2. Use the relationship you established in part 1 to find the m your work. (1 point)

The angle θ to the diameter that she should row is; θ = 56.44°

It should be noted that;

a = 90° - θ. Thus;

b = 2θ

For any circle, the angle subtended (in radians) is equal to the arc length (d_w ) divided by the radius (1.2). Thus; d_w = 4θ .

The time required to walk this distance is given by;

t_w = 4θ/5 = 0.8θ

The distance rowed is given by: cos θ = d_r/2.4

d_r = 2.4cos θ while the time needed for it is;

t_r = 2.4cos θ/3.5

t_r = 0.6857θ

Thus, total time is;

T(θ) = t_r + t_w

T(θ) = 0.6857θ + 0.8θ

T(θ) = 1.4857θ

Now we need the critical numbers:

T'(θ) = 1 - 1.2 sin θ

At T'(θ) = 0, we have;

1 - 1.2 sin θ = 0

1/1.2 = sin θ

θ = sin⁻¹(1/1.2)

θ = 56.44°

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For the given equation, either 3x + 7 = 0 or x + 7 = 0

Now,

or

So, possible values of x is : -7 and -7/3

[tex](3x + 7)(x + 7) = 0 \\ \\ \\3x + 7 = 0 \\ \\ 3x = - 7 \\ \\ x = \frac{ - 7}{3} . \\ \\ \\ x + 7 = 0 \\ \\ x = - 7.[/tex]

The graph of [tex]\mathbf{y=\sin{3x}}[/tex] is given by,

Here given the function is [tex]y=\sin{3x}[/tex]

when [tex]x=0\Rightarrow y=\sin{3\times 0}=\sin0=0[/tex], then it passes through the origin (0,0).

When [tex]x=\frac{\pi}{6}\Rightarrow y=\sin{3\times\frac{\pi}{6}}=\sin\frac{\pi}{2}=1[/tex]

Since we know that, [tex]-1\leq\sin{x}\leq1,\forall x[/tex], then the function has maximum height at [tex]x=\frac{\pi}{6}[/tex].

Again when [tex]x=\frac{\pi}{3}\Rightarrow y=\sin{(3\times\frac{\pi}{3})}=\sin\pi=0[/tex], again the function is 0.

So clearly the function is the Oscillating function with a maximum value of the function as 1 and a minimum value of the function as -1.

Range of the oscilaltion of the function = 1-(-1) = 1+1 = 2

Using graphing calculator we get the graph of function [tex]y=\sin3x[/tex],

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Answer:

Step-by-step explanation:

[tex]x=\frac{-(-9)\pm\sqrt{(-9)^2-4(2)(4)} }{2 \times 2} \\x=\frac{9\pm\sqrt{81-32} }{4} \\x=\frac{9\pm\sqrt{49} }{4} \\x=\frac{9 \pm 7}{4} \\either~x=\frac{9+7}{4} =\frac{16}{4} =4\\or\\x=\frac{9-7}{4} =\frac{2}{4} =\frac{1}{2}[/tex]

Answer:

yes

Step-by-step explanation:

the FIRST derivative of a function tells us the slope of a tangent line to the curve at any point. if is positive, then the curve must be increasing. If is negative, then the curve must be decreasing.

the SECOND derivative gives us the slope of the slope function (in other words how fast the slope of the original function changes, and if it is accelerating up - positive - or if it is avengers down - negative).

so, the first derivative would be fully sufficient to get the answer of if the slope of the function at that point is positive or negative.

but because it is only a "if" condition and not a "if and only if" condition, the statement is still true.

there are enough cases, where the slope is positive, but the second derivative is not > 0 (usually = 0).

but if even the second derivative is positive, then, yes, the slope of the original function must be positive too.

The correct option regarding the recursively defined strings is given by:

c) Both i) and ii).

First we start with string 101, we have that:

101 -> 1w -> 10w -> 101

Which belongs to alphabet S.

For string 001, we have that:

001 -> 0w -> 00w -> 001.

Which belongs to alphabet S.

Hence statement c is correct.

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Answer: A'(-3, 7), B'(3, 6), C'(-7, -2)

Step-by-step explanation:

Reflecting over y = x maps (x,y) onto (y,x).

Answer:

-3 is a zero of the function  False

-1 is a zero of the function  True

1 is a zero of the function   False

2 is a zero of the function  True

4 is a zero of the function   False

Answer:

300 cupcakes

Step-by-step explanation:

[tex]27 = .09c[/tex]

[tex]c = \frac{27}{.09} = \frac{2700}{9} = 300[/tex]

In total, the bakery sold 300 cupcakes on a certain day.

A percentage is a value per hundredth. Percentages can be converted into decimals and fractions by dividing the percentage value by a hundred.

Given, A bakery sold 27 mocha cupcakes in a day, which was 9% of the total number of cupcakes sold that day.

let, 'x' be the total number of cupcakes sold that day.

Therefore, 9% of 'x' is 27 which is,

(9/100)×x = 27.

0.09x = 27.

x = 27/0.09.

x = 300.

So, The number of cupcakes sold that day is 300.

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The values of the functions are g(-0.5) = -1, g(0.3) = 0 and g(0.5) = 1

The function is given as:

[tex]g(x) = \left[\begin{array}{cc}-2&-2.5 < x \le -1.5\\-1&-1.5 < x \le -0.5\\0&-0.5 < x < 0.5&1&0.5 \le x < 1.5\end{array}\right[/tex]

To calculate g(-0.5), we make use of the domain -1.5 < x ≤ -0.5

At this domain;

g(x) = -1

So, the value of g(-0.5) is

g(-0.5) = -1

To calculate g(0.3), we make use of the domain -0.5 < x  0.5

At this domain;

g(x) = 0

So, the value of g(0.3) is

g(0.3) = 0

To calculate g(0.5), we make use of the domain 0.5 ≤ x  1.5

At this domain;

g(x) = 1

So, the value of g(0.5) is

g(0.5) = 1

Hence, the values of the functions are g(-0.5) = -1, g(0.3) = 0 and g(0.5) = 1

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The graph is shown in the attached image.

The maximum profit will be 956 birrs for both cows and sheep.

The amount of money earned by any seller on the cost price is called the profit.

Given that:-

From the given data we can see that the total number of animals cows and sheep is 16.

C + S = 16

To raise a cow need 2 Br

To raise Sheep need 5 Br

The number of sheep is 12 and cows 4.

So the amount required to raise sheep and cows is:-

Sheeps = 12 x 2 = 24 Br

Cows = 4 x 5 = 20 Br

Total = 44 Br

The selling price of cows and sheep are 100 and 50 Br.

Cows = 100 x 4 = 400Br

Sheeps = 50 x 12 = 600 Br

Total = 1000 Br

So the profit will be calculated as follows:-

P = 1000 - 44 = 956 Br

Therefore the maximum profit will be 956 birrs for both cows and sheep.

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Answer:

(-2, 1)

Step-by-step explanation:

You can read the solution from graph. The solution is where the two lines intersect. That happens in point (-2, 1).

---

Alternative:

If you want to be sure, you can alway double check by solving the system of equations.

First equation: [tex]y = \frac{1}{2}x + 2[/tex]

Second equation: [tex]y = -\frac{1}{2}x[/tex]

Substituting y in first equation with y from second.

[tex]y = \frac{1}{2}x + 2[/tex]

[tex]-\frac{1}{2}x = \frac{1}{2}x + 2[/tex]

Adding [tex]\frac{1}{2}x[/tex] on both sides.

[tex]-\frac{1}{2}x + \frac{1}{2}x = \frac{1}{2}x + 2 + \frac{1}{2}x[/tex]

[tex]0 = 1x + 2[/tex]

[tex]0 = x + 2[/tex]

[tex]-2 = x[/tex]

Substituting x with -2.

[tex]y = -\frac{1}{2}x[/tex]

[tex]y = -\frac{1}{2}(-2)[/tex]

[tex]y = 1[/tex]

As you see you get the same result as from reading the graph, (-2, 1).

The value of the temperature in function notation is gotten as; f(x) = 91 - 11x

Let us first find the relationship between temperature and how long the turkey sits out.

The temperature after the normal 390 minutes  is equal to approximately 6.5 hours.

Let us create a ratio and solve for x, which represents the temperature change during that extra hour after the "normal time sitting out".

Thus;

(7.5/6.5) = (80/80+ x)

Solving for x gives x = -10.7.

This means that for every extra hour it sits out, the turkey cools approximately 11°. When we add that to 80°, we have 91° which is the expected temperature after 390 minutes (6.5 hours) of sitting out.

Thus, the motion as a function of time is;

f(x) = 91 - 11x

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The length of the kitchen in the drawing using the scale factor is: B. 5/6.

We are given a scale factor of 1:24.

Let the length of the kitchen in the drawing = x

Actual length of kitchen = 20 ft.

Using the scale factor, we have:

1/24(20) = 20/24

= 5/6

The length of the kitchen in the drawing is: B. 5/6.

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Answer:

1/2 cup of chocolate chips

Step-by-step explanation:

Given ratio:

Let x be the unknown amount of chocolate chips:

[tex]\implies \sf \dfrac{1}{3}:2=x:3[/tex]

[tex]\implies \sf \dfrac{\frac{1}{3}}{2}=\dfrac{x}{3}[/tex]

Cross multiply:

[tex]\implies \sf 3 \cdot \dfrac{1}{3}=2 \cdot x[/tex]

[tex]\implies \sf 1=2x[/tex]

[tex]\implies \sf x=\dfrac{1}{2}[/tex]

Therefore, 1/2 a cup of chocolate chips will be needed for 3 cups of flour.

Let that be x

The income statement illustrates that the net income will be $3530.

The income statement will be:

Revenue

Consulting revenue 18350

Expenses

Miscellaneous expenses 720

Rent expense 4820

Salaries expense 8370

Telephone expenses 910

Total expenses 14820

Net income = 18350 - 14820 = 3530

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[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \: Acceleration_{dog} = 0[/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

A dog is moving at a constant speed of 8 m/s, that concludes that there's no change in its speed with respect to time.

And Acceleration is define as rate of change in velocity, but since velocity/speed is constant. change in velocity = 0

Henceforth, Acceleration of dog is 0 as well.

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Answer: Acceleration = 0 ✅

Step-by-step explanation:

Hii, let me help you out! (:

Acceleration means "change in speed (which is also known as velocity, V, in physics) per a specific amount of time.

Part 1 is Successfully completed!

                                              ↪

Now let's focus on finding the acceleration of the dog.

Like I said above, [tex]\sf Acceleration=change\;in\;speed\;per\;a\;specific\;amount\;of\;time[/tex]

Well, we are provided with the information that the dog's speed is constant. This means that it doesn't change. So the dog keeps on moving at a speed of 8 m/s. This means that its speed doesn't change, so the change in speed is 0. And this means that its acceleration is 0.

Voila! There's our answer, cheers! (:

Hope I helped! Best wishes.

Reach far. Aim high. Dream big.

[tex]\underbrace[/tex]

Answer:

11. always

12. always

13. always

14. never

15. never

16. always

17. always

18. sometimes

19. sometimes

20. never

Step-by-step explanation:

11. A line can be defined by at least two points

12. A plane can be defined by at least three points

13. If two planes intersect, then they form a line at the intersection.

14. If two lines intersect, then they form a point at the intersection (not a segment).

15. A line does not have any endpoints (infinite in both ways).

16. If two planes are not parallel they will always intersect.

17. If two lines are not parallel they will always intersect.

18. Two points are sometimes collinear. It depends on where they are.

19. Two points are sometimes coplanar. It depends on where they are.

20. Ray MN and NM are not the same ray because the end points are different.

The probability that the results indicate an unsuccessful market for the product and the product is actually unsuccessful is P=0.77.

Probability is defined as the ratio of the number of favourable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.

Events:

S: success

F: failure

MS: market research forecast a success

MF: market research forecast a failure

The information we have is:

P(S)=0.70

P(F)=0.30

P(S|MS)=0.90

P(F|MS)=0.20

If P(F|MS)=0.20, we can derive that P(F|MF)=0.80. That is, the failed products were predicted to be a failure based on market research 80 per cent of the time.

We also can conclude that P(S|MF)=0.10.

We can calculate the probability of having a forecast of a failure, given that the product is actually unsuccessful as:

[tex]P(MF|F) = \dfrac{P(F|MF)\times P(F)}{P(F|MF)\times P(F)+P(S|MF)\times P(S)}[/tex]

[tex]P(MF|F) =\frac{(0.8\times 0.3)}{0.8\times 0.3)+(0.1\times 0.7}[/tex]

[tex]P(MF|F) =\dfrac{0.24}{0.31}=0.77[/tex]

The probability that the results indicate an unsuccessful market for the product and the product is actually unsuccessful is P=0.77.

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Answer: Option (2)

Step-by-step explanation:

We need the angle to be included between the two mentioned sides.

Also, the sides need to be corresponding for the ratio, and both sides of the triangle need to be in either the numerators or the denominators.

The fractions that are between 12/13 and 19/20 are 13/14, 14/15, 15/16, 16/17, 17/18, and 18/19 total number of fractions is 6

Fraction number consists of two parts, one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.

We have:

Fractions that are between 12/13 and 19/20 such that:

The numerator(N) is one less than the denominator(D).

N =  D - 1

N = (12, 19)

D = (13, 20)

D = 14, N = 13

D = 15, N = 14

D = 16, N = 15

D = 17, N = 16

D = 18, N = 17

D = 19, N = 18

The fractions that are between 12/13 and 19/20:

N/D = {13/14, 14/15, 15/16, 16/17, 17/18, 18/19}

Thus, the fractions that are between 12/13 and 19/20 are 13/14, 14/15, 15/16, 16/17, 17/18, and 18/19 total number of fractions is 6

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The value of this irrational Expression is 40.77 .

An expression is a mathematical statement consisting of variables , constants and mathematical operators.

The expression given is

7√22 +3√7

√22 = 4.69

√7 = 2.65

32.83 + 7.94

40.77

The value of this irrational Expression is 40.77 .

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The graph is attached and all the sub parts have been answered.

A function is  away of relating a dependent variable to an independent variable .

It is given that

Current weight of Rex at 2 months =6 pounds

Let x represents the age in months of Rex

then a linear model that represents the Rex’s current weight, in pounds, as a function of his age, in months. is

Let y be the current weight of Rex

then

y = 6 + 9(x -2)

The table  that represents Rex’s current weight, in pounds, as a function of his age, in months

2              6

3              15              

4              24

5              33

6              42

7              51

8              59

The graph is plotted for the given data and attached .

If Rex continues to grow at the rate of 9 pounds per month beyond the expected six months, how much will Rex weight by the time he is one year old

6 + 9*(12-2)

96 pounds.

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Answer:

B -o.60

Step-by-step explanation:

34 - 40 = -6.  -6 divide by 10 = -3/5 or - 0.6. So answer is B

The value of (fg)(x)= 3x³+ x²

An expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).

Given:

f(x) = -3x+1

g(x) = [tex]x^{2}[/tex]

Now, (fg)(x)

=f(x) * g(x)

=  (-3x+1) * ([tex]x^{2}[/tex])

=-3x³+ x²

Hence, (fg)(x)= 3x³+ x²

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