A 2.300×10^−2 M solution of glycerol (C3H8O3) in water is at 20.0°C. The sample was created by dissolving a sample of C3H8O3 in water and then bringing the volume up to 1.000 L. It was determined that the volume of water needed to do this was 999.0 mL . The density of water at 20.0°C is 0.9982 g/mL.

Required:
a. Calculate the molality of the glycerol solution.
b. Calculate the mole fraction of glycerol in this solution.
c. Calculate the concentration of the glycerol solution in percent by mass.
d. Calculate the concentration of the glycerol solution in parts per million.

Answers

Answer 1

Answer:

a) Based on the given information, the volume of the solvent given is 999 ml and the density of water given is 0.9982 gram per ml.  

The mass of solvent can be calculated by the formula mass = density * volume

mass = 0.9982 * 999 = 0.997 Kg

The molarity of the solution given is 2.300 * 10^-2 M

Molality of the glycerol solution can be calculated by using the formula,  

Molality = molarity/solvent (kg) = 2.300 * 10^-2 / 0.997 = 0.023 m

b) Molarity or the moles of the solute given is 2.300 * 10^-2 moles

The moles of solvent can be determined by using the formula, n = mass of solvent/mol.wt = 997/18 (mol.wt of solvent is 18 g/mol), now putting the values we get,  

n = 997/18 = 55.4

The mole fraction of the glycerol will be = 2.300 * 10^-2 M/(2.300 * 10^-2)+55.40

= 4.15 * 10^-4

c) The mass percent of glycerol can be determined by using the formula,  

mass of solute/mass of solution * 100% ----- (i)

The mass of solute can be determined by using the formula,

n = mass of solute/mol.wt of solute

The n or the no. of moles is 2.300 * 10^-2 and the molecular weight of glycerol is 92.09 g/mol. Now putting the values we get,  

mass = 2.300 * 10^-2 * 92.09 = 2.12 grams

Now putting the values in equation (i) we get,  

mass percent = 2.12 / 997 * 100% = 0.21%

d) Based on the above calculation, the mass of solute (glycerol) is 2.12 g or 2.12 * 1000 mg

The volume of water is 999 ml or 999 * 10^-3 L

The concentration of the glycerol solution will be,  

Concentration = 2.12 * 10^3 mg/999 * 10^-3 L  

= 2.12/999 * 10^6 mg/L

= 2122.1 ppm

Answer 2

Considering the solution of molality, mole fraction, mass percentage and ppm, you obtain that:

a) The molality of the glycerol solution is 0.02306 molal.

b) The mole fraction of glycerol in the solution is 4.15×10⁻⁴.

c) The percent by mass is 0.212%.

d) The concentration of the glycerol solution is 2118.07 ppm.

a. Molality

Molality is the ratio of the number of moles of any dissolved solute to kilograms of solvent.

The Molality of a solution is determined by the expression:

[tex]molality=\frac{number of moles of solute}{kilogramsof solvent}[/tex]

In this case, you have a 2.300×10⁻² M solution of glycerol (C₃H₈O₃) in water. The sample was created by dissolving a sample of C₃H₈O₃ in water and then bringing the volume up to 1.000 L.

So, being the molarity the number of moles of solute that are dissolved in a certain volume, the number of moles of glycerol can be calculated as:

number of moles of glycerol= 2.300×10⁻² M× 1 L

number of moles of glycerol= 2.300×10⁻² moles

On the other side, the volume of water needed was 999 mL and the density of water at 20.0∘C is 0.9982 [tex]\frac{g}{mL}[/tex]. So, the mass of water needed can be calculated as:

999 mL×0.9982[tex]\frac{g}{mole}[/tex] = 997.2 grams of water= 0.9972 kg of water

Then, the molality of the solution is:

[tex]molality=\frac{2.300x10^{-2} moles}{0.9972 kg}[/tex]

molality= 0.02306 molal

Finally, the molality of the glycerol solution is 0.02306 molal.

b. Mole fraction

The molar fraction is a way of measuring the concentration that expresses the proportion in which a sustance is found with respect to the total moles of the solution.

In this case, the number of moles of glycerol= 2.300×10⁻² moles

Having 997.2 grams of water, the moles of solvent can be determined knowing that the molar mass of water is 18[tex]\frac{g}{mole}[/tex]:

[tex]number of moles of water=997.2 gramsx\frac{1 mole}{18 grams}[/tex]

number of moles of water= 55.4 moles of water

Being the number of total moles the sum of the moles of grycerol and the numbers of moles of water, the mole fraction can be calculated as:

[tex]mole fraction=\frac{2.300x10^{-2} moles}{2.300x10^{-2}moles+55.4 moles}[/tex]

mole fraction= 4.15×10⁻⁴

In summary, the mole fraction of glycerol in the solution is 4.15×10⁻⁴.

c. Percent by mass

The Percentage Composition is a measure of the amount of mass that an element occupies in a compound and indicates the percentage by mass of each element that is part of a compound.

The mass percentage of a component of the solution is defined as the ratio of the mass of the solute to the mass of the solution, expressed as a percentage.

The mass percentage is calculated as the mass of the solute divided by the mass of the solution, the result of which is multiplied by 100 to give a percentage. This is:

[tex]percent by mass=\frac{mass of solute}{mass of solution}x100[/tex]

In this case, remmeber that you have a number of moles of glycerol of 2.300×10⁻² moles .

Being the molar mass glycerol 92.09 [tex]\frac{g}{mole}[/tex], the mass of glycerol can be calculated as:

2.300×10⁻² moles×92.09 [tex]\frac{g}{mole}[/tex]= 2.11807 grams of glycerol

Remembering that you have 997.2 grams of water, the percent by mass is calculated as:

[tex]percent by mass=\frac{mass of glycerol}{mass of glycerol + mass of water}x100[/tex]

Solving:

[tex]percent by mass=\frac{2.11807 grams}{2.11807 grams + 997.2 grams}x100[/tex]

[tex]percent by mass=\frac{2.11807 grams}{999.31807 grams}x100[/tex]

percent by mass= 0.212%

Finally, the percent by mass is 0.212%.

d. Parts per million

Parts per million (ppm) is a unit of measurement of concentration that measures the number of units of substance in each million units of the whole. In this case, the concentration measurement refers to mg of glycerol per L of solution.

Being the mass of glycerol 2.11807 grams equal to 2118.07 mg (1 g=1000mg), the concentration is:

[tex]concentration=\frac{2118.07 mg}{1 L solution}[/tex]

Solving:

concentration= 2118.07 ppm

In summary, the concentration of the glycerol solution is 2118.07 ppm.

Learn more about:

molality: brainly.com/question/20366625?referrer=searchResults brainly.com/question/4580605?referrer=searchResultsmole fraction: brainly.com/question/14434096?referrer=searchResults brainly.com/question/10095502?referrer=searchResultsmass percentage: brainly.com/question/19168984?referrer=searchResults brainly.com/question/18646836?referrer=searchResults brainly.com/question/24201923?referrer=searchResults brainly.com/question/9779410?referrer=searchResults brainly.com/question/17030163?referrer=searchResultsppm: brainly.com/question/16727593?referrer=searchResults brainly.com/question/13565240?referrer=searchResults

Related Questions

A light wave has frequency of 4.5 * 10^19 Hz. How would this number appear on a scientific calculator? a. 4.E195 b. 19E4.5 c. 4.519E d. 4.5E19

Answers

Answer:

B

Explanation:

17. Consider the reaction shown and identify the statement that is not true.
825°C
CaCO3(s)
+ CaO(s) + CO2(g)
a.
This reaction is balanced as written.
b. The reactant must be heated for this reaction to occur.
c. The products are a solid and a gas.
d. Water must be present for this reaction to occur.
There are no solutions used in this reaction.
e.

Answers

Answer: Water must be present for this reaction to occur.

Explanation:

Decomposition reactions require breaking of bonds which require energy and thus all of the decomposition reactions are endothermic reactions.

The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) whereas liquids are represented by (l) and gases are represented by (g) after their chemical formulas.

The balanced chemical reaction of [tex]CaCO_3[/tex] decomposition is:

[tex]CaCO_3(s)\rightarrow CaO(s)+CO_2(g)[/tex]

The decomposition of [tex]CaCO_3[/tex] requires heat and leads to formation of CaO as solid and [tex]CO_2[/tex] as product.

Thus the the statement that is not true is Water must be present for this reaction to occur.

The number of nitrogen atoms in one mole of nitrogen gas are...

Answers

Explanation:

The number of nitrogen atoms in one mole of nitrogen gas are 6.02214179×1023 nitrogen atoms.

Hope this helps...

The temperature of your water was 22.4 degrees Celsius. The volume of hydrogen collected was 37.1 mL. The atmospheric pressure in the lab room was 29.18 inches Hg. The difference in the water level between the beaker and the burette is 18.4 cm. What was the mass of the magnesium ribbon used?

Answers

Answer:

The correct answer is 27.22 mg.

Explanation:

Based on the given information, the temperature of the water given is 22.4 degree C or 22.4 + 273 = 295.4 K

The volume of the gathered hydrogen is 37.1 ml or 0.0371 L

The pressure mentioned in the lab room is 29.18 in Hg or 29.18 × 2.54 = 74.1172 cm Hg.

18.4 cm is the difference given in the water level between the burette and the beaker, so the pressure is,

74.1172 cm - 18.4 cm = 55.7172 cm Hg or 557.172 mmHg

760 mmHg is equal to 1 atm, therefore, 557.172 mmHg will be equal to,

557.172 mm Hg / 760 mm Hg × 1 atm = 0.733 atm

The moles of hydrogen gas can be calculated by using the ideal gas equation, that is, PV = nRT

n = PV / RT

Putting the values we get,

n = 0.733 atm × 0.0371 L / 0.0821 atm L mol⁻¹ K⁻¹ × 295.4 K

n = 0.00112 mol

Let us consider the equation,

2 HCl + Mg ⇒ H₂ + MgCl₂

By seeing the reaction it is clear that for the generation of 1 mole of hydrogen gas, 1 mole of magnesium is needed.

The moles of magnesium is 0.00112 moles and the molecular mass of magnesium is 24.305 gram per mol

The mass of magnesium ribbon can be determined by using the formula, mass = mole × molecular mass

mass = 0.00112 mole × 24.305 g/mol

mass = 0.02722 grams or 27.22 mg.

The reaction that takes place in a hydrogen-oxygen fuel cell is


2H2(g)+O2(g)⟶2?


Select the major product of the reaction and determine whether the reaction is exothermic or endothermic.



H2O2 , endothermic


H2O2 , exothermic


H2O , endothermic


H2O , exothermic

Answers

Answer:

H20; exothermic

Explanation:

A fuel cell is a device that converts chemical potential energy (energy stored in molecular bonds) into electrical energy. A PEM (Proton Exchange Membrane) cell uses hydrogen gas (H2) and oxygen gas (O2) as fuel. The products of the reaction in the cell are water, electricity, and heat.

Determine the boiling point of a solution that contains 70.6 g of naphthalene (C10H8, molar mass = 128.16 g/mol) dissolved in 722 mL of benzene (d = 0.877 g/mL). Pure benzene has a boiling point of 80.1°C and a boiling point elevation constant of 2.53°C/m.

Answers

Answer:

Boiling point of the solution is 82.3°C

Explanation:

Boiling point elevation is defined as the increasing of a boiling point of a substance by the addition of a solute. The formula is:

ΔT = K×m×i

Where ΔT is change in temperature (Final T - 80.1°C), K is boiling point elevation constant (2.53°C/m), m is molality of the solution (moles of naphthalene / kg of benzene) and i is Van't Hoff factor (1 for Naphthalene)

Moles of 70.6g of naphthalene are:

70.6g × (1mol / 128.16g) = 0.5509 moles

Kg of 722mL of benzene are:

722mL × (0.877g / mL) × (1kg / 1000g) = 0.633kg of benzene

Replacing in boiling point elevation formula:

(T - 80.1°C) = 2.53°C/m×(0.5509mol / 0.633kg)×1

T - 80.1°C = 2.2°C

T = 80.1°C + 2.2°C

T = 82.3°C

Boiling point of the solution is 82.3°C

The boiling point of the solution is 82.21°C.

Number of moles of solute = 70.6 g/128.16 g/mol = 0.55 moles

Mass of solvent= density of solvent× volume of solvent

= 722 mL × 0.877 g/mL = 633.2 g or 0.6332 Kg

Molality of the solution = 0.55 moles/0.6332 Kg = 0.869 m

We know that;

ΔT = K m i

ΔT = Boiling point depression

K = Boiling point constant

m = molality of solution

i = Van't Hoff factor

ΔT =  2.53°C/m × 0.869 m × 1

ΔT = 2.2°C

Recall that;

ΔT = Boiling point of solution-  Boiling point of pure solvent

Boiling point of solution = Boiling point of pure solvent + ΔT

Boiling point of solution =  80.1°C + 2.2°C

Boiling point of solution = 82.21°C

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Lilly is doing a science experiment with a substance in a sealed jar. At first the substances molecules are moving around each other. What will happen to Lily substance if she transfers energy into the substance and causes a face change? after the phase change, the substance molecules will move...

Answers

Explanation:

faster and the substance will be a gas.

According to the forces of attraction and principles of phase change the substance molecules will move faster and the substance will be a gas.

What are forces of attraction?

Forces of attraction  is a force by which atoms in a molecule  combine. it is basically an attractive force in nature.  It can act between an ion  and an atom as well.It varies for different states  of matter that is solids, liquids and gases.

The forces of attraction are maximum in solids as  the molecules present in solid are tightly held while it is minimum in gases as the molecules are far apart . The forces of attraction in liquids is intermediate of solids and gases.

The physical properties such as melting point, boiling point, density  are all dependent on forces of attraction which exists in the substances.

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A boy reached his home by riding motorcycle within 5 minutes by travelling 8 km distance ,them what is his average velocity?​

Answers

Answer:24 kilometers

Explanation:Density divided by time

What is the [H+] concentration of blood, given the ph is 2.5?

Answers

Answer:

0.00316

Explanation:

You have to use the following equation:

[tex]pH=-log[H^+][/tex]

You are given the pH and need to find the concentration of H+.  Plug in the given components and solve.

[tex]2.5=-log[H^+]\\H^+ = 10^{-2.5}\\H^+=0.00316[/tex]

The concentration of H is 0.00316.

1. An electric iron has a
power rating of 750W
a. How many joules of
electric energy does it
change into heat energy
every second?
b. How many joules of
work can it do in 3
seconds
c. How long does it take
the iron to do 1500J of
work?
2. Use the kinetic particle
theory to explain why a
solid has a definite shape
and liquid has none.​

Answers

Explanation:

a) E = P × t

E = 750 × 1 s = 750 J

b) E = P × t

E = 750 × 3s = 2250 J

c) E = P × t

1500 = 750 × t

t = 1500/750

t = 2 s

2. Convert 6.578 x 1023 atoms of magnesium to moles.
6.578 x 1023 atoms x
mol
atoms

Answers

Answer:

1.092 moles of Mg

Explanation:

Avogadro's number is a constant that define the number of particles (Such as atoms, molecules, electrons, ions) that you have in 1 mole. That means in 1 mole you have 6.022x10²³ of the particle in question.

If you have 6.578x10²³ atoms of Mg -and 1 mole of Mg contains 6.022x10²³ atoms of Mg-:

6.578x10²³ atoms of Mg × (1 mole Mg / 6.022x10²³ atoms of Mg) =

1.092 moles of Mg

Why does a skunk have very few predators

Answers

Answer:

because of their chemical defenses. (more info below)

Explanation:

Skunks have relatively few natural predators of their species. This is a testament to the effectiveness of their chemical defenses. Unfortunately, several skunks are killed when they cross busy roads at night. Deterrence is also not effective against a predator with a poor sense of smell like a Great Horned Owl.

hope I helped!

Consider the following reaction where Kc = 77.5 at 600 K: CO(g) + Cl2(g) COCl2(g) A reaction mixture was found to contain 4.24×10-2 moles of CO(g), 4.48×10-2 moles of Cl2(g) and 0.114 moles of COCl2(g), in a 1.00 Liter container. Indicate True (T) or False (F) for each of the following: T 1. In order to reach equilibrium COCl2(g) must be produced. T 2. In order to reach equilibrium Kc must decrease. T 3. In order to reach equilibrium CO must be produced. F 4. Qc is greater than Kc. F 5. The reaction is at equilibrium. No further reaction will occur.

Answers

Answer:

The reaction mentioned in the question is:  

CO (g) + Cl₂ (g) ⇔ COCl₂ (g), the equilibrium constant or Kc will be 77.5 at 600 K. In the given mixture, the moles of CO given is 4.24 × 10⁻² moles, the moles of Cl₂ given is 4.48 × 10⁻² moles, and the moles of COCl₂ given is 0.114 moles. The volume of the container is 1.00 L.  

The concentration or Molarity can be determined by using the formula, concentration (M) = mole/volume (L),  

The molarity of CO = 4.24 × 10⁻² moles / 1.00 L = 4.24 × 10⁻² M

The molarity of Cl₂ = 4.48 × 10⁻² moles / 1.00 L = 4.48 10⁻² M

The molarity of COCl₂ = 0.114 moles / 1.00 L = 0.114 M

The reaction quotient or Qc,  

Qc = [COCl2]/[CO][Cl2]  

Qc = 0.114 / 4.24 × 10⁻² × 4.48 × 10⁻²

Qc = 60.03

Thus, Qc is less than Kc. Hence, the reaction will proceed in forward direction so that equilibrium can be attained, that is, until Qc becomes equal to Kc.  

Therefore, the product (COCl₂) will be produced, and the reactants CO and Cl₂ will get consumed.  

1. The given statement is true.  

2. The given statement is true.  

3. The given statement is false. In order to reach equilibrium, the reactants must be consumed.  

4. The given statement is true.  

5. The given statement is false, that is Qc is not equal to Kc.  

What formula would I use if I was given [OH-] and wanted to find POH?*
1 point
pH = -log[H+]
[H+]= 10^-pH
pOH = -log [OH-]
O [OH-] = 10^-POH

Answers

Answer:

pOH = -log[OH-]

Explanation:

Hello,

To calculate the pH or pOH of a substance, we relate it the negative logarithm of either the H+ or OH- concentration.

pOH is used to find the alkalinity of a solution my measuring the concentration of the hydroxide ion [OH-]. Solutions having a pOH value that is greater than 7 are said to be acidic while solutions with value less than 7 are alkaline.

pH = -log[H+]

While

pOH = -log[OH-]

Note: the pOH value of a solution depends on the concentration of the hydroxide ion in the solution.

Given that benzaldehyde is a meta- director, in the same Marvin editor draw all three resonance structures for the carbocation intermediate that results from STEP 2 in the electrophilic aromatic substitution reaction when benzaldehyde reacts with Br2 in the presence of FeBr3. If you do not remember the structure of the benzene derivative, consult the L3 complete lecture notes slides #21 - 24.

Answers

Answer:

The reaction of FeBr3/Br2 with benzaldehyde will yield a major product in which the -Br is attached to the benzaldehyde at the meta position.

Explanation:

In chemistry, resonance is a way of describing bonding in certain molecules or ions by the combination of several contributing structures into a resonance hybrid in valence bond theory. Resonance structures often explain the formation of certain major and minor products in organic chemistry reactions.

Aromatic aldehydes and ketones undergo electrophilic substitution reactions such as nitration, sulphonation and halogenation. Since the aldehydic group (-CHO) and ketonic group (-COR or -COAr) are electron-withdrawing, they are deactivating and m-directing.

In benzaldehyde, the ring becomes deactivated at ortho & para positions due to an electron withdrawing aldehyde group. Hence electrophilic substitution is favored at Meta position.

This implies that the reaction of FeBr3/Br2 with benzaldehyde will yield a major product in which the -Br is attached to the benzaldehyde at the meta position.

How many moles are in 87.62 grams of strontium?

Answers

Explanation:

it's one mole because the atomic mass is treated as molar mass and the atomic mass of strontium is 87.62 grams/mol

The catalyst used in the industrial production of ammonia: Select the correct answer below: A. enables equilibrium to be reached more quickly B. increases the equilibrium constant C. shifts the equilibrium of the reaction to favor the products D. none of the above

Answers

Answer: A. enables equilibrium to be reached more quickly..

Explanation:

The catalyst can be define as an important ingredient may be a protein in the form of enzyme that is used to speed up the rate of the chemical reaction. The catalyst cause a transformational change in the substrate to produce product. The catalyst do not get consumed in the reaction. In the availability of the catalyst, the forward and reverse rates of the reactions will speed up this will allow the equilibrium to reach faster.

Consider a sample of 3.5 mol of N2(g) at T1 = 350 K, that undergoes a reversible and adiabatic change in pressure from p1 = 1.50 bar to p2 = 0.25 bar. Assume that N2(g) under such conditions can be considered an ideal gas with CV,m = 3 R.
A) What is the final temperature T2 of the gas?B) What is ∆U for the gas in the process?C) What are q and w exchanged by the system in the process?D) What is ∆H for the gas in the process?E) What is ∆S for the gas in the process?F) What is ∆Suni for the universe in the process?

Answers

Answer:

Part A is just T2 = 58.3 K

Part B ∆U = 10967.6 x C[tex]_{V}[/tex] You can work out C[tex]_{V}[/tex]

Part C

Part D

Part E

Part F

Explanation:

P = n (RT/V)

V = (nR/P) T

P1V1 = P2V2

P1/T1 = P2/T2

V1/T1 = V2/T2

P = Pressure(atm)

n = Moles

T = Temperature(K)

V = Volume(L)

R = 8.314 Joule or 0.08206 L·atm·mol−1·K−1.

bar = 0.986923 atm

N = 14g/mol

N2 Molar Mass 28g

n = 3.5 mol N2

T1 = 350K

P1 = 1.5 bar = 1.4803845 atm

P2 = 0.25 bar = 0.24673075 atm

Heat Capacity at Constant Volume

Q = nCVΔT

Polyatomic gas: CV = 3R

P = n (RT/V)

0.986923 atm x 1.5 = 3.5 mol x ((0.08206 L atm mol -1 K-1 x 350 K) / V))

V = (nR/P) T

V = ((3.5 mol x 0.08206 L atm mol -1 K-1)/(1.5 x 0.986923 atm) )x 350K

V = (0.28721/1.4803845) x 350

V = 0.194 x 350

V = 67.9036 L

So V1 = 67.9036 L

P1V1 = P2V2

1.4803845 atm x 67.9036 L = 0.24673075 x V2

100.52343693 = 0.24673075 x V2

V2 = P1V1/P2

V2 = 100.52343693/0.24673075

V2 = 407.4216 L

P1/T1 = P2/T2

1.4803845 atm / 350 K = 0.24673075 atm / T2

0.00422967 = 0.24673075 /T2

T2 = 0.24673075/0.00422967

T2 = 58.3 K

∆U= nC[tex]_{V}[/tex] ∆T

Polyatomic gas: C[tex]_{V}[/tex] = 3R

∆U= nC[tex]_{V}[/tex] ∆T

∆U= 28g x C[tex]_{V}[/tex] x (350K - 58.3K)

∆U = 28C[tex]_{V}[/tex] x 291.7

∆U = 10967.6 x C[tex]_{V}[/tex]

Please balance the following equation: NH4NO3 ---> N2 + O2 + H2O
Please show your work, I keep getting it wrong and I don't know what I'm doing wrong.

Answers

Answer:

2NH4NO3->2N2+O2+4H2O

Explanation:

U have to ensure that they are equal both side s hope it helps

According to collision theory, what three factors govern the effect of temperature on the rate of a chemical reaction?

Answers

Answer:

Collision theory states that the rate constant for a chemical reaction is composed

of three factors, (1) the absolute number of collisions, Z, between molecules; (2) The

fraction of collisions, f, with an energy greater than the activation energy; and (3) the

fraction of molecules, p, in which the molecules are in the correct orientation to react.

k = Zfp Equation 1

The absolute number of collisions, Z, increases with temperature. However, it has

been shown that at 25o

C, the increase in the number of collisions accompanying a 10o

C

increase in temperature accounts for only about 2% of the increase in the reaction rate.

Similarly, while it is important that molecules be in the proper orientation to react when

they collide, molecular orientation is independent of temperature. Thus it follows that the

major factor controlling reaction rates is the fraction, f, of molecules in the reaction

mixture with an energy greater than the activation energy. This factor, f, depends on the

absolute temperature. It has been shown that f is related to Ea by the following equation

Explanation:

Is a forward or reverse reaction favored?
Review the reversible reactions given, along with the associated equilibrium constant Kat room temperature. In each case, determine whether the forward or reverse reaction is favored. CH3COOH – CH3C00++ H+ Choose... Ka=1.8 x 10-5 Choose... AgCl → Agt + Cl Ksp=1.6 x 10-10 Al(OH)3 + A13+ + 30H Choose... Ksp=3.7 x 10-15 A+BAC Choose... K=4.9 x 103

Answers

Answer:

(a) [tex]CH_3COOH \rightleftharpoons CH_3COO^-+ H^+[/tex]: reverse reaction is favored.

(b) [tex]AgCl \rightleftharpoons Ag^+ + Cl^-[/tex]: reverse reaction is favored.

(c) [tex]Al(OH)_3 \rightleftharpoons Al^{3+} + 3OH^-[/tex]: reverse reaction is favored.

(d) [tex]A+B\rightleftharpoons C[/tex]: forward reaction is favored.

Explanation:

Hello,

(a) [tex]CH_3COOH \rightleftharpoons CH_3COO^-+ H^+[/tex]:

In this case, since the Ka is lower than 1, we infer the reverse reaction is favored since the reactant (acetic acid) will tend to have a higher concentration.

(b) [tex]AgCl \rightleftharpoons Ag^+ + Cl^-[/tex]:

In this case, since the Ka is lower than 1, we infer the reverse reaction is favored since the reactant (silver chloride) will tend to have a higher concentration.

(c) [tex]Al(OH)_3 \rightleftharpoons Al^{3+} + 3OH^-[/tex]

In this case, since the Ka is lower than 1, we infer the reverse reaction is favored since the reactant (aluminium hydroxide) will tend to have a higher concentration.

(d) [tex]A+B\rightleftharpoons C[/tex]

In this case, since the Ka is greater than 1, we infer the forward reaction is favored since the product (C) will tend to have a higher concentration.

Regards.

Solve: Turn off Show summary. Use the Choose reaction drop down menu to see other equations, and balance them. Check your answers and then write the balanced equations.

__Al+ __HCl→ __AlCl3+ __H2


__NaCl → __Na + __Cl2


__Na2S+__HCl→__NaCl+ __H2S


Please help!!

Answers

Answer: See below

Explanation:

To balance equations, you want to have the same amount of elements on the product and reactants side.

__Al+ __HCl→__AlCl₃+ __H₂

We see that there are 3 Cl on the products side and 1 on the reactants side, but there are 2 H on the product and 1 on reactant. To fulfill them both, let's put a 6 at HCl.

__Al+ 6HCl→__AlCl₃+ __H₂

Now that we have a 6 at HCl, we can fill in AlCl₃ and H₂.

__Al+ 6HCl→ 2AlCl₃+ 3H₂

All we have left is to fill in Al.

2Al+ 6HCl→ 2AlCl₃+ 3H₂

-----------------------------------------------------------------------------------------------------------------

__NaCl→ __Na+ __Cl₂

Since we have 2 Cl on the products, we must put 2 on the reactants.

2NaCl→ __Na+ 1Cl₂

With 2 NaCl, we can fill in Na.

2NaCl→ 2Na+ 1Cl₂

-----------------------------------------------------------------------------------------------------------------

__Na₂S+ __HCl→ __NaCl+ __H₂S

We see 2 Na on reactants, so we can put 2 on the products.

__Na₂S+ __HCl→ 2NaCl+ __H₂S

With 2 H and 2 Cl on the products, we can put a 2 at HCl.

1Na₂S+ 2HCl→ 2NaCl+ 1H₂S

An iceberg has a volume of 0.1642 ML. What is the mass of the ice(in kg) composing the iceberg( at 0o C)? The density of ice at 0o C is 0.917g/cm^3

Answers

Answer:

1.5x10¯⁴Kg

Explanation:

Data obtained from the question include the following:

Volume = 0.1642mL = 0.1642cm³

Density = 0.917g/cm³

Mass =.?

The Density of a substance is simply defined as the mass per unit volume of the substance. Mathematically, it is represented as:

Density = Mass /volume

With the above formula, we can calculate the mass of the ice as follow:

0.917 = Mass / 0.1642

Cross multiply

Mass = 0.917 x 0.1642

Mass = 0.151g

Finally, we shall convert 0.1506g to kg. This is illustrated below:

1000g = 1k

Therefore, 0.151g = 0.151/1000 = 1.5x10¯⁴Kg

what forms of technology are scientists using to study El Nino

Answers

Answer:

a network of buoys.

Explanation:

It is operated by noaa. The buoys transmit some of the data on a daily basis to NOAA through a satellite in space.

354.5 g of chlorine gas (MW = 70.9 g/mol) is held in a vessel with a fixed volume of 70. L.


What is the pressure of the gas in atmospheres if it's temperature is 30.0°C?


___ atm

Answers

Answer:

1.77 atm

Explanation:

We have to check the values that gives the problem:

V= 70 L

mass =354.5 g

Molas weight= 70.9 g/mol

T=30 ºC

P= ?

We can find the moles of chlorine if we use the molar weight:

[tex]354.5g~\frac{1~mol}{70.9~g}[/tex]

[tex]5~mol[/tex]

Now, we have the moles, volume, temperature therefore we can use the ideal gas equation:

[tex]P*V=n*R*T[/tex]

We know the R value:

[tex]0.082\frac{atm*L}{mol*K}[/tex]

We have “K” units for the temperature, so we need to do the conversion:

[tex]30+273.15=303.15~K[/tex]

With all the data we can plug the values into the equation:

[tex]P*70L=5mol*303.15K*0.082\frac{atm*L}{mol*K} [/tex]

[tex]P=\frac{5mol*303.15K*0.082\frac{atm*L}{mol*K}}{70L}[/tex]

[tex]P=1.77~atm [/tex]

I hope it helps!

Calculate the mean free path of electrons in a metal, such as silver, at room temperature form heat capacity and heat conduction measurements. Take EF ¼ 5 eV, K ¼ 4:29 102 J/s m K, and Cel v ¼ 1% of the lattice heat capacity. (Hint: Remember that the heat capacity in (21.8) is given per unit volume!)

Answers

Answer:

= 4 * 10-8    = 400 Angstrom

Explanation:

EF = 5 eV, K = 4.29 x 102 J/(s m K), and Cvel = 1% of the lattice heat capacity

K= 1/3 (Cv)*v*l

v is fermi velocity which is equal to [tex]v = (2E_f/m)^{0.5}[/tex]

after putting mass of electron as [tex]9.1 * 10^{-31}kg[/tex] and [tex]E_f = 5 eV[/tex] we get [tex]v= 1.33 * 10^6 m/s[/tex]

[tex]C_v[/tex] is 1% of lattice heat capacity

Heat Capacity of Aluminium is [tex]0.897 J g^{-1}K^-1[/tex]

Density = [tex]2.6989 g \ cm^{-3}[/tex]

For  lattice heat capacity you need to use the heat capacity for alimunium given  and then multiply with density to get per unit volume term

Heat Capacity per unit volume =   [tex]0.897 J g^{-1}K^-1[/tex] * [tex]2.6989 g \ cm^{-3}[/tex]

[tex]= 2.42 J K^{-1} cm^{-3} \\\\= 2.42* 10^6 J K^{-1} m^{-3}[/tex]

Cv = 1% of heat capacity per unit volume

[tex]=0.01 * 2.42* 10^8 J K^{-1} m^{-3} \\\\= 2.42* 10^4 J K^{-1} m^{-3}[/tex]

Putting values in this equation K= 1/3 (Cv)*v*l

[tex]l = 3K/(C_v * v )\\\\ = 3 * 4.29 * 10^2 / (2.42* 10^4 * 1.33 * 10^6 )[/tex]

[tex]= 4 * 10^{-8 }[/tex]

  = 400 Angstrom

In addition to mass balance, oxidation-reduction reactions must be balanced such that the number of electrons lost in the oxidation equals the number of electrons gained in the reduction. This balancing can be done by two methods: the half-reaction method or the oxidation number method. The half-reaction method balances the electrons lost in the oxidation half-reaction with the electrons gained in the reduction half-reaction. In either method H2O(l), OH−(aq), and H+(aq) may be added to complete the mass balance. Which substances are used depends on the reaction conditions.

Answers

Answer:

OH−(aq), and H+(aq)

Explanation:

Redox reactions may occur in acidic or basic environments. Usually, if a reaction occurs in an acidic environment, hydrogen ions are shown as being part of the reaction system. For instance, in the reduction of the permanganate ion;

MnO4^-(aq) + 8H^+(aq) +5e-------> Mn^2+(aq) + 4H2O(l)

The appearance of hydrogen ion in the reaction equation implies that the process takes place under acidic reaction conditions.

For reactions that take place under basic conditions, the hydroxide ion is part of the reaction equation.

Hence hydrogen ion and hydroxide ion are included in redox reaction half equations depending on the conditions of the reaction whether acidic or basic.

Classify each amino acid according to whether its side chain is predominantly protonated or deprotonated at a pHpH of 7.40.7.40. The pKapKa values of the Asp, His, and Lys side chains are 3.65, 6.00, and 10.53,3.65, 6.00, and 10.53, respectively.

Answers

Answer: His and Lys are deprotonated but Asp will be protonated.

Explanation:

As the pH is given as 7.4 and pK of His is given as 6.00. There will occur a positive charge on His when it's pH < pK therefore, it is neutral at the given pH.

As the pK value of Lys is 10.53 that is greater than the pH of 7.40. Therefore, charge on Lys is positive.

As the pK value of Asp is 3.65 which is less than the pH value of 7.40. Hence, Asp has a negative charge.

Therefore, we can conclude that His and Lys are deprotonated but Asp will be protonated.

What is an oxidation state?

Answers

Answer:

Oxidation state shows the total number of electrons which have been removed from an element (a positive oxidation state) or added to an element (a negative oxidation state) to get to its present state

The total enthalpy of the products in a reaction is 0 kJ, and the total enthalpy of the reactants is 100 kJ. What is the ΔH for the reaction? Choose the correct answer. –393.5 kJ –100 kJ 0 kJ +100 kJ

Answers

Answer: -100 kJ

Explanation:

Heat of reaction or enthalpy of the reaction is the energy released or absorbed during the course of the reaction.

Heat of reaction is represented by the symbol [tex]\Delta H[/tex].

[tex]\Delta H=H_{products}-H_{reactants}[/tex]

[tex]\Delta H[/tex] = enthalpy of reaction = ?

[tex]H_{products}[/tex] = enthalpy of products = 0 kJ

[tex]H_{reactants}[/tex] = enthalpy of reactants = 100 kJ

[tex]\Delta H=0kJ-100kJ[/tex]

[tex]\Delta H=-100kJ[/tex]

Thus the ΔH for the reaction is -100kJ

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