Pulling on the cord, exerting a force of 15 N for 2 s and then 25 N for 3 s, and measuring the final angular velocity of the disk.
What is torque?Torque is defined as the rate of change of angular momentum.[tex]\tau = \frac{dL}{dt} \\\\[/tex]
[tex]Fr = \frac{\Delta L}{\Delta t} \\\\Fr = \frac{\Delta m\omega ^2r}{\Delta t} \\\\F = \frac{\Delta m\omega ^2}{\Delta t}[/tex]
[tex]F = \frac{m\Delta \omega ^2}{\Delta t} \\\\F = \frac{m(\omega _f^2 - \omega _i^2)}{t_2 - t_1}[/tex]
where;
[tex]\omega _i[/tex] is the initial angular velocity
[tex]\omega _f[/tex] is the final angular velocity
Since the disk is initial at rest, applying a force such as 15 N gives the disk its first angular velocity and applying 25 N force for 3 seconds gives the disk its final angular velocity.
Thus, the best procedure to determine the relationship between applied torque and the resulting change in angular momentum of the disk is
Pulling on the cord, exerting a force of 15 N for 2 s and then 25 N for 3 s, and measuring the final angular velocity of the disk.Learn more about torque on a disk here: https://brainly.com/question/25482609
large roll of fabric
Costume Rendering
Scissors
Pattern
Bolt
Answer:
Do we have to choose out of those three?
Explanation:
A 1.4-cm-tall object is 22 cm to the left of a lens with a focal length of 11 cm . A second lens with a focal length of -5 cm is 37 cm to the right of the first lens.
Calculate the distance between the final image and the second lens.
Calculate the image height.
Answer:
can you explain yourself more please
Explanation:
Please please help me please
3. At an early age, what happened to Cesar’s home?
Answer: He died later in 78 BC and was accorded a state funeral. Hearing of Sulla's death, Caesar felt safe enough to return to Rome. Lacking means since his inheritance was confiscated, he acquired a modest house in the Subura, a lower-class neighbourhood of Rome. hope this helps. Can u give me brainliest
Explanation:
3. A ball thrown vertically upward returns to its starting point in 4s. Find its initial speed. [4]
Answer:
9.8 ×4 equal 39.2 m/s This is v intial
Two identical objects, A and B, move along straight, parallel, horizontal tracks. The graph above represents the position as a function of time for the two objects.
(a) At a time of 2 seconds, where the lines intersect, do the displacements of the two objects from their initial positions have the same magnitude? Briefly explain your answer.
(b) At a time of 2 seconds, where the lines intersect, do the velocities of the two objects have the same magnitude? Briefly explain your answer.
(c) At a time of 2 seconds, where the lines intersect, which object, if either, has a net force with a greater magnitude exerted on it? If the net force has the same magnitude for both objects, indicate this explicitly
(d) In a clear, coherent paragraph-length response, explain your response to part (c). Be sure to reference and compare the graphed information for both objects A and B.
Answer:
After a little online search, I've found the graph of this question, the graph can be seen below.
a) The displacement is defined as the distance between the final position and the initial position.
In the graph, the vertical axis represents the distance. We also can see that both of the lines start in position 0, so at any given time, the displacement of the objects is given by the vertical position in the graph.
Thus, at t = 2 seconds, both lines have the same y-value, this means that the displacements have the same magnitude.
b) The velocity is related to the slope of the curve,
We can clearly see that the slope of graph A and the slope of gaph B are different at t = 2 seconds (graph A is steeper) then we can conclude that the velocities do not have the same magnitude.
c) By Newton's second law, we know that F = m*a
Force equals mass times acceleration.
Acceleration is the rate of change of velocity. When the position graph is a straight line, in any point of the line the slope will be the same, thus the object has always the same velocity, thus the object is not accelerated.
If we do not have a straight line (like in graph A) then the velocity is changing, then we have acceleration, then we have a force.
Then object A has a greater net force (because object B has a net force equal to 0)
d) It is already explained in point c.
A bicycle rider pushes a 13kg bicycle up a steep hill. the incline is 24 degree and the road is 275m long. the rider pushes the bike parallel to the road with a force of 25N.
A. How much work does the rider do on the bike?
B. How much work is done by the force of gravity on the bike?
Answer:
A. W = 6875.0 J.
B. W = -14264.6 J.
Explanation:
A. The work done by the rider can be calculated by using the following equation:
[tex] W_{r} = |F_{r}|*|d|*cos(\theta_{1}) [/tex]
Where:
[tex]F_{r}[/tex]: is the force done by the rider = 25 N
d: is the distance = 275 m
θ: is the angle between the applied force and the distance
Since the applied force is in the same direction of the motion, the angle is zero.
[tex] W_{r} = |F_{r}|*|d|*cos(0) = 25 N*275 m = 6875.0 J [/tex]
Hence, the rider does a work of 6875.0 J on the bike.
B. The work done by the force of gravity on the bike is the following:
[tex] W_{g} = |F_{g}|*|d|*cos(\theta_{2}) [/tex]
The force of gravity is given by the weight of the bike.
[tex] F_{g} = -mgsin(24) [/tex]
And the angle between the force of gravity and the direction of motion is 180°.
[tex] W_{g} = |mgsin(24)|*|d|*cos(\theta_{2}) [/tex]
[tex] W_{g} = 13 kg*9.81 m/s^{2}*sin(24)*275 m*cos(180) = -14264.6 J [/tex]
The minus sign is because the force of gravity is in the opposite direction to the motion direction.
Therefore, the magnitude of the work done by the force of gravity on the bike is 14264.6 J.
I hope it helps you!
Answer pls quick or dont i dk what to say
Answer:
C!
Explanation:
Cold fronts generally advance at average speeds of 20 to 25 mph. toward the east — faster in the winter than summer — and are usually oriented along a northeast to southwest line.
Answer:
I think not sure B sorry if this is wrong yay if im right
Explanation:
What would be a good reason to increase friction between surfaces? to allow objects to slide past each other easily to reduce wear and tear to provide traction so that slipping does not occur to avoid contact that results in increased temperature and overheating
Answer:
B to provide traction so that slipping does not occur
Explanation:
To increase friction between two surfaces, allow the objects to slide past each other thereby force that is called friction.
What is friction?Friction is a type of force acting on an object to hinder its motion . It is negative by direction, since this force, hinder the motion of the object. Friction is also known as an opposing force because it always acts in the opposite direction of a moving or attempting to move body.
The virtue of friction causes a moving body to slow down. Friction is useful at times because it prevents car tires from skidding on the road and also allows us to walk on the pavement without slipping.
To increase friction , make an uneven, rugged, or sticky point of contact. When two or more bodies slide or rub against each other, three things can happen: small irregularities, nooks and crannies on the surfaces can catch on each other.
To find more on friction, refer here:
https://brainly.com/question/13000653
#SPJ2
Where does lymph come from?
You set a tuning fork into vibration at a frequency of 683 Hz and then drop it off the roof of the Physics building where the acceleration due to gravity is 9.80 m/s2. Determine how far the tuning fork has fallen when waves of frequency 657 Hz reach the release point
Answer:
The distance traveled by the tuning fork is 9.37 m
Explanation:
Given;
source frequency, [tex]f_s[/tex] = 683 Hz
observed frequency, [tex]f_o[/tex] = 657 Hz
The speed at which the tuning fork fell is calculated by applying Doppler effect formula;
[tex]f_o = f_s [\frac{v}{v + v_s} ][/tex]
where;
[tex]v[/tex] is speed of sound in air = 343 m/s
[tex]v_s[/tex] is the speed of the falling tuning fork
[tex]657 = 683[\frac{343}{343 + v_s} ]\\\\\frac{657}{683} = \frac{343}{343 + v_s}\\\\0.962 = \frac{343}{343 + v_s}\\\\0.962(343 + v_s) = 343\\\\343 + v_s = \frac{343}{0.962} \\\\343 + v_s = 356.55\\\\v_s = 356.55 - 343\\\\v_s = 13.55 \ m/s[/tex]
The distance traveled by the tuning fork is calculated by applying kinematic equation as follows;
[tex]v_s^2 = v_o^2 + 2gh[/tex]
where;
[tex]v_o[/tex] is the initial speed of the tuning fork = 0
g is acceleration due to gravity = 9.80 m/s²
[tex]v_s^2 = 0 + 2gh\\\\h = \frac{v_s^2}{2g} \\\\h = \frac{13.55^2 }{2\times 9.8} \\\\h = 9.37 \ m[/tex]
Therefore, the distance traveled by the tuning fork is 9.37 m
4
What happens because the Earth's orbit
is NOT a perfect circle?
Help Resources
A. We are always the exact same distance away from the
Sun throughout the entire year.
B. At certain timesh during the year, we are closer to the Sun
than at other times.
C. The shape of Earth's orbit does not affect the distance
from the Sun.
State the collective name given to protons, neutrons in the nucleus of an atom.
2 Define the mass number.
3 An atom has atomic number of 28 and mass number of 64.
Find
1, Neutron number.
2, Proton number.
Answer: See explanation
Explanation:
1. The collective name given to protons, neutrons in the nucleus of an atom is referred to as the nucleon.
2. The mass number simply means the total number of both the protons and the neutrons that we have in a nucleus.
3. Atomic number = Protons = 28
Mass number = 64.
Neutron = Mass Number - Protons
Neutron = 64 - 28 = 36
4. The number of Protons is also the number of atomic number which is 28.
Electron spin: Radio astronomers can detect clouds of hydrogen too cool to radiate optical wavelengths of light by means of the 21 cm spectral line corresponding with the flipping of the electron in a hydrogen atom from having its spin parallel to the proton spin to having it antiparallel. From this wavelength, and thus E between states, find the magnetic field experienced by the electron in a hydrogen atom
Answer:
the magnetic field experienced by the electron is 0.0511 T
Explanation:
Given the data in the question;
Wavelength λ = 21 cm = 0.21 m
we know that Bohr magneton μ[tex]_B[/tex] is 9.27 × 10⁻²⁴ J/T
Plank's constant h is 6.626 × 10⁻³⁴ J.s
speed of light c = 3 × 10⁸ m/s
protein spin causes magnetic field in hydrogen atom.
so
Initial potential energy = -μ[tex]_B[/tex]B × cos0°
= -μ[tex]_B[/tex]B × 1
= -μ[tex]_B[/tex]B
Final potential energy = -μ[tex]_B[/tex]B × cos180°
= -μ[tex]_B[/tex]B × -1
= μ[tex]_B[/tex]B
so change in energy will be;
ΔE = μ[tex]_B[/tex]B - ( -μ[tex]_B[/tex]B )
ΔE = 2μ[tex]_B[/tex]B
now, difference in energy levels will be;
ΔE = hc/λ
2μ[tex]_B[/tex]B = hc/λ
2μ[tex]_B[/tex]Bλ = hc
B = hc / 2μ[tex]_B[/tex]λ
so we substitute
B = [(6.626 × 10⁻³⁴) × (3 × 10⁸)] / [2(9.27 × 10⁻²⁴) × 0.21 ]
B = [ 1.9878 × 10⁻²⁵ ] / [ 3.8934 × 10⁻²⁴ ]
B = 510556326.09
B = 0.0511 T
Therefore, the magnetic field experienced by the electron is 0.0511 T
a 0.1 kg object oscillates as a simple harmonic motion along x axis with a frequency f=3.185 hz. At a position x1 , the object has a kinetic energy of o.7 j and a potential energy 0.3 J.The amplitude of oscillation A is:
Answer:
The total energy must be .7 J + .3 J = 1 J for a particle at the endpoint or midpoint of motion.
Also, omega = (k / m)^1/2
f = omega / (2 * pi)
omega^2 = 4 pi^2 * f^2 = k / m
k = 4 * pi^2 * f^2 * m = 40.05
Max KE or PE = 1/2 k A^2
A^2 = 2 * E / k = 2 * 1 / k = .0499
A = .223 meters
d. What is the net force on the bowling ball rolling lane
Answer:
Friction.
Explanation:
balance Al +N₂ --> AIN
Answer:
[tex]2Al + N_{2} ==> 2AlN[/tex]
Explanation:
What does the outer part of the disk turn into?
1) Planets and Moons
2) Interstellar Cloud
3) Planetary Nebula
4) It gets sucked into the star
Answer:
what does the outer part of the disk turn into
Explanation:
4) it gets sucked into the star
PLEASE HELP ME PLEASE! BRAINLEST
Answer:
10kg
Explanation:
Weight is "how much does gravity drag this down".
Mass is "how much matter is there here".
The relation is:
[tex]F_g = mg[/tex]
where [tex]F_g[/tex] is the weight, [tex]m[/tex] is the mass and [tex]g[/tex] is the gravitational acceleration (roughly equal to 10N/kg on Earth).
From the task we know that:
[tex]F_g = 100N\\g = 10\frac{N}{kg}[/tex]
So let's input it into the relation:
[tex]100N = m\cdot 10\frac{N}{kg}\\10N = m \cdot 1\frac{N}{kg}\\10N \cdot \frac{kg}{N} = m\\~\\m = 10kg[/tex]
Helppp answer question pic in photo
1. If a spring has a spring constant of 2 N/m and it is stretched 5 cm, what is the force of
the spring?
what is liang most likely trying to do
Answer:
Who is liang
Explanation:
i need more info if i'm going to help you out
He is most likely trying to figure out how to upload the picture to Brainly.
He knows that his question cannot be answered as long as nobody can see the picture.
Which of the following is NOT a geological event caused by the movement of tectonic plates?
A) Sand Dunes
B) Mountain forming
C) Earthquakes
D) Volcanoes
Which feature of electromagnets makes them more useful than permanent
magnets in many modern technologies?
A. Electromagnets are not dependent on a power supply.
B. The strength of the magnetic field is more consistent in
electromagnets.
C. Electromagnets cannot be turned on and off.
D. The current can be adjusted to control the strength of the
magnetic field.
Answer:
The current can be adjusted to control the strength of the
magnetic field.
According to Kepler's second law at the two shaded areas above are equal then...
A. it takes the same amount of time for planet A to travel between T1 and T2 as it does to travel between T3 and T4
B. Planet A will cause an eclipse on Planet B during those time intervals
C. it takes Planet A more time to travel between T1 and T2 as it does to travel between T3 and T4
D. it takes Planet A less time to travel between T1 and T2 as it does to travel between T3 and T4
Answer:
A. Kepler's second law says that the radius vector sweeps equal areas in equal times.
if the dissipated power between a and b equal 210 watt then VB equal
Answer:
correct answer is A
Explanation:
The diagram shows a series circuit with three resistors and two power sources.
In a series circuit the current through the entire circuit is constant and the resistance is the sum of the resistances in the circuit.
When the power sources are placed in opposite position the voltage between them is subtracted.
V_b - 30 = I (10 + 4 + 6)
V_b = I (20) - 30
V_b = 30 - 2 20
V_b = 10 V
the correct answer is A
A wheelbarrow full of bricks is lifted to the top of a wall. If the mass of the loaded wheelbarrow is 3000.0 g and the height of the wall is 0.45 meters, what is its GPE?
Answer:
the Gravitational potential energy is 13.23 J
Explanation:
The computation of the GPE is shown below:
GPE stands for Gravitational potential energy
The following formula should be used for the same
= mass × gravity × height
= 3000 g × 9.8m/sec^2 × 0.45 m
= 13.23 J
Hence, the Gravitational potential energy is 13.23 J
We simply applied the above formula so that we can easily determine the GPE
A wheel rotating with a constant angular acceleration turns through 19 revolutions during a 3 s time interval. Its angular velocity at the end of this interval is 18 rad/s. What is the angular acceleration of the wheel? Note that the initial angular velocity is not zero. Answer in units of rad/s 2 .
Answer:
The magnitude of the angular acceleration of the wheel is 14.53 rad/s².
Explanation:
The angular acceleration can be found by using the following equation:
[tex] \omega_{f}^{2} = \omega_{0}^{2} + 2\alpha \Delta \theta [/tex] (1)
Where:
[tex] \omega_{f}[/tex]: is the final angular velocity = 18 rad/s
[tex]\omega_{0}[/tex]: is the initial angular velocity
α: is the angular acceleration =?
Δθ = 19 rev*(2π/1 rev) = 119.4 rad
The initial angular velocity can be found knowing that the wheel turns through 19 revolutions during a 3 s time interval:
[tex] \omega_{f} = \omega_{0} + \alpha t [/tex]
Where:
t: is the time = 3 s
By solving the above equation for ω₀ we have:
[tex] \omega_{0} = \omega_{f} - \alpha t [/tex] (2)
Now, by entering equation (2) into (1) we have:
[tex] \omega_{f}^{2} = (\omega_{f} - \alpha t)^{2} + 2\alpha \Delta \theta [/tex]
[tex] \omega_{f}^{2} = \omega_{f}^{2} - 2\omega_{f} \alpha t + (\alpha t)^{2} + 2\alpha \Delta \theta [/tex]
[tex](9\alpha)^{2} + 130.8 \alpha = 0[/tex]
By solving the above equation for "α" we have:
α = -14.53
The minus sign means that the wheel is decelerating.
Hence, the angular acceleration of the wheel is -14.53 rad/s².
I hope it helps you!
The volumes of two bodies are measured to be
V₁ = (10.2 ± 0.02) cm³ and V₂ = (6.4 ± 0.01) cm³. Calculate sum and difference in
volumes with error limits.
Answer:
sum of volumes = (16.6 ± 0.03) cm³
and difference of volumes = (3.8 ± 0.03) cm³
Explanation:
Here,
V₁ = (10.2 ± 0.02) cm³ and V₂ = (6.4 ± 0.01) cm³.
Now,
∆V = ± (∆V₁ + ∆V₂)
= ± (0.02 + 0.01) cm³
= ± 0.03 cm³
V₁ + V₂ = (10.2 + 6.4) cm³ = 16.6 cm³ and
V₁ - V₂ = (10.2 - 6.4) cm³ = 3.8 cm³
Thus, sum of volumes = (16.6 ± 0.03) cm³
and difference of volumes = (3.8 ± 0.03) cm³
-TheUnknownScientist
Answer:
I hope it's helpful .............
HELP ME PLEASE <333, NUMBER 3 ONLY!
Answer:
b
Explanation:
is correct .....................
i think
