4. T or F X-rays, ultraviolet light, and gamma rays all can travel through interplanetary space, so they are examples of waves.
5. What happens to the amplitude of water waves as you get farther from the disturbance that caused them? Why?

Answer:

Force = 9600N

Explanation:

If this is the right question, there should have been a question before about the what the change in the momentum of the ball was. The answer to that was 9.6kg m/s. For this part, we divide this by the time taken which was 0.001s which give us the resultant force.

resultant force = change in momentum ÷ time

= 9.6kgm/s ÷ 0.001s

= 9600N

The velocity is 6.75

The velocity in the equation stated above can be calculated as follows

m= 2,000
p= 2.25

y= 6000

velocity= 2.25 × 6000/ 2000
= 13500/2000
= 6.75

Hence the velocity is 6.75

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Answer:

D

Explanation:

The magnitude is 13 m/s

   the direction is east    the   units  are  m/s

(i) For position coordinates p(x, y),  the path of horizontal projectile is parabolic.

(ii)  The time to reach the ground is 0.96 s.

(iii) The distance from the cliff of the ball on hitting the ground is 9.6 m.

(iv) The velocity with which the ball hits the ground is 9.4 m/s.

(v) The direction of the ball to the horizontal just before it hits the

ground is 90 degrees.

When an object is thrown at an angle from the horizontal direction, the object is said to be in projectile motion. The object which follows the projectile motion.

Given is a ball is thrown forward horizontally from the top of a cliff

with a velocity of 10m/s.  The height of the cliff above the ground is 4.5m.

(i) The equation formed by the ball is at point (x,y) given by

y =yo + Voy x t - 1/2gx²

The equation is in the form of parabola.

Thus, the ball follows parabolic path.

(ii) The time to reach the ground is

t = √2h/g

t =  √(2x 4.5)/9.81

t= 0.96 s

iii) Horizontal distance traveled

R = u x t

R = 10 x 0.96

R = 9.6 m

Thus, the distance from the cliff of the ball on hitting the ground is 9.6 m.

(iv) The velocity with which the ball hits the ground.

v = √2gh

Plug the values, we get

v = √(2 x 9.81 x 4.5)

v = 9.4 m/s

(v) The direction of the ball to the horizontal will be 90 degrees just before it hits the ground.

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The number of formula units would be  2.5 x  [tex]10^2^3[/tex]

This is mathematically given as: mole x Avogadro number

Molar mass of the aluminum sulfide (Al2S3) sample = 26.98 x 2 + 32.06 x 3

= 53.96 + 96.18 = 150.14 g/mole

Mole of 62.2 g aluminum sulfide = 62.2/150.14 = 0.4143 moles

Formular unit = 0.4143 x 6.023 x [tex]10^2^3[/tex] = 2.5 x  [tex]10^2^3[/tex]

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The magnetic field strength willl be 2 T. A force known as the Lorentz force acts on the charge when it is subject to an electric and magnetic field.

Lorentz force is defined as the force acting on point charge when it is moving in an electric and magnetic field.

The given data in the problem is ;

B is the magnetic field strength =? T.

Current, I =?

L is the length of the wire

The magnetic force is found as;

F= BIL

15 N  = B × 3 A ×  2.5 m

B = 2 T

Hence, the magnetic field strength willl be 2 T.

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The wavelength of the first harmonic of the standing wave is 2L.

A standing wave is one in which the obvious points remain fixed as the vibration continues. A standing wave occurs in a wind instrument such as a trumpet, saxophone etc.

We know from  the formula of the first harmonic that the wavelength of the first harmonic of the standing wave is 2L.

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ILS is a type of facility that has a frequency of 108.15 Megahertz.

ILS is an acronym for instrument landing system and it can be defined as a precision radio navigation system that is designed and developed to provide an aircraft (airplane) with short-range guidance, so as to enable it approach a runway during bad weather or at night.

Generally, ILS uses two main directional radio signals and these include:

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You should switch your headlights from high beam to low beam when a vehicle approaching from the opposite direction gets no closer than 492.126 feet away from you.

Low beams, often known as dipped beams have a close-range focus. The most crucial and commonly utilized beam in an automobile is the low beam.

When a car coming from the other direction is no closer than 492.126 feet away from you, you should lower your headlights from high to low beam.

Hence, a vehicle approaching from the opposite direction gets no closer than 492.126 feet away from you.

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Answer:

Density is defined as mass per unit volume. its SI unit is: kg/m³

Explanation:

Answer:

Density is defined as mass per unit volume. its SI unit is: kg/m³

Explanation:

from answer above

The power exerted by the cyclist is determined as 50 W.

The power exerted by the cyclist is calculated as follows;

P = FV

where;

P = 20 x 2.5

P = 50 W

Thus, the power exerted by the cyclist is determined as 50 W.

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In the gaseous state,  particles transfer significant amounts of energy by both conduction and convection.

The term convection refers to a pattern of heat transfer in which there is the movement of a significant amount of matter. In convection, the particles of a fluid are moved from one point to another.

Thus, in the gaseous state,  particles transfer significant amounts of energy by both conduction and convection.

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The time of motion of the track star is determined as 0.837 s.

The time of motion of the track star is calculated as follows;

T = (2u sinθ)/g

where;

T = (2 x 12 x sin20)/9.8

T = 0.837 s

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Answer:

B

Explanation:

Answer:

it is c

Explanation: i just did it

Answer:

20.37m/s

Explanation:

For this problem, we'll need a basic kinematic equation for both directions

Vertical direction:

[tex]y(t)=\frac{1}{2}a_{y}t^{2}+v_{o_y}t+y_{o}[/tex]

Knowing that the acceleration in the y-direction is due to gravity, and is constant near the surface of the Earth, where the rock is being thrown, we get [tex]a_{y}=g=-10m/s^{2}[/tex].  We're also given that the initial vertical height is 83m, so [tex]y_o=83m[/tex].  Additionally, we're given that the stone is thrown horizontally, and thus initially, it has no vertical velocity.  Only velocity in the x-direction.  Thus, [tex]v_{o_y}=0m/s[/tex].  Substituting known values into our equation:

[tex]y(t)=\frac{1}{2}(-10)t^{2}+(0)t+(83)[/tex]

[tex]y(t)=-5t^{2}+83[/tex]

This equation is true for all times until the acceleration changes (isn't constant... i.e. when it hits the ground).

What now?

We want to find the specific time when it does hit the ground.  Why?  Because this is the point in time where we know some extra information about what is happening in the x direction, and that will help us deal with the x-direction equation.  

When the stone does hit the ground, the output of this function (measuring the height of the stone) is zero, which leaves only one unknown value, t... the time associated with that y:  the time that it takes to hit the ground:

[tex]0=-5(t_{ground})^{2}+83\\-83=-5(t_{ground})^{2}\\\frac{-83}{-5}=(t_{ground})^{2}\\16.6=(t_{ground})^{2}\\\sqrt{16.6}=\sqrt{(t_{ground})^2}\\4.074309757seconds=t_{ground}[/tex]

Again, this is the time that the stone hits the ground.  Knowing how special this time is, one might give it a special subscript to keep track of it.  

[tex]t_{ground}=4.074309757seconds[/tex]

Horizontal direction

Reusing the basic kinematic equation for the horizontal direction:

[tex]x(t)=\frac{1}{2}a_{x}t^{2}+v_{o_x}t+x_{o}[/tex]

Note that in the horizontal direction, there is no acceleration (after the rock is released), so [tex]a_{x}=0[/tex].  Also, if we define the base of the cliff as our origin, then at the top of the cliff where the rock is released, the initial x-position is still zero, aka, [tex]x_{o}=0[/tex]

[tex]x(t)=\frac{1}{2}(0)t^{2}+v_{o_x}t+(0)\\x(t)=v_{o_x}t[/tex]

While we don't know the initial horizontal velocity, we do know an output of the function for one specific input... we know that when the stone hits the ground, that the stone's horizontal distance is 93m from the cliff.  So, if we input [tex]t_{ground}[/tex] into this function, it will give an output of 93.  The only remaining unknown is the initial velocity in the x direction.  One equation, one unknown, we can solve this:

[tex]x(t_{ground})=v_{o_x}t_{ground}\\83=v_{o_x}(4.074309757)\\\frac{83}{4.074309757} =v_{o_x}\\20.37154879m/s =v_{o_x}\\[/tex]

If there were a component of initial velocity in the y direction, we would need to use the Pythagorean theorem to combine them.  However, as the initial y component of velocity is zero, the initial velocity is simply the initial x velocity.

Paying attention to directions, round to the answer to the nearest hundredth:

[tex]20.37m/s =v_{o}\\[/tex]

The mass of 1 cm² piece of copy paper is 0.0072 g.

Assuming the dimensions of a piece of paper is 21.0 x 29.7 cm

The area of the piece of paper = 21.0 * 29.7 = 623.7 cm²

Mass of 623.7 cm² = 4.5 g

Mass of 1 cm² piece of copy paper = 4.5/623.7 cm² = 0.0072 g

Therefore, the mass of 1 cm² piece of copy paper is 0.0072 g.

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The cornea is  responsible of refraction light 1/3 in eye.

In addition to the protective function, it plays a fundamental role in the formation of vision. Transparent, it works like a lens over the iris, focusing light from the pupil towards the retina.

Normally, the cornea and lens deflect (refract) incoming light rays, focusing them on the retina. The shape of the cornea is fixed, but the lens changes shape to focus on objects at different distances from the eye.

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Answer:

Explanation:

[tex]\text{Since the fulcrum lies in between the load and effort, it is class I lever.}[/tex]

[tex]\text{Mechanical advantage (M.A.) of levers is given by,}[/tex]

[tex]\text{M.A.=effort armload arm=50cm,10cm}[/tex]

[tex]\text{Thus, mechanical advantage , M.A. = 5.}[/tex]

[tex]\text{Given, effort (E)=10N, Load(L)=?}[/tex]

∴ [tex]L=E \times M.A.[/tex]

[tex]=10\times5=50N[/tex]

Answer:

[tex]\fbox {100 cm}[/tex]

Explanation:

Finding Mechanical Advantage :

MA = Load / Effort

MA = 1000/250

MA = 4

Finding length of effort arm :

Load arm = Effort arm / 4

Effort arm = 25 cm x 4

Effort arm = 100 cm

The velocity of the ball at position A is 3.13 m/s.Since all energy is converted to KE.

The potential energy is due to the virtue of the position and the height. The unit for the potential energy is the joule.

A person has the most potential energy due to her position. when he is sitting on the highest point.

Given data;

Mass,m = .5 kg

Height,H = 0.5 m

Acceleration due to gravity,g = 9.8 m/s²

H is the height

The potential energy is found as;

The potential energy is mainly dependent upon the height of the object.

Potential energy = mgh

The potential energy at point B;

PE = mgh

PE = ( 1.5 kg) ( 9.8 m/s2) (0.5 m)

PE = 7.35 J

Since all energy is converted to KE, the kinetic energy at point B;

KE = 0.5mv^2

KE = PE

7.35 = 0.53(1.5) v^2

V = 3.13 m/s

Hence, the velocity of the ball at position A is 3.13 m/s.

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19.8 N force is tending to lift Rover vertically off the ground.

The horizontal velocity component ([tex]v_{x}[/tex]) describes the influence of the velocity in displacing the projectile horizontally. The vertical velocity component ([tex]v_{y}[/tex]) describes the influence of the velocity in displacing the projectile vertically.

According to the question,

The women pulls the dog with a force of 30 N at an angle of  29° from the horizontal.

Horizontal component=  30cos(29°) = 22.2 N

Vertical component = 30sin(29°) = 19.8 N

Therefore,

The horizontal component would tend to make the dog move forward and the vertical component would tend lift it off the ground.

Hence,

19.8 N force is tending to lift Rover vertically off the ground.

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Answer:

Motion of an object that travels in a curved path under the influence of Earth's gravitational field. Examples include throwing a ball, javelin throw, and golf ball.

Explanation:

Answer:

1. In sports.

2. In programming or Animation.

3. In home appliances.

4. In military.

Explanation:

1. In sports. Being common in sports, projectile motion is applied in motion of a projectile which is usually a ball. This is because we are able to calculate the angle of the flight developed by a ball to maximize its distance or velocity. For example in baseball and basketball.

2. In programming or Animation. Considering that there is a challenge for animators and programmers in modern world, physics is applied in televisions or video games. For example a baseball being hit by a player in video game or TV, it should look real. Hence the application of projectile motion.

3. In home appliances. Appliances for example hose or water gun uses an application of projectile motion. As the water exits the hose or water gun, the angle over which the water travels depends on the distance moved and force that is being applied.

4. In military. Bullets being shot from the barrel of the gun is a projectile in air. The speed of the bullet is higher than that of the water exiting the hose therefore it will travel a longer distance. The manufacturers of weapons such as a gun tries to maximize the speed while minimizing gun's recoil.

D. It allows the flow of an electric current in the circuit.

Closed circuit allows the flow of current in the circuit from the battery to the bulb. If the circuit is open then the current will not reach to the bulb or other appliances.

So we can conclude that It is important to have a closed circuit because it allows the flow of an electric current in the circuit.

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Answer: The cricket ball bc of the material

Explanation:

If all the wires have the same diameter, they will all stretch by the same percent. The elasticity does not depend upon the length.

Distance is a numerical representation of the distance between two locations. The distance can refer to a physical length or an estimate based on other factors in physics or common use.

|AB| is a symbol for the distance between two points A and B.

A physiological method for identifying far-off or unseen items using sound waves that the objects reflect back to the source, such as a bat. Each one will enlarge by the same percentage.

Hence, they will all stretch by the same percentage.

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Explanation:

The periscope is used in the submarines to see what is going on the water surface.

It is also used in some gun turrets and it is used in armed vehicles.

✨Hope it helps.✨

a. The free-body diagram for the glass when it is at the top of the circle is attached below.

b. The equation for the net force on the glass at the top of the circle in terms of w, Fn, m, v, and r is mg x g + N -  mg x Vtop² /R =0

c. The glass will fall out of the bucket if the normal force between the glass and bucket equals zero. The speed with which she spin the bucket to prevent this from happening is 3.83 m/s.

d. The string will break if the tension on it is more than 100 N. The range of speeds can  prevent the string from breaking is 3.83< Vtop<4.99 m/s

When two or more forces are acting on the system of objects, then the to attain equilibrium, net force must be zero.

Given, Angela has a bucket of mass 2 kg tied to a string. She places a drinking glass of mass 0.5 kg in the bucket. She spins the bucket in a vertical circle of radius 1.5 m. She must swing the bucket to keep the glass from falling out.

a. The free body diagram of the bucket and glass is attached below.

b. Bucket will undergo centrifugal force

Fb = mVtop² /R

From the equilibrium of forces, we have

For bucket,

T +mb xg - N =  mb x Vtop² /R..............(1)

For glass,

mg x g + N =  mg x Vtop² /R..............(2)

Thus, this is the net force equation on the glass.

c. On adding both the equations. we have

T + (mb + mg) xg = (mb + mg) Vtop² /R

Substituting the values, T = 0 and from the question, we get

0 + (2+0.5) 9.81 = (2+0.5)(Vtop²/0.5)

Vtop = 3.83 m/s

Thus, the speed of spin to prevent glass from falling out is 3.83 m/s

d. The string will break if the tension on it is more than 100 N

100 + (2+0.5) 9.81 = (2+0.5)(Vtop²/0.5)

Vtop = 4.99 m/s

Thus, the range of velocity is  3.83< Vtop<4.99 m/s

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[tex]\textsf {a) As there is no change in the initial and final positions, the displacement is}\\\textsf {equal to 0.}[/tex]

b) Finding total distance :

Distance travelled from 0 s to 5 s :

Distance travelled from 5 s to 10 s :

Distance travelled from 10 s to 15 s :

Distance travelled from 15 s to 20 s :

Distance travelled from 20 s to 25 s :

Distance travelled from 25 s to 30 s :

Distance travelled from 30 s to 35 s :

Distance travelled from 35 s to 40 s :

Total = 75 + 150 + 162.5 + 190 + 237.5 + 225 + 150 + 50

Total = 1240 m

c) velocity at t = 15 s

d) average velocity

e) average speed

f) Part d uses displacement whereas part e uses distance

The correct option is 2. The solid state is more dense than the liquid state.

The solid form of most substances is denser than the liquid phase so a block of most solids will sink in the liquid but a block of ice floats in liquid water because ice is less dense. Upon freezing the density of water decreases by about 9%. This is due to cooling of intermolecular vibrations allowing the molecules to form steady hydrogen bonds and locking into positions of hexagonal packing upon freezing to ice. These bonds are shorter in the crystal than in the liquid.

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