2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l)
If 538 mol
of octane combusts, what volume of carbon dioxide is produced at 31.0 ∘C
and 0.995 atm?

Answer: 285.63g of MgCl2.

Explanation:

Very easy stiochemistry question. Use the dimensional analysis. For example 1 m x 100 cm / 1m and meters get canceled out and 1 m is 100 cm.

For the question, start with the given things. You know that it was started with 72.8 grams of magnesium. Convert it to molar mass (to use moles for comparison), and then find the mass of mg.

Answer:

A solvent front is the point on a chromatography paper or plate where the solvent has reached the end of the stationary phase and has migrated as far as it can go. It is the farthest point reached by the solvent in the chromatography process.

Answer:

56.11 g/mol

Explanation:

To determine the molar mass of potassium hydroxide, we need to find the atomic mass of each element in the compound and add them up.

The atomic mass of potassium (K) is 39.10 g/mol, the atomic mass of oxygen (O) is 16.00 g/mol, and the atomic mass of hydrogen (H) is 1.01 g/mol.

So, the molar mass of potassium hydroxide (KOH) is:

Molar mass of K = 39.10 g/mol

Molar mass of O = 16.00 g/mol

Molar mass of H = 1.01 g/mol

Molar mass of KOH = Molar mass of K + Molar mass of O + Molar mass of H

= 39.10 g/mol + 16.00 g/mol + 1.01 g/mol

= 56.11 g/mol

Therefore, the molar mass of potassium hydroxide (KOH) is 56.11 g/mol.

A mass of 37.0 g of sulfur must be used to produce 25.7 L of gaseous sulfur dioxide at STP.

The molar ratio of S₈ to SO₂ is 1:8.

At STP, one mole of gas occupies 22.4 L. Therefore, 25.7 L of SO₂ gas will contain;

25.7 L / 22.4 L/mol = 1.15 mol of SO₂.

The number of moles of S₈ needed is calculated as;

= 1.15 mol SO₂ / 8 mol S₈ per 1 mol SO₂

= 0.144 mol S₈.

The mass of S₈ needed is calculated as;

0.144 mol S₈ × 256.6 g/mol = 37.0 g of S₈.

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Answer:

90g

Explanation:

Ans. 90 gram

we know that,

n = wt/m.wt

where, n=  moles

wt.= weight

m.wt = molecular weight

putting values we get

5 = wt./18 ( molecular weight of water is 18

wt.= 90

hence  ans.= 90 gram

Answer: H2O + CO2 --> H2CO3

Explanation:

Water and Carbon Dioxide react to form Carbonic Acid

H2O + CO2 --> H2CO3

Answer:

Since that means that we have 0.223 moles of PbCl2 in 1000mL of solution.

Also since mole ratio of the ions Pb2+:Cl- is 1:2

Thus, moles of Pb2+ = 0.223moles

concentration of Pb2+= 0.223M

Moles of Cl- = 2x0.223 moles

Concentration of Cl- = 0.446M

Explanation:

Answer:

V ≈ 2144.66 m³

Explanation:

Volume of sphere formula is:

V = 4/3 πr³

Radius is half the diameter so we divide the given diameter, 16 by 2 to get 8, the radius. Now we can solve

V = 4/3 π (8)³

V = 4/3 (512π)

V = 2048/3 π

V ≈ 2144.66 m³

Answer:

4/3 x π

Explanation:

The correct ratio of components is:  For every 3 moles of carbon dioxide produced, 5 moles of oxygen react.

This ratio can be derived directly from the balanced chemical equation:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

The balanced equation shows that for every 3 moles of carbon dioxide produced, 5 moles of oxygen are required. This means that if we have a certain amount of propane, we need to use this ratio to determine the amount of oxygen needed for the reaction. Similarly, if we have a certain amount of oxygen, we can use this ratio to calculate the amount of carbon dioxide that will be produced.

It is important to note that the other ratios provided in the question are incorrect because they do not match the coefficients in the balanced chemical equation.

Therefore, the correct option is: for every 3 moles of carbon dioxide produced, 5 moles of oxygen react.

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First, we need to write the balanced chemical equation for the reaction:

2 NO2(g) + H2O(l) → HNO3(aq) + NO(g)

From the equation, we can see that 2 moles of NO2 react with 1 mole of H2O to produce 1 mole of HNO3 and 1 mole of NO. Therefore, we need to determine which reactant is limiting and calculate the amount of HNO3 that can be produced based on that.

To do this, we can use the mole ratio of NO2 to H2O:

5.0 mol NO2 × (1 mol H2O / 2 mol NO2) = 2.5 mol H2O

Since we have 11.0 mol of H2O, it is not limiting and we will use up all of the NO2.

Therefore, we can calculate the amount of HNO3 that can be produced from 5.0 mol of NO2:

5.0 mol NO2 × (1 mol HNO3 / 2 mol NO2) = 2.5 mol HNO3

Therefore, the largest amount of HNO3 that could be produced is 2.5 mol, rounded to the nearest 0.1 mol.

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Answer:

3.8 ⋅*10^-14

Explanation:

The standard free energy change (ΔG°) for the reaction at 298 K can be calculated using the following equation:

ΔG° = ΣnΔGf°(products) - ΣnΔGf°(reactants)

where ΔGf° is the standard molar free energy of formation of the species and n is the stoichiometric coefficient.

ΔG° = [1×ΔGf°(Fe2O3)] - [1×ΔGf°(FeO) + 1×ΔGf°(Fe) + 1×ΔGf°(O2)]

ΔG° = [1×(-822.16 kJ/mol)] - [1×(-271.9 kJ/mol) + 1×(0 kJ/mol) + 1×(0 kJ/mol)]

ΔG° = -550.26 kJ/mol

The standard enthalpy change (ΔH°) and standard entropy change (ΔS°) can be used to calculate the standard free energy change (ΔG°) at any temperature using the following equation:

ΔG° = ΔH° - TΔS°

where T is the temperature in Kelvin.

ΔG° = ΔH° - TΔS° = (-550.26 kJ/mol) - (298 K)(-0.08996 kJ/K/mol) = -524.05 kJ/mol

Now, we can calculate the equilibrium constant (K) for the reaction at 298 K using the following equation:

ΔG° = -RTlnK

where R is the gas constant (8.314 J/K/mol) and T is the temperature in Kelvin.

-524.05 kJ/mol = -(8.314 J/K/mol)(298 K)lnK

lnK = -200.16

K = e^(-200.16) = 3.89×10^(-87)

Therefore, the value of K for the reaction at 25 °C is 3.89×10^(-87). Answer: 3.8 ⋅*10^-14.

Answer:

A position-time graph can support the statement that a positive slope results when an individual is moving away from the origin. This is because a positive slope on a position-time graph represents a positive velocity, which means that the object is moving in a positive direction (away from the origin). Conversely, a negative slope would indicate that the object is moving in a negative direction (towards the origin).

Option A and B are incorrect. A negative slope on a position-time graph indicates that the object is moving towards the origin, not away from it. A horizontal line on a position-time graph indicates that the object is not moving at all (velocity is zero), not moving at a non-zero velocity.

Option D is also incorrect. The speed of an individual can be determined from a position-time graph by calculating the slope of the graph at any point, which gives the velocity (speed and direction) of the individual at that point..

mark me brilliant

1) Bromination of propylene to form 2-bromopropane using NBS and a Lewis acid catalyst.

Bromination is a chemical process in which bromine is added to a molecule. This can be done by either direct substitution or as a substitution reaction, allowing for the addition of one or more bromine atoms to the molecule. Bromination is a commonly used organic reaction, particularly in the laboratory, and can be used to alter the properties of a compound. It can also be used to produce a wide range of products, including aromatics and halogenated compounds. Bromination is particularly useful in pharmaceutical synthesis, as the products of this reaction often have desirable bioactivity.

2) Reduction of 2-bromopropane to 2-propanol using NaBH₄
3) Reaction of 2-propanol with phosphorus tribromide to form 2-bromopropanol
4) Alkylation of 2-bromopropanol with methyl iodide to form 2-bromopropyl methyl ether
5) Reduction of 2-bromopropyl methyl ether to 2-methoxypropane using NaBH₄
6) Reaction of 2-methoxypropane with phosphorus tribromide to form 2-bromo-2-methoxypropane
7) Reduction of 2-bromo-2-methoxypropane to Compound X using NaBH₄

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The maximum mass of water that can be produced by the reaction is 43.3 g, rounded to three significant figures.

The balanced chemical equation for the reaction between butane and oxygen is:

C4H10 + 13/2 O2 → 4 CO2 + 5 H2O

From the equation, we can see that 1 mole of butane reacts with 13/2 moles of oxygen to produce 5 moles of water.

moles of butane = 34. g / 58.12 g/mol = 0.585 mol

moles of oxygen = 200. g / 32.00 g/mol = 6.25 mol

Determining the limiting reactant.

butane : oxygen = 0.585 mol : 6.25 mol

= 0.0936 : 1.00

stoichiometric ratio = 1 : 13/2

= 0.7692 : 1.00

Since the actual ratio is lower than the stoichiometric ratio for oxygen, it is the limiting reactant.

The maximum amount of water that can be produced is determined by the amount of limiting reactant (oxygen).

moles of water = 5/13 * 6.25 mol

= 2.403 mol

Finally, we can convert the moles of water to grams:

mass of water = 2.403 mol * 18.015 g/mol

= 43.3 g

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Answer:

Explanation:

We can use the formula:

q = mcΔT

where q is the heat absorbed, m is the mass, c is the specific heat, and ΔT is the change in temperature.

Given:
specific heat of iron (c) = 0.449 J/g°C
initial temperature (T1) = 24.0°C
final temperature (T2) = 82.1°C
heat absorbed (q) = 948.0 J

Substituting the given values into the formula, we get:

q = mcΔT
948.0 J = m(0.449 J/g°C)(82.1°C - 24.0°C)
948.0 J = m(0.449 J/g°C)(58.1°C)
m = 948.0 J ÷ (0.449 J/g°C × 58.1°C)
m = 33.1 g

Therefore, the mass of the iron piece is 33.1 g (to three significant figures)

the oxidation number of copper in copper oxide is 2...

Answer: +2

Explanation: Copper has a +2 oxidation number in CuO.

This is due to the fact that oxygen has an oxidation number of 2, and the entire chemical has a neutral charge. Consequently, the following equation can be used to determine copper's oxidation number:

(+2) + (-2) = 0

In order to counteract the -2 oxidation number of oxygen in CuO, copper must have an oxidation number of +2.

Explanation:

The temperature change of a substance when it absorbs or loses energy can be calculated using the specific heat capacity of the substance. The specific heat capacity of water is approximately 4.18 J/(g°C), which means that it takes 4.18 joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.

To calculate the temperature change of the water sample when 50 joules of energy is added, we need to use the following equation:

q = m * c * ΔT

where q is the amount of energy absorbed by the water, m is the mass of the water sample, c is the specific heat capacity of water, and ΔT is the resulting temperature change.

Rearranging the equation to solve for ΔT, we get:

ΔT = q / (m * c)

Plugging in the values, we get:

ΔT = 50 J / (m * 4.18 J/(g°C))

We need to know the mass of the water sample to calculate the temperature change. Let's assume a mass of 10 grams:

ΔT = 50 J / (10 g * 4.18 J/(g°C))

ΔT = 1.2°C

Therefore, if 50 joules of energy is added to a 10-gram sample of water, the resulting temperature change will be approximately 1.2 degrees Celsius.

The second-law efficiency of this freezer is 94.7%.

The second-law efficiency of a refrigerator or freezer is described as as the ratio of the desired cooling effect  which is the heat removed from the cold reservoir) to the energy input required to achieve this cooling effect.

The second-law efficiency of a refrigerator  formula is

η = Qc / W

we have the equation as

Qh = mCΔT = Qc

Tc = -7°C = 266 K

Th = 25°C = 298 K  and

W = Qh / (1 - Tc/Th) = Qc / (1 - Tc/Th) = 3.3 W

we have found  Qc = 3.125

W  = 3.3 W

we then substitute into the  second-law efficiency formula:

η = Qc / Wmin

η= 3.125 W / 3.3 W

η= 0.947 or 94.7%

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Answer:

we need to know the definitions of the two types of mutations:

Looking at the definitions, we can see that a chromosomal mutation can affect many genes at once, while a gene mutation can affect only one or a few nucleotides. Therefore, a chromosomal mutation could have the most drastic effect on a gene, because it could alter or delete an entire gene or multiple genes, resulting in major changes in the phenotype or function of an organism. A gene mutation could also have significant effects on a gene, but it could also be silent or minor depending on the location and type of the mutation. Therefore, the answer is a chromosomal mutation. One possible way to back up this choice is to give an example of a chromosomal mutation that causes a genetic disorder, such as Down syndrome or Turner syndrome.

Answer:

9.98%

Explanation:

To find the percent of NaCl in the mixture, we need to divide the mass of NaCl by the total mass of the mixture, and then multiply by 100 to express it as a percentage.

Step 1: Find the total mass of the mixture

total mass = mass of NaCl + mass of water

total mass = 23.5 g + 212 g

total mass = 235.5 g

Step 2: Calculate the percent of NaCl

% NaCl = (mass of NaCl / total mass) x 100

% NaCl = (23.5 g / 235.5 g) x 100

% NaCl = 0.0997876857 x 100

% NaCl = 9.978768677%

% NaCl = 9.98%

Therefore, the percent of NaCl in the mixture is 9.98%.

The enthalpy of the reaction is -94.1308 kJ/mol of the metal.

First, we need to calculate the amount of heat absorbed by the water in the calorimeter. We can use the formula:

q = m × C × ΔT

where q is the amount of heat absorbed by the water, m is the mass of the water, C is the specific heat capacity of water, and ΔT is the temperature change of the water.

q = 100 g × 4.184 J/g-°C × 3.81°C = 1601.304 J

Next, we need to calculate the amount of heat released by the reaction. We can use the formula:

q = n × ΔH

where q is the amount of heat released, n is the number of moles of the metal, and ΔH is the enthalpy change of the reaction.

We know that 0.017 moles of metal reacted, and we can assume that all the heat released by the reaction was absorbed by the water in the calorimeter.

Therefore:

q = n × ΔH

1601.304 J = 0.017 mol × ΔH

ΔH = 1601.304 J / 0.017 mol = 94130.8235 J/mol

Finally, we need to convert the answer from joules to kilojoules:

ΔH = 94130.8235 J/mol / 1000 J/kJ = -94.1308 kJ/mol

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The theoretical yield of sodium sulfate, Na₂SO₄, formed from the reaction of 4.9 g of sulfuric acid, H₂SO₄ and 5.0 g of sodium hydroxide, NaOH is 7.1 g

First, we shall determine the limiting reactant. This is shown below:

H₂SO₄ + 2NaOH -> Na₂SO₄ + 2H₂O

From the balanced equation above,

98 g of H₂SO₄ reacted with 80 g of NaOH

Therefore,

4.9 g of H₂SO₄ will react with = (4.9 × 80) / 98 = 4 g of NaOH

From the above calculation, we can see that only 4 g of NaOH out of 5 g is needed to react with 4.9 g H₂SO₄.

Thus, the limiting reactant is H₂SO₄

Finally, we shall determine theoretical yield of sodium sulfate, Na₂SO₄ formed. Details below:

H₂SO₄ + 2NaOH -> Na₂SO₄ + 2H₂O

From the balanced equation above,

98 g of H₂SO₄ reacted to produce 142 g of Na₂SO₄

Therefore,

4.9 g of H₂SO₄ will react to produce = (4.9 × 142) / 98 = 7.1 g of Na₂SO₄

Thus, the theoretical yield of sodium sulfate, Na₂SO₄ formed is 7.1 g

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the original temperature of the h ot iron bar was 327.9°C.

We can use the specific heat of iron to do this:

Q1 = m1 * C1 * (Ti - 32.8°C)

Q1 = 408 g * 0.45 J/g °C * (Ti - 32.8°C)

Q1 = 183.6 J/g °C * (Ti - 32.8°C)

where m1 is the mass of the iron bar, C1 is the specific heat of iron, and Ti is the initial temperature of the iron bar.

Next, let's calculate the heat gained by the cold water when it is heated from 20.0°C to 32.8°C:

Q2 = m2 * C2 * (32.8°C - 20.0°C)

Q2 = 1000 g * 4.184 J/g °C * (32.8°C - 20.0°C)

Q2 = 52272 J

where m2 is the mass of the water, C2 is the specific heat of water.

Since the energy lost by the iron bar is gained by the water, we can set Q1 equal to Q2:

Q1 = Q2

183.6 J/g °C * (Ti - 32.8°C) = 52272 J

Now, let's solve for Ti:

183.6 J/g °C * Ti - 60236.8 J = 0

183.6 J/g °C * Ti = 60236.8 J

Ti = 327.9°C

Therefore, the original temperature of the h ot iron bar was 327.9°C.

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The method for determining the sum of Vitamin C in fruit juice ordinarily includes adding an indicator (such as DCPIP) to the juice test and titrating the test with a standard arrangement of ascorbic corrosive until the marker changes colour.

In any case, there are a few variables that seem to make this strategy troublesome to utilize for other natural product juices such as cranberry, blackcurrant, or pomegranate juice:

In this manner, whereas the strategy for deciding the sum of Vitamin C in natural product juice can be a valuable apparatus, it may not be appropriate for all sorts of natural product juices and may have to be be adjusted or adjusted to account for these variables. 

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The term that would best describe the solution formed if 80g KBr dissolved in 100g water is unsaturated solution.

A saturated solution is a solution with solute that dissolves until it is unable to dissolve anymore, leaving the undissolved substances at the bottom.

On the other hand, an unsaturated solution is that solution that is capable of dissolving more of a solute at the same temperature.

According to this question, 80 grams of KBr were dissolved in 100 grams of water at 35 degrees Celsius. This means that the solution is unsaturated because it can still dissolve more KBr.

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The primary difficulties in creating a low-cost, portable water purification system include assuring efficient pollution removal, compact design, durability etc.

In order to create a low-cost, portable water purification system, engineers must overcome several main obstacles and challenges, including: ensuring the removal of contaminants effectively; designing a compact and lightweight system; guaranteeing durability and reliability in harsh environments; providing an affordable, sustainable power source; and addressing cultural and social factors that may affect user acceptance and adoption.

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The amount of heat absorbed during the reaction is 385.9 cal.

Calorimetry is the science of measuring the heat absorbed or evolved during the course of a chemical reaction or change of state.

The amount of heat in a reaction can be calculated as follows;

Q = mc∆T

Where;

Q = 45.4 × 1 × {31.5 - 23)

Q = 45.4 × 8.5

Q = 385.9 cal

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First, we need to calculate the heat gained by the cold water and the heat lost by the hot water:

Qcold = mcΔT = (30 g)(4.184 J/g-°C)(1.93°C) = 242.06 J

Qhot = mcΔT = (70 g)(4.184 J/g-°C)(-1.93°C) = -546.53 J

Since energy is conserved, we can assume that the heat gained by the cold water and calorimeter is equal to the heat lost by the hot water:

Qcold + Qcalorimeter = Qhot

Qcalorimeter = Qhot - Qcold

Qcalorimeter = -546.53 J - 242.06 J = -788.59 J

Therefore, the heat capacity of the calorimeter can be calculated as:

Ccalorimeter = Qcalorimeter / ΔT

Ccalorimeter = (-788.59 J) / (1.93°C)

Ccalorimeter ≈ -408.4 J/°C

Note that the negative sign indicates that the calorimeter loses heat when the system gains heat, which is expected since the calorimeter is absorbing some of the heat from the hot water.