Answer:
The catcher does negative work on the ball because the force exerted by the catcher is opposite in direction to the motion of the ball.
Explanation:
Using Bernoulli's equation Calculate the percentage increase in the speed of the air on the upper surface of the wings relative to the lower surface,if aircraft mass is 3.3×10^5kg,Total wing area is 500m^2 ,Flight level speed of 9600km/h and density of air is 1.2kgm^-3??
Explanation:
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Given the displacement vector D = (4î − 8ĵ) m, find the displacement vector R (in m) so that D + R = −3Dĵ. (Express your answer in vector form.)
Answer:
--------------------------------
Explanation:
Help please thank you
What is picture ..........
Answer:
In its most general sense, a picture is a visual representation of something, especially in the form of a painting, drawing, photograph, or the like. A picture can also refer to a mental image, among other senses.
The desperate contestants on a TV survival show are very hungry. The only food they can see is some fruit hanging on a branch high in a tree. Fortunately, they have a spring they can use to launch a rock. The spring constant is 900 N/m, and they can compress the spring a maximum of 45 cm. All the rocks on the island seem to have a mass of 500 g.
a) With what speed does the rock leave the spring?
b) To what height can the rock be launched?
Answer:
a) v = 18.86 m / s, b) h = 8.85 m
Explanation:
a) For this exercise we can use the conservation of energy relations.
Starting point. Like the compressed spring
Em₀ = K_e + U = ½ k x² + m g x
the zero of the datum is placed at the point of the uncompressed spring
Final point. With the spring if compress
Em_f = K = ½ m v²
how energy is conserved
Em₀ = Em_f
½ k x² + m g x = ½ m v²
v² = [tex]\frac{k}{m}[/tex] x² + 2gx
let's reduce the magnitudes to the SI system
m = 500 g = 0.500 kg
x = -45 cm = -0.45 m
the negative sign is because the distance in below zero of the reference frame
let's calculate
v² = [tex]\frac{900}{0.500}[/tex] 0.45² + 2 9.8 (- 0.45)
v = √355.68
v = 18.86 m / s
b) For this part we use the conservation of energy with the same initial point and as an end point at the point where the rock stops
Em_f = U = m g h
Em₀ = Em_f
½ k x²2 + m g x = m g h
h = ½ [tex]\frac{k}{g}[/tex] x² + x
let's calculate
h = [tex]\frac{1}{2} \ \frac{900}{9.8 } \ 0.45^2[/tex] - 0.45
h = 8.85 m
measured from the point where the spring is uncompressed
What is Na2SO4?
Help pleaseeee.
Alternate current
Hello!
I need solve 2 questions, I tried but im so bad at physics :(
1. If the frequency in the network is 50Hz, what is the period of this voltage?
2. The effective voltage value in the network is 230V. What is its maximum value?
I would like an explanation with a calculation for my understanding!!
Thanks in advance you all!
sorry bro but i don't know his i am also bad
Explanation:
but maybe you can you the formula of volatage as well as
The provided text reads: "a typical lightning bolt may transfer 10^20 electrons in a fraction of a second, developing a peak current of up to 10 kiloamperes." Using the value of the elementary charge of 1.6x10^-19 C We can estimate the total charge of the lightning bolt to be about *
1.6E1 C
1.6E4 C
1.6E10 C
1.6E20 C
Answer:
1.6e20
Explanation:
4. What quantity of heat is required to raise the temperature of 100
grams of water from 25°C to 45°C? I
Answer:
Q = 836.4 Joules.
Explanation:
Given the following data;
Mass = 100 grams
Initial temperature = 25°C
Final temperature = 45°C
We know that the specific heat capacity of water is equal to 4.182 J/g°C.
To find the quantity of heat;
Heat capacity is given by the formula;
[tex] Q = mcdt[/tex]
Where;
Q represents the heat capacity or quantity of heat.
m represents the mass of an object.
c represents the specific heat capacity of water.
dt represents the change in temperature.
dt = T2 - T1
dt = 45 - 25
dt = 20°C
Substituting the values into the equation, we have;
[tex] Q = 100*4.182*20[/tex]
Q = 836.4 Joules.
Forces act on a box that is initially at rest as shown. Coefficient of friction between the object and the surface is μ=0.1.
If the box' mass is 6kg box and if it is moving with acceleration of 0.4m/s2, what distance will the box travel if it was pushed for 4s?
Answer:
3.2 m
Explanation:
From the question given above, the following data were obtained:
Coefficient of friction (μ) = 0.1
Initial velocity (u) = 0 m/s
Mass (m) = 6 Kg
Acceleration (a) = 0.4 m/s²
Time (t) = 4 s
Distance (s) =.?
The distance travelled can be obtained as illustrated below:
s = ut + ½at²
s = (0×4) + (½ × 0.4 × 4²)
s = 0 + (0.2 × 16)
s = 0 + 3.2
s = 3.2 m
Thus, the box will travel 3.2 m in 4 s.
Which of the following is a conductor?
copper
water
aluminum
all of the above
Answer:
D all of the above
Explanation:
electricity moves easily through all of them and none of them prevent the flow of electricity
When an object threw to the free space to make an angle of 25 degree at an initial speed of 15 m/sec, the ball takes time to reach another position 1.12 sec. Find the travelling path of the object.
Answer:
The horizontal distance traveled by the projectile is 15.23 m.
Explanation:
Given;
angle of projection, θ = 25⁰
initial velocity of the projectile, u = 15 m/s
time of flight, t = 1.12 s
The the travelling path of the object is calculated as the range of the projectile
[tex]R = u_x t\\\\R = (15\ Cos \ 25^0) \times 1.12\\\\R = 13.595 \times 1.12\\\\R = 15.23 \ m[/tex]
Therefore, the horizontal distance traveled by the projectile is 15.23 m.
What does the power source in a circuit provide?
the means to break a circuit
a path along which electricity can flow
static electricity
a steady flow of electrons
plsssssssssssssssssss answer plss not in a meen way but plssss anwer correctly
Explanation:
The primary function of a power supply is to convert electric current from a source to the correct voltage, current, and frequency to power the load. As a result, power supplies are sometimes referred to as electric power converters. Some power supplies are separate standalone pieces of equipment, while others are built into the load appliances that they power. Examples of the latter include power supplies found in desktop computers and consumer electronics devices. Other functions that power supplies may perform include limiting the current drawn by the load to safe levels, shutting off the current in the event of an electrical fault, power conditioning to prevent electronic noise or voltage surges on the input from reaching the load, power-factor correction, and storing energy so it can continue to power the load in the event of a temporary interruption in the source power (uninterruptible power supply).
hope my ans helps
be sure to follow me
Stay safe
A kicker punts a football from the very center of the field to the sideline 41 yards downfield. (A football field is 53 yards wide.)What is the angle between the direction of the net displacement of the ball and the 50-yard line of the field
Answer:
Ur answer is 12 sir!
Explanation:
HAve a good day sir
5. If it takes 50 seconds to lift 10 Newtons of books to a height of 7 meters, calculate the power
required
Answer:
P = 1.4 Watts
Explanation:
Given that,
Weight of books, W = 10 N
It takes 50 seconds to lift the books to a height of 7m. We need to find the power required. Let the power be P. It can be done as follows :
[tex]P=\dfrac{W}{t}\\\\P=\dfrac{mgh}{t}\\\\P=\dfrac{10\times 7}{50}\\\\P=1.4\ W[/tex]
So, the power required is 1.4 watts.
An 80 N force causes a spring to compress 0.15 m. What is the spring constant? What is the potential energy of the spring?
The spring constant of the given spring is= -533.33
The potential energy of the spring= 6 Joule
What is force?
A push or pull that causes object to change its state of rest or motion.
It can also change the direction of a moving body.Force is a product of mass and acceleration.For spring;
K is the spring constant.
⇒Force = -kx
⇒80N=0.15m ×-k
⇒K=-80/0.15
⇒K= -533.333
So the spring constant is 533.333
Potential Energy=1/2kx²
⇒0.5×533.33 ×0.15×0.15
⇒5.95.99 N
Learn more about force here: http://brainly.com/question/25239010
#SPJ2
NEED HELP What color is the container for R-134a refrigerant? A. Light blue B. Yellow C. Dark green D.White and yellow
Answer:
It is A. Light blue
_____________
Hope this helps!
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Which phrase best completes the diagram?
Goals of Social Policy:
Providing citizens with an education ➡️Ensuring the safety of citizens➡️?
A. Helping people who live in poverty.
B. Increasing aid to foreign countries.
The correct answer is:
A. Helping people Who live in poverty
Answer:
Did you ask the question and answer it for yourself?
Answer:
Your amazing thank you, A was right.
10. John does 176 J of work lifting himself a distance of 0.40 m. How
much force must John apply to accomplish this?
O 440 m
O 440 J
O 440 N
O 70.4 J
A force of 100N moves a body on a horizontal frictionless surface when......
I. Friction force exerted on the body is less than 100N
II. Friction force exerted on the body is more than 100N
III. None of these
IV. Both of I and II
Answer:
I. Friction force exerted on the body is less than 100N
Explanation:
For a body to be static, the moving force must be equal to the frictional force. Since the frictional force is a force of opposition. It tends to oppose the moving force acting on an object.
Hence if the moving force is greater than the force of friction, the Force of fiction will not be able to overcome the moving hence the body will tend to move.
Therefore, for a body to move, Fm > Ff or Ff < Ff
Fm is the moving force
Ff is the force of friction
Given
Fm = 100N
For the 100N body to move the frictional force must be less than 100N
What is the name of the supercontinent that developed during the Paleozoic?
Laurasia
Tethys
Pangaea
Rodinia
You have two cylindrical bar magnets with the same mass, length, and dipole moment, but different moments of inertia, I1 and I2. You place each bar magnet so that it is initially oriented perpendicular to a uniform magnetic field. When you let each bar magnet go from rest, you find that magnet 1 takes less time than magnet 2 to rotate so that it is parallel to the magnetic field. Is I1 greater than, less than, or equal to I2
Answer:
[tex]l1 < l2[/tex]; [tex]l1[/tex] is less than [tex]l2[/tex]
Explanation:
Firstly, we take a look at the concept of moment of inertia, This concept comes from the fact that it resists change in motion. A body that has a higher value of moment of inertia requires more force ( torque) to change its position as compared to a body with lesser value of moment of inertia.
Now taking a look at the situation in the question, both the magnets are placed in similar magnetic field, so having the same amount of force, hence torque acts on both magnets.
Since magnet 1 takes less time to rotate compared to magnate 2, hence magnet 1's moment of inertia should be less than that of magnet 2.
Therefore, [tex]l1 < l2[/tex]; [tex]l1[/tex] is less than [tex]l2[/tex]
The stem cell therapy is ethical?
how is sound produced by using pipel wind instruments
Answer33
Explanation
33
Chromosomes _____.
carry thousands of genes
can be analyzed in a karyotype
always occur in pairs
are tight coils of DNA
are carried on genes
Answer:
The correct answer for this would be D.
Explanation:
Are tight coils of DNA
Two bicycle tires are set rolling with the same initial speed of 4.0 m/s along a long, straight road, and the distance each travels before its speed is reduced by half is measured. One tire is inflated to a pressure of 40 psi and goes a distance of 18.2 m; the other is at 105 psi and goes a distance of 92.6 m. Assume that the net horizontal force is due to rolling friction only and take the free-fall acceleration to be g = 9.80 m/s2. What is the coefficient of rolling friction μr for the tire under low pressure?
Answer:
The coefficient of rolling friction will be "0.011".
Explanation:
The given values are:
Initial speed,
[tex]v_i = 4.0 \ m/s[/tex]
then,
[tex]v_f=\frac{4.0}{2}[/tex]
[tex]=2.0 \ m/s[/tex]
Distance,
s = 18.2 m
The acceleration of a bicycle will be:
⇒ [tex]a=\frac{v_f^2-v_i^2}{2s}[/tex]
On substituting the given values, we get
⇒ [tex]=\frac{(2.0)^2-(4.0)^2}{2\times 18.2}[/tex]
⇒ [tex]=\frac{4-8}{37}[/tex]
⇒ [tex]=\frac{-4}{37}[/tex]
⇒ [tex]=0.108 \ m/s^2[/tex]
As we know,
⇒ [tex]f=ma[/tex]
and,
⇒ [tex]\mu_rmg=ma[/tex]
⇒ [tex]\mu_r=\frac{a}{g}[/tex]
On substituting the values, we get
⇒ [tex]=\frac{0.108}{9.8}[/tex]
⇒ [tex]=0.011[/tex]
PLEASEEEE HELP ASAP
What are the two main divisions
of the peripheral nervous system?
A. Muscular Nervous System, Digestive Nervous
System
B. Circulatory Nervous System, Endocrine
Nervous System
C. Somatic Nervous System, Autonomic Nervous
System
A cart moves with negligible friction or air resistance along a roller coaster track. The cart starts from rest at the top of a hill of unknown height. It then goes down that first hill and up another circularly shaped hill of height 10 meters and radius 15 meters. The ride is designed so that the cart just barely loses contact with the track at the top of the second hill (10 meters above ground level). What is the height of the starting hill relative to ground
Answer:
hinit = 17.5 m
Explanation:
Assuming no friction present, the mechanical energy must be conserved, which means that at any point of the trajectory, the sum of the gravitational potential energy and the kinetic energy must keep the same.At the top of the hill, since it starts from rest, all the energy must be potential, and we can express it as follows:[tex]E_{o} = U_{o} = m*g*h_{init} (1)[/tex]
When the car arrives to the top of the second hill, as we know that it is lower than the first one, the energy of the car, must be part gravitational potential energy, and part kinetic energy.We can express this final energy as follows:[tex]E_{f} = U_{f} + K_{f} = m*g* h_{2} + \frac{1}{2} *m*v_{f} ^{2} (2)[/tex]
In order to find hinit, we need to make (1) equal to (2), and solve for it.In (2) we have the value of h₂ (10 m), but we still need the value of the speed at the top of the second hill, vf.Now, when the car is at the top of the hill, there are two forces acting on it, in opposite directions: the normal force (upward) and the weight (downward).We know also that there is a force that keeps the car along the circular track, which is the centripetal force.This force is just the net downward force acting on the car (it's vertical at the top), and is just the difference between the weight and the normal force.If the cart just barely loses contact with the track at the top of the second hill, this means that at that point the normal force becomes zero.So, the centripetal force must be equal to the weight.The centripetal force can be expressed as follows:[tex]F_{c} = m*\frac{v_{f} ^{2}}{R} (3)[/tex]
We have just said that (3) must be equal to the weight:[tex]F_{c} = m*\frac{v_{f} ^{2}}{R} = m*g (4)[/tex]
Simplifying, and rearranging, we can solve for vf², as follows:[tex]v_{f}^{2} = R*g (5)[/tex]
Replacing (5) in (2), simplifying and rearranging in (1) and (2) we finally have:[tex]h_{init} = h_{2} + \frac{1}{2} R = 10m + 7.5 m = 17.5 m (6)[/tex]
Calculate the electrical force that acts on one plate of a parallel plate capacitor. The potential difference between the plates is 10 volts, and the plates are squares 20 cm on a side with a separation of 3 cm. If the plates are insulated so the charge cannot change, how much external work could be done by letting the plates come together
Answer:
The work done in bringing the plates together is 5.9 x 10⁻¹⁰ J.
Explanation:
Given;
potential difference between the plates, V = 10 V
length of each square side of the plates, L = 20 cm = 0.2 m
area of the plates, A = 0.2 x 0.2 = 0.04 m²
separation of the plates, d = 3 cm = 0.03 m
The work done in bringing the plates together is calculated as;
W = ¹/₂qV
[tex]W = \frac{1}{2} (\frac{\epsilon_0 A }{d}V) \times V\\\\W = \frac{\epsilon_0 A V^2}{2d}\\\\W = \frac{8.85 \times 10^{-12} \ \times \ 0.04\ \times \ 10^2}{2(0.03)} \\\\W = 5.9 \times 10^{-10} \ J[/tex]
Therefore, the work done in bringing the plates together is 5.9 x 10⁻¹⁰ J.
Please help
A meteoroid with a mass of 1,000 kg enters Earth's atmosphere with a velocity of 4,400 m/s. What is the magnitude of the meteorold's momentum at
that instant?
