is option D.

Radioactive decay is a type of nuclear reaction in which the unstable nucleus of a radioactive element releases energy in the form of nuclear radiation. Alpha decay, decay, and beta decay are a few examples of radioactive decay.

The radioactive deacy is acompained by the release of the enormous amount of energy,the nuclear power generation with the help of the nuclear reaction is one of the most significant application of the radioactive decay.

¹⁴C₆   ⇒ ¹⁴N₇ + Beta particle

Beta particles are the negatively charged electron emitted from radioactive decay.

For the given reaction the unstable carbon atom losses a beta particle to produce a stable nitrogen atom.

Thus the given radioactive decay can is completed by beta particle emission.

Learn more about radioactive decay from here

https://brainly.com/question/1770619

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Answer:

The electrical force on 2nd charge (3 Q) will also be equal to F.

Explanation:

The electrical force between two electrically charged particles is given by the Coulomb's Law. The mathematical formula of Coulomb's Law is as follows:

F = kQ₁Q₂/r²

where,

F = Electrical Force exerted by both particles on each other

k = Coulomb's Constant

Q₁ = Magnitude of 1st Charge = Q

Q₂ = Magnitude of 2nd Charge = 3 Q

r = Distance between the charges

Therefore,

F = k(Q)(3 Q)/r²

F = 3 kQ²/r²

Since, it is clear from the formula that the magnitude of force applied by the first charge on 2nd charge is equal to the force applied by 2nd charge on 1st charge.

Therefore, the electrical force on 2nd charge (3 Q) will also be equal to F.

Answer:

Hey!

Your answer is C!

Explanation:

HOPE THIS HELPS!!

Straight line with no slope explains what a velocity time graph would look like with no acceleration. The correct option is 3.

When there is no acceleration, the item is travelling at a steady speed. The y-axis of a velocity-time graph represents velocity, while the x-axis represents time.

A straight line with no slope implies constant velocity, where the velocity remains constant over time. There is no change in velocity, which indicates that there is no acceleration.

Thus, on the velocity-time graph, a straight line with no slope depicts an object travelling with no acceleration. The correct option is 3.

For more details regarding velocity-time graph, visit:

https://brainly.com/question/33512397

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Your question seems incomplete, the probable complete question is:

Which explains what a velocity time graph would look like with no acceleration?

Answer:

-450 m/s

Explanation:

Momentum is conserved.

p₀ = p

0 = (1.5 kg) (1.5 m/s) + (0.005 kg) v

v = -450 m/s

Answer:

r = 4.23 m

Explanation:

To find the radius of the circular path of the electron you use the following formula:

[tex]r=\frac{mv}{qB}[/tex]  (1)

This formula can be used because the motion of the electron is perpendicular to the direction of the magnetic field vector.

m: mass of the electron = 9.1*10^-31 kg

q: charge of the electron = 1.6*10^-19 C

B: magnitude of the magnetic field = 1.02*10^-5 T

v: velocity of the electron = 7.6*10^6 m/s

You replace the values of m, v, q and B in the equation (1):

[tex]r=\frac{(9.1*10^{-31}kg)(7.6*10^6 m/s)}{(1.6*10^{-19}C)(1.02*10^{-5}T)}\\\\r=4.23m[/tex]

hence, the raiuds of the orbit of the electron is 4.23m

Answer:

Nancy Elizabeth Lieberman (nacido el 1 de julio de, 1958), apodado "Señora mágica", ] es un ex profesional jugador de baloncesto y entrenador de la WNBA (WNBA) que es actualmente un organismo de radiodifusión para los New Orleans Pelicans de la Nacional La Asociación de Baloncesto (NBA) y la entrenadora principal de Power , un equipo en el BIG3 que lideró en su Campeonato 0.]bLieerman es considerada como una de las figuras más importantes del baloncesto femenino estadounidense.

Explanation:

Answer:

F/L =  8*10^-4 N/m

Explanation:

To calculate the magnitude of the force per meter in the central wire, you take into account the contribution to the force of the others two wires:

[tex]F_N=F_{1,2}+F_{2,3}[/tex]   (1)

F1,2 : force between first and second wire

F2,3 : force between second and third wire

The force per meter between two wires of the same length is given by:

[tex]\frac{F}{L}=\frac{\mu_oI_1I_2}{2\pi r}[/tex]

μo: magnetic permeability of vacuum =  4pi*10^-7 T/A

r: distance between wires

Then, you have in the equation (1):

[tex]\frac{F_N}{L}=\frac{\mu_oI_1I_2}{2\pi r}+\frac{\mu_oI_2I_3}{2\pi r}\\\\\frac{F_N}{L}=\frac{\mu_oI_1}{2\pi r}[I_2+I_3][/tex]

But

I1 = I2 = I3 = 10A

r = 10cm = 0.1m

You replace the values of the currents and the distance r and you obtain:

[tex]\frac{F_N}{L}=\frac{\mu_oI^2}{\pi r}\\\\\frac{F_N}{L}=\frac{(4\pi*10^{-7}T/A)(20A)^2}{2\pi (0.1m)}=8*10^{-4}\frac{N}{m}[/tex]

hence, the net force per meter is 8*10^-4 N/m

Answer:

The student is going at the bottom of the slide with a velocity of 8.66 m/s

Explanation:

Given;

mass of the student, m = 74 kg

height of the water slide, h = 11.3 m

work done, W = -5.42 × 10³ J

Apply work energy theorem;

[tex]W = \frac{1}{2}mv_f^2+ mgh_f-(\frac{1}{2}mv_o^2 + mgh_o)\\\\ W + \frac{1}{2}mv_o^2 + mgh_o -mgh_f= \frac{1}{2}mv_f^2\\\\ W + \frac{1}{2}mv_o^2 +mg(h_o-h_f) = \frac{1}{2}mv_f^2\\\\\frac{W}{m} + \frac{1}{2} v_o^2 + g(h_o-h_f) = \frac{1}{2}v_f^2\\\\\frac{2W}{m}+ v_o^2 + 2g(h_o-h_f) = v_f^2\\\\v_f = \sqrt{\frac{2W}{m}+ v_o^2 - 2g(h_f-h_o)} \\\\v_f = \sqrt{\frac{2(-5.42*10^3)}{74}+ (0)^2 - 2*9.8(-11.3)}\\\\v_f=\sqrt{-146.4865+221.48} \\\\v_f = \sqrt{74.9935} \\\\v_f = 8.66 \ m/s[/tex]

Therefore, the student is going at the bottom of the slide with a velocity of 8.66 m/s

Answer:

The new volume is  [tex]11.6L[/tex]

Explanation:

[tex]pressure \alpha \frac{1}{volume}[/tex]

Given data

initial pressure p1= 100atm

initial volume v1= 3.7L

final pressure p2= 32 atm

final volume v2= ?

Apply Boyle's law we have

[tex]p1v1= p2v2\\[/tex]

[tex]v2= \frac{p1v1}{p2}[/tex]

Substituting our data we have

[tex]v2= \frac{100*3.7}{32} \\v2=\frac{370}{32} \\v2= 11.6 L[/tex]

The new volume is [tex]11.6L[/tex]

Answer:

A

Explanation:

A)

INCORRECT

No, Gauss's Law can not be derived from Coulomb's Law alone. Since, Coulomb's Law provides electric field produced by a single point charge. Therefore, it is important to assume principle of super position along with Coulomb's law to get the field due to all charges. So, Gauss's Law can be proved by the help of both Super Position Principle and Coulomb's law.

B)

CORRECT

Yes, Gauss' law states that the net number of lines crossing any closed surface in an outward direction is proportional to the net charge enclosed within the surface.

C)

CORRECT

Yes, Coulomb's law can be derived from Gauss' law and symmetry.

D)

CORRECT

Yes, Gauss's Law applies to a closed surface of any shape.

E)

CORRECT

Yes, if a closed surface encloses no charge, the electric field is zero everywhere on the surface.

Answer:

Ok

Explanation:

Please mark brainliest

Answer:

It is larger

Explanation:

I believe the answer would be "It is larger" since v = 2v (since it's in series), which would increase the magnetic field and thus produced a bigger angle.

Answer:

a) [tex]E_T=134,484\frac{N}{C}\hat{i}+149954.66\frac{N}{C}\hat{j}[/tex]

b) zero

Explanation:

a) To find the electric field at point C, you sum the contribution of the electric fields generated by the other two charges. The total electric field at C is given by:

[tex]E_T=E_1+E_2[/tex]

E1: electric field of charge 1

E2: electric field of charge 2

It is necessary to calculate the x and y components of both E1 and E2. You take into account the direction of the fields based on the charge q1 and q2:

[tex]E_1=k\frac{q_1}{r_{1,3}}[cos\theta\hat{i}+sin\theta \hat{j}]\\\\E_2=k\frac{q_2}{r_{2,3}}[cos\phi\hat{i}-sin\phi \hat{j}]\\\\[/tex]

r13: distance between charges 1 and 3

r12: charge between charges 2 and 3

k: Coulomb's constant = 8.98*10^9 Nm^2/C^2

Thus, you first calculate the distance r13 and r23, and also the angles:

[tex]r_{1,3}=3.00m\\\\r_{2,3}=\sqrt{(3.00m)^2+(4.00m)^2}=5.00m\\\\\theta=90\°\\\\\phi=tan^{-1}(\frac{4.00}{3.00})=53.13\°[/tex]

Next, you replace the values of all parameters in order to calculate E1 and E2:

[tex]E_1=(8.98*10^9Nm^2/C^2)(\frac{3.30*10^{-4}C}{(3.00m)^2})\hat{j}\\\\E_1=329266.66\frac{N}{C}\\\\E_2=(8.98*10^9Nm^2/C^2)(\frac{6.24*10^{-4}C}{(5.00m)^2})[cos53.13\°\hat{i}-sin(53.13\°)\hat{j}]\\\\E_2=224140.8[0.6\hat{i}-0.8\hat{j}]=134484\hat{i}-179312\hat{j}[/tex]

finally, you obtain for ET:

[tex]E_T=134,484\frac{N}{C}\hat{i}+(329266.66-179312)\frac{N}{C}\hat{j}\\\\E_T=134,484\frac{N}{C}\hat{i}+149954.66\frac{N}{C}\hat{j}[/tex]

b) The x component of the force exerted by A on C is zero because there is only a vertial distance between them. Thus, there is only a y component force.

Answer:

The magnitude of the acceleration is [tex]a_r = 1.50 \ m/s^2[/tex]

The direction is  [tex]\theta = 32.5 6^o[/tex] north of  east

Explanation:

From the question we are told that

   The force exerted by the wind is  [tex]F_{sail} = (330 ) \ N \ north[/tex]

   The force exerted by water is  [tex]F_{keel} = (210 ) \ N \ east[/tex]

      The mass of the boat(+ crew) is  [tex]m_b = 260 \ kg[/tex]

Now Force is mathematically represented as

      [tex]F = ma[/tex]

Now the acceleration towards the north is mathematically represented as

      [tex]a_n = \frac{F_{sail}}{m_b}[/tex]

substituting values

       [tex]a_n = \frac{330 }{260}[/tex]

      [tex]a_n = 1.269 \ m/s^2[/tex]

Now the acceleration towards the east is mathematically represented as

       [tex]a_e = \frac{F_{keel}}{m_b }[/tex]

substituting values

      [tex]a_e = \frac{210}{260}[/tex]

      [tex]a_e =0.808 \ m/s^2[/tex]

The resultant acceleration is  

      [tex]a_r = \sqrt{a_e^2 + a_n^2}[/tex]

substituting values

     [tex]a_r = \sqrt{(0.808)^2 + (1.269)^2}[/tex]

      [tex]a_r = 1.50 \ m/s^2[/tex]

The direction with reference from the north is evaluated as

Apply SOHCAHTOA

        [tex]tan \theta = \frac{a_e}{a_n}[/tex]

       [tex]\theta = tan ^{-1} [\frac{a_e}{a_n } ][/tex]

substituting values

     [tex]\theta = tan ^{-1} [\frac{0.808}{1.269 } ][/tex]

    [tex]\theta = tan ^{-1} [0.636 ][/tex]

   [tex]\theta = 32.5 6^o[/tex]

Answer:

75m/s

Explanation:

...................

Answer:

Useless

Explanation:

Question

Explanation:

We have,

Mass of a baseball is 0.147 kg

Initial velocity of the baseball is 44.5 m/s

The ball is moved in the opposite direction with a velocity of 55.5 m/s

It is required to find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat.

Change in momentum,

[tex]\Delta p=mv-mu\\\\\Delta p=m(v-u)\\\\\Delta p=0.147\times ((-55.5)-44.5)\\\\\Delta p=-14.7\ kg-m/s\\\\|\Delta p|=14.7\ kg-m/s[/tex]

Impulse = 14.7 kg-m/s

Therefore, the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat is 14.7 kg-m/s