A 30 kg child went down a 10 m tall slide. Assuming no energy was lost as friction, what was the child's velocity when he reached the
bottom?
I

Answer:

the kinetic energy of the combined 1.5 kg block when it reaches the bottom of the plane is 10.62 J

Explanation:

Given that the data in the question;

angle of inclination with respect to the ground [tex]\theta[/tex] = 30°

length of plane d = 2m

m₁ = 1 kg

m₂ = 0.5 kg

now, velocity of the first block at midpoint;

[tex]\frac{1}{2}[/tex]mv² = mgsin[tex]\theta[/tex][tex]\frac{d}{2}[/tex]

[tex]\frac{1}{2}[/tex]v² = gsin[tex]\theta[/tex][tex]\frac{d}{2}[/tex]

v² = gsin[tex]\theta[/tex]d

v = √( gsin[tex]\theta[/tex]d)

g is 9.8 m/s

so we substitute

v = √( 9.8 × sin30° × 2)

v = √( 19.6 )

v =  3.13 m/s

Now, velocity just after collision of the blocks will be;

(m₁ + m₂)v₂ = m₁v

v₂ = m₁v / (m₁ + m₂)

we substitute

v₂ = (1 × 3.13) / (1 + 0.5)

v₂ = 3.13 / 1.5

v₂ = 2.0866 m/s

now, final kinetic energy will be;

[tex]KE_f[/tex] = (m₁ + m₂)gsin[tex]\theta[/tex][tex]\frac{d}{2}[/tex] + Initial Kinetic energy

[tex]KE_f[/tex] = (m₁ + m₂)gsin[tex]\theta[/tex][tex]\frac{d}{2}[/tex] + [tex]\frac{1}{2}[/tex]mv₂²

we substitute

[tex]KE_f[/tex] = [(1 + 0.5)9.8 × sin30 × [tex]\frac{2}{2}[/tex]] + [[tex]\frac{1}{2}[/tex] × 1.5 × 2.0866 ]

[tex]KE_f[/tex] = 7.35 + 3.2654

[tex]KE_f[/tex] = 10.62 J

Therefore, the kinetic energy of the combined 1.5 kg block when it reaches the bottom of the plane is 10.62 J

Answer: 9.42

Explanation: yes

It would be 50 kg.

Mass doesn't change.

Weight can.

position in a gravitation field (c)

Answer:

The answer is C. position in a gravity field

There actually three assertions here: one in A and two more in B.

All three assertions, as well as the reasoning described in this mess, are all False.

The correct choice from the list is e), but that doesn't even describe the complete Falseness of this disaster.

Answer:

6 V.

Explanation:

We'll begin by calculating the equivalent resistance of the circuit. This can be obtained as follow:

Resistor 1 (R₁) = 3 Ω

Resistor 2 (R₂) = 3 Ω

Equivalent Resistance (R) =?

Since the two resistor are in parallel connection, the equivalent resistance can be obtained as:

R = (R₁ × R₂) / (R₁ + R₂)

R = (3 × 3) / (3 + 3)

R = 9/6

R = 1.5 Ω

Finally, we shall determine the total voltage in the circuit. This can be obtained as follow:

Current (I) = 4 A

Equivalent Resistance (R) = 1.5 Ω

Total voltage (V) =?

V = IR

V = 4 × 1.5

V = 6 V

Thus, the total voltage in the circuit is 6 V

Answer:

The correct solution is "1230 K".

Explanation:

The given values are:

[tex](V_{rms})_1= 200 \ m/sec[/tex]

[tex](V_{rms})_2= 350 \ m/sec[/tex]

[tex]T_1=400 \ K[/tex]

As we know,

⇒  [tex]V_{rms} \propto \sqrt{T}[/tex]

or,

⇒  [tex]\frac{(V_{rms})_1}{(V_{rms})_2} =\sqrt{\frac{T_1}{T_2} }[/tex]

On substituting the values, we get

⇒  [tex]\frac{200}{350} =\sqrt{\frac{400}{T_2} }[/tex]

⇒   [tex]T_2=1230 \ K[/tex]

Answer:

Please see the direction of force in the attachment

Explanation:

As the particle enters the capacitor, it experiences electric. In order to move in the same direction as the electron was moving before entering the capacitor, the force due to the electric field of capacitor must be balanced by the magnetic field.

The direction of particle is shown in the attachment.

As we know,

Force = q (v *B)

Answer:

C. Solids,Liquids, Gases

Answer:

The beat frequency = 2.0 Hz

Explanation:

From the given information

The 3rd harmonic frequency of the note is equivalent to thrice note A fundamental frequency.

i.e.

[tex]f_{3A} = 3f_A[/tex]

where;

[tex]f_A =[/tex] note A fundamental freq.

replacing 440 Hz for [tex]f_A[/tex]

[tex]f_{#a} = 3 (440 \ Hz)[/tex]

[tex]f_{3A} = 1320 Hz[/tex]

However, the 2nd harmonic of the E is equivalent to two times the fundamental frequency of the note E.

i.e.

[tex]f_{2E} = 2f_E[/tex]

[tex]f_E =[/tex]  note E fundamental freq.

replacing 659 Hz for [tex]f_E[/tex]

[tex]f_{2E} = 2(659)[/tex]

[tex]f_{2E} = 1318 \ Hz[/tex]

Finally, the beat frequency when the E string is properly tuned is:

[tex]\Delta f = f_{3A}-f_{2E}[/tex]

[tex]\Delta f = 1320 \ Hz - 1318 \ Hz[/tex]

[tex]\Delta f = 2.0 \ Hz[/tex]

Thus, the beat frequency = 2.0 Hz

Answer:

Air exerts forces on falling objects near earth's surface

Explanation:

Falling objects are typically subject to air resistance which prevents the force of gravity on the object

We have that the  is mathematically given as

Fn=36000N

Question Parameters:

mass of 2.0 x 10^3 kg

the radius of curvature is 24 m and

the roller coaster car has a tangential speed of 17 m/s

Generally the equation for the Force   is mathematically given as

F=ma

Fn-fg=mv^2/r

Fn=m(v^2/r+g)

Therefore

Fn=2000(12^2/18+9.8)

Fn=36000N

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Answer:

[tex]\theta_c = 36.78^o[/tex]

Explanation:

The relationship between the refractive index and the critical angle is given as follows:

[tex]\eta = \frac{1}{Sin\ \theta_c} \\\\Sin\ \theta_c = \frac{1}{\eta}\\\\\theta_c = Sin^{-1}(\frac{1}{\eta} )[/tex]

where,

η = refractive index = 1.67

θc = critical angle =?

Therefore,

[tex]\theta_c = Sin^{-1}(\frac{1}{1.67} )[/tex]

[tex]\theta_c = 36.78^o[/tex]

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Answer:

33.6 / 96   is the fraction of the temperature between ice and freezing

33.6 / 96 = .35

So C = .35 * 100 = 35 deg C  where the ice point would be 0 deg C

You can convert C to F

F = 9 / 5 * C + 32 = 9/5 * 35 + 32 = 95 deg F

Answer:

The ratio of the new volume to the old volume is 8 to 1.

Explanation:

Let's first list what we know:

Since the new cube has sides double the length of the sides of the old cube, and 4 doubled is 8, the length of the sides of the new cube is 8.

The equation for the volume of a cube is [tex]V = s^3[/tex], where "V" is the volume and "s" is the lengths of the sides.

Now, let's solve for the volume of the new cube:

[tex]V = s^3[/tex]

[tex]V = 8^3[/tex]

[tex]V = 512[/tex]

The volume of the new cube is 512 [tex]m^3[/tex].

The ratio of the new volume to the old volume is 512 : 64.

Let's simplify the ratio:

512 : 64

8 : 1

The ratio of the new volume to the old volume is 8 to 1.

P.S. This question should be in the mathematics subject, not the physics subject. (I pretty much only do math problems, so yes, it does matter. I don't know about the others though.)

The direction of the magnetic field in the center of the coil point towards the up. So, the correct option is D.

Right-hand grip rule states that, if you are holding a current carrying conductor with your right hand, such that the curled fingers point towards the direction of current flowing through the conductor, then the thumb will point towards the direction of the magnetic field.

Here,

From the current carrying conductor given,

The current is flowing through the conductor in a direction from left to right or it can be said as, the current is flowing in a clockwise direction.

So, we can apply the right-hand grip rule in this conductor.

According to the right-hand grip rule, stretch the thumb of the right hand and point it towards the direction of flow of current in the conductor. Then the remaining curled fingers will be pointed upwards in the conductor.

Hence,

The direction of the magnetic field in the center of the coil point towards the up.

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Answer:

1000kg

Explanation:

F=MA

Rearrange the formula: M=F/A

plug in values for F (force), and A (acceleration).

M=4000/4

M=1000kg

i think.

not sure tho.

The mass of the jet that accelerates at 4 m/s^2 after a 4000 N force from the engines is 1000 kg.

Newton's second law of motion states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. Mathematically, the law can be expressed as F = ma, where F is the net force acting on the object, m is its mass, and a is its acceleration. This law is fundamental to the understanding of the motion of objects under the influence of external forces.

Rearranging the formula to solve for mass, we get:

m = F / a

Substituting the given values, we get:

[tex]m = 4000 N / 4 m/s^2[/tex]

m = 1000 kg

Therefore, the mass of the jet that accelerates at 4 m/s^2 after a 4000 N force from the engines is 1000 kg.

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Answer:

they're reactions

Explanation:

The relationship between the valence electrons and position is: the number of valence electrons determines the position

This is the number of electrons in the outermost shell of an atom.

NOTE: The outermost shell is called valence shell

This is where an element is located in the periodic table

The position of an element in the periodic table is determined by the number of valence electrons.

For example

Sodium, Na (atomic number of 11) has the following electronic configuration

Since the valence electron is 1, thus, sodium is located in group 1 of the periodic table.

Thus, we can see that the position of an element in the periodic table is related to the valence electron(s) in the atomic shell of the element.

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Answer:

Critical mass is the minimum mass of fissionable material required to sustain a nuclear fission reaction, and a supercritical mass, which will provide more than enough neutrons to sustain a fission reaction at the time of detonation.

Explanation:

Answer:

[tex]0.00195\ \text{m}[/tex]

[tex]0.00293\ \text{m}[/tex]

Explanation:

m = Order = 1

D = Distance between screen and slit = 3.09 m

d = Slit distance = 1.01 mm

[tex]\lambda[/tex] = Wavelength = 639 nm

Distance from the first bright fringe from the central bright fringe is given by

[tex]y=\dfrac{m\lambda D}{d}\\\Rightarrow y=\dfrac{1\times 639\times 10^{-9}\times 3.09}{1.01\times 10^{-3}}\\\Rightarrow y=0.00195\ \text{m}[/tex]

Distance from the first bright fringe from the central bright fringe is [tex]0.00195\ \text{m}[/tex]

Distance from the second dark fringe from the central bright fringe is given by

[tex]y=(m+\dfrac{1}{2})\dfrac{\lambda D}{d}\\\Rightarrow y=(1+\dfrac{1}{2})\dfrac{639\times 10^{-9}\times 3.09}{1.01\times 10^{-3}}\\\Rightarrow y=0.00293\ \text{m}[/tex]

Distance from the second dark fringe from the central bright fringe is [tex]0.00293\ \text{m}[/tex].

Answer:

Explanation:

When the person stands 5.80 ft from the mirror of the wall.

a) The first image is found by multiplying the distance of the left mirror to the person.

i.e.

2 × 5.80 = 11.6 ft

b) The second image is deduced by the addition of the distance of the first image with the distance created by the right mirror.

i.e.

(2 × 13.7 ) + 11.6

= 39 ft

c) The third image is acquired by the addition of the image presented by the left mirror and the image presented by the right mirror.

(2 × 5.80) + 39

= 50.6 ft

Answer:

[tex]39000\ \text{kg m/s}[/tex]

West

Explanation:

m = Mass of car = [tex]1.3\times 10^{3}\ \text{kg}[/tex]

t = Time = 9 seconds

u = Initial velocity = 30 m/s

v = Final velocity = 0

Impulse is given by

[tex]J=m(v-u)\\\Rightarrow J=1.3\times 10^3(0-30)\\\Rightarrow J=-39000\ \text{kg m/s}[/tex]

The magnitude of the total impulse applied to the car to bring it to rest is [tex]39000\ \text{kg m/s}[/tex].

The direction is towards west as the sign is negative.

Answer:

Usually an eletric shock. You can be left with numbness and MAYBE problems with your eyes.

Explanation: