Answer:
a) According to the maximum-shear-stress failure theory, the static factor of safety of the shaft is 2.440.
b) According to the distortion-energy failure theory, the static factor of safety of the shaft is 2.816.
Explanation:
First, we need to determine the torque experimented by the shaft ([tex]T[/tex]), measured in kilonewton-meters, whose formula is described:
[tex]T = \frac{\dot W}{\omega}[/tex] (Eq. 1)
Where:
[tex]\dot W[/tex] - Power, measured in kilowatts.
[tex]\omega[/tex] - Angular velocity, measured in radians per second.
If we know that [tex]\dot W = 10\,kW[/tex] and [tex]\omega = 20.944\,\frac{rad}{s}[/tex], then the torque experimented by the shaft:
[tex]T = \frac{10\,kW}{20.944\,\frac{rad}{s} }[/tex]
[tex]T =0.478\,kN\cdot m[/tex]
Let consider that shaft has a circular form, such that shear stress is determined by the following formula:
[tex]\tau = \frac{16\cdot T}{\pi\cdot D^{3}}[/tex] (Eq. 2)
Where:
[tex]D[/tex] - Diameter of the shaft, measured in meters.
[tex]\tau[/tex] - Torsional shear stress, measured in kilopascals.
If we know that [tex]D = 0.03\,m[/tex] and [tex]T =0.478\,kN\cdot m[/tex], the torsional shear stress is:
[tex]\tau = \frac{16\cdot (0.478\,kN\cdot m)}{\pi\cdot (0.03\,m)^{3}}[/tex]
[tex]\tau \approx 90164.223\,kPa[/tex]
a) According to the maximum-shear-stress failure theory, we get that maximum shear stress limit is:
[tex]S_{ys} = 0.5\cdot S_{ut}[/tex] (Eq. 3)
Where:
[tex]S_{ys}[/tex] - Ultimate shear stress, measured in kilopascals.
[tex]S_{ut}[/tex] - Ultimate tensile stress, measured in kilopascals.
If we know that [tex]S_{ut} = 440\times 10^{3}\,kPa[/tex], the ultimate shear stress of the material is:
[tex]S_{ys} = 0.5\cdot (440\times 10^{3}\,kPa)[/tex]
[tex]S_{ys} = 220\times 10^{3}\,kPa[/tex]
Lastly, the static factor of safety of the shaft ([tex]n[/tex]), dimensionless, is:
[tex]n = \frac{S_{ys}}{\tau}[/tex] (Eq. 4)
If we know that [tex]S_{ys} = 220\times 10^{3}\,kPa[/tex] and [tex]\tau \approx 90164.223\,kPa[/tex], the static factor of safety of the shaft is:
[tex]n = \frac{220\times 10^{3}\,kPa}{90164.223\,kPa}[/tex]
[tex]n = 2.440[/tex]
According to the maximum-shear-stress failure theory, the static factor of safety of the shaft is 2.440.
b) According to the distortion-energy failure theory, we get that maximum shear stress limit is:
[tex]S_{ys} = 0.577\cdot S_{ut}[/tex] (Eq. 5)
If we know that [tex]S_{ut} = 440\times 10^{3}\,kPa[/tex], the ultimate shear stress of the material is:
[tex]S_{ys} = 0.577\cdot (440\times 10^{3}\,kPa)[/tex]
[tex]S_{ys} = 253.88\times 10^{3}\,kPa[/tex]
Lastly, the static factor of safety of the shaft is:
[tex]n = \frac{253.88\times 10^{3}\,kPa}{90164.223\,kPa}[/tex]
[tex]n = 2.816[/tex]
According to the distortion-energy failure theory, the static factor of safety of the shaft is 2.816.
Should transistors used in switching circuits be biased in the active region? Why or why not?
Answer:
no
Explanation:
No. More power is dissipated when the transistor is in its active region. In general, transistors in switching circuits are biased either "on" or "off". Time spent in the active region is minimized.
_____
On the other hand, speed can be enhanced if the transistors are active. So, it's a speed/power trade-off. Usually power is of more interest, particularly when there are millions of switching circuits. However, in certain applications, speed may be the priority, so the transistor will be biased in its active region.
________ is the most theoretical computing discipline, focusing mostly on finding new and better ways for computers to work
Answer:
Computer science
Explanation:
Computer science is the most theoretical computing discipline, focusing mostly on finding new and better ways for computers to work.
What is computer programming?The process of carrying out a specific computation through the design and construction of an executable computer program is known as computer programming.
Tasks like analysis, creating algorithms, and assessing the precision and resource use of those algorithms are all part of programming.
As we know,
The study of computing, robotics, and information is known as computer science. Algorithmic, computing theory, information theory, and automation are examples of academic areas in computer science.
Thus, computer science is the most theoretical computing discipline, focusing mostly on finding new and better ways for computers to work.
Learn more about computer programming here:
brainly.com/question/14618533
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The critical resolved shear stress for a metal is 36 MPa. Determine the maximum possible yield strength (in MPa) for a single crystal of this metal that is pulled in tension.
Answer:
72 MPa
Explanation:
Critical resolved shear stress = 36 MPa
calculate the maximum possible yield strength for a single crystal of the metal
first we have to express the critical resolved shear stress as
бy = 2т[tex]_{critical}[/tex]
given that the minimum stress needed to introduce yielding curve will occur at Ψ = λ = 45
where : бy = yielding stress
t[tex]_{critical}[/tex] = 36MPa
therefore the maximum possible yield strength
= (2) * (36)
= 72 MPa
How are weather and climate different
Answer:
- weather refers to short-term changes in the atmosphere
- climate describes what the weather is like over a long period of time in one area.
What is the meaning of *binuhat lakas nang loob na ibinaon
Answer:
carried courage buried
Explanation:
its Filipino
(TCO 7) Find the resolution of the Fourier transform if a signal is sampled at 16,384 samples/second and we collect a total of 8,192 data points and then apply the FFT algorithm to them.
Answer:
Resolution of Fourier transform = 2Hz
Explanation:
Given:
Sample signals = 16,384 samples/second
Number of data points = 8,192 oints
Find:
Resolution of Fourier transform
Computation:
Resolution of Fourier transform = fs / N
Resolution of Fourier transform = 16,384 / 8,192
Resolution of Fourier transform = 2Hz
power cords can be damaged by Which of the following?
In a dual cycle, the pressure and temperature at the beginning of the compression process are: 100 KPa and 290 K. During the heat addition process, the first one-third of the total qH occurs at constant volume and the last two-thirds occurs at constant pressure. Assume that the total qH is 2400 kJ/kg, and the compression ratio is 10. Calculate the maximum pressure and temperature and the thermal efficiency of this cycle. Compare the results with those of a conventional Otto cycle having the same given variables.
Answer:
kkklhfh254+326+-9643-5*/1546509866
"%&!83
Explanation:
A car makes a hissing noise each time the A/C system and engine are turned off. Technician A says that the noise is caused by a refrigerant leak. Technician B says that the noise is caused by equalization of system pressures. Who is correct?
Answer:
It's equalization of the system
Explanation: If there was a leak it would likely leak all the time even if the car was turned off. Plus, a system leak bad enough to hear would drain the system of refrigerant very quickly and would no longer cool.
Your company is planning to build a pipeline to transport gasoline from the refinery to a field of storage tanks. The parameters for the prototype system are a pipe diameter of 1 m, with a flow velocity of 0.5 m/s at 25°C. The model system will use water at STP with a geometric scaling factor of 1 : 20. What fluid velocity is required in the model system to guarantee kinematic similarity in the form of equal Reynolds numbers?
Answer:
The model system will need water flowing at a velocity of 2.07 meters per second to guarantee kinematic similarity in the form of equal Reynolds numbers.
Explanation:
The Reynolds number ([tex]Re_{D}[/tex]) is a dimensionless criterion use for flow regime of fluids, which is defined as:
[tex]Re_{D} = \frac{\rho \cdot v\cdot D}{\mu}[/tex] (Eq. 1)
Where:
[tex]\rho[/tex] - Density, measured in kilograms per cubic meter.
[tex]\mu[/tex] - Dynamic viscosity, measured in kilograms per meter-second.
[tex]v[/tex] - Average flow velocity, measured in meters per second.
[tex]D[/tex] - Pipe diameter, measured in meters.
We need to find the equivalent velocity of water used in the prototype system. In this case, we assume that [tex]Re_{D,gas} = Re_{D,w}[/tex]. That is:
[tex]\frac{\rho_{w}\cdot v_{w}\cdot D_{w}}{\mu_{w}} = \frac{\rho_{gas}\cdot v_{gas}\cdot D_{gas}}{\mu_{gas}}[/tex] (Eq. 2)
Where subindex [tex]w[/tex] is used for water and [tex]gas[/tex] for gasoline.
If we know that [tex]\rho_{gas} = 690\,\frac{kg}{m^{2}}[/tex], [tex]\mu_{gas} = 0.006\,\frac{kg}{m\cdot s}[/tex], [tex]v_{gas} = 0.5\,\frac{m}{s}[/tex], [tex]D_{gas} = 1\,m[/tex], [tex]\rho_{w} = 1000\,\frac{kg}{m^{3}}[/tex], [tex]\mu_{w} = 0.0018\,\frac{kg}{m\cdot s}[/tex] and [tex]D_{w} = 0.05\,m[/tex], then we get the following formula:
[tex]57500 = 27777.778\cdot v_{w}[/tex]
The fluid velocity for the prototype system is:
[tex]v_{w} = 2.07\,\frac{m}{y}[/tex]
The model system will need water flowing at a velocity of 2.07 meters per second to guarantee kinematic similarity in the form of equal Reynolds numbers.
Legal metrology would protect consumers from businesses that do not take measurements according to defined measuring regulations.
From what my research concluded, true
Za answa iz:
True
Twust meh
2) Why should you use a standard resistor so that the balance point is near the center of the bridge?
Answer:
Explanation:
I think I will say it is because most, if not all resistors have been made to standard already.
The value for the resistor that is chosen for two fixed arms from the Wheatstone Bridge have to be quite bear each other, as much as possible. The arm that moves and the other that doesn't move, their resistance values are made to be quite close as well. This makes the resistance of the arm that moves to be set somewhere in the middle, and as a result, the measurements don't exceed beyond the resistance range of the arm that moves.
I hope you understand?
Four friends plan to apply to an engineering college for their master’s degrees. Identify which course is most likely to be accepted in an engineering college for admission to a master’s degree program in robotics. Tanya has completed her bachelor’s degree in chemical engineering. In high school, she participated in several technical competitions. Nick graduated in mechanical engineering. Patricia completed an online certificate course in CADD. Matthew completed a certificate course in software testing. He wants to get into software quality in the robotics industry.
Answer:
mechanical engineering
Explanation:
Note, in the case of Patricia and Mathew, they both completed not a bachelor's degree but a certificate course, which does not meet the requirements of a master's degree program in an engineering college.
Furthermore, even though Tanya has a bachelor’s degree in chemical engineering it is less relevant to the field of Robotics.
But Nick who graduated in mechanical engineering (in other words having a bachelor in mechanical engineering) is most likely to be accepted in an engineering college for admission to a master’s degree program in robotics because he has a background in the field of Robotics.
Realiza las siguientes conversiones.
4 Hm2 a Dm2=_______________
21345 Cm2 a M2=_____________
0,592 Km2 a M2=______________
0,102 M2 a Cm2=______________
23911 Km2 a Hm2=_____________
Answer:
a) 4 hectómetros cuadrados equivalen a 400 decámetros cuadrados.
b) 21345 centímetros cuadrados equivalen a 2,135 metros cuadrados.
c) 0,592 kilómetros cuadrados equivalen a 592000 metros cuadrados.
d) 0,102 metros cuadrados equivalen a 1020 centímetros cuadrados.
e) 23911 kilómetros cuadrados equivalen 2391100 hectómetros cuadrados.
Explanation:
a) 4 hectómetros cuadrados a decámetros cuadrados:
Según las unidades de área y sus escalas utilizadas por el Sistema Internacional de Pesos y Medidas, un hectómetro cuadrado equivale a 100 decámetros cuadradps. Entonces, obtenemos el dato equivalente por la siguiente regla de tres simple:
[tex]x = 4\,Hm^{2}\times\frac{100\,Dm^{2}}{1\,Hm^{2}}[/tex]
[tex]x = 400\,Dm^{2}[/tex]
4 hectómetros cuadrados equivalen a 400 decámetros cuadrados.
b) 21345 centímetros cuadrados a metros cuadrados:
Según las unidades de área y sus escalas utilizadas por el Sistema Internacional de Pesos y Medidas, un metro cuadrado equivale a 10000 centímetros cuadrados. Entonces, obtenemos el dato equivalente por la siguiente regla de tres simple:
[tex]x = 21345\,cm^{2}\times \frac{1\,m^{2}}{10000\,cm^{2}}[/tex]
[tex]x = 2,135\,m^{2}[/tex]
21345 centímetros cuadrados equivalen a 2,135 metros cuadrados.
c) 0,592 kilómetros cuadrados a metros cuadrados:
Según las unidades de área y sus escalas utilizadas por el Sistema Internacional de Pesos y Medidas, un kilómetro cuadrado equivale a 1000000 metros cuadrados. Entonces, obtenemos el dato equivalente por la siguiente regla de tres simple:
[tex]x = 0,592\,km^{2}\times \frac{1000000\,m^{2}}{1\,km^{2}}[/tex]
[tex]x = 592000\,m^{2}[/tex]
0,592 kilómetros cuadrados equivalen a 592000 metros cuadrados.
d) 0,102 metros cuadrados a centímetros cuadrados:
Según las unidades de área y sus escalas utilizadas por el Sistema Internacional de Pesos y Medidas, un metro cuadrado equivale a 10000 centímetros cuadrados. Entonces, obtenemos el dato equivalente por la siguiente regla de tres simple:
[tex]x = 0,102\,m^{2}\times \frac{10000\,cm^{2}}{1\,m^{2}}[/tex]
[tex]x = 1020\,cm^{2}[/tex]
0,102 metros cuadrados equivalen a 1020 centímetros cuadrados.
e) 23911 kilómetros cuadrados a hectómetros cuadrados:
Según las unidades de área y sus escalas utilizadas por el Sistema Internacional de Pesos y Medidas, un kilómetro cuadrado equivale a 100 hectómetros cuadrados. Entonces, obtenemos el dato equivalente por la siguiente regla de tres simple:
[tex]x = 23911\,km^{2}\times \frac{100\,Hm^{2}}{1\,km^{2}}[/tex]
[tex]x = 2391100\,Hm^{2}[/tex]
23911 kilómetros cuadrados equivalen 2391100 hectómetros cuadrados.
Nicole designs the hardware configuration of workstations that will be deployed to a newly formed company. She sets up the networking capabilities and policies that will govern the workstations when connected to the company network. What is her role in her company?
Answer:
a Network Engineer (architect)
Explanation:
Indeed, as a Network Engineer, we would expect Nicole to be in charge of planning, setting up, and managing the software and hardware components of the computer networks so that they function as intended.
A Network Engineer therefore would be responsible for setting up the networking capabilities and policies that will govern the workstations when connected to the company network.
gasoline has a comparatively high btu per galloon rating around?
Answer:
116,090 Btus
Explanation:
A robot with artificial intelligence would best be suited for
what are the two safety precautions taken before driving a car
Answer:
1. Check mirrors2. Put on your seat beltExplanation:
1. Checking your mirrors are very important because if someone screwed with them then it can mess up your driving.
2. Putting on your seat belt is a law so you must put it on and it can save your life one day.
What is the stress term called which is a measure of the stiffness or resistance to deflection?
Modulus of Elasticity (E)
Extreme Fiber Bending (F )
Horizontal Shear Parallel to the Grain (F //)
Compression Perpendicular to the Grain (F z )
Answer:Modulus of Elasticity (E)-------- A
Explanation:
The modulus of elasticity, Young's modulus E is a measure of a material's stiffness or resistance to being elastically deformed when stressed or due to tension According to Hook's law the modulus of elasticity is defined as the ratio of the stress to the strain and defined as the slope of its stress-strain region in the stress and strain graph.
--The stiffer a material, the higher the elastic modulus and vice versa for a less stiff material.
it can be calculated with this formulae
Young’s modulus equation is E = tensile stress/tensile strain
= (FL) / (A X change in L)
where F = applied force,
L = initial length,
A = square area,
E = Young’s modulus in Pascals (Pa).
It is desired to enrich the partial pressure of hydrogen in a hydrogen–nitrogen gas mixture for which the partial pressures of both gases are 0.1013 MPa (1 atm). It has been proposed to accomplish this by passing both gases through a thin sheet of some metal at an elevated temperature; in as much as hydrogen diffuses through the plate at a higher rate than does nitrogen, the partial pressure of hydrogen will be higher on the exit side of the sheet. The design calls for partial pressures of 0.051 MPa (0.5 atm) and 0.01013 MPa (0.1 atm), respectively, for hydrogen and nitrogen. The concentrations of hydrogen and nitrogen (CHC
H and CNC N , in mol/m3mol/m
3 ) in this metal are functions of gas partial pressures (pH2 and pN2p
H 2 and p N , in MPa) and absolute temperature and are given by the following expressions:
CH=2.5×103√pH2exp(−27,800J/mol/RT)
CN=2.75×103√pN2exp(−37,600J/mol/RT )
Furthermore, the diffusion coefficients for the diffusion of these gases in this metal are functions of the absolute temperature, as follows:
DH(m2/s)=1.4×10−7exp(−13,400J/mol/RT)
DN(m2/s)=3.0×10−7exp(−76,150J/mol/RT)
Is it possible to purify hydrogen gas in this manner? If so, specify a temperature at which the process may be carried out, and also the thickness of metal sheet that would be required. If this procedure is not possible, then state the reason(s) why.
Answer:
T = 3460 K
Explanation:
See attachment for calculation.
Since the temperature we have is above the melting point of the metal, then we can conclude that it is too high for the diffusion process to be possible.
A gear train has two gears. The driver gear has 8 teeth and a diametral pitch of 6 teeth/inch. the follower gear has 24 teeth. What is the diametral pitch of the follower gear?
Answer:
18 teeth/inch
Explanation:
Given that: i. driver gear has 8 teeth and diametral pitch of 6 teeth/inch.
ii. follower gear has 24 teeth.
Let the followers diametral pitch be represented by x.
Then,
8 teeth ⇒ 6 teeth/inch
24 teeth ⇒ x teeth/inch
So that;
x = [tex]\frac{24 x 6}{8}[/tex]
= [tex]\frac{144}{8}[/tex]
= 18 teeth/inch
The diametral is 18 teeth/inch
The development of various technologies led to many historic events. Use information from the Internet to describe one major historic event
initiated by a technological development or discovery
-
Sometimes, world events lead to the development of a technology. Perform online research and identify a historic event that required the
development of technologies. Discuss one technology created because of this event. How does it continue to affect human lives today?
Answer:
1. Industrial revolution was initiated or borne through the production of Steel
2. World War 1 led to the development of Tanks
Explanation:
The production of Steel through the Bessemer Process in the middle of the nineteenth century was a major technological development that spurred the Industrial revolution. This invention led to the widespread use of steel in the production of many things including vehicles and airplanes.
During the First World War in 1914, soldiers found the use of just their armaments in battle as not so productive. This led to the development of Tanks in 1915 that would continue moving towards the enemy even when being shot at.
At an operating frequency of 5 GHz, a 50 lossless coaxial line with insulating material having a relative permittivity r = 2.25 is terminated in an antenna with an impedance ZL = 150 . Use the Smith chart to find Zin. The line length is 30 cm.
Answer:
The answer is "150 [tex]\Omega[/tex]".
Explanation:
Its line length must be converted into wavelengths for the Smith chart to be used.
[tex]\to \beta = \frac{2 \pi }{\lambda } \\\\\to u_p = \frac{\omega }{\beta}\\\\\lambda =\frac{2 pi}{\beta} =\frac{2 \pi U_p}{\omega}=\frac{c}{\sqrt{\varepsilon_r f}}[/tex]
[tex]= \frac{3 \times 10^8}{ 2.25 \times (5 \times 10^9)}\\\\= \frac{3}{ 2.25 \times 5\times 10 }\\\\= \frac{3}{ 22.5 \times 5 }\\\\= \frac{3}{ 112.5}\\\\= 0.04 \ m.[/tex]
[tex]l =\frac{0.30 }{0.04 } \times \lambda[/tex]
[tex]= 7.5 \lambda[/tex]
Because it is an integrated half-wavelength amount,
[tex]Z_{in} = Z_L = 150 \ \Omega[/tex]
A concrete batch plant has a batching chamber capacity of 12.5 cy and an average batching cycle time of 3 min. Plant efficiency is 84%. What is the estimated batching production in cy/hr?
Answer:
The estimated batching production is 210 cy/hr
Explanation:
Given;
capacity of the batching chamber of the plant, Q = 12.5 cy
average batching cycle time, t = 3 min
plant efficiency, n = 84 %
The estimated batching production is calculated as efficiency of the machine multiplied by the production rate in hour. This is given by the solution below;
Batching production = (nQ )/ t
[tex]Batching \ production = 0.84(\frac{12.5 \ cy}{3 \ min} *\frac{60 \ min}{1 \ hr})\\\\ Batching \ production = 210 \ cy/hr[/tex]
Therefore, the estimated batching production is 210 cy/hr
Two vehicles collided head on while traveling on a curve tangent with a 3% grade. Vehicle V1 skidded 195 feet downhill before colliding with vehicle V2. Vehicle V2 skidded 130 feet. The police report estimates that the speed of both vehicles at impact was 25 mph, based on vehicle deformation. Assume a coefficient of friction of 0.48. What is V1 speed at the beginning of the skid?
Answer:
Speed V1 at the beginning of the skid = 57.075 mph
Explanation:
Calculate the V1 speed at the beginning of the skid
V1 ( speed before brake was applied ) = ?
distance travelled by Vehicle 1 = 195 ft
curve tangent for vehicle 1 = - 3% = - 0.03
coefficient of friction = 0.48
speed at Impact = 25 mph
To determine the V1 speed at the beginning of the skid we have to apply AASTHO
d1 = [tex]( \frac{VA^{2} - VA^{12} }{30(F+N)} )[/tex]
195 = [tex](\frac{VA^2- 25^2}{30(0.48-0.03)} )[/tex]
Hence : VA = 57.075 mph
1. A gas pressure difference is applied to the legs of a U-tube manometer filled with a liquid with S = 1.5. The manometer reading is 286 mm. Find the pressure difference in kPa. (10 points)
2. Convert the pressure 2.5 psi into units of inches of mercury and feet of water (10 points)
Answer:
1) The pressure difference is 4.207 kilopascals.
2) 2.5 pounds per square inch equals 5.093 inches of mercury and 5.768 feet of water.
Explanation:
1) We can calculate the gas pressure difference from the U-tube manometer by using the following hydrostatic formula:
[tex]\Delta P = \frac{S\cdot \rho_{w}\cdot g \cdot \Delta h}{1000}[/tex] (Eq. 1)
Where:
[tex]S[/tex] - Relative density, dimensionless.
[tex]\rho_{w}[/tex] - Density of water, measured in kilograms per cubic meter.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]\Delta h[/tex] - Height difference in the U-tube manometer, measured in meters.
[tex]\Delta P[/tex] - Gas pressure difference, measured in kilopascals.
If we know that [tex]S = 1.5[/tex], [tex]\rho_{w} = 1000\,\frac{kg}{m^{3}}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]\Delta h = 0.286\,m[/tex], then the pressure difference is:
[tex]\Delta P = \frac{1.5\cdot \left(1000\,\frac{kg}{m^{3}} \right)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.286\,m)}{1000}[/tex]
[tex]\Delta P = 4.207\,kPa[/tex]
The pressure difference is 4.207 kilopascals.
2) From Physics we remember that a pound per square unit equals 2.036 inches of mercury and 2.307 feet of water and we must multiply the given pressure by corresponding conversion unit: ([tex]p = 2.5\,psi[/tex])
[tex]p = 2.5\,psi\times 2.037\,\frac{in\,Hg}{psi}[/tex]
[tex]p = 5.093\,in\,Hg[/tex]
[tex]p = 2.5\,psi\times 2.307\,\frac{ft\,H_{2}O}{psi}[/tex]
[tex]p = 5.768\,ft\,H_{2}O[/tex]
2.5 pounds per square inch equals 5.093 inches of mercury and 5.768 feet of water.
A very long rectangular fin is attached to a flat surface such that the temperature at the end of the fin is essentially that of the surrounding air, i.e. 20C. Its width is 5 cm; thickness is 1 mm; thermal conductivity is 200 W/m.K; and base temperature is 40C. The heat transfer coefficient is 22 W/m2 .K. Estimate the temperature at a distance of 5 cm from the base and the rate of heat loss from the entire fin.
Answer:
The answer is below
Explanation:
Given that:
x = 5 cm = 0.05 m, width (w) = 5 cm = 0.05 m, thickness (t) = 1 mm = 0.001 m, k = thermal conductivity = 200 W/mK, h = heat transfer coefficient = 22 W/m².K, Tb = base temperature = 40°C, T∞ = 20°C
[tex]m=\sqrt{ \frac{hp}{kA} }=\sqrt {\frac{22*(2*0.05+2*0.001)}{200*(0.05*0.001)}} =15\ m^{-1}\\\\\frac{T-T_{\infty}}{T_b-T_{\infty}} =e^{-mx}\\\\\frac{T-20}{40-20} =e^{-15*0.05}\\\\T-20=9.45\\\\T=29.45^oC\\\\The\ rate\ of\ heat\ loss\ is:\\\\\dot{Q}=\sqrt{hpkA}(T_b-T_{\infty})\\ \\\dot{Q}=\sqrt{22*(2*0.05+2*0.001)*200*0.05*0.001}*(40-20)\\\\\dot{Q}=3\ W[/tex]
If a 2 1/8 inch diameter medium carbon steel rod is to be turned between centers to a 2 inch diameter using high speed cutting bits without using a coolant, find the following:
Picture linked
Answer:
I think 1 31/32
Explain and justify which type of model to use in the final design phase to present to a client.
Answer:
Visualization model
Explanation:
This type of model uses a computer to analyze and simulate data that require processing to enable presentation to users in a meaningful manner where even a layman could have a clue and understand the results expected. Through this model, results are presented in various forms such as plots of a the results against time for displaying relationships. For example a model that uses an animation could display results in various dimensions such as 2D and 3D ,and position in terms of orientation and position in respect to time.
Answer:
The correct answer is a prototype.
Explanation:
The prototype should be fully functional in order to test out the design, but aesthetics do not necessarily need to be considered yet. The prototype can allow constructive feedback from the client and team members, and it can be smaller than the eventual finished product. It can be used to “sell” an idea to a client.
A hypothetical metal has the simple cubic (SC) crystal structure. If its atomic weight is 70.4 g/mol and the atomic radius is 0.126 nm. Compute its density (in g/cm3)
Answer:
[tex]7304g/cm^3[/tex]
Explanation:
Density is the mass per unit volume, it is usually measured in kg/m³.
The density of a crystal structure is given by:
[tex]\rho=\frac{mass\ of\ atoms\ in\ unit\ cell}{volume\ unit\ cell} =\frac{nA}{V_cN_A} \\\\\rho=density, n= number\ of\ atoms/unit=1\ atom/unit\ cell,A=atomic\ weight=70.4\ g/mol,N_A=avogadro\ constant=6.023*10^{23}atoms/mol,V=volume=2R^3=[2(0.126*10^{-8})]^3cm\\\\\rho=\frac{1*70.4}{[2(0.126*10^{-8})]^3*6.023*10^{23}} =7304g/cm^3[/tex]
Answer:
7.307g/cm^3
Explanation:
The other guy is mostly right but his conversion factor was off. It should be 1.26x10^-8 on the bottom
