5.) This car battery
measures at 12.6 V
with a voltmeter. If it
produces 0.53 A of current for
a vehicle's headlight when
connected, what is the
resistance of the headlight
bulb?

Answer:

they can asked to sue

Explanation:

bud

Answer:

The correct response will be "13.755 kN".

Explanation:

According to the question,

The given values are:

a = 300 mm

i.e.,

  = 0.3 cm

b = 200 mm

i.e.,

  = 0.2 dm

Internal pressure,

[tex]P_{in}=100[/tex]

Now,

The area of the elliptical shape window will be:

⇒  [tex]A = \pi ab[/tex]

On substituting the values, we get

⇒      [tex]=3.14\times 0.300\times 0.200[/tex]

⇒      [tex]=0.1885 \ m^2[/tex]

By using the table,

At 10 km, the atmospheric pressure will be

⇒  [tex]p_o=27.03 \ kPa[/tex]

Now,

The outward force will be:

⇒  [tex]F_{net}=p_{in}A-p_{0}A[/tex]

⇒          [tex]=(p_{in}-p_{0})A[/tex]

⇒          [tex]=(100-27.03)\times (0.1885)[/tex]

⇒          [tex]=13.755 \ kN[/tex]

When charged objects touch, you can assume that the charges move between the objects, so that the total amount of charge doesn't change but it splits equally between the two objects.

-- like two water tanks standing next to each other, with a different amount of water in each one.  When you connect a pipe between their bottoms, some water flows across until the LEVEL of water is the same in both tanks.

-- like one hard full balloon and one soft mooshy balloon.  When you connect them together, some air flows from the hard balloon into the soft balloon, until the pressure of air is the same in both balloons.  

The total amount of charge on your two objects is (+6.0 μC  -  2.0 μC).  That's +4.0 μC  .

When they touch, charges move around until the charge is the same on both objects . . . +2 μC.

Answer:

P = 24.32 W

Explanation:

The question is, "Two resistors 5 Ω and 10 Ω are connected in parallel with a 9 V power supply. Calculate the output power of the power supply.".

The voltage of the power supply, V = 9 V

Resistor 1, R₁ = 5 Ω

R₂ = 10 Ω

The equivalent of parallel combination of resistors is given by :

[tex]\dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}\\\\\dfrac{1}{R_{eq}}=\dfrac{1}{5}+\dfrac{1}{10}\\\\R_{eq}=3.33\ \Omega[/tex]

The power of the output is given by :

[tex]P=\dfrac{V^2}{R_{eq}}\\\\=\dfrac{9^2}{3.33}\\\\P=24.32\ W[/tex]

So, the output power is equal to 24.32 W.

Answer:

Mars

Explanation:

In the 1960s, humans set out to discover what the red planet has to teach us. Now, NASA is hoping to land the first humans on Mars by the 2030s. Mars has captivated humans since we first set eyes on it as a star-like object in the night sky.

good luck

please mark me as a brainliest

Answer:

   [tex]c_{e1} = \frac{(m_2 c_{e2} \ + m_3 c_{e3} ) \ (T_{Teq} - T_2) }{m_1 (T_1 - T_{eq}) }[/tex]

Explanation:

This is a calorimeter problem where the heat released by the console is equal to the heat absorbed by the cupcake and the plate.

           Q_c = Q_{abs}

where the heat is given by the expression

           Q = m c_e ΔT

            m₁ c_{e1) (T₁-T_{eq}) = m₂ c_{e2} (T_{eq} -T₂) + m₃ c_{e3} (T_{eq}- T₁)

note that the temperature variations have been placed so that they have been positive

They ask us for the specific heat of the console

           [tex]c_{e1} = \frac{(m_2 c_{e2} \ + m_3 c_{e3} ) \ (T_{Teq} - T_2) }{m_1 (T_1 - T_{eq}) }[/tex]

Answer:

Explanation:

Given that:

distance (z) = 7.86 m

mass of the person = 81.7 kg

Acceleration (a) = 0.729 m/s²

By using Newton's second law along the vertical axis:

[tex]T - mg = ma\\ \\ T = ma + mg \\ \\ T = m(a+g) \\ \\[/tex]

T = 81.7 (0.729 +9.8)

T = 860.22 N

The work done now is:

[tex]W_T = T\times z \\ \\[/tex]

[tex]W_T = 860.22 \times 7.86[/tex]

[tex]\mathbf{W_T =6761.3292\ N}[/tex]

Answer:

3.591 N

Explanation:

Applying,

F = Bvq................. Equation 1

Where F = magnitude of force on the molecule, B = Magnetic field, v = Velocity of the molecule, q = charge of the molecule.

From the question,

Given: B = 0.57 Tesla, q = 9×10⁻⁸ C, v = 7×10⁷ m/s

Substitute these values into equation 1

F = 0.57×9×10⁻⁸×7×10⁷

F = 35.91×10⁻¹

F = 3.591 N

Hence the force on the molecule is 3.591 N

The point on the standing wave which is referred to as a node is point B and is denoted as option B.

This is also called stationary wave and it is referred to as a combination of two waves moving in opposite directions, each having the same amplitude and frequency.

A node is referred to as a point along a standing wave where the wave has minimum amplitude which is therefore denoted as point B in the graph given below.

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Answer:

please give me brainlist and follow

Explanation:

Since density is described as mass divided by volume, as volume decreases, density increases. With enough drop in volume, the helium balloon becomes too dense to float.

Answer:

dolphin and wolf

Explanation:

the sharks jaw is way to small for it and is shaped differently

Answer:

Late adulthood

Explanation:

Just did it :)

Answer:

K_{total} = 19.4 J

Explanation:

The total kinetic energy that is formed by the linear part and the rotational part is requested

         [tex]K_{total} = K_{traslation} + K_{rotation}[/tex]

let's look for each energy

linear

        [tex]K_{traslation}[/tex] = ½ m v²

rotation

        [tex]K_{rotation}[/tex] = ½ I w²

the moment of inertia of a solid sphere is

       I = 2/5 m r²

we substitute

       [tex]K_{total}[/tex] = ½ mv² + ½ I w²

angular and linear velocity are related

           v = w r

we substitute

           K_{total} = ½ m w² r² + ½ (2/5 m r²) w²

           K_{total} = m w² r² (½ + 1/5)

           K_{total} = [tex]\frac{7}{10}[/tex] m w² r²

let's calculate

           K_{total} = [tex]\frac{7}{10}[/tex]   6.40 16.0² 0.130²

           K_{total} = 19.4 J

Answer:

Tactical movement

Explanation:

Speed and time play a significant factor in Tactical movement. The correct option is B.

Tactical movement refers to the coordinated and strategic movement of military units or teams to achieve a specific objective. It is a fundamental aspect of military operations and involves the use of various tactics and techniques to move troops and equipment safely and efficiently on the battlefield.

Tactical movement can involve various modes of transportation, such as on foot, in vehicles, or by air. It also involves the use of cover and concealment to avoid detection by the enemy, and the use of communication and signal systems to coordinate movements and maintain situational awareness.

The success of the tactical movement depends on many factors, including the terrain and weather conditions, the size and composition of the units involved, the available resources and equipment, and the tactics and strategies employed by both friendly and enemy forces. It requires careful planning, training, and execution to ensure that the movement is successful and achieves the desired outcome.So, tactical movement is an essential component of military operations, and plays a critical role in achieving victory on the battlefield.

Here in the Question,

Tactical movement refers to the movement of military units or teams in a coordinated and strategic manner to achieve a specific objective. In such movements, speed and time are critical factors because they determine the success or failure of the mission. The speed of movement can help to surprise the enemy, take advantage of a weakness in their defense, or seize a key position before they can respond. Time is also important because the longer it takes to achieve the objective, the more likely the enemy is to detect and counter the movement. Therefore, tactical movement requires careful planning and execution to ensure that the right units move at the right speed and at the right time to achieve the desired outcome.

Therefore, the correct option is B i.e Tactical movement.

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Answer:

[tex]q=1118.865W[/tex]

Explanation:

From the question we are told that

Diameter of the cylinder [tex]D=0.3m[/tex]

Length of the cylinder [tex]L=1.75m[/tex]

Surface temperature of cylinder [tex]T_s=30 \textdegree C=303k[/tex]

Speed of air [tex]V=10m/s[/tex]

Temperature of air [tex]T=20 \textdegree C[/tex]

Generally the equation for Reynolds number is mathematically given by

[tex]Re_D=\frac{VD}{v}[/tex]

where

[tex]v=15.27*10^-^6[/tex]

[tex]Re_D=\frac{10*0.3}{15.27*10^-^6}[/tex]

[tex]Re_D=1.96*10^5[/tex]

Generally the equation for Nusselt number is mathematically given by

[tex]N_u=0.6(Re_D)^{0.6}(Pr)^{0.37}[/tex]

where

Prandtl number

[tex]Pr=0.71[/tex]

[tex]N_u=0.6(Re_D)^{0.6}(Pr)^{0.37}[/tex]

[tex]N_u=0.6(1.96*10^5)^{0.6}(0.71)^{0.37}[/tex]

[tex]N_u=791.53[/tex]

Generally the equation for convective heat transfer is mathematically given by

[tex]h=Nu \frac{k}{D}[/tex]

where

[tex]k=25.7*10^{-3}[/tex]

[tex]h=791.53*\frac{25.7*10^{-3}}{0.3}[/tex]

[tex]h=67.81W/m^2K[/tex]

Generally the equation for surface area of a cylinder is mathematically given by

[tex]A=\pi DL[/tex]

[tex]A=\pi *0.3*1.75[/tex]

[tex]A=1.65m^2[/tex]

Generally the equation for convective heat transfer is mathematically given by

[tex]q=h4(T_s-T_{inty)}[/tex]

[tex]q=(67.81)*1.65*(30-20)\\[/tex]

[tex]q=1118.865W[/tex]

Answer:

6.15 s

Explanation:

From the question,

Applying the law of conservation of momentum

Momentum of the Heavier skater = Momentum of the lighter skater.

Mv = mV................. Equation 1

Where M = mass of the heavier skater, m = mass of the lighter skater, v = Velocity of heavier skater, V = velocity of the lighter skater.

But,

v = r/t........................ Equation 2

V = r/t'................ Equation 3

Where r = radius of the circular rink, t = time taken for the heavier skater to reach the edge, t' = time taken for the lighter skater to reach the edge.

Substitute equation 2 and equation 3 into equation 1

M(r/t) = m(r/t')............. Equation 4

Given: M = 65 kg, m = 40 kg, r = 50/2 = 25 m, t = 10 s.

Substitute into equation 4 and solve for t'

65(25/10) = 40(25/t')

162.5 = 1000/t'

t' = 1000/162.5

t' = 6.15 seconds

Answer:

the only correct answer is: Photons of lower-frequency light don't have enough energy to eject an electron

Explanation:

This question is in the model of the photoelectric effect, where some electrons are expelled from the metal by the action of a ray of light.

This effect was explained by Einstein supposes that the light rays are formed by photons and the energy of these photons is given by the Planco relation

           K = h f - Ф

where K is the kinetic energy of the ejected electrons and Ф is the work function, it keeps the electrons inside the material.

When analyzing this expression there is a minimum frequency (threshold) for which K = 0

           hf = Ф

Below this frequency the photons in the light beam do not have the energy to expel the electrons from the material.

Let's examine the answers

a) True. You agree with the above

b) False. The analysis is in terms of individual shock

c) False. The expulsion does not have to do with the number of photons but with the energy of each one

therefore the only correct answer is: Photons of lower-frequency light don't have enough energy to eject an electron

Answer: it is the earth gravity :’)

Explanation:

Earth's gravity keeps the air molecules of the atmosphere from escaping the area surround Earth

Answer:

=> Black holes are points in space that are so dense they create deep gravity sinks. Beyond a certain region, not even light can escape the powerful tug of a black hole's gravity.

=> Anything that ventures too close—be it star, planet, or spacecraft—will be stretched and compressed like putty in a theoretical process aptly known as spaghettification.

[tex] \infty \infty [/tex]

Answer:

a) 6.24 × 10⁻³ V

b) 4.16 × 10⁻³ m²/s

Explanation:

Given that:

(a)

Area A = 0.026 m²

[tex]\dfrac{dB}{dt}=0.24 \ T/s[/tex]

[tex]e=\dfrac{d\phi}{dt} \\ \\ = \dfrac{d}{dt}(BA) \\ \\ =A\dfrac{dB}{dt} \\\\= 0.026 \times 0.24 \\ \\ = 0.00624\ V \\ \\ \mathbf{= 6.24 \times 10^{-3} \ V}[/tex]

(b)

[tex]Here; \\ \\ e =0\\\\ \dfrac{d}{dt}(BA) =0 \\ \\ \implies B\dfrac{dA}{dt}+ A\dfrac{dB}{dt} = 0 \\ \\ B\dfrac{dA}{dt}= -A\dfrac{dB}{dt} \\ \\ \dfrac{dA}{dt}= -\dfrac{A}{B} \dfrac{dB}{dt} \\ \\ = -\dfrac{0.026}{1.5}\times 0.24 \\ \\ \dfrac{dA}{dt}= 4.16 \times 10^{-3}\ m^2/s[/tex]

Answer: SORRY

SORRY AM DOING IT FOR POINTS

Explanation:

Answer:

 f = 7.9487 10¹³ Hz

Explanation:

The photoelectric effect was correctly explained by Einstein assuming that the radiation is composed of photons, which behave like particles.

           hf = K + Ф

It indicates the frequency and the kinetic energy, let's look for the work function

          Ф = hf - K

let's reduce the magnitudes to the SI system

          K = 0.332 eV (1.6 10⁻¹⁹ J / 1 eV) = 0.5312 10⁻⁻¹⁹ J

let's calculate

          Ф = 6.63 10⁻⁻³⁴  6.64 10¹¹ - 0.5312 10⁻¹⁹

          Ф = 4.40 10⁻²² - 0.5312 10⁻¹⁹

          Ф = 5.27 10⁻²⁰ J

for the minimum frequency that produces photoelectrons, the kinetic energy is zero

           hf = Ф  

           f = Ф / h

           f = 5.27 10⁻²⁰ / 6.63 10⁻³⁴

           f = 7.9487 10¹³ Hz

Answer:

a.  0.00189 kg

b. 18.552 mN

c. 1.363 kN

d. Since the molecular density is high, the force exerted by the sample is thus high.

Explanation:

(a) Find the mass of the gas. kg

Using PV = mRT/M where P = pressure on gas = atmospheric pressure = 1.013 × 10⁵ Pa, V = volume of gas = L³ where L = length of cube = 11.6 cm = 0.116 cm,m = mas of gas, R = molar gas constant = 8.314 J/mol-K, T = temperature of gas = 291 K and M = molar mass of gas = 28.9 g/mol

So, m = PVM/RT = PL³M/RT

Substituting the values of the variables into the equation, we have

m = PL³M/RT

= 1.013 × 10⁵ Pa × (0.116)³ × 28.9 g/mol/ 8.314 J/mol-K × 291 K

= 0.0457 × 10⁵ Pa g/mol/2419.374J/mol

= 1.89 × 10⁻⁵ × 10⁵ g

= 1.89 g

= 1.89 × 10⁻³kg

= 0.00189 kg

(b) Find the gravitational force exerted on it. mN

The gravitational force, F exerted on it is its weight W

So, F = W = mg where m = mass of gas = 1.89 × 10⁻³ kg and g = acceleration due to gravity = 9.8 m/s²

F = mg

= 1.89 × 10⁻³ kg × 9.8 m/s²

= 18.522 × 10⁻³ kgm/s²

= 18.552 × 10⁻³ N

= 18.552 mN

(c) Find the force it exerts on each face of the cube. kN

Since pressure, P = F/A where F = force exerted on each face and A = area of each face = L² where L = length of side of cube = 11.6 cm = 0.116 m

So, F = PA since P = atmospheric pressure = 1.013 × 10⁵ Pa,

F = PL²

= 1.013 × 10⁵ Pa (0.116 m)²

= 0.01363 × 10⁵ N

= 1.363 × 10³ N

= 1.363 kN

(d) Why does such a small sample exert such a great force

To answer this question, we need to find the density of the gas in the cube.

So density of gas,ρ = m/V where m = mass of gas = 1.89 g and V = volume of gas = L³ and L = length of side of cube = 11.6 cm

ρ = m/V = m/L³ = 1.89 g/(11.6 cm)³ = 1.89 g/1560.896 cm³ = 0.00121 g/cm³

We now find the number of moles of gas in a cm³ by dividing its density by its molar mass.

So n = ρ/M = 0.00121 g/cm³ ÷ 28.9 g/mol = 23687.67 mol/cm³

Since there are 6.022 × 10²³/mol, we find the number of molecules in a cm³ which is n × 6.022 × 10²³/mol = 23687.67 mol/cm³ × 6.022 × 10²³/mol

= 143731.1 × 10²³ molecules/cm³

= 1.437311 × 10²⁸ molecules/cm³

≅ 1.44 × 10²⁸ molecules/cm³

Since the molecular density is high, the force exerted by the sample is thus high.

Answer:

[tex]\color{Blue}\huge\boxed{Answer} [/tex]

Answer:

[tex]P_{sp}=178.4W/kg[/tex]

Explanation:

From the question we are told that:

Mass of fish [tex]m_f=650kg[/tex]

Cross-sectional area [tex]A=0.92 m^2[/tex]

Drag coefficient of [tex]\mu= 0.0091[/tex]

Seawater  density [tex]\rho= 1026 kg/m^3.[/tex]

Speed of  Fish [tex]v=30 m/s[/tex]  

Generally the equation for Drag force F_d is mathematically given by

[tex]F_d = \mu * \rho *A v^2 /2[/tex]

[tex]F_d = 0.0091* 0.92* 1026* 30^2/2 \\F_d= 3865. 35 N[/tex]  

Generally the equation for high speed  Power  [tex]P_{sp}[/tex] is mathematically given by

[tex]P_{sp}=3865*35*\frac{v}{m_f}[/tex]

[tex]P_{sp}=F_d*35*\frac{30}{650}[/tex]

[tex]P_{sp}=178.4W/kg[/tex]

Answer:

.5 A

Explanation:

Answer:

protons

Explanation: