Answer:
Money made by tickets=
2753 x $5 = $13765
We have to subtract the cost of the concert from the money made by tickets to get our profit. Therefore,
$13765 - $8000 = $5765
When the expression 3(x²+6-3x) - (2x²-8) + 3(x² + 4x) is simplified, the coefficient
of x is
A. 7
B. 4
C. 3
D. 2
The correct answer is option C which is 3.
What is an expression?Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication and division.
The given expression will be solved as follows:-
E = 3( x² +6 -3x)- ( 2x² - 8 ) +3(x² + 4x )
E = 3x²+18-9x-2x²+8+3x²+12x
E= 4x² +3x+8
We can see the coefficient of x is 3.
Therefore the correct answer is option C which is 3.
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Match the function with the graph.
a. y = |x+ 5|
b. y= |x-5| + 2
c. y= |x-5|
d. y=|x| -5
i did a and it was wrong. i don’t understand lol please help
C. y= |x-5|
you have the right idea, it's being shifted horizontally so the shift would be shown inside of the brackets. However, it would be |x-5| not |x+5| because the graph is shifting to the right.
For doing a certain a Job
Answer:
added in picture
Step-by-step explanation:
added in picture
Answer:
$71,744.53
Step-by-step explanation:
The earnings triple every day, so you can calculate them for the 15 days. For the total, you also have to add them up.
See the calculations in below picture.
Which function is positive for the entire interval [–3, –2]? On a coordinate plane, a curved line with a minimum value of (0, negative 3) crosses the x-axis at (negative 3, 0) and (3, 0), and crosses the y-axis at (0, negative 3). On a coordinate plane, a curved line with a minimum value of (2, negative 3) crosses the x-axis at (negative 1, 0) and (5, 0), and crosses the y-axis at (0, negative 1.5). On a coordinate plane, a curved line with a minimum value of (2, 4) and a maximum value of (0.5, 6), crosses the x-axis at (negative 1.5, 0) and crosses the y-axis at (0, 5). On a coordinate plane, a curved line with a minimum value of (negative 1.75, negative 3.9) and a maximum value of (0, 2), crosses the x-axis at (negative 2.2, 0), (negative 0.75, 0), and (0.75, 0), and crosses the y-axis at (0, 2). Mark this and return
The function is shown to be positive throughout the whole range [-3, -2] in graph (B).
According to the question,
Four alternative graphs representing various functions are supplied to us; our task is to identify the function graph that is positive over the whole range [-3, -2]. A closed interval exists. Therefore, it includes both -3 and -2.The graph of the Y value must be in a positive area during this interval. Therefore, we must choose a function that is positive over the whole range [-3, -2].Looking at the graph, we can see that the graph B has positive y-values in the range [-3, -2].
Hence The function is shown to be positive throughout the whole range [-3, -2] in graph (B).
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Which classification describes the following system of equations?
12x+5y-3z= 36
x-2y+4z=3
9x-10y+5z = 27
A consistent and independent system of equations describes the given system of equations.
The consistent and independent system of equations are given below.
12x+5y-3z= 36x-2y+4z=39x-10y+5z = 27What is a consistent independent equation?A consistent equation is a system of linear equations that is consistently unbiased when it has precisely one solution. While this is the case, the graphs of the lines within the system move at exactly one point. In inconsistent, a system of linear equations is inconsistent if it has no solutions.
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can someone please help me
Answer:
Domain: All real numbers
Range: y≤4
The longest side of an isosceles obtuse triangle measures 20 centimeters. The other two side lengths are congruent but unknown.
What is the greatest possible whole-number value of the congruent side lengths?
The unknown side length will be 14 cm if the longest side of an isosceles obtuse triangle measures 20 centimeters option third 14 is correct.
What is the triangle?The triangle can be defined as a three-sided polygon in geometry, and it consists of three vertices and three edges. The sum of all the angles inside the triangle is 180°.
The question is incomplete.
The complete question is:
The longest side of an isosceles obtuse triangle measures 20 centimeters. The other two side lengths are congruent but unknown. What is the greatest possible whole-number value of the congruent side lengths?
9 cm
10 cm
14 cm
15 cm
We have:
The longest side of an isosceles obtuse triangle measures 20 centimeters.
Let's assume the unknown side length is x:
In the isosceles obtuse triangle, two sides are congruent.
As we know the sum of the two sides in a triangle is greater than the third side length:
x + x > 20
2x > 20
x > 10
a² + b² < c²
14 will satisfy the above two inequaility.
Thus, the unknown side length will be 14 cm if the longest side of an isosceles obtuse triangle measures 20 centimeters option third 14 is correct.
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What is the distance between the tick marks on the number line?
A number line going from 0 to 2 in increments of 1. There are 5 equals spaces between each number.
One-fifth
One-fourth
4
5
Mark this and return
Answer:
1/5
Step-by-step explanation:
2 units divided into 5 marks each = 10 marks
2/10 = 1/5 unit each mark
3.) Let t= the number of tomatoes Tye planted last year.
This year she planted 3 times as many. Write an
algebraic expression to show how many tomatoes Tye
planted this year.
Answer:
3t
Step-by-step explanation:
The algebraic expression to show the number of tomatoes Tye planted this year is 3t
How to write the algebraic expression of Tye?From the first statement given in the question, we were told that:
t is the number of tomatoes Tye planted last yearFrom the above statement, we can write the algebraic expression to show the number of tomatoes Tye planted this year. This is shown below:
Number of tomatoes planted last year = tNumber of tomatoes planted this year =?Number of tomatoes planted this year = 3 × Number of tomatoes planted last year
= 3t
Thus, from the above illustration we can say that the algebraic expression is 3t
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A square with side lengths 12 feet. 4 2 feet by 2 feet squares are cut out of each corner of the square.
Tariq designed the pool shown. The owner of the pool has one square cover to use. Find the area of the space that needs to be covered. (The four corners are squares.)
The area that needs to be covered is
ft2.
A square with side lengths 12 feet. 4 2 feet by 2 feet squares are cut out of each corner of the square.
Find the Area of the Space.[tex] \mathbb{SOLUTION:} [/tex][tex] \bold{A = Length \: x \: Width} [/tex][tex] \bold{A = 12 \: ft \: x \: 4.2 \: ft } [/tex][tex] \blue{\bold{A = 50.4 \: ft} }[/tex][tex] \bold{ A\red{ = 50.4 } \: x \: 2 \: ft} [/tex][tex] \boxed{ \bold{ A = 100.80 ft²}}[/tex]"If the 2 is quantity use multiply it again"
••••••••••••••••••••••••••••••••••••••••••••••••NOTE:The way to solve a square area is by measuring the length and width of your area then multiplying those two numbers together to get the area in feet squared (ft2).
"Problem has been solve"
(ノ^_^)ノ
[tex]\large\bold{SOLUTION} \\ [/tex]
GIVEN :-
A square with side lengths 12 feet.4.2 feet by 2 feet squares are cut out of each corner of the square .FIND :-
Find the area of the space that needs to be covered .By finding the area of the space that needs to be covered we must use multiplication and multiply the given measurements .
[tex] \bold{Formula:}[/tex]
[tex] \qquad \boxed{ \bold{ \: \: Area = Length \times Width \: \: }}[/tex]
Now let's start solving :-
[tex] \quad \sf \implies{Area = Length \times Width} \\ [/tex]
[tex] \quad \sf \implies{Area = 12ft \times 4.2ft} \\ [/tex]
[tex] \quad \sf \implies{Area = 12feet \times 4.2ft = \pmb{50.4 ft}} \\ [/tex]
[tex] \quad \sf \implies{Area = 50.4ft \times 2ft = \pmb{100.80ft^2}} \\ [/tex]
Therefore, the area of the space that needs to be covered is 100.80ft² .
[tex] \underline{ \rule{185pt}{3pt}}[/tex]
Given: Lines p and q are parallel and r is a transversal.
Prove: ∠2 ≅ ∠7
Parallel lines p and q are cut by transversal r. On line p where it intersects with line r, 4 angles are created. Labeled clockwise, from the uppercase left, the angles are: 1, 2, 4, 3. On line q where it intersects with line r, 4 angles are created. Labeled clockwise, from the uppercase left, the angles are: 5, 6, 8, 7.
A 2-column table with 4 rows. Column 1 is labeled statements with the entries p is parallel to q and r is a transversal, A, B, angle 2 is congruent to angle 7. Column 2 is labeled reasons with the entries given, vertical angles are congruent, correlated angle theorem, transitive property.
Which statements could complete the proof?
A:
B:
The statements that would complete the proof where ∠2 ≅ ∠7 by the transitive property are:
∠2 ≅ ∠3
∠3 ≅ ∠7
What is the Transitive Property?The transitive property states that if x = y, and y = z, then x = z.
From the image given below, we have:
∠2 ≅ ∠3 because they are vertical angles which must be congruent.
∠3 ≅ ∠7 because corresponding angles are congruent.
Applying the transitive property, we can state that: ∠2 ≅ ∠7.
Therefore, the statements that would complete the proof are:
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find the length of each arc and round the answer to the nearest tenth
PLEASE HURRY IF YOU CAN
The length of arc for the options 1,2,3 and 4 willl be 60.39,61.23,10.4 and 7.851 respectively.
What is angle measurement?An angle measure is the measurement of the angle created by two rays or arms at a shared vertex in geometry. A protractor is used to measure angles in degrees (°).
As a result, when measuring angles in radians,
The length of the arc is:
[tex]\rm l = r \theta[/tex]
Unit conversions;
1 π = 180°
1° = 180/π
315°= 5.49 rad
270° = 4.71 rad
60° = 1.04 rad
150°=2.617 rad
The measure of the length of arc for the given radius;
[tex]\rm L_1 = R_1 \theta \\\\ L_1 = 1 \times 5.49 \\\\\ L_1 = 60.39 \\\\ L_2 = 13 \times 4.71 \\\\ L_2 = 61.23 \\\\ L_3 = 10 \times 1.04 \\\\ L_4 = 10.4 \\\\ L_4 = 3 \times 2.617 \\\\ L_4 = 7.851[/tex]
The length of arc for the options1,2,3 and 4 willl be 60.39,61.23,10.4 and 7.851 respectively.
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Line mn is parallel to line pq, mp is perpendicular to mn, and nqis perpendicular to pq. consider each statement and determine whether it is true or false. circle the correct answer. options:
The true statements are:
Lines mn and pq have the same slopeThe product of the slopes of mn and mp is -1How to determine the true statements?The lines are given as:
Lines mn, pq, mp, mn, nq and pq
From the question, the lines are either parallel lines or perpendicular lines
As a general rule,
Parallel lines have equal slope
This means that:
Lines mn and pq have the same slope
Assume two perpendicular lines have slopes m and n.
The relationship between their slopes is:
m * n = -1
This means that:
The product of the slopes of perpendicular lines mn and mp is -1
Hence, the true statements are (a) and (c)
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Complete question
Line mn is parallel to line pq, mp is perpendicular to mn, and nq is perpendicular to pq. consider each statement and determine whether it is true or false. circle the correct answer.
Pptions:
Lines mn and pq have the same slopeThe slope of line pq is undefined. The product of the slopes of mn and mp is -1Lines mp and mq are parallel.Solve the system of equations by substitution.
x + y = A system of equations. StartFraction 3 over 8 EndFraction x plus StartFraction one-third EndFraction y equals StartFractions 17 over 24 EndFraction.
x + 7y = 8
(, )
A will have a value of 2. The value of A is found by the substitutional equation system.
What is the system of two equations?A set of two linear equations with two variables is called a system of linear equations. They create a system of linear equations when evaluated collectively.
The given equation in the problem is;
Equation 1: [tex]\rm \frac{3}{8} + \frac{1}{3} y= \frac{17}{24}[/tex]
Equation 2: [tex]x+7y=8[/tex]
Rearrange equation 2 as;
x=8-7y
Substitute the value of x;
[tex]\rm \frac{3}{8} + \frac{1}{3} y= \frac{17}{24} \\\\ \frac{3}{8}(8-7y)+\frac{1}{3}y=\frac{17}{24} \\\\ \frac{-21}{8} y+\frac{1}{3} = \frac{17}{24}-3 \\\\ \frac{-63y+8y}{24}=\frac{17-72}{24}\\\\ \frac{-55 \ y}{24} = - \frac{55}{24}\\\\ y= 1[/tex]
Substitute the value of y in equation 2 as;
x+7y=8
x+7(1)+8
x=8-7
x=1
The system of equations by substitution obtained the value of A is;
x + y = A
1+1=A
A=2
Hence the value of A will be 2.
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a−(−3.75)=6.11
What is a?
Answer:
a = 2.36
Step-by-step explanation:
a-(-3.75)=6.11
The negative 3.75 is being subtracted from the 'a'. A negative number being subtracted from another number makes it positive. So, 3.75 is actually being added to 'a' which is equal to 6.11
I re-wrote the question as:
a + 3.75 = 6.11
Subtract 3.75 from both sides to leave 'a' by itself
a + 3.75 = 6.11
-3.75 -3.75
a = 2.36
ABC has the points A(1,7) B(-2,2) and C(4,2) as it’s vertices
The measure of the longest side of ABC is _ units. ABC is_triangle. If ABD is formed with the point D(1,2) as it’s third vertex, then ABD is _triangle . The length of side AD is_units
Part 1
Using the distance formula,
[tex]AB=\sqrt{(-2-1)^{2}+(2-7)^{2}}=\sqrt{34}\\\\BC=\sqrt{(-2-4)^{2}+(2-2)^{2}}=6\\\\AC=\sqrt{(1-4)^{2}+(7-2)^{2}}=\sqrt{34}[/tex]
So, the measure of the longest side is 6 units.
Part 2
Triangle ABD will have vertices A(1,7), B(-2, 2), and D(1,2).
We already know that [tex]AB=\sqrt{34}[/tex]
Using the distance formula,
[tex]AD=\sqrt{(1-1)^{2}+(7-2)^{2}}=5\\\\BD=\sqrt{(-2-1)^{2}+(2-2)^{2}}=3[/tex]
So, ABD is a scalene triangle.
Part 3
From part 2, we know that the length of side AD is 5 units.
Measure the height of the palm tree indirectly using a mirror that is placed on the ground a certain distance away from the tree. The distance from the
mirror to the base of the palm tree is 2.5 m and the distance from the mirror to the person's foot is 0.5 m. The person is 1.78 m tall.
Answer:
(b) 8.9 m
Step-by-step explanation:
The mirror ensures that angle 1 is congruent to angle 2, so the triangles in the diagram are similar. The ratios of height to mirror distance are proportional.
__
setupThe height of the object is proportional to its distance from the mirror, so we have ...
(tree height)/(tree-to-mirror) = (person height)/(person-to-mirror)
(tree height)/(2.5 m) = (1.78 m)/(0.5 m)
solutionMultiplying this proportion by 2.5 m, we find ...
tree height = (2.5 m)(1.78/0.5) = 8.9 m
The height of the palm tree is 8.9 meters.
A pair of dice is rolled. What is the probability that the sum is 9 or that the first number is a 2?
Answer:
9/2 or 6/2
Step-by-step explanation:
The sum of nine should be amended by adding 6 + 2 +1 = 9
so when adding these numbers you will get the sum of 9
1/(x+2)+1/(x+3)=2/x+9
Answer:
4x82x929wjdjdejdjekke
[tex] \frac{1}{x + 2} + \frac{1}{x + 3} = \frac{2}{x + 9 } \\ \frac{(x + 3 ) + (x + 2)}{ {x}^{2} + 5x + 6 } = \frac{2}{x + 9} \\ \frac{2x + 5}{ {x}^{2} + 5x + 6 } = \frac{2}{x + 9} \\ 2( {x}^{2} + 5x + 6) = (x + 9)(2x + 5) \\ 2 {x}^{2} + 10x + 12 = 2 {x}^{2} + 5x + 18x + 45 \\ 2 {x}^{2} + 10x + 12 = 2 {x}^{2} + 23x + 45 \\ 2 {x}^{2} - 2 {x}^{2} + 10x - 23x + 12 - 45 = 0 \\ - 13x - 33 = 0 \\ - 13x = 33 \\ x = \frac{33}{ - 13} \\ x = - 2.54[/tex]
Hope it helps
Please give brainliest
Pls someone help me on this question
Answer: [tex]x=65^{\circ}, y=65^{\circ}, z=65^{\circ}[/tex]
Step-by-step explanation:
All radii of a circle are congruent, so by the base angles theorem
z = y = (180-50)/2 = 65.Also, angles x and y are inscribed in the same arc, and they are thus congruent, meaning x = 65.
Write 5.54 million in ordinary form
Answer:
5,540,000Step-by-step explanation:
Write 5.54 million in ordinary form
5.54 * [tex]10^{6}[/tex] =
5540000
or
5.54 * 1000000 =
5540000
The area of a rectangular piece of land is 2/3 square mile.
One dimension is 1 1⁄2 miles.
Answer:
4/9 miles
Step-by-step explanation:
[tex]\sf Area = \dfrac{2}{3} \ square \ miles\\[/tex]
[tex]\sf length = 1\dfrac{1}{2}=\dfrac{3}{2} \ miles[/tex]
[tex]\sf Width \ of \ rectangle = \dfrac{Area}{length}[/tex]
[tex]\sf = \dfrac{2}{3} \div \ \dfrac{3}{2}\\\\ =\dfrac{2}{3}*\dfrac{2}{3}\\\\ =\dfrac{4}{9} \ miles\\[/tex]
Use KCF method for faction division.
K- Keep the first fraction.
C - Change the division to multiplication.
F - Flip the second fraction.
What is the area of the figure?
Answer:
21.5
Step-by-step explanation:
break the shape down to make two shapes: a triangle and rectangle.
triangle = A=bxh/2
3x5=15/2=7.5
Rectangle = A=bxh
2x7=14
7.5+14= 21.5
Hope this helps :)
Answer:
21.5
Step-by-step explanation:
(all steps provided in image attached)
The Johnsons’ new swimming pool measures 3x^2-2x+1 ft in length and x+2 ft in width. What is the area of the new swimming pool, in square feet?
Answer:
[tex]3x^3 + 4x^2 -3x + 2[/tex]
Step-by-step explanation:
The area of the swimming pool will be equal to [tex]length * width[/tex].
We know that the length is [tex]3x^2-2x+1[/tex] and the width is [tex]x+2[/tex].
Therefore we can substitute those into the equation:
[tex](3x^2-2x+1)(x+2)\\[/tex]
Then, we expand the brackets using a grid (attached).
After this, we collect like terms to find the final answer:
[tex]3x^3+6x^2-2x^2-4x+x+2\\3x^3 + 4x^2 -3x + 2[/tex]
Our final answer is: [tex]3x^3 + 4x^2 -3x + 2[/tex]
Hey guys. Need help here
Quayleen wants to decorate her Christmas tree. She wants to place the tree on a wooden block covered with coloured paper with picture of Santa Claus on it. She must know the exact quantity of paper to buy for this purpose. If the box has length, breadth and height as 80 cm, 40 cm and 20 cm respectively. How many square sheets of paper of side 40 cm would she require?
[tex]\bullet\:{\boxed{\tt{\red{{Given :}}}}}[/tex]
• Length of the wooden box [tex](l)[/tex] = 80cm.
• Breadth of the wooden box [tex](b)[/tex] = 40cm.
• Height of the wooden box [tex](h)[/tex] = 20cm.
• Side of the square sheet paper = 40cm.
[tex]\bullet\:{\boxed{\tt{\red{{To : Find :}}}}}[/tex]
The number of sheets required.
[tex] \bullet\:{\boxed{\tt{\red{{Formula \: \: used :}}}}}[/tex]
[tex] \star{\underline{\boxed{{\sf{{{TSA}} = \underline{\underline{{\purple\sf 2(lb+bh+hl)}}}}}}}} \star[/tex]
[tex]\star{\underline{\boxed{{\sf{{{Area \: of \: square}} = \underline{\underline{{\purple{\sf side \times side }}}}}}}}}\star[/tex]
[tex]\star{\underline{\boxed{{\sf{{{Number \: of \: sheets \: required} = {{{\purple{\sf \dfrac{TSA}{area \: of \: one \: sheet}}}}}}}}}}} \star[/tex]
[tex] \bullet\:{\boxed{\tt{\red{{Concept :}}}}}[/tex]
As Quayleen wants to place the tree on a wooden block covered with coloured paper with picture of Santa Claus on it. So for knowing the number of sheets required, we need two things one the TSA and Area of one sheet. Once, we will get the values we will divide them to get the answer. Let's Start !!
[tex] \bullet\:{\boxed{\tt{\red{{Solution :}}}}}[/tex]
As we know that ::
Total surface area of cuboid [tex]\large[ \sf 2(lb+bh + hl)][/tex]
Here,
✧ Length [tex](l)[/tex] = 80cm
✧ Breadth [tex](b)[/tex] = 40cm
✧ Height [tex](h)[/tex] = 20cm
Now, by putting the values we get :
[tex] \longrightarrow 2 \bigg[ (80 \times 40) + (40 \times 20) + (20 \times 80) \bigg]\sf {cm}^{2}[/tex]
[tex]\longrightarrow 2 \bigg[ (3200) + (800) + (1600) \bigg] \sf {cm}^{2} [/tex]
[tex] \longrightarrow 2 \bigg[ 5600 \bigg] \sf {cm}^{2} [/tex]
[tex] \longrightarrow 11200 \: \sf {cm}^{2}[/tex]
Hence, the total surface area of the wooden box is 11200 cm²
Now,
The area of each sheet of paper will be :
[tex] \sf \longrightarrow side \times side[/tex]
[tex]\sf \longrightarrow (40 \times 40) \: {cm}^{2} [/tex]
[tex]\longrightarrow \sf (1600) \: {cm}^{2} [/tex]
Hence, the area of each sheet of paper is 1600 cm²
Now,
For finding the number of sheets required
[tex] \longrightarrow \tt \dfrac{total \: surface \: area \: of \: box}{ area \: of \: one \: sheet} [/tex]
[tex]\longrightarrow \sf\dfrac{ \cancel{11200}_{7}}{\cancel{1600}_{1}}[/tex]
[tex] \longrightarrow \purple{ \sf 7}[/tex]
Therefore, Quayleen requires 7 sheets.
[tex]\rule{280pt}{2pt}[/tex]
Hey can I have help on this question with an explanation please :)
Step-by-step explanation:
i hope this is helpful!........
Please Help Me! What is cos B?
Answer:
cos B = 0.4706
Step-by-step explanation:
The cosine of an angle in a right-angled triangle is the ratio of its adjacent side and the hypotenuse, so:
[tex]cos B = \frac{adjacent}{hypotenuse}\\\\cos B = \frac{8}{17} \\\\cos B = 0.4706[/tex]
Option B
Which of the following is correct for determining the length of x to the nearest tenth of a metre?
cos 42 = x/6
tan 48 = x/5
sin 48 = x/5
tan 42 =x/6
The school basketball team has 15 players. Seven players are more than 74 inches tall, 6 players are taking honors classes, and 5 players are
both more than 74 Inches tall and taking honors classes.
If 2 players are randomly selected from the team, what is the probability that both players are more than 74 Inches tall or taking honors classes?
O A.
64
225
O B.
Oc.
O D
169
225
Answer:
A
Step-by-step explanation:
64
