4 A soldier wears boots, each having an area of 0.016 m² in contact with the ground. The soldier weighs 720 N. (a) (i) Write down the equation that is used to find the pressure exerted by the soldier on the ground. (ii) Calculate the pressure exerted by the soldier when he is standing to attention, with both boots on the ground.

Answers

Answer 1

(a) The average pressure exerted by the person is 40,000 N/m².

(b) The average pressure exerted by the elephant has 295,000 N/m².

The average pressure exerted by the elephant is about 7 times greater than the average pressure exerted by the person.

The average pressure exerted by each is defined as the force per unit area.

Mathematically, the formula for average pressure is given as;

P = F/A

where;

F is the applied force

A is the area of each object

P = W / A

where;

W is weight of the person

A is the area of surface in contact

The average pressure exerted by the person is calculated as follows;

P = (640 N) / (0.016)

P = 40,000 N/m²

The average pressure exerted by the elephant is calculated as follows;

P = (4.13 x 10⁴ N) / (0.14)

P = 295,000 N/m²

Thus, the average pressure exerted by the elephant and the person depends on their weight and area of their shoes.

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Related Questions

Air at 273K and 1.01x10³Nm2 pressure contains 2.70x1025 molecules per cubic meter. How many molecules per cubic meter will there be at a place where the temperature is 223K and pressure is 1.33x10 Nm-2

Answers

The molecules of O2 that are present in 3.90 L flask at a temperature of 273 K and a pressure of 1.00 atm is 1.047 x 10^23 molecules of O2

Step 1: used the ideal gas equation to calculate the moles of O2

that is Pv=n RT where;

P(pressure)= 1.00 atm

V(volume) =3.90 L

n(number of moles)=?

R(gas constant) = 0.0821 L.atm/mol.K

T(temperature) = 273 k

by making n the subject of the formula by dividing both side by RT

n= Pv/RT

n=[( 1.00 atm x 3.90 L) /(0.0821 L.atm/mol.k x273)]=0.174 moles

Step 2: use the Avogadro's law constant to calculate the number of molecules

that is according to Avogadro's law

1 mole = 6.02 x10^23 molecules

0.174 moles=? molecules

by cross multiplication

the number of molecules

= (0.174 moles x 6.02 x10^23 molecules)/ 1 mole =1.047 x 10^23 molecules of O2

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