Answer:
A) m[tex]_{T}[/tex] = 0.3025 * 0.0476 * 92.13 = 1.327 Ibm
B) T= 63.32°F
Explanation:
Given data:
1000 gallon tank currently contains 100.0 gallons of liquid toluene
and A gas saturated with toluene vapor at 85°F and 1 atm
A) Calculate quantity of toluene ( Ibm ) that will enter the atmosphere when the tank is filled
m[tex]_{T}[/tex] = [tex]n_{gas} * Y_{T} * M_{T}[/tex]
[tex]n_{gas}[/tex] (total mole of gas) = 0.3025 Ib-mole ( calculated using : [tex]\frac{PV}{RT}[/tex] )
[tex]Y_{T}[/tex] (mole fraction of toluene) = 0.0476 ( calculated using [tex]\frac{P_{T} }{P}[/tex] )
M[tex]_{T}[/tex] = 92.13 Ibm/Ib-mole
therefore: m[tex]_{T}[/tex] = 0.3025 * 0.0476 * 92.13 = 1.327 Ibm
B) using Antoine equation to solve for T
Antoine equation : [tex]log_{10} (P_{T} ) = A - \frac{B}{T+C}[/tex]
PT( partial pressure ) = 18.95 ( calculated using : [tex]y_{tb} * P[/tex] )
A = 6.95805
B = 1346.773
T = ?
C = 219.693
to calculate T make T the subject the subject of the equation
T + 219.693 = 1346.773 / 5.68044
∴ T = 17.40°C
convert T to Fahrenheit
T = 1.8 * 17.40 +32
= 63.32°F
An LED lamp powered by a USB-based portable battery has an effective resistance of 500 Ohm. If the battery is rated for 10,000 mAh, then how long can the lamp be powered and what is the total power consumed by the lamp? The operating voltage of a USB powered device is 5V. Assume that the battery is also rated at 5V.
Answer:
Time = 1000 h
Power = 0.05 W = 50 mW
Explanation:
First we will find the current consumed by the lamp. For this purpose we can use the Ohm's Law. The equation of Ohm's Law is written as follows:
V = IR
I = V/R
where,
I = Current = ?
V = Voltage = 5 V
R = Resistance = 500 Ω
Therefore,
I = 5 V/500 Ω
I = 0.01 A = 10 mA
Now the time duration of the operation f lamp can be found by:
Time = Rating/Current
Time = 10000 mAh/ 10 mA
Time = 1000 h
The power consumption of lamp is given as follows:
Power = IV
Power = (0.01 A)(5 V)
Power = 0.05 W = 50 mW
A current of 1.0 A from a 1.0 mm diameter wire enters a sphere which is 1.0 m in radius and exits through a 1.0 mm diameter wire on the opposite side of the sphere. What is the smallest value of current density in the sphere?
Answer:
The current density in the sphere is 0.32 A/m²
Explanation:
Given that,
Current = 1.0 A
Diameter = 1.0 mm
Radius of sphere = 1.0 m
We need to calculate the current density in the sphere
Using formula of current density
[tex]J=\dfrac{I}{A}[/tex]
Where, I = total current
A = area of sphere
Put the value into the formula
[tex]J=\dfrac{1.0}{\pi\times(1.0)^2}[/tex]
[tex]J=0.32\ A/m^2[/tex]
Hence, The current density in the sphere is 0.32 A/m²
un avión aterriza en la superficie de un portaaviones a 50 m/s y se detiene por completo en 120 metros, ¿cuál es la aceleración necesaria para detenerlo?
Answer:
La aceleración necesaria para detener el avión es - 10.42 m/s².
Explanation:
Un movimiento uniformemente acelerado (M.U.A) es aquél cuya aceleración es constante y la velocidad de un objeto cambia a medida que el movimiento evoluciona.
Siendo la aceleración "a" el cambio de velocidad al tiempo transcurrido en un punto A a B, la velocidad inicial la velocidad que tiene un cuerpo al iniciar su movimiento en un período de tiempo y la velocidad final la velocidad que tiene un cuerpo al finalizar su movimiento en un período de tiempo, entonces en M.U.A se cumple:
Vf² - Vo² = 2*a*d
donde:
Vf: Velocidad final Vo: Velocidad inicial a: Aceleración d: Distancia recorridaEn este caso:
Vf: 0 m/s, porque el avión se detieneVo: 50 m/sa: ?d: 120 mReemplazando:
(0 m/s)² - (50 m/s)² = 2*a*120 m
Resolviendo:
[tex]a=\frac{(0 m/s)^{2} -(50 m/s)^{2} }{2*120 m}[/tex]
a= - 10.42 m/s²
La aceleración necesaria para detener el avión es - 10.42 m/s².
A cart with an unknown mass is at rest on one side of a track. A student must find the mass of the cart by using Newton’s second law. The student attaches a force probe to the cart and pulls it while keeping the force constant. A motion detector rests on the opposite end of the track to record the acceleration of the cart as it is pulled. The student uses the measured force and acceleration values and determines that the cart’s mass is 0.4kg . When placed on a balance, the cart’s mass is found to be 0.5kg . Which of the following could explain the difference in mass?
Answer choices:
A) The track was not level and was tilted slightly downward.
B) The student did not pull the cart with a force parallel to the track.
C) The wheels contain bearings that were rough and caused a significant amount of friction.
D) The motion sensor setting was incorrect. The student set it up so that motion away from the sensor would be the negative direction.
Answer: The correct answer is A) The track was not level and was tilted slightly downward.
Explanation: This is because of the two values: 0.4 kg and 0.5 kg. I won't go into much detail but due to this difference of mass, we know that the track was not level.
"The track was not level and was tilted slightly downward" could explain the difference in the mass.
Mostly because the university student or learners calculates a mass of just over the spring quantity, the vehicle speed seems to have been higher than there would have had to be.Option B, as well as Option C, are wrong because the acceleration would've been smaller in each of these 2 circumstances, so that computed mass would've been larger.
Thus Option A is appropriate.
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For both resonance curves and Fourier spectra, amplitude is plotted vs frequency, but these two types of plots are not the same. Describe how they are different.
Answer:
he peaks are the natural frequencies that coincide with the excitation frequencies and in the second case they are the natural frequencies that make up the wave.
Explanation:
In a resonance experiment, the amplitude of the system is plotted as a function of the frequency, finding maximums for the values where some natural frequency of the system coincides with the excitation frequency.
In a Fourier transform spectrum, the amplitude of the frequencies present is the signal, whereby each peak corresponds to a natural frequency of the system.
From this explanation we can see that in the first case the peaks are the natural frequencies that coincide with the excitation frequencies and in the second case they are the natural frequencies that make up the wave.
what is the force produced on a body of 30kg mass when a body moving with the velocity of 26km/hr is acceleted to gain the velocity of 54 km/hr in 4 sec
Answer:
F = 58.35 [N]
Explanation:
To solve this problem we must use Newton's second law, which tells us that force is equal to the product of mass by acceleration. But first we must use the following equation of kinematics.
We have to convert speeds from kilometers per hour to meters per second
[tex]\frac{26km}{hr}*\frac{1000m}{1km}*\frac{1hr}{3600s}=\frac{7.22m}{s} \\\frac{54km}{hr}*\frac{1000m}{1km}*\frac{1hr}{3600s}=15\frac{m}{s}[/tex]
[tex]v_{f}=v_{o}+(a*t) \\[/tex]
where:
Vf = final velocity = 15 [m/s]
Vi = initial velocity = 7.22 [m/s]
a = acceleration [m/s^2]
t = time = 4 [s]
Note: the positive sign of the above equation is because the car increases its speed
15 = 7.22 + (a*4)
a = 1.945 [m/s^2]
Now we can use the Newton's second law:
F = m*a
F = 30*1.945
F = 58.35 [N]
An 10.2-kg stone at the end of a steel (Young's modulus 2.0 x 10^11 N/m2) wire is being whirled in a circle at a constant tangential
speed of 11.6 m/s. The stone is moving on the surface of a frictionless horizontal table. The wire is 3.62 m long and has a radius of
4.10 x 10^-3m. Find the strain in the wire.
Answer:
[tex]3.6\times 10^{-5}[/tex]
Explanation:
m = Mass of stone = 10.2 kg
v = Tangential velocity = 11.6 m/s
l = Length of wire = 3.62 m
r = Radius of wire = [tex]4.1\times 10^{-3}\ \text{m}[/tex]
A = Area of wire = [tex]\pi r^2[/tex]
Y = Young's modulus of steel = [tex]2\times 10^{11}\ \text{N/m}^2[/tex]
[tex]\varepsillon[/tex] = Strain
The force acting on the stone will be centripetal
[tex]F=\dfrac{mv^2}{l}\\\Rightarrow F=\dfrac{10.2\times 11.6^2}{3.62}\\\Rightarrow F=379.15\ \text{N}[/tex]
Stress is given by
[tex]\sigma=\dfrac{F}{A}\\\Rightarrow \sigma=\dfrac{379.15}{\pi (4.1\times 10^{-3})^2}\\\Rightarrow \sigma=7179488\ \text{N/m}^2[/tex]
Young's modulus is given by
[tex]Y=\dfrac{\sigma}{\varepsilon}\\\Rightarrow \varepsilon=\dfrac{\sigma}{Y}\\\Rightarrow \varepsilon=\dfrac{7179488}{2\times 10^{11}}\\\Rightarrow \varepsilon=3.6\times 10^{-5}[/tex]
Strain in the wire is [tex]3.6\times 10^{-5}[/tex].
Given a force of 10 N and an acceleration of 5 m/s2, what is the mass?
Answer:
2kg
Explanation:
i think i found it yous welcom
An FM radio station, 20 miles away, broadcast at a 93.4 MHz frequency(a) What is the wavelength of the radio wave associated with this signal ?(b) How long does it take for the signal to reach your radio from the station ?
Answer:
(a) Wavelength = 3.21 m (b) Time = [tex]1.07\times 10^{-4}\ s[/tex]
Explanation:
Given that,
The frequency of FM radio station, f = 93.4 MHz
(a) We need to find the wavelength of the radio wave associated with this signal. The relation between wavelength and frequency is given by :
[tex]c=f\lambda\\\\\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{93.4\times 10^6}\\\\\lambda=3.21\ m[/tex]
(b) It is given that, an FM radio station, 20 miles away. Let t is time taken for signal to reach your radio from the station. So,
[tex]t=\dfrac{d}{c}\\\\t=\dfrac{20\times 1609.34}{3\times 10^8}\\\\t=1.07\times 10^{-4}\ s[/tex]
Hence, this is the required solution.
Omar observes that many buildings in his city were built using limestone. He has read that acid rain can damage limestone. He also knows that limestone reacts with acids and that chemical reactions are affected by temperature. With this in mind, he conducts an investigation to see how the amount of damage to the limestone is affected by the amount of acid on the stone.
Which statement describes the correct plan for his procedure?Rhonda watched a video taken by a camera that was lifted into the upper atmosphere by a weather balloon. She saw the balloon pop when it reached a certain height. Afterward, Rhonda wondered what effect the air pressure at high altitudes has on the volume of gas in balloons.
What scientific practice is Rhonda performing
Answer:he conducts the investigation to see the effect acidic water has on limestone
Explanation:
There are two unitless vectors:
F1 = 8.92 i + 17.37 j
F2 = 8.31 i - 10.97 j
A third vector is added to them such that they add up to to the null vector:
F1 + F2 + F3 = 0
What is the angle of the third vector with respect to the +x-axis?
Answer:
[tex]200.38^0[/tex]
Explanation:
Given the forces:
F1 = 8.92 i + 17.37 j
F2 = 8.31 i - 10.97 j
If a third vector is added to them such that they add up to to the null vector as F1 + F2 + F3 = 0
then to get F3:
F3 = -F2-F1
F3 = -(8.31 i - 10.97 j)-(8.92 i + 17.37 j )
F3 = -8.31 i + 10.97 j-8.92 i - 17.37 j
F3 = -8.31i-8.92i+10.97j-17.37j
F3 = -17.23i-6.4j
from the vector:
x = -17.23 and y = -6.4
angle of the third vector with respect to the +x-axis is expressed as:
[tex]\theta = tan^{-1}\frac{y}{x}\\ \theta = tan^{-1}\frac{-6.4}{-17.23}\\\theta = tan^{-1}0.3715\\\theta = 20.38^0[/tex]
Hence the angle the vector makes with the x axis will be [tex]\theta = 180+20.38 = 200.38^0[/tex]
A cannon ball is shot horizontally off a 37.0 m cliff and lands a distance of 18.5 m
from the base of the cliff. Whall was the initial horizontal velocity of the cannon ball?
Answer:
vₓ = 6.73 m/s
Explanation:
Assuming no other external influences than gravity, in the horizontal direction (which we make to coincide with the x- axis) , speed is constant, so, applying the definition of average velocity, we can write the following equation:[tex]v_{x} = \frac{\Delta x}{\Delta t} (1)[/tex]
Now, in the vertical direction (coincident with the y- axis) , as both movements are independent each other, initial velocity is zero, so we can write the following equation for the vertical displacement:[tex]\Delta h = \frac{1}{2} * g * t^{2} (2)[/tex]
where Δh = -37.0 m , g = -9.8 m/s2Solving (2) for t, we get:[tex]t = \sqrt{\frac{2*\Delta h}{g} } =\sqrt{\frac{2*37.0m}{9.8m/s2}} = 2.75 s (3)[/tex]
Taking t₀ = 0, ⇒ Δt = tReplacing (3) in (1), we get:[tex]v_{x} = \frac{\Delta x}{\Delta t} = \frac{x}{t} = \frac{18.5m}{2.75s} = 6.73 m/s[/tex]
As the horizontal velocity is constant, the initial horizontal velocity is just the average one, i.e., 6.73 m/s.1. A 5.00 kg box is being pulled at constant speed up a 30o incline by a force of 45.0 N parallel to the incline. Determine the coefficient of kinetic friction between the box and the plane.
Answer:
μ = 0.48
Explanation:
To solve this problem we must make a free body diagram locating each of the respective forces on the boxes.
We must pay special attention that the body is moving at a constant speed, therefore there is no acceleration, and the sum of forces is equal to zero.
Attached is an image with the sum of forces and the equations of the sum of forces on the x & y axes.
The solution of all equations can be seen, in the attached image.
based on how this sample looks, which term describes the matter that makes up granite?
OA. pure substance
OB. element
OC. mixture
OD. compound
Answer:
C. mixture
Explanation:
A mixture is an impure substance. It has the following properties;
It's composition is indefinite Their constituents retain their identities i.e. physical properties are retained Constituents react differently to changed conditionsThey can easily be separated into constituents by physical methods.Granite is a rock. A rock is usually formed by a combination of different minerals.
Granite is made up of many compounds and so it is a mixture.
Complete each statement by dragging the forms of energy into their appropriate boxes.
wind turbine
roller coaster going downhill
toaster
car
A
converts electrical energy into thermal energy.
A
converts rotational energy into electrical energy.
A
converts gravitational energy into mechanical energy.
A
converts rotational energy into mechanical energy.
Statements 1,2,3 and 4 match statements B, C, A, and D respectively.A wind turbine converts rotational energy into electrical energy.
What is the law of conservation of energy?According to the Law of conservation of energy. Energy can not be created nor be destroyed, it can transfer from one to another form.
1.A wind turbine converts rotational energy into electrical energy.
2.A roller coaster going downhill converts gravitational energy into mechanical energy
3. Toaster converts electrical energy into thermal energy
4.A car converts rotational energy into mechanical energy.
Hence,statements 1,2,3 and 4 match statements B, C, A, and D respectively.
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A 1200-kg car pushes a 2100-kg truck that has a dead battery to the right. When the driver steps on the accelerator, the drive wheels of the car push against the ground with a force of 4500 N. Which, if any, of the following gives a correct acceleration constraint for this problem? The variable ac is the acceleration of the car, and the variable t is the acceleration of the truck.
a. ac=at
b. ac=−at
c. ac=21001200at
d. ac=12002100at
e. There are no acceleration constraints for this problem.
Answer:
Option A: a_c = a_t
Explanation:
Let's denote the force acting on the car due to the truck as F_ct
Similarly, the force acting on the truck due to the car is denoted as F_tc.
Now, F_ct = m_c × a_c
Where;
m_c is mass of car
a_c is acceleration of car
Also, F_tc = m_t × a_t
Where;
m_c is mass of truck
a_c is acceleration of truck
Now, since the car is the one pushing the truck, from Newton's laws, we can say that they stick together and move in the same direction at the same acceleration.
Thus, the truck will move with an acceleration equal to that of the car pushing it.
Thus; a_c = a_t
I need help with this answer
decomposition
A decomposition reaction is just the opposite of combination reaction
If the shoe has less mass, it will experience _______________ (more, less, the same) friction as it would with more mass.
We recommend that our students get at least _____ hours of behind-the-wheel instruction.
A. 6
B. 10
C. 25
D. 50
1pt During a phase change, as energy is added, the temperature of a substance
O A. increases
O B. is constant
O C. decreases
O D. first increases and then decreases to its original value
Answer:
D
Explanation:
Because first phase thr it will follow the law of thermodynamics as it will reach the equilibrium point then decrrases afterwards
Sheldon and Penny are sitting in the back seat of a car that is moving in the x-direction with avelocity of 20 m/s. Sheldon makes a snide remark and Penny responds by throwing the cap ofher soda bottle at him with a velocity of 11 m/s (in what we'll call the y-direction) in theirreference frame. From the point of view of someone standing alongside the road, the speed ofthat cap would be closest to:
Complete Question
The complete question is shown on the first uploaded image
Answer:
The correct option is E
Explanation:
From the question we are told that
The velocity in the x direction is [tex]v_x = 20 \ m/s[/tex]
The velocity of the cap of the soda bottle in the y direction is [tex]v_y = 11 \ m/s[/tex]
Gnerally the speed of the cap as seen by the observer is mathematically represented as
[tex]v_c = \sqrt{v_x^2 + v_y^2}[/tex]
=> [tex]v_c = \sqrt{ 20^2 + 11^2}[/tex]
=> [tex]v_c = 22.83 \ m/s [/tex]
=> [tex]v_c = 23 \ m/s [/tex]
Which of the following is a form of kinetic energy?
A. Electrical energy
B. Potential energy
C. Sound energy
D. Nuclear energy
HELP URGENT
Answer:
Electrical energy ⚡ Hope this helps you Stay happy and safe Do mark as brainliest ✌️Answer:
Potential Energy. It's wrong but it was worth a try
Similar to Hippocrates, modern scientists who study etiology believe that
sickness is caused by spiritual events such as demons entering the body.
diseases come from natural causes such as bites from infected insects.
all diseases can be cured by the right combinations of different treatments.
the best treatment for a germ is a calming practice such as yoga or massage.
In Medicine, "etiology" means the origin or cause of a disease.
Similar to Hippocrates, modern scientists who study etiology believe that diseases come from natural causes such as bites from infected insects.
Answer:diseases come from natural causes such as bites from infected insects
Explanation: just took test
A force of 40 N is applied tangentially to the rim of a solid disk of radius 0.10 m. The disk rotates about an axis through its center and perpendicular to its face with a constant angular acceleration of 145 rad/s2. Determine the mass of the disk.
Answer:
m = 2,759 kg
Explanation:
For this exercise we use the torque relationship
τ = I α
the moment is
τ= F r sin θ
since the force is tangential to the ring, the angle is 90º sin 90 = 1
τ = F r
the moment of inertia of a ring is given by
I = m r²
let's substitute
F r = m r²α
m = F / r α
let's calculate
m = 40 / (0.10 145)
m = 2,759 kg
When a car's starter is in use, it draws a large current. The car's lights draw much less current. As a certain car is starting, the current through the battery is 64.2 A and the potential difference across the battery terminals is 9.36 V. When only the car's lights are used, the current through the battery is 1.96 A and the terminal potential difference is 11.3 V.
A. Find the battery's EMF.
B. What is its internal resistance?
Answer:
EMF = 11.35 V
R = 0.031Ω
Explanation:
To find the battery's EMF and the internal resistance we need to use Ohm's law:
[tex] V = IR [/tex]
Where:
V: is the voltage
I: is the current
R is the resistance
We have:
The current through the battery is 64.2 A and the potential difference across the battery terminals is 9.36 V:
[tex] \epsilon = V + IR [/tex]
[tex] \epsilon = 9.36 V + 64.2A*R [/tex] (1)
When only the car's lights are used, the current through the battery is 1.96 A and the terminal potential difference is 11.3 V:
[tex] \epsilon = 11.3 V + 1.96A*R [/tex] (2)
By solving equation (1) and (2) for R we have:
[tex] 9.36 V + 64.2A*R = 11.3 V + 1.96A*R [/tex]
[tex]R = \frac{1.94 V}{62.24A} = 0.031 \Omega[/tex]
Hence, the internal resistance is 0.031 Ω.
Now, by entering R into equation (1) we can find the battery's EMF:
[tex]\epsilon = 9.36 V + 64.2A*0.031 \Omega[/tex]
[tex] \epsilon = 11.35 V [/tex]
Therefore, the battery's EMF is 11.35 V.
I hope it helps you!
What is the direction of the magnetic field if an electron moving in the positive x direction experiences a magnetic force in the positive z direction
Given :
An electron moving in the positive x direction experiences a magnetic force in the positive z direction.
To Find :
The direction of the magnetic field.
Solution :
We know, force is given by :
[tex]\vec{F}=q(\vec{v}\times \vec{B)}[/tex]
Here, q = -e.
[tex]\vec{F}=(-e)(\vec{v}\times \vec{B)}\\\\\hat{k}=(-e)(\hat{i}\times \vec{B})[/tex]
Now, for above condition to satisfy :
[tex]\hat{i}\times \vec{B}=-\hat{k}[/tex]
So, [tex]\vec{B}=-\hat{j}[/tex]
Therefore, direction of magnetic field is negative y direction.
Hence, this is the required solution.
Determine the accelerations that result when a 12-N net force is applied to a 3-kg object and then to a 6-kg object.
ans: 4m/s²
and 2m/s²
step:
f=m.a
in first condition
f=12N , M=3kg
so,
12=3.a
a=12/3
a=4m/s².
similarly
in second condition
f=12N ,M=6Kg
so,
12=a.6
a=12/6
a=2m/s²
Which formula describes Boyle's law?
ОА.
OB.
D = m/v
V1T2 = V2T
P1V1 = P2V2
P1T2 = P2T1
Ос.
OD
Answer: P1V1 = P2V2
Explanation:
"NEED HELP FAST" Which of the following is a vector quantity?
A. Time
B. Velocity
C. Temperature
D. Distance
Answer:
the answer is b. b velocity. remember v=v
Consider the system consisting of two pendulums coupled by a spring. Write the equations of motion in matrix form. Use small angle approximation.
Answer:
hello your question is incomplete attached below is the complete question
and solution to the question
Explanation:
To write The equation of the motion in Matrix form
i)First we write the net torque equation for left mass
ii)Next we write the net torque equation for right mass
iii) represent the equation of motion in Matrix form
