29 POINTS PLEASE I NEED THIS ANSWER
A laboratory received 400 g of radioactive radon and 16 days later 25 g of the radioactive remained. What is the halflife of the radon? [Recall: half-life is the length of time it takes a substance to decay to half of its mass]

Answer:

a) below

b) log_35 (8) = x

c) x = 0.58487

Step-by-step explanation:

a) 35^x=8

apply the exponent rule

xln(35) = ln(8) → x = ln(8)/ln(35) → x = 3ln(2)/ln(35)

x = 0.58487

c) log_35 (8) = x

x = log_35 (8)

base form (Rewrite 8 in power)

x = log_35 (2^3)

log rule: log_a(x^b) = b*log_a(x)

log_35 (2^3) = 3log_35(2)

x = 3log_35(2)

x = 0.58487

The total area available for cars to park is 858 square meters, the number of compact parking space is 68 and the number of non-compact parking space is 52

The total area available

The dimension of the parking lot is:

78 meters by 19 meters

The dimension of the aisle is:

8 meters by 78 meters

The total area available is the difference between the area of the parking lot and the area of the aisle.

So, we have:

Available Area = 78 * 19 - 8 * 78

Available Area = 858

Hence, the total area available for cars to park is 858 square meters

The number of parking space

The total area available for cars to park is 858 square meters, and the area of each parking spot is 12.5 square meters

So, the number of parking lot is:

n = 858/12.5

n = 68.64

Remove the decimal

n = 68

Hence, the number of parking space is 68

The number of parking space for non-compact parking space

The total area available for cars to park is 858 square meters, and the dimension of each parking spot is 5.5 meter by 3 meters

So, the number of parking lot is:

n = 858/(5.5 * 3)

n = 52

Hence, the number of parking space is 52

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Answer:

The above answer is correct!

To put it a bit more simply:

First box: C. 858

Second box: C. 68

Third box: B. 52

Step-by-step explanation:

Hope this helps!

Answer:

$1.35

Step-by-step explanation:

8n = 10.80

Divide both sides by 8 to get n alone.

n = 10.80/8 = $1.35

The transformation that took place is a horizontal stretch by a factor of 2

We are given that Polygon ABCD transformed to create polygon A'B'C'D'. Clearly, the polygon is first a translation of the polygon ABCD 1 unit to the right and then it is horizontally stretched by a scale factor of 2.

Since the length of the polygon was earlier 2 units and then the length of the Polygon A'B'C'D' is 4 units. Hence, the transformation that took place in the Polygon ABCD is a horizontal stretch by a factor of 2

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Answer: A Horizontal Stretch by a Factor of 2

Step-by-step explanation:

To complete the chart make sure you to determine the number of girls and boys in each belt category, and verify the total people.

This requires you to complete the chart presented based on graph, a data chart, or similar.

Note: This question is incomplete; due to this, the answer is based on general knowledge.

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Answer:

False

Step-by-step explanation:

Angles 1 and 2 are not adjacent because they do not share any common line segments with each other.

Answer:

False

Step-by-step explanation:

The definition of adjacent angles is two angles that share a common side and a common vertex. Also, they don't overlap

So in this case ∠1 and ∠2 share the common vertex A but do not share the common side, so these angles are not adjacent.

In this diagram, an example of adjacent angles would be ∠1 and ∠3.

Here's a visual example to understand what I meant  

Answer:

4:25

8:125

Step-by-step explanation:

Surface Ratio is the "Similarity Ratio" to the power of 2

Volume Ratio is the "Similarity Ratio" to the power of 3

It's logical and deductable by paying attention to the correlation between the "Side"s(or "Diameter"s) and the "Surface" and the "Volume"s in simple shapes like Circles and square.

By paying attention to the formula of the "Surface Area" and the "Volume" or the m /m^2 /m^3 ( the units of measurement) we can easily notice the relation.

[tex]\\ \rm\Rrightarrow (2x^2)^3.2yx^0=8x^6.2y=16x^6y[/tex]

[tex]\\ \rm\Rrightarrow (2x^4y^3)^3.2x^4y^4=8x^{12}y^6.2x^4y^4=16x^{16}y^{10}[/tex]

[tex]\\ \rm\Rrightarrow (m^3n^0(2m^3n^2)^4)^2=(m^316m^{12}n^8)^2=(16m^{15}n^8)^2=256m^{30}n^{16}[/tex]

[tex]\\ \rm\Rrightarrow (2xy^3)^2.2x^2y^0=4x^2y^6.2x^2=8x^4y^6[/tex]

Answer:

steps below

Step-by-step explanation:

(a) first green: 8/23 AND 2nd green: 7/22

AND: multiplication.. 8/23 x 7/22 = 28/253 ≈ 0.11 (11%)

(b) 15/23 x 8/22

Answer: 1344g

Step-by-step explanation:

if 1 ounce = 28 grams and we have 48 ounces,

multiply 48 by 28 to find the amount of grams

48×28 = 1344g

This is a statistics problem involving Group Frequency Distribution Table. See the attached and the details below.

By dividing observations into intervals and tabulating the frequencies for each interval, data can be organized.  A grouped frequency table is the end product.

The intervals in this distribution are referred to as classes.

This is obtained by dividing the sum of the product of all mid points and their frequencies by the total number of observations.

That is Estimated Mean = (f * x)/n ------See the attached sheet.

⇒ 503/50

= 10.06

The median of the 50 observations = 28

This is arrived at by dividing the sum of 25th and the 26th number by 2.

That is (28 + 28)/28=28

This median falls in to the third class -  25-29. Hence, the median group is 25-29.

The estimated median value is computed as follows:

Estimated Median = L + (((n/2)-B)/G) x w

Where :

Inserting the values we have :

L = 25

n = 50

B = 0 + 1  = 1

G = 2

w = 5

Estimated Median = 25 + (((50/2)-1)/2 ) * 5

= 25 + (24/2) * 5

= 85

By observation, the modal group is 30-34. This is because it has the highest frequency of 4.

Hence, the Estimated Mode (EM) is arrived at using the formula:

EM = L + (fₙ-fₙ₋₁)/(fₙ-fₙ₋₁)  +  (fₙ-fₙ₊₁) x w

where:

Note that

L = 30

fn-1 = 2

fn = 4

fn+1 = 3

w = 5

Hence,

EM = 30 + (4-2)/((4-2) + (4-3)) x 5

= 30 + (2/(2+1)) x 5

= 30 + (2/3) x 5

EM =  33.33

In summary,

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Answer:

To have one significant figure means to have one number with a significant value. Since all of the answers are greater than one, the final answer with the correct sig figs involves using the two leftmost numbers. If the second leftmost number is greater than 5, round the leftmost number up one unit. If the number is less than 5, leave the leftmost number alone. Finally, change all of the values besides the leftmost to zero. There should be no decimal place because having it would mean the zeros to the left of the decimal place are significant.

 29 x 31
--------------  =  3329.6      ------>     3,000
   0.27

 4.8 x 37
---------------  =  845.7       -------->    800
   0.21

 9.7 x 26
---------------   =  11463.6      ------->   10,000
  0.022

Answer:

The graph of g(x) is shifted up 2 units.

Length of the rectangle is 8 units

Step-by-step explanation:

Area of the rectangle = 48 units

Length = x + 2

⇒ Area = Length × Breadth

48 = x (x + 2)

48 = x² + 2x

x² + 2x - 48 = 0

x² + 8x - 6x + 48 = 0 (Product Sum rule to factorise)

x(x + 8) - 6(x + 8) = 0

(x - 6)(x + 8) = 0

⇒ x = 6, -8 (negative value is neglected)

∴ x = 6

x + 2 = 8

Answer:

Your answer is B

Step-by-step explanation:

6.14 Checkpoint: Systems of Linear Inequalities

I took the test.

Answer:

3/2

Step-by-step explanation:

[tex] {x}^{3} = \frac{27}{8} [/tex]

[tex] x = \sqrt[3]{ \frac{27}{8} } = \frac{3}{2} [/tex]

Answer:

A

Step-by-step explanation:

In this problem you'd simply distribute the 10. So 10x15 and 10*n

150+10n

             - - - - - - - -- - - - - - - - - - -- -- - - - - - - -- - - - - - - - - - -- - - - - - - -- - - - - -

[tex]\blue{\textsf{\textbf{\underline{\underline{Question:-}}}}[/tex]

       What is 10(15+n) equal to?

[tex]\blue\textsf{\textbf{\underline{\underline{Answer and how to solve:-}}}}[/tex]

Multiply 10 times 15:-

150

Multiply 10 times n:-

10n

Add the terms:-

150+10n

           -- - - - - - - - - - - -- - - - - - - - - - -- - - - - -- -- - - - - - - - - - - - - -- - - - - - - -

Answer

Please see attached photo below for detailed analysis

Explanation

The equation of the ellipse formed is x²/11.7² + y²/12² = 1

The formula for calculating the equation of an ellipse is expressed as;

x²/a² + y²/b² = 1

where

a and b are the minor an major axis respectively;

Given the following

b = 12

e = 0.5

Determine the value of a

e² = √b²-a²/b

0.5² = √12²-a²/12
12 * 0.25 = √144-a²

9 = 144 -  a²

a² = 136

a = 11.7

Substitute into the fomula

x²/11.7² + y²/12² = 1

Hence the equation of the ellipse formed is x²/11.7² + y²/12² = 1

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Answer:

76

U

768

Is just for fun heh brother

Answers:  

k = -3.5

Intersection point is (0.5, -2.5)

================================================

Explanation:

Apply the derivative to y=2x^2-3 and you should get dy/dx = 4x

The derivative helps determine the slope of the tangent at any point on the curve.

The slope of the tangent line y = 2x+k is 2.

We want the slope of the tangent to be 2, so we'll replace the dy/dx with 2 and solve for x.

dy/dx = 4x

2 = 4x

x = 2/4

x = 0.5

Plug this into the curve's original equation.

y = 2x^2 - 3

y = 2(0.5)^2 - 3

y = -2.5

Therefore, the tangent line y = 2x+k and the curve y = 2x^2-3 intersect at the point (0.5, -2.5). This is the point of tangency.

We'll use the coordinates of this point to determine k.

y = 2x+k

-2.5 = 2(0.5) + k

-2.5 = 1 + k

k = -2.5-1

k = -3.5

Visual verification is shown below. I used GeoGebra to make the graph, but you could use any other tool you prefer (such as Desmos).

Answer:

area: 105.3

perimeter: 66.7

Step-by-step explanation:

area: 13*16.2/2 = 105.3            formula S = B*H

perimeter: 31+16.2+19.5 = 66.7      

Answer:

[tex]c = 9[/tex]

Step-by-step explanation:

[tex] {(x - a)}^{2} = {x}^{2} - 2ax + {a}^{2} \\ 2ax = 6 \\ a = 3 \\ c = {a }^{2} \\ c = 9[/tex]

Answer:

I believe it 2 cos(20 - ℼ/8) - 1 or 2 sin(20 + ℼ/4) - 1

Step-by-step explanation:

area triangle:

(1.7m×2m)×2

= 1.7m²

-> 2 triangles so: 1.7m²×2= 3.4m²

area rectangles(walls):

2m×3m

= 6m²

-> 2 walls so: 6m²×2=12m²

area bottom rectangle:

3m×2m=6m²

-> total area:

6m²+12m²+3.4m²= 21.4m²

Answer:

The two-point form of a line is used for finding the equation of a line given two points (x1,y1) ( x 1 , y 1 ) and (x2,y2) ( x 2 , y 2 ) on it. The two point-form of a line is:y−y1=y2−y1x2−x1(x−x1) y − y 1 = y 2 − y 1 x 2 − x 1 ( x − x 1 ) OR y−y2=y2−y1x2−x1(x−x2) y − y 2 = y 2 − y 1 x 2 − x 1 ( x − x 2 ) .

Answer:

B, 12, 48.

Step-by-step explanation:

Hope this helped!