The number of employees taking the bus to an office is reduced by 1.1% from the last year. The relative change will be 1.1%.
What is an expression?Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.
Given that:-
28.6% of city employees ride the bus to work. Last year,29.7% of city employees rode the bus to work.
The relative change will be calculated as follows:-
Relative change = Present year data - Last year's data
Relative change = 28.6 - 29.7
Relative change = -1.1%
Therefore the number of employees taking the bus to an office is reduced by 1.1% from the last year. The relative change will be 1.1%.
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Help please I need as quick as possible!
Answer: [tex]\sum^{24}_{n=1} (4n+5)[/tex]
Step-by-step explanation:
This is an arithmetic series with a common difference of 4, so we can immediately eliminate the two left-hand options.
To determine which of the two options on the right is correct, we can determine the first term of each sum expanded out.
For the top right, the first term is 4(0)+5=5, which does not match the first term of the given sequence.For the bottom right, the first term is 4(1)+5=9, which does match the first term of the given sequence.How much would it cost to buy a piece of candy for 50 cents plus tax
Answer:
it depends on which state your in or in your even in the us usually it is either 6% or 4% some times more or less % so im going to do both
50*0.06=53
50*0.04=52
Hope This Helps!!!
We calculate the value of the hypotenuse of the right triangle whose legs measure 3 and 4cm respectively
Help please it's due today
[tex]{\huge \underline{{ \fbox \color{red}{A}}{\fbox \color{green}{n}}{\fbox \color{purple}{s}}{\fbox \color{brown}{w}}{\fbox \color{yellow}{e}}{\fbox \color{gray}{r } }}}[/tex]
Answer :- The result is 5cm
[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{\bf \red {c {}^{2} = a {}^{2} + b {}^{2}} }[/tex]
[tex] \: \: \: \: \: \: \boxed{ \bf \green{c {}^{2} = (3cm) {}^{2} + (4cm) {}^{2}}}[/tex]
[tex] \: \: \: \: \: \: \: \: \boxed{ \bf \gray{c {}^{2} = 9cm {}^{2} + 16cm {}^{2} }}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \bf \blue {c {}^{2} = 25cm {}^{2} }}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \bf \green{\not{\sqrt {c {}^{ \not{2} }}} = \sqrt{25cm {}^{2} }}}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \bf \red{c = 5cm}}[/tex]
[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
[tex]\qquad \tt \rightarrow \: hypotenuse = 5 \:\:cm [/tex]
____________________________________
[tex] \large \tt Solution \: : [/tex]
[tex] \textsf{Pythagoras Theorem } [/tex]
[tex]\qquad \tt \rightarrow \: h {}^{2} = p {}^{2} + b {}^{2} [/tex]
[ h = hypotenuse, p = perpendicular and b = base ]
[tex]\qquad \tt \rightarrow \: {h}^{2} = {3}^{2} + {4}^{2} [/tex]
[tex]\qquad \tt \rightarrow \: {h}^{2} = 9 + 16[/tex]
[tex]\qquad \tt \rightarrow \: h {}^{2} = 25[/tex]
[tex]\qquad \tt \rightarrow \: h = \sqrt{25} [/tex]
[tex]\qquad \tt \rightarrow \: h = 5 \: \: cm[/tex]
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
Solve (2465)8*(465)8
Answer:
73,358,400
Step-by-step explanation:
(2465)8 × (465)8
= 19,720 × 3,720
= 73,358,400
find the perimeter.
D. 9.5 cm
To find the perimeter you need to add all the sides.
2.1 + 2.1 + 1 + 3.3 + 1 = 9.5
Challenge Anyone?......
Answer:
0.2 [or 2/10 ; or 1/5]
Step-by-step explanation:
100x = 1/10×200
100x = 20
÷100 ÷100
x = 0.2
check:
100 × 0.2 = 20
1/10 × 200 = 20
20 = 20
[true statement]
(Or, you know that 100 is half of 200, and to get from 100 to 200 we had to multiply by 2, and that 100 x 2/10 will be equal; this is harder to word though)
need help i don't know what im doing?
Answer:
X=5
Step-by-step explanation:
f(1)= -1^2+4(1)+12=15
f(2)= -2^2+4(2)+12=16
f(3)= -3^2+4(3)+12=15
f(4)= -4^2+4(4)+12=12
f(5)= -5^2+4(5)+12=7
g(1)=1+2=3
g(2)=2+2=4
g(3)=3+2=5
g(4)=4+2=6
g(5)=5+2=7
so g(5)=f(5)= X=5
Answer:
Step-by-step explanation:
You're suppose to plug in the values 1, 2, 3, 4, 5, and 6 into f(x) and g(x) to find where they're equal to find the solution to f(x) = g(x) (when the column values are equal).
So for example
f(1) = -(1)^2 + 4(1) + 12
f(1) = -1 + 4 + 12
f(1) = 15
g(1) = 1 + 2
g(1) = 3
put these two values in the table for f(1) and g(1)
f(2) = -(2)^2 + 4(2) + 12
f(2) = -4 + 8 + 12
f(2) = 16
g(2) = 2 + 2
g(2) = 4
f(3) = -(3)^2 + 4(3) + 12
f(3) = -9 + 12 + 12
f(3) = 15
g(3) = 3 + 2
g(3) = 5
f(4) = -(4)^2 + 4(4) + 12
f(4) = -16 + 16 + 12
f(4) = 12
g(4) = 4 + 2
g(4) = 6
f(5) = -(5)^2 + 4(5) + 12
f(5) = -25 + 20 + 12
f(5) = 7
g(5) = 5 + 2
g(5) = 7
f(5) = g(5) so the solution is when x=5
f(6) = -(6)^2 + 4(6) + 12
f(6) = -36 + 24 + 12
f(6) = 0
g(6) = 6 + 2
g(6) = 8
The drink you usually buy is on sale, the price has been reduced by $2 per can, this means you can get 28 cans for the same price that you usually pay for 20 cans, determine the original price
Answer:
The answer is $2.80.
Step-by-step explanation:
The price was reduced to two dollars and you buy 28 cans for the same price in which you got 20 cans at original price. So you need to take 28 cans times 2, which you will receive 56. Take 56 the price divided by 20 the original price cans and you will receive 2.8 or $2.80. To double check your work, take 2.80 times 20 and see if you get 56. #BallersKnowMath
Find the greatest number which divides 6168, 2447, and 3118 leaving the same remainder in each case.
Answer:
Greatest number which divides 6168 is 3084,the greatest number which divides 2447 is1223.5 , and the greatest number which divides 3118 is 1559.
find the midpoint of each line segment
Answer:
([tex]\frac{7}{2}[/tex],[tex]\frac{1}{2}[/tex])
Step-by-step explanation:
For this you use the midpoint formula
[tex](\frac{x_{2} +x_{1} }{2} ,\frac{y_{2} +y_{1} }{2} )[/tex]
the points would be (2,1) and (5,2)
The midpoint would be ([tex]\frac{7}{2}[/tex],[tex]\frac{1}{2}[/tex])
Urgent help needed algebra 2
replace F with 95:
95 = 9/5C + 32
Subtract 32 from both sides:
63 = 9/5C
Divide both sides by 9/5:
C = 35
answer: 35 Celsius
Find the equation of a line that passes through the point (-2,1) and has a gradient of -3.
Leave your answer in the form
y
=
m
x
+
c
A straight line passing through the point (-2,1) and having a gradient of -3 yields the equation y = -3x - 5.
We know that a straight line is an infinitely long line with no curves on it. A straight line's equation is
y = mx + c...(1), where m is the gradient of the straight line and c is a constant.
Given that the gradient of the given straight line = m = -3.
Putting this value in (1), we get
y = -3x + c ...(2)
Again, the given straight line passes through the point (-2,1). So, we can put x = -2 and y = 1 to get the value of the constant c.
So, 1 = (-3)(-2) + c
i.e. 6 + c = 1
i.e. c = 1 - 6 = -5
(2) can be written as
y = -3x - 5
Therefore the equation of the given straight line is
y = -3x - 5
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Drag the tiles to the correct boxes to complete the pairs. Match each function to its domain and range.f(x)=5x-3
f(x) is a linear function, so both the domain and the range are the set of real numbers.
*Need Help*Match each rational expression to its simplest form.
Find the slope of every line that is parallel to
the line on the graph
Answer:
[tex] - \frac{1}{6} [/tex]
Step-by-step explanation:
Using the slope formula:
[tex] \frac{ - 1 - 0}{0 - ( - 6)} = - \frac{1}{6} [/tex]
which has more KE ? a 2 g bee flying at 1 m/s OR a 1 g wasp flying at 2 m/s [tex] \\ [/tex] ty! ~
Answer: Wasp has greater kinetic energy of 0.002 Joules
Given for bee:
mass: 2g = 2 × 10⁻³ kgvelocity: 1 m/sGiven for wasp:
mass: 1 g = 1 × 10⁻³ kgvelocity: 2 m/sFormula:
Kinetic Energy (J) = ½ × mass (kg) × velocity² (m/s)Kinetic energy of bee:
½ × 2 × 10⁻³ × 1² = 1 × 10⁻³ Joules ≈ 0.001 JoulesKinetic energy of wasp:
½ × 1 × 10⁻³ × 2² = 2 × 10⁻³ Joules ≈ 0.002 JoulesFrom this, it is determined wasp has greater kinetic energy.
Find the monthly house payment necessary to amortize the following loan. In order to purchase a home, a family borrows $110,000 at 2.9% for 30 yrs. What is their monthly payment? Round the answer to the nearest cent.
The monthly payment for purchasing the home will be $457.85.
What is a monthly payment?The term loan refers to a sort of credit vehicle in which a sum of money is lent to another party in exchange for the value or principal amount being repaid in the future.
Then the formula of monthly payment (MP) will be
[tex]\rm MP = P \times \dfrac{r(1+r)^n}{(1+r)^n - 1}\\[/tex]
In order to purchase a home, a family borrows $110,000 at 2.9% for 30 years.
We have
P = $110,000
r = 0.029 / 12 = 0.0024
n = 30 × 12 = 360
Then the monthly payment will be
[tex]\rm MP = 110,000\times \dfrac{0.0024(1+0.0024)^{360}}{(1+0.0024)^{360} - 1}\\\\[/tex]
On further solving, we have
MP = 110000 × 0.0024 × 1.723
MP = $ 457.85
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i need help. Part A: Create a five-number summary and calculate the interquartile range for the two sets of data. (5 points)
Part B: Are there any outliers present for either data set? Justify your answer mathematically. (5 points)
Five number summary and IQR of both the data sets are different.
For school A: Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17, IQR=9.5
For school B: Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19, IQR=7.5
No, the box plots are not symmetric.
Part A:
The given data sets are
School A : 9,14,15,17,17,7,15,6,6
School B : 12,8,13,11,19,15,16,5,8
Arrange the data in ascending order.
School A : 6,6,7,9,14,15,15,17,17
School B : 5,8,8,11,12,13,15,16,19
Divide each data set into four equal parts.
School A : (6,6),(7,9),14,(15,15),(17,17)
School B : (5,8),(8,11),12,(13,15),(16,19)
For school A:
Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17
The interquartile range of the data is
For school B:
Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19
[tex]IQR=Q_3-Q_1\\ =Q_3-Q_1\\ =16-6.2\\ =9.5[/tex]
The interquartile range of the data is
[tex]IQR=Q_3-Q_1\\ =Q_3-Q_1\\ =15.5-8\\ =7.5[/tex]
Part B:
The box plots are not symmetric because the data values are different. Five number summary and IQR of both the data sets are different.
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The table shows the percentage of students in each of three grade levels who list fishing as their favorite leisure activity
Fishing
6th Grade (38%) 48%
9th Grade (29%) 50%
11th Grade (33%) 32%
Total (100%) (0.38)(0.48) + (0.29)(0.5) + (0.33)(0.32) = 0.433 or 43.3%
Find the probability that a student is a 9th grader, given that fishing is their favorite leisure activity.
Using conditional probability, it is found that there is a 0.3349 = 33.49% probability that a student is a 9th grader, given that fishing is their favorite leisure activity.
What is Conditional Probability?Conditional probability is the probability of one event happening, considering a previous event. The formula is:
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which:
P(B|A) is the probability of event B happening, given that A happened.[tex]P(A \cap B)[/tex] is the probability of both A and B happening.P(A) is the probability of A happening.In this problem, we have that the probabilities are given as follows:
[tex]P(A) = 0.433, P(A \cap B) = 0.29 \times 0.50 = 0.145[/tex]
Hence the conditional probability is:
[tex]P(B|A) = \frac{0.145}{0.433} = 0.3349[/tex]
0.3349 = 33.49% probability that a student is a 9th grader, given that fishing is their favorite leisure activity.
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the length of a cell is 2/3 mm. If the area of the cell is 1/12 square mm, whtat is the width of the cell
Answer:
0.125 mm
Step-by-step explanation:
A/L=W
W=0.125
1
Which equation is equivalent to 1/4 + x = -5/4? Select all that apply.
X= 6/4
X= -6/4
X=-1/4=-5/4
X=-3/2
X=-3/4
Answer:
1/4 + x = (-5)/4
x = -5/4 - 1/4
x = (-5)-1 /4
x = (-6)/4
Which of the following is equivalent to the expression, i^39?
O A. -1
OB. 1
O C. -i
O D. i
Which graph shows the greatest integer function?
By critically observing the given graphs, we can logically deduce that "graph C" returns greatest integer that is less than or equal (≤) to x.
What is a greatest integer function?A greatest integer function can be defined as a type of function which returns the greatest integer that is less than or equal (≤) to the number.
Mathematically, the greatest integer that is less than or equal (≤) to a number (x) is represented as follows:
y = [x].
By critically observing the given graphs, we can logically deduce that y in "graph C" returns greatest integer that is less than or equal (≤) to x.
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d) Suppose you pick one marble from the bag at random. Find the expected value of its number.
(c) Suppose you pick 9 marbles from the bag at random with replacement. Find the probability that you pick at least one purple marble.
C) The probability that you pick at least one purple marble is 98%.
ProbabilityThe question is incomplete, since the number of marbles of each color in the bag is missing: 3 blue, 5 green, and 2 purple marbles.
Now, to answer the questions, the following calculations must be done:
C) 100 - (2/9x9) = X100 - 2 = X98 = XLearn more about probability in brainly.com/question/27656131
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Answer:C) The probability that you pick at least one purple marble is 98%.
Step-by-step explanation:
answer is equivalent to ?
√16
√49
SA
A.
OB.
O c.
D.
16
49
16
49
316
The solution of the given expression is 9. So the correct answer is option B.
The complete question is given below:-
(√16 - √49 )² The solution of the given equation will be
A. 16
B .9
C .49
D. 316
What is an expression?Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.
The given expression will be calculated as:-
(√16 -√49 )² = (√16)² -2 (√16)(√46) + (√49 )²
= ( 16 - 2(4)(7) + 49 )
= ( 16 - 56 + 49 )
= 9
Therefore the solution of the given expression is 9. So the correct answer is option B.
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If ( 3 y − 9 ) 2 + 7 = 43 , then what is(are) the values of y?
Answer:
y = 5 and y = 1
Step-by-step explanation:
[tex]\textsc {Subtract 7 from each side :}[/tex]
⇒ (3y - 2)² + 7 - 7 = 43 - 7
⇒ (3y - 2)² = 36
[tex]\textsc {take the square root on each side :}[/tex]
⇒ √(3y - 9)² = √36
⇒ 3y - 9 = ±6
[tex]\textsc {When equal to +6, add 9 on each side :}[/tex]
⇒ 3y - 9 + 9 = 6 + 9
⇒ 3y = 15
[tex]\textsc {Divide by 3 on each side :}[/tex]
⇒ 3y/3 = 15/3
⇒ y = 5
[tex]\textsc {When equal to -6, add 9 on each side :}[/tex]
⇒ 3y - 9 + 9 = -6 + 9
⇒ 3y = 3
[tex]\textsc {Divide by 3 on each side :}[/tex]
⇒ 3y/3 = 3/3
⇒ y = 1
Determine whether each set of data can be modeled by an exponential function. If so, find the exponential
function that fits the data.
It can be modeled by an exponential function, f(x) is divided by 3 each time x increases by 1.
This means that the base of the exponential function is 1/3, and since the value of f(x) when x=0 is 81, [tex]f(x)=81\left(\frac{1}{3} \right)^{x}[/tex]
Prove: m/EIF = m/GIH
Step
m/EIF+m/FIG = 180
m/FIG+m/GIH
= 180
m/EIF+mZFIG= m/FIG+mZGIH
m/EIF = m/GIH
Reason
Distributive Property Transitive Property of Equality Definition of Supplementary Angles
Subtraction Property of Equality Multiplication Property of Equality Simplify
Division Property of Equality Reflexive Property of Equality Addition Property of Equality
Substitution Property of Equality Definition of Complementary Angles
An
13
Se
Tea
16
Finis
The question is incomplete. Below you will find the missing content in the figure.
Prove: m/EIF = m/GIH
Step Reason
m∠EIF+m∠FIG = 180°
m∠FIG+m∠GIH= 180°
m∠EIF+m∠FIG= m∠FIG+m∠GIH
m∠EIF = m∠GIH
The figure is shown below.
The correct answer is m∠EIF = m∠GIH
Here lines FH and GE intersect each other at the point I.
we have to prove the angle
m∠EIF = m∠GIH
so,
m∠EIF+m∠FIG = 180° as angels ∠EIF and ∠FIG forming a linear pair summing up to 180°. angels ∠EIF and ∠FIG form straight angels on a line EG.
m∠FIG+m∠GIH= 180° as angels ∠FIG and ∠GIH forming a linear pair summing up to 180°. angels ∠FIG and ∠GIH form straight angels on a line FH.
m∠EIF+m∠FIG= m∠FIG+m∠GIH because of the substitution property of equality. we replace 180° by m∠FIG+m∠GIH.
m∠EIF = m∠GIH because of the subtraction property of equality. We can subtract the same elements from both sides by the subtraction property of equality.
Therefore m∠EIF = m∠GIH.
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If x = 3, then 3x – 4 = 5. x = 3 law of detatchment
Answer:
3x-4=5
Step-by-step explanation:
it is correct
Huilan is 8 years older than Thomas. The sum of their ages is 80. What is Thomas's age?
[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
[tex]\texttt {\:Thomas's age = 44 years } [/tex]
[tex]\texttt {\:Hulian's age = 36 years } [/tex]
____________________________________
[tex] \large \tt Solution \: : [/tex]
[tex] \textsf{Assume Thomas's age be ' x ' } [/tex]
[tex] \textsf{and that of Huilan's age be y } [/tex]
[tex] \texttt{we have two conditions :} [/tex]
[tex]\qquad \tt \rightarrow \:y = x + 8[/tex]
it can be simplified as : -
[tex]\qquad \tt \rightarrow \:y - x= 8 \: \: \: \: \: \: \: \: \: - (1)[/tex]
[tex] \texttt{Next condition } [/tex]
[tex]\qquad \tt \rightarrow \:x + y = 80 \: \: \: \: \: \: \: - (2)[/tex]
`` Add both equations ``
[tex]\qquad \tt \rightarrow \:y - x + x + y = 8 + 80[/tex]
[tex]\qquad \tt \rightarrow \:2y = 88[/tex]
[tex]\qquad \tt \rightarrow \:y = 44[/tex]
[tex] \large \textsf{For x :} [/tex]
[tex]\qquad \tt \rightarrow \:y - x = 8[/tex]
[tex]\qquad \tt \rightarrow \:44 - x = 8[/tex]
[tex]\qquad \tt \rightarrow \:x = 44 - 8[/tex]
[tex]\qquad \tt \rightarrow \:x = 36[/tex]
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
Answer:
[tex]\fbox {36 years old}[/tex]
Step-by-step explanation:
Let :
⇒ Age of Huilan = x
⇒ Age of Thomas = x - 8
Then :
⇒ x + x - 8 = 80
⇒ 2x = 88
⇒ x = 44
Thomas's age :
⇒ x - 8
⇒ 44 - 8
⇒ 36 years old
