-2/3 - (-1 1/3)


A. -1 2/3
B. -2/3
C. -1/3
D. 2/3

Answers

Answer 1

Answer is 2/3

Hope this helps


Related Questions

A human gene carries a certain disease from the mother to the child with a probability rate of 39%. That is, there is a 39% chance that the child becomes infected with the disease. Suppose a female carrier of the gene has four children. Assume that the infections of the four children are independent of one another. Find the probability that all four of the children get the disease from their mother. Round to the nearest thousandth.

Answers

Answer:

[tex]Probability = 0.023[/tex]

Step-by-step explanation:

Given

Represent the given probability with P(Gene)

[tex]P(Gene) = 39\%[/tex]

[tex]Children = 4[/tex]

Since all 4 children get the disease, the required probability is calculated as thus:

[tex]Probability = P(Gene)^4[/tex]

[tex]Probability = 39\%^4[/tex]

Convert % to decimal

[tex]Probability = 0.39^4[/tex]

[tex]Probability = 0.02313441[/tex]

[tex]Probability = 0.023[/tex] Approximated

Pls i beg you help meeeeeee

Answers

Answer:

is thisssssssssssssssssss right????????????????????????????

Find the slope of the line

Answers

Answer:

3/5

Step-by-step explanation:

m = change in y / change in x

m = 3 / 5


3/5
Is the answer hope this helps

The data set below represents the total number of home runs that a baseball player hit each season for 11 seasons of play. What is the interquartile range of the data? 14, 22, 19, 21, 30, 32, 25, 15, 16, 27, 28 12 16 22 28

Answers

Answer:

The interquartile range of the data is 12

Step-by-step explanation:

Data : 14, 22, 19, 21, 30, 32, 25, 15, 16, 27, 28 12 16 22 28

Data in ascending order : 12 ,14 ,15 ,16 ,16 ,19 ,21 ,22 ,22 ,25 ,27 ,28 ,28 ,30 ,32

Lower quartile :12 ,14 ,15 ,16 ,16 ,19 ,21

Q1 is the median of lower quartile

n = 7

Median =[tex]\frac{n+1}{2} \text{th term}=\frac{7+1}{2}=4 \text{th term}[/tex]=16

Upper quartile :22 ,25 ,27 ,28 ,28 ,30 ,32

Q3 is the median of upper quartile

n = 7

Median =[tex]\frac{n+1}{2} \text{th term}=\frac{7+1}{2}=4 \text{th term}[/tex]=28

IQR = Q3-Q1=28-16= 12

Hence the interquartile range of the data is 12

Answer:

A: 12

Step-by-step explanation:

edg2020

If b^2 = 25 then b= Answer it please

Answers

Answer:

b = 5

mark me as brainliest plz!! :DD

A large brick oven takes 64 minutes to cook 16 pizzas. How long would it take to cook two pizzas?

Answers

Answer:

It would take 8 minutes to cook 2 pizzas in a brick oven.

Step-by-step explanation:

Answer:

It would take 8 minutes to cook 2 pizzas in a brick oven.

Please help me with this!
I will give you a thanks!

Answers

-2 + 6
.................
-2+6 . Count the spaces . That’s what I used to do

Kim sold a house for $250,000 and made a 2% commission. How much money did Kim make from commission for selling the house?
$250.00

$5,000.00

$255,000.00

$500,000.00

Answers

Answer:

5000

Step-by-step explanation:

2% of 250,000 is 5000

$5,000.00 because that’s the right answer thats why

Can I please have answer

Answers

Answer:start on -4 go over 3 right and up 4

Step-by-step explanation:

Answer:

Start at -4 on the y axis(the axis that goes up and down). Then draw a line from this point that goes to the right 3 squares, and up 4 squares. Then just continue the line with the same movements to the right, and opposite movements to the left.

Step-by-step explanation:

Magic

What are the Odds of an event happening if the probability of the event happening is (Event
0.25]?

Answers

Answer:

odds and probably are the same. If there is 0.25 chance that means there is basically a 25% chance the event will happen or 1/4 chance.

Step-by-step explanation:

i have no idea i just need to ask

The following is an excerpt from a soccer magazine. Read and answer the question The ball should weigh between 410–450 g (14–16 oz), with a circumference of 68–70 cm (27–28 in). The ball's weight must be in the range of 410 to 450 g (14 to 16 oz) and inflated to a pressure of 0.6 and 1.1 bars (8.7 and 16.0 psi) at sea level. Create a compound inequality for the weight using min and max weight values, leave units out, just the numerical answer.

Answers

Answer:

A) 410 ≤ x ≤ 450 AND 68 ≤ y ≤ 70

B) 410 ≤ x ≤ 450 AND 0.6 ≤ x ≤ 1.1

Step-by-step explanation:

In the first statement we are told that the ball should weigh between 410–450 g (14–16 oz), with a circumference of 68–70 cm (27–28 in).

If the weight is x, it means we have the inequality as;

410 ≤ x ≤ 450

If the circumference is denoted as y, we have;

68 ≤ y ≤ 70

Compound inequality is when we join two inequalities with the word "OR" or the word "AND.

Thus, the compound inequality is;

410 ≤ x ≤ 450 AND 68 ≤ y ≤ 70

Similar to he first statement, in the second statement, we have;

410 ≤ x ≤ 450

If the inflated pressure is denoted by z, then we have;

0.6 ≤ x ≤ 1.1

Like in the first statement, the compound inequality can be represented as;

410 ≤ x ≤ 450 AND 0.6 ≤ x ≤ 1.1

The standard normal distribution has a mean of

and a standard deviation of

Answers

The standard normal distribution has a mean of 0 and a standard deviation of 1

The inside of an oven is set to rise to a temperature of 298°F. So far it has risen 76% If this amount.

Which would be the best way to estimate the number of degrees Fahrenheit the inside of the oven has risen so far?

Answers

Answer:

226.48°F

Step-by-step explanation:

Temperature of the oven = 298°F

if it has risen 76% of this amount so far, the number of degrees Fahrenheit the inside of the oven has risen so far can be expresses as:

= 76% of 298

= 76/100 * 298

= (76*298)/100

= 0.76*298

= 226.48°F

The temperature inside the oven so far is 226.48°F

Suppose the time to process a loan application follows a uniform distribution over the range 77 to 1515 days. What is the probability that a randomly selected loan application takes longer than 1414 days to process

Answers

Answer:

The probability is approximately 0.2222

Step-by-step explanation:

The correct question is as follows;

Suppose the time to process a loan application follows a uniform distribution over the range 7 to 15 days. What is the probability that a randomly selected loan application takes longer than 14 days to process

Please check attachment for solution to question

In a certain college,20% of the physics majors belong to ethnic minorities. If 10 students are selected at random from the physics majors, what is the probability that exactly 7 belong to an ethnic minority?

Answers

Answer:

0.000786432

Step-by-step explanation:

In a certain college,20% of the physics majors belong to ethnic minorities

The proportion p = 20%

= 0.2

q = 1 - 0.2 = 0.8

1f 10 students are selected at random from the physics majors

n = 10

x = 7

The formula for Binomial Probability is

= nCx × p^ x × (1−p)^ n−x .

= 10C7 × p⁷ × (0.8) ^10 - 7

= 0.000786432

The probability that exactly 7 belong to an ethnic minority is 0.000786432

what are the two consecutive odd integers whose product is 99.

Answers

Answer:

9and 11

Step-by-step explanation:

it also can be -9 and -11

The blue dot is at what value on the number line?
?
3
1

Answers

Answer:

5

Step-by-step explanation:

count

help needed please answer asap

Answers

3 hours
4,300-700=3,600
She can type 20 word per minute
20 times 60= 1,200 times 3= 3,600

Radio blackouts are among the most common space weather events to affect Earth. Minor radio blackouts occur, on average, twice per year. Use a Poisson process to model the phenomenon. (a) Given that 3 events have occurred in the first half of the year, what is that probability that 3 events will happen in the rest of the year? (b) How many radio blackouts do you expect to see in two years? (c) Starting from now, how long must we wait so that the probability of seeing the next radio blackout is at least 0.5? (d) Find the probability that the time to the 4th blackout is at most 2 years.

Answers

Answer:

a.  P(x = 3) = 0.061313

b. The expected number of radio blackouts = 4

c.  It is not possible to determine the next radio blackout

d. P(x = 4) = 0.19537

Step-by-step explanation:

From the given information:

Using a Poisson process to model the phenomenon:

Since minor radio blackouts occur, on average, twice per year.

Then:

[tex]\lambda = 2 \ years[/tex]

From question (a)

time t = 1/2 (i.e half of the year)

Let x be the random variable that denotes the probability that 3 events will happen in the rest of the year.

Then:

[tex]P(x = 3) = \dfrac{e^{-\lambda t} \times (\lambda t)^x}{x!}[/tex]

[tex]P(x = 3) = \dfrac{e^{-2* 0.5} \times (2 * 0.5)^3}{3!}[/tex]

P(x = 3) = 0.061313

b).

The number of radio blackouts  we expect to see in two years can be estimated as follows:

we know that:

t = 2 years

E(x) = λ × t

E(x) = 2 × 2

E(x) = 4

The expected number of radio blackouts = 4

c).

The amount of time we need to wait given that the probability of seeing the next radio blackout is at least 0.5 is as follows:

Here, the time (t) = ???

Thus:

P(x =1) = 0.5

[tex]P(x = 1) = \dfrac{e^{-\lambda t} \times (\lambda t)^x}{x!} = 0.5[/tex]

[tex]\dfrac{e^{-\lambda t} \times (\lambda t)^x}{x!} = 0.5[/tex]

Thus, it is not possible to determine the probability (50%) of seeing the next radio blackout.

d)

The probability that the time to the 4th blackout is at most 2 years can be computed as follows:

Here;

x =4 , t = 2

Thus:

[tex]P(x = 4) = \dfrac{e^{-4 } \times (4)^4}{4!}[/tex]

P(x = 4) = 0.19537

Circle O has a circumference of approximately 44 in.
What is the approximate length of the diameter, d2
7 in
14 in
22 in
44 in

Answers

Answer:

14 in

Step-by-step explanation:

Given:

Circumference of circle = 44 in

Required:

The length of the diameter of the circle.

SOLUTION:

Circumference of circle = πd

Circumference = 44 in

π = 3.14

d = ?

Plug the values into the formula

44 = 3.14*d

Divide both sides by 3.14

44/3.14 = d

14.01 = d

d ≈ 14 in

2(x-3)=x-5+x plz help

Answers

Answer:

x is undefined

Step-by-step explanation:

Simplify the expression, we get

2x-6=2x-5

This will not work

There are no solutions

Let M = 18,526.6 find the smallest power of 10 that will exceed M

A. 10^6
B. 10^ -1
C. 10^5

Answers

i believe that it’s c
10^5

??????????number line

Answers

Answer:

A. 6 B. 8 min C. yes

Step-by-step explanation:

Identify the equation for the graph shown.
A)
y = x - 4
B)
y = 5x - 2
4-3x6
D)
y = 2x - 5

Answers

Y=2x-5
I think
Hope this helps

Answer:

(D) y = 2x - 5

Step-by-step explanation:

First locate where the line touches the y axis or vertical axis. Then find the rise over run or rate of change (slope) by using the triangle method.

I call this the triangle method because it involves drawing vertical(up, and down), and horizontal(left, and right) lines from the original or diagonal line (hypotenuse or longest line) to create a right (90 degree, because the angle between them forms a square) triangle. First draw a line going to the right from a point on the original line, and form a triangle by connecting the next point with a line going up, and down (vertical line) with the line going to the right (horizontal line)

Then count the units of the vertical line and divide them by the units counted by the horizontal line.

This is k(for constant) or m(slope or steepness of a graph ) = change in or rise of y divided by the change in or rise of x = ∆y(change in or rise of y)/∆x(change in or run of x).

For this graph, starting from -5 or the point where the line touches the y axis. Draw a line going up 1 square to the right, and another going up 2 squares. Repeat this, and you will realise that it's the same pattern every time. Because the line goes up 2 squares, every time it goes to the right 1 square. There is a change of 2 in y every change of 1 in x or rise of 2 for every run of 1. Therefore, the slope is 2/1 = 2. Then since we know the graph touches the y axis at -5, y = 2x - 5

What is the least common multiple of six and eight?

Answers

Answer:

24

plz mark me as brainliest :DD

Answer:

The LCM for 6 and 8 = 24

Step-by-step explanation:

Because 24 is the first multiple they have in common.

6 | 8

12| 16

18 | 24  <-- 24

24 | 32

^

24       Least Common Multiple

Lilliana is training for a marathon. She runs the same distance every day for a week on Monday,
Wednesday, and Friday, she runs 2 laps on a running trail and then runs 6 more miles. On Tuesday and
Sunday, she runs 4 laps on the trail and then runs 2 more miles. On Saturday, she just runs laps. How
many laps does Lilliana run on Saturday?

Answers

Answer: 6 miles

Step-by-step explanation:

WEDNESDAY + FRIDAY (# OF MILES)

The Miles Covered by Each Lap = 3x

The Miles on Top of That = 6

TUESDAY + SUNDAY (# OF MILES)

The Miles Covered by Each Lap = 5x

The Miles on Top of That = 2

You want to now put that into an equation! Therefore, you want to put the number of miles from Wednesday and Friday on one side and the number of miles from Tuesday and Sunday on the opposite side.

SOLVING EQUATION FOR MILES PER LAP

Step 1) 3x + 6 = 5x + 2

given equation from what we put together.

Step 2) -3x + 3x + 6 = 5x + 2 -3x

subtract 3x from both sides.

Step 3) -2 + 2x + 2 = 6 -2

subtract 2 from both sides.

Step 4) 2 × x = 4

divide both sides by 2 because you want to put the variable (x) on one side.

Step 5) x = 2 miles for each lap

Now you want to go look back at the equation and plug in 2 for the variable x.

Step 6) 5 ×2 + 2 = 12

PEMDAS!

Step 7) 12 ÷ 2 = 6

SHE RUNS 2 MILES ON SATURDAYS!

A= 1,321 +0.3433m
The equation above can be used to estimate the body surface area A, in square centimeters, of a child with mass
m, in grams, where 3,000 sms 30,000 Which of the following statements is consistent with the equation?
O a
A. For each increase of 1 gram in mass, A increases by approximately 0.3433 square centimeter.
Ob
B. For each increase of 0.3433 gram in mass, A increases by approximately 1 square centimeter.
Ос
C For each increase of 1 gram in mass, A increases by approximately 1,321 square centimeters.
Od
D. For each increase of 1,321 grams in mass, A increases by approximately 1 square centimeter.

Answers

Answer:

Option A: For each increase of 1 gram in mass, A increases by approximately 0.3433 square centimeter.

Step-by-step explanation:

We are given the function;

A= 1321 + 0.3433m

To find the rate of increase of the area, we will find the derivative of the function. Thus;

dA/dm = 0.3433

This means that the area increases at the rate of 0.3433 Sq.metre for each additional 1 gram added to the mass.

Looking at the given options, the one that corresponds to our answer is Option A

Help!!!!!!!Plz!!!!!!!

Answers

Answer:

I'm so confused

Step-by-step explanation:

7th grade math help me plzzz

Answers

Answer:

a. -7 + 3

b. draw 7 negatives + 7 positives

Step-by-step explanation:

Answer:

3.a) -7 + 3

3.b) 4

I hope this helps!

. The article "Wind-Uplift Capacity of Residential Wood Roof-Sheathing Panels Retrofitted with Insulating Foam Adhesive" (P. Datin, D. Prevatt, and W. Pang, Journal of Architectural Engineering, 2011:144–154) presents a study of the failure pressures of roof panels. Following are the failure pressures, in kPa, for five panels constructed with 6d smooth shank nails. These data are consistent with means and standard deviations presented in the article. 3.32 2.53 3.45 2.38 3.01 Find a 95% confidence interval for the mean failure pressure for this type of roof panel.

Answers

Answer:

The 95% confidence interval  is   [tex] 2.354 <   3.526 [/tex]

Step-by-step explanation:

From the question we are told that

   The sample size is  n =  5

    The sample  data is  3.32  2.53  3.45  2.38   3.01

Gnerally the sample mean is mathematically represented as

      [tex]\= x  =  \frac{\sum x_i}{n}[/tex]

=>    [tex]\= x  =  \frac{3.32+  2.53 +3.45+ 2.38+ 3.01 }{5}[/tex]

=>    [tex]\= x  =   2.94 [/tex]

Generally the standard deviation is mathematically represented as

     [tex]s =  \sqrt{ \frac{ \sum (x_i -  \= x )^2}{n-1} }[/tex]

=> [tex]s =  \sqrt{ \frac{  ( 3.32 -  2.94  )^2 +  ( 2.53 -  2.94  )^2+ \cdots + ( 3.01  -  2.94  )^2}{5-1} }[/tex]

=>  [tex]s =   0.472 [/tex]  

Generally the degree of freedom is mathematically represented  as

    [tex]df =  n-1[/tex]

=>  [tex]df =  5-1[/tex]

=>  [tex]df =  4 [/tex]    

From the question we are told the confidence level is  95% , hence the level of significance is  

      [tex]\alpha = (100 - 95 ) \%[/tex]

=>   [tex]\alpha = 0.05[/tex]

Generally from the t distribution table the critical value  of  [tex]\frac{\alpha }{2}[/tex] at a degree of freedom of   [tex]df =  4 [/tex]  is  

   [tex]t_{\frac{\alpha }{2} ,df } =  2.77[/tex]

Generally the margin of error is mathematically represented as  

      [tex]E =t_{\frac{\alpha }{2} ,df }  *  \frac{\sigma }{\sqrt{n} }[/tex]

        [tex]E = 2.77 *  \frac{0.472 }{\sqrt{5} }[/tex]

        [tex]E = 0.586 [/tex]

Generally 95% confidence interval is mathematically represented as  

      [tex]\= x -E <  \mu <  \=x  +E[/tex]

     [tex]2.94-0.586 <  2.94  + 0.586[/tex]

     [tex] 2.354 <   3.526 [/tex]

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