421+0 is greater than or is less than 4210l​

Answer:

Eastward, at 11 m/s^2

Explanation:

64N-31N=unbalanced force of 33N

F=ma

33N=(3kg)a

a=11m/s^2 to the East

Answer:

400 N

Explanation:

From the question,

F = kmm'/r²........................ Equation 1

Where F = gravitation force, m and m' = mass 1 and mass 2 respectively, r = distance between the masses.

Given; F = 800 N

Substitute these values into equation 1

800 = kmm'/r².............. Equation 2

If the distance is doubled (2r), and one of the mass is doubled (2m), The new force is

F' = k(2m)(m')/(2r)²

F' = 2kmm'/4r²

F' = kmm'/2r²................. Equation 3

Comparing equation 2 and equation 3

F' = F/2............................ Equation 4

Substitute the value of F into equation 4

F' = 800/2

F' = 400 N

Answer:

The answer is "Option D"

Explanation:

Please find the graph file in the attached file.

Using formula:

[tex]\to v= \rho \lambda \\\\\ \to \lambda= 130 \cm \\\\ \to v= 335 \frac{cm}{s}\\\\ \to \rho= \frac{v}{\lambda} \\\\[/tex]

      [tex]=\frac{335}{130} \\\\ = 2.57 \approx 2.50 \ Hz[/tex]

Answer:

623.6N

Explanation:

There are 2.2 pounds in one kilogram, so you must divide 140 lb by 2.2 to convert the units to kilograms.

140/2.2 = 63.6 kg

The gravitational force also known as weight would equal mass times acceleration due to gravity.

Fg = (63.6 kg)(9.8 m/s^2) = 623.6N

Answer:

Solution given:

force=20N

distance travelled=6m

work done=force *displacement=20*6=120joule

Work done=120joule.

Work done=Force×Displacement

[tex]\\ \rm\longmapsto Work\:done=20(6)[/tex]

[tex]\\ \rm\longmapsto Work\:done=120J[/tex]

Answer:

500 Joules

Explanation:

W(work)= force * distance

w = 100*5

W= 500

Thus Kinetic energy of the object is 200J when mass is 25 kg and velocity is 4 m/s.

Carbon is the element modeled

Answer:

0.8sec

Explanation:

Σf= 7.5-5= 2.5 N to the left

Σf=m*a=>2.5=2a=>a=1.25 m/s²

Lets say that the speed is 1m/s

a=speed-0/x=>x=1/1.25=>x=0.8

Hence the time will be 0.8sec

Answer:

fiction

Explanation:

When two opposite forces act perpendicular to an axis, it causes rotational motion or torque.

Torque and couple are both related to rotational motion and are often used interchangeably, but they refer to slightly different concepts.

Torque is a measure of the force that causes an object to rotate around an axis or pivot point.

It is equal to the force applied multiplied by the perpendicular distance between the axis and the line of action of the force. Torque is a vector quantity, meaning it has both magnitude and direction. Its unit of measurement is Newton-meters (Nm) or foot-pounds (ft-lbs) in the English system.

A couple, on the other hand, is a pair of equal and opposite forces that act on a body but do not cause it to translate. Instead, they create a pure rotational motion.

A couple generates torque, but unlike a single force, it doesn't have a line of action or a specific point of application. Instead, a couple is characterized by its magnitude and the distance between the forces. Couples are often used in mechanics to model rotational systems and analyze the behavior of rotating bodies.

Torque is the measure of the force that causes rotational motion, while a couple is a pair of forces that create pure rotational motion without causing any translation.

Therefore, If two opposite forces act perpendicular to an axis, it causes rotational motion or torque.

To learn more about torque click:

https://brainly.com/question/17816858

#SPJ3

Answer:

Option C. The force between them would be 4 times larger than with the

initial masses.

Explanation:

To know which option is correct, we shall determine the force of attraction between the two masses when their masses are doubled. This can be obtained as follow:

From:

F = GMₐM₆/ r²

Keeping G/r² constant, we have

F₁ = MₐM₆

Let the initial mass of both objects to be m

F₁ = MₐM₆

F₁ = m × m

F₁ = m²

Next, let the masses of both objects doubles i.e 2m

F₂ = MₐM₆

F₂ = 2m × 2m

F₂ = 4m²

Compare the initial and final force

Initial force (F₁) = m²

Final (F₂) = 4m²

F₂ / F₁ = 4m² / m²

F₂ / F₁ = 4

F₂ = 4F₁ = 4m²

From the above illustrations, we can see that when the mass of both objects doubles, the force between them would be 4 times larger than with the

initial masses.

Thus, option C gives the correct answer to the question.

Answer:

B: Relay

Explanation:

Out of all the options, the only device that relies upon the magnetic field of an electric current.

The principle relies upon the principle of electro magnetic attraction whereby when the circuit detects a faulty current, it makes the electromagnetic field to become energized which in turn produces the temporary magnetic field. This magnetic field then moves the relay armature which is used in opening or closing the connections.

Answer:

noice.

Explanation:

thanks for points.... idrk what im supposed to do

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yeah same.

Answer:

[tex]\boxed {\boxed {\sf 8 \ m/s}}[/tex]

Explanation:

Speed is equal to distance over time.

[tex]s=\frac{d}{t}[/tex]

The distance is 400 meters and the time is 50 seconds.

[tex]d= 400 \ m \\t= 50 \ s[/tex]

Substitute the values into the formula.

[tex]s=\frac { 400 \ m }{ 50 \ s}[/tex]

Divide.

[tex]s= 8 \ m/s[/tex]

The speed of the car is 8 meters per second.

Answer:

The weight of the object X is approximately 3.262 N (Acting downwards)

The weight of the object Y is approximately 8.733 N (Acting downwards)

Explanation:

The question can be answered based on the principle of equilibrium of forces  

The given parameters are;

The weight of Z = 12 N (Acting downwards)

The weight of the pulleys = Negligible

From the diagram;

The tension in the in the string attached to object Z = The weight of object Z = 12 N

The tension in the in the string attached to object X = The weight of the object X  

The tension in the in the string attached to object Y = The weight of the object Y

Given that the forces are in equilibrium, we have;

The sum of vertical forces acting at a point, [tex]\Sigma F_y[/tex] = 0

Therefore;

[tex]T_{1y} + T_{2y} + T_{3y} = 0[/tex]

[tex]T_{1y} = -( T_{2y} + T_{3y} )[/tex]

Where;

[tex]T_{1y}[/tex]  = The weight of object Z = 12 N

[tex]T_{1y}[/tex]  = 12 N

[tex]T_{2y}[/tex] = The vertical component of tension, T₂ = T₂ × sin(24°)

∴  [tex]T_{2y}[/tex] = T₂ × sin(156°)

Similarly;

[tex]T_{3y}[/tex] = T₃ × sin(50°)

From [tex]T_{1y} = -( T_{2y} + T_{3y} )[/tex], and [tex]T_{1y}[/tex]  = 12 N, we have;

12 N = -(T₂ × sin(156°) + T₃ × sin(50°))...(1)

Given that the forces are in equilibrium, we also have that the sum of vertical forces acting at a point, ∑Fₓ = 0

Therefore at point B, we have;

T₁ₓ + T₂ₓ + T₃ₓ = 0

The tension force, T₁, only has a vertical component, therefore;

∴ T₁ₓ = 0

∴ T₂ₓ + T₃ₓ = 0

T₂ₓ = -T₃ₓ

T₂ₓ =  T₂ × cos(156°)

T₃ₓ = T₃ × cos(50°)

From T₂ₓ = -T₃ₓ, we have;

T₂ × cos(156°) = - T₃ × cos(50°)...(2)

Making T₃ the subject of equation (1) and (2) gives;

Making T₃ the subject of equation in equation (1), we get;

12 = -(T₂ × sin(156°) + T₃ × sin(50°))

∴ T₃ = (-12 - T₂ × sin(156°))/(sin(50°))

Making T₃ the subject of equation in equation (2), we get;

T₂ × cos(156°) = - T₃ × cos(50°)

∴ T₃ = T₂ × cos(156°)/(-cos(50°))

Equating both values of T₃ gives;

(-12 - T₂ × sin(156°))/(sin(50°)) = T₂ × cos(156°)/(-cos(50°))

-12/(sin(50°)) = T₂ × cos(156°)/(-cos(50°)) + T₂ × sin(156°)/(sin(50°))

∴ T₂ = -12/(sin(50°))/((cos(156°)/(-cos(50°)) + sin(156°)/(sin(50°))) ≈ -8.02429905283

∴ T₂ ≈ -8.02 N

From T₃ = T₂ × cos(156°)/(-cos(50°)), we have;

T₃ = -8.02× cos(156°)/(-cos(50°)) = -11.3982199717

∴ T₃ ≈ -11.4 N

The weight of the object X = -T₂ × sin(156°)

∴ The weight of the object X ≈ -(-8.02 × sin(156°)) = 3.262 N

The weight of the object X ≈ 3.262 N (Acting downwards)

The weight of the object Y = -(T₃ × sin(50°))

∴ The weight of the object Y = -(-11.4 × sin(50°)) ≈ 8.733 N

The weight of the object Y ≈ 8.733 N (Acting downwards)

Answer:

KE=1/2mv*

Explanation:

write the numbers inorder to the symbols

Ans use this formula to solve the problem

Answer:

I don't rlly know anyone in harry Potter so I simp for........MYSELF :)

Answer:

Either Draco Malfoy or Harry Potter

Explanation:

UvU

Answer:

6 m/s

Explanation:

p=mv

p=3 kg.m/s

m=0.5 kg

rearrange and substitute to find v:

(3)=(0.5)v

v=3/0.5

v=6 m/s

Answer:

bottle opener and door knob

Explanation:

Answer:

bottle opener

door handle

Answer:

Force = 125 Newton

Explanation:

Given the following data;

Pressure = 50 pa

Area = 2.5 m²

To find the force applied;

Force = pressure * area

Substituting into the formula, we have;

Force = 50 * 2.5

Force = 125 Newton

Answer:

0.25 m/s squared

Explanation:

Mass of the body (m)= 24kg

Applied force on the body(F)= 6N

Acceleration of the body (a)= ?

Solution

F = ma

a = F/m

a = 6N/24kg

a = 0.25m/s^2

Answer: The acceleration of the body is 0.25m/s^2

I hope this helps

Answer:

[tex]\boxed {\boxed {\sf a=\frac {1}{3} \ m/s^2}}[/tex]

Explanation:

Force is the product of mass and acceleration.

[tex]F=ma[/tex]

The mass is 24 kilograms and the force is 8 Newtons. Let's convert the Newtons to make the problem easier.

Substitute the known values into the formula.

[tex]8 \ kg*m/s^2= (24 \ kg )*a[/tex]

Since we are solving for a, we must isolate the variable. It is being multiplied and the inverse of multiplication is division. Divide both sides by 24 kilograms.

[tex]\frac {8 \ kg*m/s^2}{24 \ kg}= \frac{(24 \ kg )*a}{24 \ kg}[/tex]

The kilograms will cancel, hence our earlier unit conversion.

[tex]\frac {8 \ m/s^2}{24 }= a[/tex]

[tex]\frac {1}{3} \ m/s^2=a[/tex]

The acceleration is 1/3 meter per square second.

Answer:

7.14285714286

Explanation:

Answer:

before this type of attack, high acceleration is the most important thing.

Explanation:

As the zebra is ambushed by the crocodile the most important thing is a quick reaction, in this attack the most likely is that the crocodile is in the water so it cannot run after the zebra.

Consequently, before this type of attack, high acceleration is the most important thing.

Answer:

Explanation:

one and three seem right soo  answer C