A can of soup weighs
23.5 ounces. The can contains
2.5 servings. How many
ounces are in 1 serving?

Answer:

X=3 y=-1

Step-by-step explanation:

X+y=2

X-y=4

so that means

y=X-4

substitute it in

X+X-4=2

2x-4=2

2x=2+4

2x=6

x=3

3+y=2

3+-1=2

y=-1

ways to check

3--1=4

double minus equal plus

3+1=4

Answer:

The system of inequalities that models the situation is

Step-by-step explanation:

Given:

Total number of banana bread and nut bread must be atmost 30

Cost of one banana bread = $2.50

Cost of one nut bread = $2.75

Kona wants to make at least $44

To Find:

The system of inequalities models the situation

Solution:

Let the number of banana bread loaves be x

Let the number of nut bread loaves be y

Then kona wants to make at most 3 loaves of bread,

So...

Then By selling one banana bread to $2.50, and each loaf of nut bread sells for $2.75,Kona wants to make at least $44. TvT hope this helps

Answer:Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?

Answer:

The fraction can not be reduced, but it can be converted to decimal form.

Exact Form: 10/7

Step-by-step explanation:

Answer:

g o f = [tex]g(f(x)) = 32x^2 + 32x + 4[/tex]

Step-by-step explanation:

Given

[tex]f(x) = 4x +2[/tex]

[tex]g(x) =2x^2 - 4[/tex]

Required:

Find g o f

This is calculated as:

[tex]gof = g(f(x))[/tex]

[tex]g(x) =2x^2 - 4[/tex]

So:

[tex]g(f(x)) = 2(4x+2)^2 - 4[/tex]

[tex]g(f(x)) = 2(4x+2)(4x+2) - 4[/tex]

[tex]g(f(x)) = 2[ 16x^2 + 16x + 4)] - 4[/tex]

[tex]g(f(x)) = 32x^2 + 32x + 8 - 4[/tex]

[tex]g(f(x)) = 32x^2 + 32x + 4[/tex]

Answer:

The answer would be 20.25 i think!

Step-by-step explanation:

Answer:

the answer is 12

I think

Answer:

[tex]x=\sqrt{14}[/tex]

Step-by-step explanation:

This triangle is a 45-45-90 triangle.

By using the image I posted, we can find x easily.

So, we have [tex]\sqrt{7}[/tex] as one of the sides.

They hypotenuse, which is x is just [tex]\sqrt{7} \sqrt{2}[/tex]

Simplify and we get x = [tex]\sqrt{14}[/tex]

Answer:

True

Step-by-step explanation:

∠BFG is an interior angle, then:

m∠BFG=[m arc(GB) + m arc(CD)] / 2

or in other words

m∠BFG = (0.5)(m arc CD + m arc GB)

Answer:

TRUEEEEEEEEEEEEEEEEEEEEEEE

Step-by-step explanation:

Answer:

33 boys

Step-by-step explanation:

Since 45% of the participants were female and there were a total of 80 students, 36 of the 80 students were female. That means that 44 of the students were male.

25% of 44 is 11. So there are 11 boys that are not employed. From there you can just subtract 44 - 11 and get 33.

33 boys are employed

Answer:

33 students

Step-by-step explanation:

Let's take this step-by-step. First, we know that the sample includes a total number of 80 high school students, and 45% of them are female.

This means that 55% of them are male students, which is required to answer the question. 80 × 0.55 = 44 male students.

Next, 25% of the male students are not employed. This means that 75% of the male students are employed. So, 44 × 0.75 = 33 male students.

Answer:

2/5 *(5x+32)

Step-by-step explanation:

This question is incomplete, the complete question is;

A rocket accelerates by burning its onboard fuel, so its mass decreases with time. Suppose the initial mass of the rocket at liftoff (including its fuel) is m, the fuel consumed at rate r, and the exhaust gases are ejected with constant velocity v(sub e) [relative to the rocket]. A model for the velocity of the rocket at time t is given by the equation:

v(t) = -gt - v(sub e) ln [(m-rt)/m]

where g is the acceleration due to gravity, and t is not too large. If g = 9.8 m/s^2, m = 30,000 kg, r = 160 kg/s, and v(sub e)= 3000 m/s, find the height of the rocket one minute after liftoff.

Answer:

the height of the rocket one minute after liftoff is 14.8441 km

Step-by-step explanation:

Given the data in the question;

Velocity of the rocket at time t is;

v(t) = -gt - [tex]V_{e\\}[/tex] ln( [tex]\frac{m-rt}{m}[/tex])

[tex]\int\limits^t_0 {v(t)} \, dt[/tex] = ₀∫⁶⁰(  -gt - [tex]V_{e\\}[/tex] ln( [tex]\frac{m-rt}{m}[/tex]) )dt

= -g([tex][\frac{t^{2} }{2}]^{60}_0[/tex]  - [tex]V_{e\\}[/tex] ₀∫⁶⁰In( [tex]\frac{m-rt}{m}[/tex]) dt

= -g([tex][\frac{t^{2} }{2}]^{60}_0[/tex]  - [tex]V_{e\\}[/tex] [ t In( [tex]\frac{m-rt}{m}[/tex]) + [tex]\frac{m}{r}[/tex] - t - mr[tex]\frac{1}{r^{2} }[/tex] In |m-rt| [tex]]^{60}_0[/tex]

= -g([tex][\frac{60^{2} }{2}][/tex]  - [tex]V_{e\\}[/tex] [ 60 (In(1 -  [tex]\frac{60r}{m}[/tex])-1) + [tex]\frac{m(In(m^{2})-In((m-60r)^2))) }{2r}[/tex] ]

we input our given values; g=9.8 m/s², m=30000 kg, Ve = 3000 m/s, r = 160 kg)

= -9.8([tex][\frac{60^{2} }{2}][/tex]  - 3000 [ 60 (In(1 - [tex]\frac{60(160)}{m}[/tex])-1) + [tex]\frac{30,000(In(30,000^{2})-In((30,000-60(160))^2))) }{2(160)}[/tex] ]

[tex]\int\limits^t_0 {v(t)} \, dt[/tex] =  14844.10 m

we convert to kilometer

[tex]\int\limits^t_0 {v(t)} \, dt[/tex] =  14844.10 ÷ 1000

[tex]\int\limits^t_0 {v(t)} \, dt[/tex] =  14.8441 km

Therefore, the height of the rocket one minute after liftoff is 14.8441 km

Answer: $73.8 15% of 60 is 9 and 8% of 60 is4.8 then if you add them all together you get 73.8$

Step-by-step explanation:

Answer:

$73.8

Step-by-step explanation:

(15+8)= 23 -> .23 = .23 times 60 = $73.8

Answer:

x=47°

Step-by-step explanation:

..,........................

Answer:

I believe it is 47.  

Step-by-step explanation:  The reason why is because for a right angle it must be 90 degrees So, the way I solved this was getting 90-43 I got the 43 from BCD.  then subtracted it and applied it to the other side,  keep in mind I am only a freshman and it might be wrong super tiny chance but it might.  

Answer:

2x² + 13x + 15

Step-by-step explanation:

| 2x | 3

x | 2x*x = 2x² | 3*x = 3x

5 | 2x*5 = 10x | 3*5 = 15

We have, 2x² + 3x + 10x + 15

Combining like terms, we would have the final expression as:

2x² + 13x + 15

Answer:

x = 3

y = 4

Step-by-step explanation:

You need to get ridof the 2y so add the equations together:

3x - 2y = 1

*add

2x + 2y = 14  

5x + 0 = 15

5x = 15

*divide by 5

x = 3

Now that we have x we can find y by substituting

2(3) + 2y = 14

6 + 2y = 14

* subtract 6

2y = 8

*divide by 2

y = 4

Hope this helps :)

The 2 {} you have are called sets. The union is what the 2 sets have in all.

You can think of this as you have green blue yellow cards. and your friend have green orange red cards. What colors do you have if you combine your cards.

Now that's just an example, in the question's case is what numbers does the 2 sets have in total.

Therefore the union of these 2 sets are {9,10,11,13}

Hope it helps!

Answer:

kkk

Step-by-step explanation:

Answer:

y = [tex]\frac{b}{1-m}[/tex]

Step-by-step explanation:

In order to get y by itself, we need to pull y out of 1 and m on the right side.

b = y(1 - m) since y(1 - m) is the same as y - my.

Once we have pulled y out of 1 and m, we can divide both sides by 1 - m

[tex]\frac{b}{1 - m}[/tex] = [tex]\frac{y(1 - m)}{1 - m}[/tex]

We can cancel out the 1 - m on the right side since (1 - m) / (1 - m) = 1

Finally we get our answer:

[tex]\frac{b}{1-m}[/tex] = y

This is the same as y = [tex]\frac{b}{1-m}[/tex]

Answer:

32 plates

Step-by-step explanation:

If the pottery class has 16 pounds  of clay and each student got 1/2 of a pound;

then;

1 plate = 1/2 pounds

xplate = 16pounds

Divide both expressions

1/x = 1/2÷16

1/x = 1/2*!6

1/x = 1/32

x = 32

Hence the student will make 32 plates

Answer:

2√5-4(3√5-2)

6√25-4√5-12√5+8

6(5)-16√5+8

30+8-16√5

38-16√5

Answer:

8

Step-by-step explanation:

Answer:

Cups at $3.20

Step-by-step explanation:

Gallon - $3.99

Quarts - $5,00

Pints - $5.20

Cups - $3.20

Answer:

45 km^2 (C)

Step-by-step explanation:

Isolate the smaller square -

We only need two side lengths, take 3km and 3km.

3×3 = 9km^2, that's the area of the smaller square.

Isolate the larger square -

Take 6km and the other 6km

6×6 = 36km^2

Add the square's areas together to get the whole area -

36 + 9 = 45km^2

All you need to do to solve these problems is to isolate the shapes and find their area's, and finally add them together.

Answer:

For multiplication you added the exponents and for division you minus the exponents

Answer:

kdkdjdduidddsisiodiod

Step-by-step explanation:

(3×6) + (2×6)

= 18 + 12

= 30 in²