3.
The color of the powdered form of a mineral is called
O fracture
O cleavage
O luster
O streak

Answer:

The answers are in the explanation

Explanation:

Based on Le Châtelier's principle, when a system in equilibrium change a condition, the system will produce a reaction in order to subtract the effect of the initial change.

For the equilibrium:

2Cl2 (g) + 2H2O (g) + heat ↔ 4HCl (g) + O2 (g)

I. Adding some Cl₂. Will produce the equilibrium shifts to the right in order to decrease the concentration of Cl₂ and produce more HCl.

II. raising the temperature at constant pressure. As the system requires heat to produce the reaction, the system will shift to the right in order to decrease the heat and produce more HCl

III. decreasing the volume at constant temperature. As the volume decreases, the pressure increases. In the left, there are 4 moles of gas and in the right there are 5. When the pressure increases the system will try to decrease the moles of gas in order to decrease the pressure. THat means the system will shift to the left in order to produce more Cl₂

Answer:

B. Creating synthetic insulin

Explanation:

In medicine, genetic engineering has been used to mass-produce insulin, human growth hormones, Follistim (for treating infertility), human albumin, monoclonal antibodies, antihemophilic factors, vaccines, and many other drugs. In research, organisms are genetically engineered to discover the functions of certain genes.

Answer:

Explanation: It is already known that 1 mole of the gas( or 32g of O2) is equivalent to 22.4 Litres of the oxygen gas. So, 8g is equivalent to = (22.4/32) × 8 = 5.6 L of the gas.

Answer:

I believe it is C?

Sorry fi it doesn't help!

Answer:

Iwill add 2 for Na and 2 for NaCl so the answer is "C"

Answer:

D) AlCl₃(aq) + 3 KOH(aq) → Al(OH)₃(s) + 3 KCl(aq)​

Explanation:

Which equation represents a double replacement reaction?

A) 2 Al(s) + 6 HCl(aq) → 2 AlCl₃(aq) + 3 H₂(g)

No, this is a single replacement reaction, in which Al replaces H in its acid.

B) 2 Al(s) + 3 Cl₂(g) → 2 AlCl₃(s)

No, this is a synthesis reaction, in which two simple substances combine to form a compound.

C) 2 AlCl₃(s) → 2 Al(s) + 3 Cl₂(g)

No, this is a decomposition reaction, in which a compound decomposes into simple substances.

D) AlCl₃(aq) + 3 KOH(aq) → Al(OH)₃(s) + 3 KCl(aq)​

Yes, this is a double replacement reaction, in which both reactants exchange their cations and anions.

Answer: A

Explanation:

Answer:

B

Explanation:

BBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB I LIKE B it's B though gl on the rest.

Answer:

see explanations

Explanation:

a. The central atom bonded to four substituent atoms and having no lone pair.

This is an AX₄ geometry => tetrahedron

b. The central atom bonded to three substituent atoms and having one lone pair.

This is an AX₃E geometry => pyramidal

c. The central atom bonded to two substituent atoms ảnd having

one lone pair.

This is an AX₂E geometry => bent angular

d. The central atom bonded to two substituent atoms and having no lone pair.

This is an AX₂ geometry => linear

_______________________________

Based upon the VSEPR Theory there are 6 parent geometry configurations and associated derived geometries.

Parent geometries  => Derivatives => Examples

For graphic images of each geometry do an internet search for 'molecular geometry'.

Answer:

oceans

Explanation:

Answer:

D. Ocean

Explanation:

oceans are the majority water on earth's surface located. They hold 97% of earths water.

Answer:

Evaporation happens when a liquid substance becomes a gas. When water is heated, it evaporates. The molecules move and vibrate so quickly that they escape into the atmosphere as molecules of water vapor. ... Once water evaporates, it also helps form clouds

Answer:

0.04 L (or 40 mL)

Explanation:

The dilution equation is: [tex]M_{s} V_{s} = M_{d} V_{d}[/tex]

[tex]M_{s}[/tex] = the molarity of the sock solution

[tex]V_{s}[/tex] = the volume of the sock solution

[tex]M_{d}[/tex] = the molarity of the diluted solution

[tex]V_{d}[/tex] = the volume of the diluted solution  

We are given the original, or stock, solution, which is [tex]M_{s} = 7.00 M NaOH[/tex], and [tex]V_{s} = 0.02 L (20 mL)[/tex]. We are also given the final molarity, which is: [tex]M_{d} = 3.5 M NaOH[/tex].

So, plugging our given into the dilution equation, results in:  

[tex]7.00 M * 0.02 L = 3.5M * V_{d}[/tex] (divide both sides by 3.5 M, in order to get [tex]V_{d}[/tex] by itself).

[tex]\frac{7.00 M * 0.02 L}{3.5M} = V_{d}[/tex]

[tex]V_{d} = 0.04 L (or 40 mL)[/tex]

So, the final volume of a 3.5 M NaOH solution, with an original solution of 20 mL of a 7.00 M NaOH solution, is 0.04 L (or 40 mL)

Hopefully this helped. Good luck!

Answer:   First we need to know how many moles of each reactant there are.

C6H12O6 :         25g/180.06g/mol=0.1388mol

O2:                    40g/32g/mol=1.25mol

The equation tells us we need 6 moles of O2 for every 1 mole of Glucose.

6 x 0.1388 = 0.8328

So, we have more O2 then needed – it is in excess.

Glucose is the limiting reagent – we use this for the calculation.

The equation tells us we make 6 moles of CO2 for every 1 mole of Glucose

So, we make 0,8328 moles of Carbon Dioxide

Explanation:

Answer:the correct answer is a.

Answer:

40 litres

Explanation:

using Boyle's law V1P1=V2P2

V1=20 l

P1= 60atm

P2= 30 atm V2=?

substituting we will have that

20×60=V2×30

V2={20×60}/30

V2=40 l

Answer:

[tex]30^{\circ}\text{C}[/tex]

Explanation:

To know the temperature at which KCl dissolves in water we need to refer to the general solubility curves.

In the case of [tex]KCl[/tex], [tex]35\ \text{g}[/tex] of it will dissolve in [tex]100\ \text{g}[/tex] of water at a minimum temperature of [tex]30^{\circ}\text{C}[/tex].

So, the the minimum temperature needed to dissolve 35 grams of KCl in 100 grams of water is [tex]30^{\circ}\text{C}[/tex].

Answer:

jhdgafhgafhagfhafg

Explanation:

Answer:

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[tex]\color{Blue}\huge\boxed{Answer} [/tex]

Use Boyle's Law: P₁V₁ = P₂V₂. Since pressure and volume are inversely related and we're increasing the pressure, we should expect the new volume to be less than 2.60 liters.

Here, P₁ = 1.00 atm, V₁ = 2.60 liters, and P₂ = 3.50 atm; we want to find the new volume, V₂, at P₂. We can modify the equation to solve for V₂:

V₂ = P₁V₁/P₂ = (1.00 atm)(2.60 L)/(3.50 L) = 0.714 L

So the volume of the gas at a pressure of 3.50 atm will be 0.743 L.

Answer:

I'd say 624.2^3 inches.

Explanation:

The more concentrated the buffer solution, the greater its buffer capacity.

An acid is any substance that in water solution tastes sour, changes blue litmus paper to red, reacts with some metals to liberate hydrogen, reacts with bases to form salts, and promotes chemical reactions.

The more concentrated the buffer solution, the greater its buffer capacity.

If the buffer capacity is 10 times larger, then the buffer solution can absorb 10 times more strong acid or base before undergoing a significant change in pH.

Hence, we need to take this into consideration when increasing either the acid or base concentration in order to increase the buffering capacity of a solution.

Learn more about acid here:

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Explanation:

[tex]6.15 \: mol \: oxygen \: \times \frac{2 \: mol \: c2h10}{9 \: mol \: oxygen} = 1.37 \: moles \: of \: c2h10 \: needed [/tex]

If it was helpfull, please select as brainliest answer. thanks;)

The number of moles of hydrogen to be 0.468.

The balanced chemical equation :

2H₂ + O₂ → 2H₂O

This implies that 2 moles of hydrogen and one mole of oxygen are required to produce 2 moles of water.

or

Thus molar ratio of ( H₂ : O₂)= 2 : 1.  

So, it requires double the moles of oxygen to get the required moles of water.

Number of moles of oxygen= 0.234 mol

So following the molar ratio concept:

We will get:

The number of moles of hydrogen to be 0.468.

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Answer:

Cost.  

Weapons Proliferation Risk.  

Meltdown Risk.  

Mining Lung Cancer Risk.

Explanation:

Hope this helped!!!

Answer:

deez cutz

Explanation:

did i get it right

These questions all involve special cases of the ideal gas law, namely Boyle's, Charles', and Gay-Lussac's Laws. The ideal gas law relates together the absolute pressure (P), volume (V), the absolute temperature (T), and number of moles (n) of a gas by the following:

PV = nRT

where R is the universal gas constant.

The special cases of the ideal gas law are obtained by holding constant all but two of the variables of a gas.

Boyle's Law relates the pressure and volume of a given mass of gas at a constant temperature: PV = k or P₁V₁ = P₂V₂.

Charles' Law relates the volume and temperature of a given mass of gas at a constant pressure: V/T = k or V₁/T₁ = V₂/T₂.

Gay-Lussac's Law relates the pressure and temperature of a given mass of gas at a constant volume: P/T = k or P₁/T₁ = P₂/T₂.

Depending on what we're given and instructed to find in each question, we can figure out which law to use.

---

Question 2:

We are given the volume of a gas at some pressure, and we're to find the new volume of the gas at a different pressure. Here, we use Boyle's Law: P₁V₁ = P₂V₂ where P₁ = 60 atm, V₁ = 20.0 L, and P₂ = 30 atm. We want to find V₂, which we can determine by rearranging the equation into the form V₂ = P₁V₁/P₂. Note that pressure and volume are inversely related according to Boyle's Law; since we're decreasing the pressure, the new volume of the gas should be greater than the initial volume of 20.0 L.

V₂ = (60 atm)(20.0 L)/(30.0 atm) = 40.0 L.

So, at 30 atm, the balloon will have a volume of 40.0 L.

---

Question 3:

This is another Boyle's Law question. The standard pressure (our initial pressure) is 1 atm. Here, we are decreasing the volume of the gas, and we want to find the new pressure; the pressure of the gas should thus increase proportionally (the pressure will be greater than 1 atm). Rearranging Boyle's Law to solve for P₂, we get P₂ = P₁V₁/V₂.

P₂ = (1 atm)(8.00 L)/(3 L) = 2.67 atm.

So, the new pressure of the gas is 2.67 atm (or 3 atm if we're considering V₂ to comprise one significant figure).

---

Question 4:

Here, we are increasing the temperature of a gas at a known pressure, and we want to determine what the new pressure will be. This is a Gay-Lussac's Law question; from the law, we see that pressure and temperature are directly proportional. Since we're increasing the temperature of the gas, we should expect the pressure of the gas to be greater than the initial 200 atm. Gay-Lussac's Law rearranged to solve for P₂ gives us P₂ = P₁T₂/T₁. When working with gas laws, temperatures must be in Kelvin (°C + 273.15 = K). So, T₁ = 300.15 K, T₂ = 350.15 K, and P₁ = 200 atm.

P₂ = (200 atm)(350.15 K)/(300.15 K) = 233 atm.

So, if the temperature is increased from 27 to 77 °C, the pressure of the gas in the tennis ball will be 233 atm. Here, it's ambiguous how many sig figs to use; if we use one sig fig per P₁, then our P₂ would equal P₁, which I think would be an absurd for a question to ask for. I would stick with either 233 atm or 230 atm (following the two sig figs of the temperatures), or you may go with however you've been instructed.

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Question 5:

This is a Charles' Law question; we're looking for the new volume of a gas when the temperature of the gas is increased. As was the case in Gay-Lussac's Law, the two parameters in Charles' Law—volume and temperature—are directly proportional. Since the temperature of the gas is increased, we should expect the new volume of the gas to also increase (V₂ will be greater than 5.00 L). Temperatures should be in Kelvin.

V₂ = V₁T₂/T₁ = (5.00 L)(300.15 K)/(250.15 K) = 5.99 L.

---

Question 6:

Another Charles' Law question. As with question 5, we want to find the new volume of the gas after a change in temperature. This time, the final temperature is lower than the initial temperature, so we should expect that V₂ will be less than the initial 0.5 L. Again, temperatures in Kelvin.

V₂ = V₁T₂/T₁ = (0.5 L)(313.15 K)/(493.15 K) = 0.317 L.

So, the volume of the balloon when it is fully cooled by your refrigerator will be 0.317 L.

---

Question 7:

This is yet another Charles' Law question, and, again, we are solving for V₂ after a change in temperature. Since the final temperature is greater than the initial temperature, V₂ should be greater than 2.2 L. Again, the temperatures should be in Kelvin.

V₂ = V₁T₂/T₁ = (2.2 L)(653.15 K)/(453.15 K) = 3.17 L.

The new volume of the gas is 3.17 L ≈ 3.2 L (two sig figs).

---

Question 8:

We return to Gay-Lussac's Law here; pressure and temperature are directly proportional, and the temperature of the gas is increased. Thus, P₂ should be greater than 3 atm. Again, remember that temperatures must be in Kelvin.

P₂ = P₁T₂/T₁ = (3 atm)(298.15 K)/(288.15 K) = 3.1 atm.

So, the pressure inside the can after the temperature rise is 3.1 atm. Not a big increase, but an increase nonetheless.

Answer:Ammonia is a compound that contains one nitrogen atom and three hydrogen atoms. Ordinarily having a characteristic of a pungent and gaseous compound.

Elemet: Hydrogen, Symbol: H, # of Atoms:5

Elemet:Nitrogen, Symbol: N, # of Atoms:1

Elemet:Oxygen, Symbol: O, #of Atoms:1

Explanation:

The number of  atoms presennt in one mole of ammonium hydroxide is 6.02 * 10^23 atoms.

The mole refers to the amount of a substance that can be used as a reference. According to Avogadro, one mole of a substance contains 6.02 * 10^23 atoms, molecules, ions etc.

In that case, we can say that the number of  atoms presennt in one mole of ammonium hydroxide is 6.02 * 10^23 atoms.

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