A day on a distant planet observed orbiting a nearby star is 21.5 hr. Also, a year on the planet lasts 69.3 Earth days. In other words, for the purposes of unit conversion, there are 24 hr in a day, 60 min in an hour, and 60 s in a minute, as it would for astronomers on Earth observing the planet. Calculate the average angular speed of the planet about its own axis of rotation in radians per second, with the second as measured on Earth. what is the speed of rotation? Calculate the average angular speed of the planet as it travels around its neighboring star, with the second as measured on Earth. what is the speed of orbit?

The explanation is shown in the picture. Hope it helps!

Edit: where I wrote "m/s" , I should have wrote m/s^2

Answer:

The work is done by the force 100 NM.

Explanation:

=5kg * 2 m/s^2

=5* 2 N (kg*m/s^2=N)

=10N

Work done = force* distance

=10N* 10

= 100 NM

For an object of mass 5 kg accelerating at the rate of 2 m/s², then the work done by the force on the object will be 100 Nm.

In physics, the word "work" involves the measurement of energy transfer that takes place when an item is moved over a range by an externally applied, at least a portion of which is applied within the direction of the displacement.

The length of the path is multiplied by the element of a force acting all along the path to calculate work if the force is constant. The work W is theoretically equivalent towards the force f times the length d, or W = fd, to portray this concept.

As per the given information in the question,

Mass of the object, m = 5 kg

Acceleration, a = 2 m/s²

Distance, d = 10 m

W = f × d

W = m × a × d

W = 5 × 2 × 10

W = 100 Nm

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Answer:

2 steps

Explanation:

:)

this makes basketball interesting

Answer:

2 steps tops. If it is more that is called "traveling".

Explanation:

Speed has no direction.

Velocity has one.

Answer:

w = 1.14 rad / s

Explanation:

This is an angular momentum exercise. Let's define a system formed by the three bodies, the platform, the bananas and the monkey, in such a way that the torques during the collision have been internal and the angular momentum is preserved.

Initial instant. The platform alone

        L₀ = I w₀

Final moment. When the bananas are on the shelf

we approximate the bananas as a point load and the distance is indicated

x = 0.45m

        L_f = (m x² + I ) w₁

angular momentum is conserved

         L₀ = L_f

         I w₀ = (m x² + I) w₁

         w₁ = [tex]\frac{I}{m x^2 + I} \ w_o[/tex]

Let's repeat for the platform with the bananas and the monkey is the one that falls for x₂ = 1.73 m

initial instant. The platform and bananas alone

        L₀ = I₁ w₁

         I₁ = (m x² + I)

final instant. After the crash

        L_f = I w

        L_f = (I₁ + M x₂²) w

the moment is preserved

        L₀ = L_f

        (m x² + I) w₁ = ((m x² + I) + M x₂²) w

         (m x² + I) w₁ = (I + m x² + M x₂²) w

we substitute

         w =  [tex]\frac{m x^2 +I}{I + m x^2 + M x_2^2} \ \frac{I}{m x^2 + I} \ w_o[/tex]

         w =  [tex]\frac{I}{I + m x^2 + M x_2^2} \ w_o[/tex]

the moment of inertia of a circular disk is

         I = ½ m_p x₂²

we substitute

         w =  [tex]\frac{ \frac{1}{2} m_p x_2^2 }{ \frac{1}{2} m_p x_2^2 + M x_2^2 + m x^2} \ \ w_o[/tex]

let's calculate

          w =[tex]\frac{ \frac{1}{2} \ 97.3 \ 1.73^2 }{ \frac{1}{2} \ 97.3 \ 1.73^2 + 21.9 \ 1.73^2 + 9.67 \ 0.45^2 } \ \ 1.67[/tex]

          w =  [tex]\frac{145.60 }{145.60 \ + 65.54 \ + 1.958} \ \ 1.67[/tex]

          w = 1.14 rad / s

Answer:

If we put pressure on a solid or a liquid, there is essentially no change in volume. ... The kinetic-molecular theory explains why gases are more compressible than either liquids or solids. Gases are compressible because most of the volume of a gas is composed of the large amounts of empty space between the gas particles.

Explanation:

Answer:

Compression distance: [tex]d \approx 0.102\,m[/tex]

Explanation:

According to this statement, we know that system is non-conservative due to the rough patch. By Principle of Energy Conservation and Work-Energy Theorem, we have the following expression that represents the system having a translational kinetic energy ([tex]K[/tex]), in joules, at the expense of elastic potential energy ([tex]U[/tex]), in joules, and overcoming work losses due to friction ([tex]W_{l}[/tex]), in joules:

[tex]K + W_{l} = U[/tex] (1)

By definitions of translational kinetic and elastic potential energies and work losses due to friction, we expand the equation described above:

[tex]\frac{1}{2}\cdot m \cdot v^{2} +\mu\cdot m\cdot g \cdot s = \frac{1}{2} \cdot k \cdot d^{2}[/tex] (2)

Where:

[tex]m[/tex] - Mass of the block, in kilograms.

[tex]v[/tex] - Final velocity of the block, in meters per second.

[tex]\mu[/tex] - KInetic coefficient of friction, no unit.

[tex]g[/tex] - Gravitational acceleration, in meters per square second.

[tex]s[/tex] - Width of the rough patch, in meters.

[tex]k[/tex] - Spring constant, in newtons per meter.

[tex]d[/tex] - Compression distance, in meters.

If we know that [tex]m = 1.2\,kg[/tex], [tex]v = 2.3\,\frac{m}{s}[/tex], [tex]\mu = 0.44[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]s = 0.05\,m[/tex] and [tex]k = 730\,\frac{N}{m}[/tex], then the compression distance of the spring is:

[tex]\frac{1}{2}\cdot m \cdot v^{2} +\mu\cdot m\cdot g \cdot s = \frac{1}{2} \cdot k \cdot d^{2}[/tex]

[tex]m\cdot v^{2} + 2\cdot m\cdot g \cdot s = k\cdot d^{2}[/tex]

[tex]d = \sqrt{\frac{m\cdot (v^{2}+2\cdot g\cdot s)}{k} }[/tex]

[tex]d \approx 0.102\,m[/tex]

Answer:

Explanation:

The answer is magnetic force

Answer:

Magnetic forces which causes attraction between the two poles

Explanation:

An object that is partly or completely submerged experiences a greater pressure on its bottom surface than on its top.

Answer:

upthrust force is an upward force exerted by a fluid that opposes the weight of a partially or fully immersed object

Answer:

Time = 13333.33 s = 222.22 min = 3.7 h

Explanation:

The total amount of energy in two cells combined will be:

[tex]Total\ Energy = 40000\ J + 40000\ J\\Total\ Energy = 80000\ J\\[/tex]

Now, we calculate the power of the batteries:

[tex]Power = (Voltage)(Current)\\Power = (3\ V)(2\ A)\\Power = 6\ Watt[/tex]

Now, we use the following formula to calculate the time  the batteries will be able to deliver the power to the flashlight:

[tex]Total\ Energy = (Power)(Time)\\\\Time = \frac{Total\ Energy}{Power}\\\\Time = \frac{80000\ J}{6\ Watt}[/tex]

Time = 13333.33 s = 222.22 min = 3.7 h

Answer:

B.Greater

Explanation:

Smack that thanks button pleasee.

Answer:direction A

Explanation:

Took test

The direction is the magnetic field in the center of the solenoid will be towards A. The direction of the magnetic field is toward the A.

A coil of wire that carries an electric current is a solenoid. A solenoid is an electromagnet formed by a helical coil of wire. Which generates a magnetic field when an electric current is passed through the coil .

A solenoid is a form of coil that produces a magnetic field when the electric current is passed through it. A solenoid is created when a conductive wire is used to make a loop.

Use your understanding of the magnetic field's form to determine the direction of the magnetic field along the middle of the solenoid.

Because the current wraps around the core of the solenoid in this scenario, it may be controlled with your fingertips. It goes with your thumb since the magnetic field is straight down the inside.

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Explanation:

1) left ⬅️

2) into the page

3) upward ⬆️

4) right ➡️

5) downward ⬇️

Answer:

 θ = 73.6º

Explanation:

To solve this exercise, let's use Newton's second law. Let's set a reference system where the x-axis is parallel to the inclined plane

with trigonometry we can find the components of the weight

           sin θ = Wₓ / W

           cos θ= W_y / W

           Wₓ = W sin θ

           W_ = W cos θ

Y axis  

           N - W_y = 0

           N = W_y

X axis

           Wₓ - fr = m a

            mg cos θ - fr = m a

indicate that friction is zero, fr = 0

            cos θ = a / g

            θ = cos⁻¹  [tex]\frac{a}{g}[/tex]

let's calculate

            θ = cos⁻¹  [tex]\frac{2.77}{9.8}[/tex]

            θ = 73.6º

Answer:

a

Explanation:

transverse waves travel at a right angle to the direction of the wave motion and the examples of transverse waves are water waves and radio waves of which radio produces sound.

Answer:

The correct option is A.

Sound waves travel as transverse waves.

Explanation:

Sound waves is a type of compression or mechanical vibrations that travel through a medium such as water, air and the energy of the medium through which it's travel cause the vibrations.

Sound travel as transverse waves because it move through a right angle direction of the wave movement and it travel through a medium such as air.

Example include Radio waves and water waves.

Therefore, Sound waves travel as transverse waves.

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Answer:

t.f. are you sure that's english? it looks like not a real thing

Explanation:

Answer:

changing from a solid to a gas without changing into a liquid. :)

Answer:

c

Explanation:

Answer:

c

Explanation:

the DNA replication happens in the s phase of interphase

Answer:

B

Explanation:

The correct answer is B on edge

(Looks like a flower with 3 petals with the most right petal covering the x-axis.)

Answer: Just pray for me, thank you.

4.3.11 QC

100% correct

1. Use the image to answer the question.

Select the equation that represents the graph.

Which table best represents the graph of the equation θ = 45°

Answers:

1. r= 4 which is C

2. A table

3. D (4.24, pi/4)

4. D Radius 1 and center (1,0)

5. B symmetrical about the vertical axis

Explanation: I did it!

Answer:

Height of resulting wave = 0.6 meters

Explanation:

Let the higher wave (wave crest) be A while the lower wave (wave trough) be B.

Given the following data;

A = 3.2m

B = 2.6m

To find the height of the resulting wave;

Height = A + B

But the lower wave becomes negative because it is below i.e on the lower trough.

Height = 3.2 + (-2.6)

Height = 3.2 - 2.6

Height of resulting wave = 0.6 meters

1. AA = HoD Ee = He Ii = He Mm = He

Bb = He ff = HoR Jj = He nn = HoR Cc = He

GG = HoD kk = HoR OO = HoD Dd = He

HH = HoD Ll = He Pp = He

This is a classic case of 'velocity components.'

Imagine a vector for velocity. Now, consider that this vector could be the hypotenuse of a right triangle, with two other sides going along the x and y-axis. These sides of the triangle will have values, and adding them up using the pythagorean theorem will prove that the sum of their squares equals the square of the original vector.

Well, okay, that's nice and all, you may be saying - but how do we solve the actual question?

Let's apply this thought to the question. This vector can have both an x component and y component (essentially, parts of the vector that travel along the x and y-axis).

Now, what could these components be? We know that the stone is thrown perfectly horizontally, meaning that the x-component is quite literally the velocity.

How about the y-component? Since it's thrown at a perfect horizontal, there isn't really any vertical velocity whatsoever. There's only horizontal velocity.

"Great, fantastic! So, what's the importance of figuring out the horizontal and vertical velocities?"

When a stone is in free fall, it experiences a gravitational acceleration. This acceleration from gravity, though, only affects the vertical velocity. Since gravity is vertical as well, it's essentially impossible for the horizontal velocity to be changed at all.

This means that to solve the horizontal distance, we simply need to find the time it takes for the rock to hit the ground and multiply said time by the horizontal velocity.

Since the vertical velocity is the only thing changed by gravity, we can write out an equation that can solve for the time:

∆Y = [tex]v_{i}[/tex]t + [tex]\frac{1}{2}[/tex]g[tex]t^{2}[/tex]

We know that initial vertical velocity is zero, so:

∆Y = [tex]v_{i}[/tex]t + [tex]\frac{1}{2}[/tex]g[tex]t^{2}[/tex]

∆Y = 0t + [tex]\frac{1}{2}[/tex]g[tex]t^{2}[/tex]

∆Y = [tex]\frac{1}{2}[/tex]g[tex]t^{2}[/tex]

We need to solve for t, so let's isolate the variable. Multiply both sides by 2 to get rid of the fraction:

∆Y * 2 =  [tex]\frac{1}{2}[/tex]g[tex]t^{2}[/tex] * 2

2∆Y = g[tex]t^{2}[/tex]

Divide both sides by g:

(2∆Y)/g = [tex]\frac{gt^{2} }{g}[/tex]

Square root both sides:

[tex]\sqrt{(2Y)/g}[/tex] = [tex]\sqrt{t^{2} }[/tex]

t = [tex]\sqrt{(2Y)/g}[/tex]

Input our values for Y and g (Y is the height of the cliff, and g is gravitational acceleration):

t = [tex]\sqrt{(2*50)/9.80}[/tex]

Solve:

t =  [tex]\sqrt{(2*50)/9.80}[/tex]

t = 3.194 (s)

Whew! That was a lot of steps to find the time! Now that we have the time, we can find the horizontal distance the rock travels:

∆x = [tex]v_{i}[/tex]t + [tex]\frac{1}{2}[/tex]a[tex]t^{2}[/tex]

The horizontal velocity has no acceleration (gravity is vertical!), so:

∆x = [tex]v_{i}[/tex]t + [tex]\frac{1}{2}[/tex]*0*[tex]t^{2}[/tex]

∆x = [tex]v_{i}[/tex]t

The horizontal velocity is 15 m/s, and the time is 3.194:

∆x = [tex]v_{i}[/tex]t

∆x = 15 * 3.194

∆x = 47.91 (m)

Since we rounded the time, it makes sense that our final answer's a little bit off to the options. The closest one is option B, which is only 0.6m off, a tiny difference that may have come from the test maker's use of '10 m/[tex]s^{2}[/tex]' as the gravitational acceleration (while we stayed as accurate as possible with 9.80) as well as our rounding of the final time.

Option B, the stone will have travelled 47.85 meters.

If you have any questions on how I got to the answer or if you're still confused on any topic I attempted to explain, just ask in the comments and I'll try to answer it to the best of my ability! Good luck!

- breezyツ

Answer:

Higher force would be required to stop 5 kg of ball

Explanation:

The force required to stop a moving object depends on its momentum.

The momentum for 8 kg of rolling ball is = 8 kg * 0.2 m/s = 1.6 kgm/s

The momentum for 5 kg of rolling ball is = 8 kg * 1.0 m/s = 5 kgm/s

Hence, momentum of 5 Kg ball is higher than the momentum of 8 Kg of ball

Hence, higher force would be required to stop 5 kg of ball

Answer:

vi = 5.25 m/s

Explanation:

We can determine the initial velocity of the runner by using the first equation of motion, as follows:

[tex]v_f = v_i + at\\[/tex]

where,

vf = final speed of the runner = 4 m/s

vi = initial speed of the runner = ?

a = deceleration of the runner = - 0.25 m/s²

t = time taken = 5 s

Therefore,

[tex]4\ m/s = v_i + (-0.25\ m/s^2)(5\ s)\\v_i = 4\ m/s + 1.25\ m/s\\[/tex]

vi = 5.25 m/s

Winter

It is winter because the Northern Hemisphere is not facing the sun.

Answer:

P = 6000 W

Explanation:

The given question is "The motor of a motorcycle gives it a speed of 90 km / h when a force of 240 N is applied to it. What is the power of the motorcycle in watts?"

Given that,

Speed of a motorcycle, v = 90 km/h = 25 m/s

Force applied to the motorcycle, F = 240 N

We need to find the power of the motorcycle. We know that,

Power = Fv

So,

P = 240 N × 25 m/s

= 6000 W

So, the required power of the motorcycle is equal to 6000 W.

Answer:

77.8 g potassium bromide can be dissolved in 100 grams of water at 40°C.

Explanation:

In a given a line of KBr is straight.