A car is traveling at 20 meters/second and is brought to rest by applying brakes over a period of 4 seconds.What is its average acceleration over this time interval?

Explanation:

potassium oxide is K2O

calcium oxide is CaO

calcium oxide is used to make glass

potassium oxide is used in fertilizer

Answer:

The answer could be "Autotrophs that photosynthesis".

Explanation:

At point X, the common characteristic can be written. The common character between protists and plants is autotrophs that photosynthesize which is the characteristic of plant-like protists. Plant-like protists are autotrophs, use carbon dioxide and water to produce glucose by the process of photosynthesis.

Answer:

The correct answer should be 12.72 pH of the mixed solution and 9.94g mass of solid BASO4 formed.

The molecules of Ba(OH)2 are : 1.00M x 0.05L = 0.05 ( moles )

The molecules of H2SO4 are : 0.494M x 0.0864L = 0.0426816

Ba(OH)2 + H2SO4 ----> BaSO4 + 2 H2O

0.0426816<--- 0.0426816

The mixed solution is Ba(OH)2 with 0.05 - 0.0426816 = 0.0073184

The concentration of mixed solution is : 0.0073184 : ( 0.05 + 0.0864 ) = 0.054 M

The pH of mixed solution is 14 - -log[0.054] = 14 - 1.27 = 12.73 PH

And the mass of BaSO4 is 0.0426816 x ( 137 + 32 + 16 x 4 ) = 9.94 gams.

If the unknown substance decolorize bromine water, it is an alkene. If it does not, litmus paper is used to test it. If the paper turns red, then the substance may be a carboxylic acid, and the reaction with sodium carbonate serves as additional confirmation. It is not a carboxylic acid if it does not react with sodium carbonate. A substance is not an alkene or a carboxylic acid if it does not decolorize bromine water and is not acidic.

The following flowchart can be used to recognize an alkene and a carboxylic acid:

1. Start with the hypothetical unknown substance.

2. Use bromine water to test the substance.

a. An alkene is a substance that discolors bromine water.

b. Move on to the following stage if the compound does not lighten bromine water.

3. Use universal indicator paper or litmus paper to test the chemical.

a. The substance might be a carboxylic acid if it is acidic and causes the paper to turn red.

b. Go to the following step if the chemical is not acidic.

4. Use sodium carbonate to evaluate the substance.

a. A substance is a carboxylic acid if it reacts with sodium carbonate to release carbon dioxide gas.

b. The chemical is not a compound if it does not react with sodium carbonate.

Therefore, if the unknown substance decolorize bromine water, it is an alkene. If it does not, litmus paper is used to test it. If the paper turns red, then the substance may be a carboxylic acid, and the reaction with sodium carbonate serves as additional confirmation.

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Your question is incomplete, most probably the complete question is:

TASK 2 - Pass 2B.P4 Identify an alkene and carboxylic acid using primary observations. To achieve 2B.P4, learners should follow guidance to identify an alkene and a carboxylic acid (for example, ethanoic acid) from primary observations. Learners will be expected to identify an alkene in the way described in 1B.4. For ethanoic acid this is by its pH and its reaction with sodium carbonate. The guidance given to the learners could be in the form of a flowchart.​

The balanced chemical equation among the given reactions is:

Sn²⁺ + 2Fe³⁺  →  Sn⁴⁺ + 2Fe²⁺

Therefore, option (C) is correct.

A chemical equation of a reaction can be defined as the representation of a reaction in terms of chemical symbols of the substances used in the given reaction. The number of atoms of substances on the balanced equation is equal on either side of the equation.

According to the law of conservation of mass, while balancing a chemical equation, the total mass (reactant side) should be equal to the total mass (product side) in a chemical equation.

In the given equation, the positive charge on reactant side should be equal to the positive charge on product side.

[tex]Sn^{2+ }+ 2Fe^{3+} \longrightarrow Sn^{4+} + 2Fe^{2+}[/tex]

The two electrons lost by the Sn²⁺ ions get converted into Sn⁴⁺ ions. These two electrons are accepted by two ions of Fe³⁺ and converted into Fe²⁺ ions.

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Answer:

C

Explanation:

nucleoid is prokaryotic

Answer:

mitochondria is found in eukaryotic cells.

Answer:

2.28

Explanation:

HCl(l) ===> H+ + cl-

HCl is a very strong acid. Almost all of it will decompose to the right. That means the concentration of H+ is 0.00530

pH = - log [H+]

pH = - log[0.00530]

pH = - - 2.2757

pH = 2.2757

Rounded this 2.28

Answer:

5.42

Explanation:

I used a calculator

Answer: 5.42 mol CO2

Explanation: Uses idea gas law

Answer:

It's a solid.

Explanation:

Solids never change their shape as opposed to gases and liquids. This is because their molecules are tightly packed together. Since all solids have a definite shape, it's volume will also be definite.

Answer:

0.99986

Explanation:

attached below is the detailed solution to the given problem

Express the ratios of the ground state energies of these atoms

ground state energies ( Ed , Ehe )

= Ed / Ehe = -13.5963 / -13.59815

                 = 0.99986

Answer:

NaBH4

H3O+

Explanation:

The conversion of 3-pentanone to form 3-pentanol is a reduction reaction. The first step of the reaction is the transfer of a hydride ion to the carbonyl from the reducing agent sodium borohydride.

After the transfer of the hydride ion, transfer of a proton from H3O+ completes the reaction mechanism hence 3-pentanol is formed from 3-pentanone.

Hi there!

Here's a screenshot of the problem being solved.

Answer:

66.0 mL HClO3

Explanation:

M1V1 = M2V2

M1 = 0.100 M HClO3

V1 = ?

M2 = 0.165 M KOH

V2 = 40.0 mL KOH

Solve for V1 --> V1 = M2V2/M1

V1 = (0.165 M)(40.0 mL) / (0.100 M) = 66.0 mL HClO3

Answer:

549.48 mmHg

Explanation:

We'll begin by calculating the number of mole of oxygen in 4 g. This can be obtained as follow:

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mass of O₂ = 4 g

Mole of O₂ =?

Mole = mass /molar mass

Mole of O₂ = 4/32

Mole of O₂ = 0.125 mole

Next, we shall convert 37.0 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T (°C) = 37.0 °C

T(K) = 37.0 °C + 273

T(K) = 310 K

Next, we shall convert 4400 mL to L.

1000 mL = 1 L

Therefore,

4400 mL = 4400 mL × 1 L / 1000 mL

4400 mL = 4.4 L

Next, we shall determine the pressure. This can be obtained as follow:

Number of mole (n) = 0.125 mole

Temperature (T) = 310 K

Volume (V) = 4.4 L

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =?

PV = nRT

P × 4.4 = 0.125 × 0.0821 × 310

Divide both side by 4.4

P = (0.125 × 0.0821 × 310) / 4.4

P = 0.723 atm

Finally, we shall convert 0.723 atm to mmHg.

1 atm = 760 mmHg

Therefore,

0.723 atm = 0.723 atm × 760 mmHg / 1 atm

0.723 atm = 549.48 mmHg

Thus, the pressure is 549.48 mmHg

Answer:

1 - D) friction

2- B) rough

3- B) gravity

4- A)smooth

5- C)gravity pulls you down

Answer:

No, they are not able to bond.

Explanation:

Hello there!

In this case, regarding chemical bonds, it is necessary to remember that these come up when a metal is bonded with a nonmetal, or, when two nonmetals get bonded; however, even there exist a type of denominated metallic, it is not eligible for boron and lithium because they tend to stable as cations (positive) and therefore, equal charges are not eligible for bonding, thus, boron and lithium would not be able to bond.

Best regards!

Answer:

[tex]HI(aq)+NaOH(aq)\rightarrow NaI(aq)+H_2O(l)[/tex]

Explanation:

Hello there!

In this case, for this neutralization reaction, it is possible to realize that one the neutralization products is water (pH=7) and the other one is the salt coming up from the cation of the NaOH and the anion of the HI:

[tex]HI(aq)+NaOH(aq)\rightarrow NaI+H_2O[/tex]

Moreover, since the solubility of NaI is large in water, we infer it remains aqueous whereas the water is maintained as liquid:

[tex]HI(aq)+NaOH(aq)\rightarrow NaI(aq)+H_2O(l)[/tex]

Which is also balanced as the number of atoms of all the elements is the same at both sides.

Best regards!

Answer:

i thinks its a. but iam not sure

Answer:

Soap that was thrown out

Answer:

force are called roll

Explanation:

force your answer give me five Points

Answer:

friction

Explanation:

The other terms honestly just don't make any sense in this context. Round objects experience less friction, since they have less of their surface touching the ground at a time. Imagine a bowling bowl: only a small part of the ball is ever touching the ground at one instant. Now imagine a waffle: almost all of the surface is touching the ground.

The net ionic equation for the reaction between Na₂SO₄ and CaCl₂ is:

SO₄²¯(aq) + Ca²⁺(aq) —> CaSO₄(s)

(Option C)

In solution, Na₂SO₄ and CaCl₂ will dissociate as follow

Na₂SO₄(aq) —> 2Na⁺(aq) + SO₄²¯(aq)

CaCl₂(aq) —> Ca²⁺(aq) + 2Cl¯(aq)

Na₂SO₄(aq) + CaCl₂(aq) —>

2Na⁺(aq) + SO₄²¯(aq) + Ca²⁺(aq) + 2Cl¯(aq) —> CaSO₄(s) + 2Na⁺(aq) + 2Cl¯(aq)

Cancel out the spectator ions (i.e Na⁺ + Cl¯) to obtain the net ionic equation

SO₄²¯(aq) + Ca²⁺(aq) —> CaSO₄(s)

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Answer:

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

[tex]n = \frac{N}{L} [/tex]

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

[tex]n = \frac{3.86 \times {10}^{23} }{6.02 \times {10}^{23} } = \frac{3.86}{6.02} \\ = 0.641196...[/tex]

We have the final answer as

Hope this helps you

Answer:

[H+]=1.43*10^-13

pH=12.84

Explanation:

Take the -log of the [OH-] to get the pOH:

pOH= -log(6.98*10^-2)=1.15

pH=14-pOH

pH=14-1.15

pH=12.843

[H+]=10^(-pH)

[H+]=10^(-12.843)

[H+]-1.43*10^-13

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Answer:

It will go to your hand.

Explanation: If you touch a hot cup/mug you'll most likely burn yourself, so it would probably go to your hand.

Answer:

Thus, the speed at B = 13 m/s

Explanation:

From the attached image:

Using the conservation of energy;

Iinital M.E = Final M.E

where;

M.E = mechanical energy

∴

[tex]\dfrac{1}{2} \times m \times v_A^2+ mgh_A = \dfrac{1}{2} \times m \times v_B^2+ mgh_B[/tex]

[tex]\dfrac{1}{2} \times m \times 3^2+m \times 9.8 \times 15 = \dfrac{1}{2} \times m \times v_B^2+ m\times 9.8 \times 7 \\ \\ \dfrac{1}{2} \times 3^2 + 9.8 \times 15 = \dfrac{1}{2} \times v^2 + 9.8 \times 7 \\ \\ \implies 151.5 = 0.5 v^2 + 68.6 \\ \\ 0.5v^2 = 151.5 - 68.6 \\ \\ 0.5 v^2 = 82.9 \\ \\ v^2 = \dfrac{82.9}{0.5} \\ \\ v^2 = 165.8 \\ \\ v = \sqrt{165.8} \\ \\ v = 12.9 \ m/s\\ \\ \mathbf{v \simeq 13 \ m/s}[/tex]