20) Mg + O2 → MgO
Reaction Type
synthesis (s)
decomposition (D)
single replacement (SR)
double replacement (DR) or combustion (C)

Explanation:

The SI Unit of sound is decibel.

or we can say that

The SI Unit of sound is watt per square metre (i.e.w/m2).

Answer:

False

Explanation:

Because laws and theories are developed for different purposes, laws never become theories, and theories do not become laws.

Number 2 represents this process on the hydrologic cycle diagram. Therefore, the correct option is option B.

One of the most significant natural processes is the hydrologic cycle, which we may often take for granted. This process causes the water in the entire earth to change forms, locations, or accessibility.

Water transitions between three distinct forms during this cycle, to put it simply. It can be found in many states of liquid, gas, or solid, including ice, steam, and water. Water will frequently transition between these three states throughout the cycle: freezing into ice, melting into water, evaporating becoming water vapor, but finally condensing back into water. Number 2 represents this process on the hydrologic cycle diagram.

Therefore, the correct option is option B.

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The alkaline earth metals are also referred to as Group 2A. elements are comparable to one another in terms of their electron configurations and thus, their properties.

From beryllium (Be) through radium, the alkaline-earth metals comprise Group 2 of the periodic table (Ra). The alkaline earth metals are so reactive because each of these elements has two electrons in its lowest energy level that they are rarely encountered alone in nature. However, they don't react as quickly as alkali metals do. Compared to the alkali metals, their chemical reactions normally proceed more slowly and generate less heat.

Be :- [He]2S2

Mg:-[Ne]3S2

Ca :-[Ar]4S2

Sr:-[Kr]5S2

Ba:-[Xe]6S2

Ra:-[Rn]7S2

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Group 2A is another name for the alkaline earth metals, which are similar to one another in terms of their electron configurations and thus, their properties.

Group 2 of the periodic table is made up of alkaline-earth metals, starting with beryllium (Be) and ending with radium (Ra). The fact that each of these elements possesses two electrons at its lowest energy level makes the alkaline earth metals extremely reactive, which is why they are rarely found by themselves in nature. They don't respond as quickly, though, as alkali metals do. Their chemical reactions often take longer and produce less heat than those of the alkali metals.

Be:- [He]2S2

Mg:-[Ne]3S2

Ca:-[Ar]4S2

Sr:-[Kr]5S2

Ba:-[Xe]6S2

Ra:-[Rn]7S2

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Cupric oxide (CuO) and cuprous oxide (Cu2O) are the names of two oxides of copper.

Both Cupric oxide (CuO) and cuprous oxide are different from one another because of the presence of number of copper atom. In one compound, copper is bonded with oxygen in 1:1 form whereas in the other compound, the copper is bonded with 2:1 form.

So we can conclude that Cupric oxide (CuO) and cuprous oxide (Cu2O) are the names of two oxides of copper.

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Enrichment of uranium-235 is done. Hence, option A is correct.

The act, process, or means of keeping something within limits the containment of health costs.

Enrichment is a process of increasing the proportion of fissile isotope found in uranium ore (represented by the symbol 'U') to make it usable as nuclear fuel or the compressed, explosive core of nuclear weapons.

Hence, option A is correct.

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Answer:

newtons law states that every body in the universe attracts every other body with a force which is directly proportional to the product of their masses and inversely proportional to square of the distance between their centers

Answer:

an object at rest tends to stay at rest

Avogadro's law states that in one mole of a substance, there are [tex]6.022 \times 10^{23}[/tex] molecules.

This means that in 1.55 moles, there are [tex]1.55(6.022 \times 10^{23})=\boxed{9.33 \times 10^{23} \text{( to 3 sf)}}[/tex]

Answer:

V = 25.7 L

Explanation:

To find the volume of Argon (Ar), you need to use the Ideal Gas Law equation. This looks like:

PV = nRT

In this formula,

        > P = pressure (atm)

        > V = volume (L)

        > n = number of moles

        > R = constant (0.0821 L*atm/K*mol)

        > T = temperature (K)

While there is a different constant that can be used if you want to keep the pressure in mmHg, there is a more common constant used when the pressure is in atm. So, to find the volume, you need to (1) convert mmHg to atm (by dividing by 760) and then (2) calculate the volume (using Ideal Gas Law).

(Step 1)

600 mm Hg              1 atm
-------------------  x  ---------------------  =  0.789 atm
                              760 mm Hg

(Step 2)

PV = nRT

(0.789 atm) x V = (0.825 mole)(0.0821 L*atm/K*mol)(300 K)

(0.789 atm) x V = 20.32

V = 25.7 L

Answer:

"A", "water changes from a gas to a solid to a liquid", according to this phase diagram, at at 0°C, as pressure is increased from 0atm to 10atm.

Explanation:

The question asks what happens at 0°C, as pressure is increased from 0atm to 10atm.

According to the question, the temperature is held constant.  The pressure changes.  In the phase diagram, we find the temperature 0°C on the horizontal axis, and all points where the temperature are 0°C are along that vertical line.

Since the pressure starts at 0atm and increases to 10atm, we start at the bottom, and move upward along that line, to see what phases of matter the substance changes to.

At the bottom, it is initially in a "gas" phase.  As it moves up, it transitions to a "solid" phase.  Later, as it continues moving up, it changes again into a "liquid" phase.

Thus, the answer would be "A", "water changes from a gas to a solid to a liquid", according to this phase diagram, at at 0°C, as pressure is increased from 0atm to 10atm.

Answer: Fe2O3

Explanation: By applying crisscross method, the formula will be Fe2O3.

Mass of hydrate + crucible = 47.29 g

Mass of anhydrous salt = 2.7 g

Molar mass of anhydrous salt CuSO4 = 159.5 g

Given,

mass of empty crucible = 42.45 g

mass of hydrate salt= 4.84 g

mass of crucible after first heating = 46.1 g

mass of crucible after second heating= 45.153 g

mass of crucible after third heating= 45.15 g

so, as per the question we need to find...

Mass of hydrate + crucible = ? g

Mass of anhydrous salt = ? g

Molar mass of anhydrous salt CuSO4 = ? g

∴Mass of hydrate + crucible = 42.45 + 4.48 = 47.29 g

The given salt is in hydrate form, to remove water from this molecule we need to perform heating .

So we are taking the substance into the crucible as it is in less quantity.

Here, we performed heating 3 times and note the weight after every heating.

After this, assume that the water is totally evaporated and the remaining salt is in anhydrous form,

∴ Mass of anhydrous salt = 45.15 - 42.45 = 2.7 g

To find the molar mass of anhydrous salt of CuSO4,

atomic weight of Cu = 63.5 g

atomic weight of S = 32 g

atomic weight of O =16 g

∴ molar mass of anhydrous salt of CuSO4 = 63.5 + 32 + (16 ×3)

                                                                   =159.5 gm

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The number of moles of [tex]Na_2SO_4[/tex] form from 5.0 moles [tex]Na_2S[/tex] is 5 moles.

Limiting reactants are those reactants that are completely used up in a chemical reaction.

4.0 mol [tex]Na_2S[/tex] will be completely used since the combining ratio is 1 : 1 : 1.

[tex]Na_2S + CuSO_4[/tex] ->[tex]Na_2SO_4 + CuS[/tex]

From the chemical equation above, 5.0 moles [tex]Na_2S[/tex] will yield 5 moles of [tex]Na_2SO_4[/tex].

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225 milliliters of a 0.8 solution of citric acid would be needed to react with 15 g of baking soda.

The volume of a substance can be calculated using the following formula:

molarity = no of moles ÷ volume

no of moles of baking soda (NaHCO3) = mass ÷ molar mass

Molar mass of baking soda = 84.007g/mol

no of moles = 15g ÷ 84.007g/mol = 0.18mol

0.8 = 0.18/volume

volume = 0.23L equivalent to 225mL

Therefore, 225 milliliters of a 0.8 solution of citric acid would be needed to react with 15 g of baking soda.

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225 millilitres of a 0.8 solution of citric acid would be needed to react with 15 g of baking soda.

Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution. Molarity is also known as the molar concentration of a solution.

[tex]Molality = \frac{Moles \;solute}{Volume of solution in litre}[/tex]

[tex]Moles of baking soda (NaHCO_3) =\frac{mass}{molar \;mass}[/tex]

Molar mass of baking soda = 84.007g/mol

[tex]Moles of baking soda (NaHCO_3) =\frac{15g}{84.007g/mol}[/tex]

[tex]Moles of baking soda (NaHCO_3) = 0.18mol[/tex]

Now, calculating volume with the molarity formula:

Molality = [tex]\frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}[/tex]

0.8 = [tex]\frac{0.18 }{Volume \;of \;solution \;in \;litre}[/tex]

Volume = 0.23L equivalent to 225mL

Therefore, 225 milliliters of a 0.8 solution of citric acid would be needed to react with 15 g of baking soda.

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Answer:

c

Explanation:

in kc we only consider gases and aquas not solids and liquids

Answer:

02 or oxygen if im not mistaken

The gas given off at the cathode is hydrogen while the gas given off at the anode is oxygen.

The term electrolysis has to do with the decomposition of a substance by the passage of a direct current through it.

The ions present in the system are[tex]H^+[/tex], [tex]OH^-[/tex] and [tex]NO_3^-[/tex] ions. The gas given off at the cathode is hydrogen while the gas given off at the anode is oxygen.

The half-reaction equation of the reduction is;

[tex]2H^+(aq) + e[/tex] → [tex]H_2(g)[/tex]

The oxidation half-reaction equation is;

[tex]4OH^- (aq)[/tex] → [tex]2H_2O(l) + 4e[/tex]

The overall equation is;

[tex]4H^+(aq) + 4OH^- (aq)[/tex] → [tex]4H_2(g) + 2H_2O(l) + 4e[/tex]

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Answer:

500ml or 0.5l

Explanation:

The concentration is 0.40 M so there are 0.40 moles in 1 l of the solution.

0.40 moles -> 1 l

but we have to go to 0.20 moles, 0.40/2 = 0.20 moles but we have to divide the volume also by 2 that makes 0.5 liters.

Answer: 0.5

Explanation:

The concentration is 0.40 M so there are 0.40 moles in 1 l of the solution.

0.40 moles -> 1 l

but we have to go to 0.20 moles, 0.40/2 = 0.20 moles but we have to divide the volume also by 2 that makes 0.5 liters.

24.25 moles of NO can be produced using 97 moles of HNO3.

Equal numbers of atoms from various elements are present in both the reactants and the products in balanced chemical equations. Varied elements' atom counts in the reactants and products of unbalanced chemical equations are different.

3 Cu + 8HNO3 g → 3 Cu(NO3)2 + 2 NO + 4 H2O

The number of moles consumed can be calculated using comparing with coefficients in the balanced reaction .

So , from above eq we get that 8 moles of HNO3 are consumed to make 2 moles of NO.

⇒  8 HNO3⇔2 NO

⇒ 1 HNO3⇔ 1/4 NO

This means that for each mole of HNO3 produces 1/4 moles of NO.

So , for 97 moles of HNO3 , [tex]\frac{1}{4} *97[/tex] moles of NO can be made,

So, total moles of NO made are 24.25 moles.

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24.25 moles of NO would be made when 97 moles of [tex]HNO_{3}[/tex] are consumed

Given reaction:

[tex]3 Cu + 8HNO_{3} - > 3 Cu(NO_{3})_{2} + 2 NO + 4 H_{2}O[/tex]

As the given reaction is already balanced so we don't need to balance it

In a balanced chemical reaction the ratio of reactants consumed and products formed always remains constant.

∵ In the given Reaction we can analyse for 8 moles [tex]HNO_{3}[/tex] consumed 2 moles of [tex]NO[/tex] are being produced.

Assuming [tex]x[/tex] moles of [tex]NO[/tex] being produced when [tex]97[/tex] moles [tex]HNO_{3[/tex] produced

∵ Ratio remains constant

⇒[tex]\frac{HNO_{3} Consumed}{NO Produced} = \frac{8}{2} =\frac{97}{x}[/tex]

⇒[tex]x=\frac{97}{4}=24.25[/tex] moles

∴ 24.25 moles of [tex]NO[/tex] would be made.

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The number of calories which are absorbed when water absorbs 6.55 KJ of energy is 1565.49 calories

To know the number of calories which are absorbed when water absorbs 6.55 KJ of energy, we shall begin by converting 6.55 KJ to joules (J). Details below:

1 KJ = 1000 J

Therefore,

6.55 KJ = (6.55 KJ × 1000 J) / 1 KJ

6.55 KJ = 6550 J

Finally, we shall convert 6550 J to calories. This is illustrated below:

4.184 J = 1 calorie

Therefore,

6550 J = (6550 J × 1 calorie) / 4.184 J

6550 J = 1565.49 calories

Thus, from the above calculations, we can conclude that the number of calories absorbed is 1565.49 calories

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Answer:

Explanation:

i ned help

Answer:

D. C₄H₁₀ and C₂H₅

A chemical formula indicating the elements of a compound and their relative proportions, as (CH₂O)n.

Since an empirical formula indicates the ratio (proportions) of the elements in the compound, it can be used, along with the molar weight of the compound, to determine the molecular formula.

The empirical formula provides the smallest whole-number ratio among elements or compounds within a molecular compound. A compound is a chemical formed from atoms of different chemical elements.

Hence, Option D is correct.

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Based on the mass ratio, the mass of H₂ produced is 3.51 g of H₂

The mass ratio of a reaction is the ratio of the masses of the reactants as well as as products in a balanced equation of a reaction.

The equation of the reaction is given below;

2 AI + 6 HCI → 2 AICI₃ + 3 H₂

From the reaction equation, 2 * 27 g of Al produces 3 * 2 g of H₂

32.25 g of Al will produce: 6/55 * 32.25 g of H₂

Therefore, mass of H₂ produced is 3.51 g of H₂

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Answer:

From the reaction equation, 2 * 27 g of Al produces 3 * 2 g of H₂

32.25 g of Al will produce: 6/55 * 32.25 g of H₂

Therefore, mass of H₂ produced is 3.51 g of H₂

Explanation:

When the circuit is opened, a spark is much more possible.

The primary purpose of an inductor is the storage of energy. This is why an inductor helps to eliminate a spark in a circuit.

In the circuit as described in the question, we know that there is no current when the circuit is closed, the current across the inductor remains constant but rapidly decreases at the opening of the circuit this could lead to a spark.

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Answer:

The energy will be added  

Explanation:

Taking into account the reaction stoichiometry, 8 moles of Ag can be produced from 8 moles of AgNO₃ and 5 moles of Zn.

In first place, the balanced reaction is:

2 AgNO₃ + Zn → 2 Ag + Zn(NO₃)₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 1 mole of Zn reacts with 2 moles of AgNO₃, 5 moles of Zn reacts with how many moles of AgNO₃?

[tex]amount of moles of AgNO_{3}= \frac{5 moles of Znx2 moles of AgNO_{3}}{1 mole of Zn}[/tex]

amount of moles of AgNO₃= 10 moles

But 10 moles of AgNO₃ are not available, 8 moles are available. Since you have less moles than you need to react with 5 moles of Zn, AgNO₃ will be the limiting reagent.

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 2 moles of AgNO₃ form 2 moles of Ag, 8 moles of AgNO₃ form how many moles of Ag?

[tex]amount of moles of Ag=\frac{8 moles of AgNO_{3}x2 moles of Ag }{2 moles of AgNO_{3}}[/tex]

amount of moles of Ag= 8 moles

Then, 8 moles of Ag can be produced from 8 moles of AgNO₃ and 5 moles of Zn.

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Answer:

0,218 moles

Explanation:

I will first explain how many liters is 256ml, that is 0,256 l.

because the m stands for milli which is a factor of 1000 -> (256 ml / 1000 = 0,256 l)

To calculate the amount of moles you multiply the volume with the concentration. So 0,256l x 0,855M = 0,218 moles.

Answer: 0.256

Explanation: