(12.7)
2. A swimming pool is in the shape of a rectangular
prism with a horizontal cross-section 10 feet by 20
feet. The pool is 5 feet deep and filled to capacity.
Water has a density of approximately 60 pounds
per cubic foot
What is the approximate mass of water in the pool?
A. 8,000 lb.
B.
12,500 lb.
C
16,700 lb.
D. 60,000 lb.

Answer:

Step-by-step explanation:

cle Graphs MC)The circle graph describes the distribution of preferred transportation methods from a sample of 400 randomly selected San Francisco residents.circle graph titled San Francisco Residents' 9, 70 to 79, 80 to 89, 90 to 99, 100 to 109, 110 to 119. The y-axis is labeled Frequency and begins at 0 with tick marks every one unit up to 14. A shaded bar stops at 10 above 60 to 69, at 9 above 70 to 79, at 5 above 80 to 89, at 4 above 90 to 99, and at 2 above 100 to 109. There is no shaded bar above 110 to 119. The graph is titled Temps in Sunny Town.A graph with the x-axis labeled Temperature in Degrees, with intervals 60 to 69, 70 to 79, 80 to 89, 90 to 99, 100 to 109, 110 to 119. The y-axis is labeled Frequency and begins at 0 with tick marks every one unit up to 16. A shaded bar stops at 2 above 60 to 69, at 4 above 70 to 79, at 12 above 80

The width of Micayla's frame is Wf = (Lf x Wp) / Lp

Let's say that the painting has a length of Lp and a width of Wp, and the frame has a length of Lf and a width of Wf. We want to find the width of the frame, which we can call x. We know that Micayla wants to keep the same ratio of length to width between the painting and the frame, so we can set up the following equation:

Lp/Wp = Lf/Wf

This equation states that the ratio of the length to the width of the painting is equal to the ratio of the length to the width of the frame. We can use this equation to solve for x, the width of the frame. First, we can cross-multiply to get:

Lp x Wf = Lf x Wp

Then, we can solve for x by isolating it on one side of the equation:

Wf = (Lf x Wp) / Lp

This equation tells us that the width of the frame is proportional to the length of the frame and the width of the painting, divided by the length of the painting. By plugging in the appropriate values for Lp, Wp, and Lf, we can solve for x and determine the width of the frame.

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The volume of a triangular prism in question number 3, obtained from the product of the area of a triangle and the thickness of the prism is 1,728 mi³

A triangular prism consists of two triangular bases and three sides that are rectangular.

The solid in the figure in question number 3 is a triangular prism, with the following dimensions.

Base length = 30 mi.

Thickness (depth of the prism) = 8 mi

Shape of the triangles = Right triangles

Leg lengths of the right triangles = 18 miles and 24 miles

The volume of the triangular prism = Area of the cross section of the triangular prism × Depth of the prism

Area of the triangular cross section of the triangular prism = (1/2) × 18 × 24 = 216 mi²

Volume of the triangular prism = 216 mi² × 8 mi = 1728 mi³

The volume of the triangular prism in the figure is therefore; 1,728 mi³

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The number of tire rotations depends on the distance traveled by the wheel and the circumference of the tire. Different tire sizes would change the circumference of the tire, and therefore the number of rotations of the wheel

1. Compare the original rotations _______ vs new rotations _________.

Without knowing the original and new rotations, answer cannot be provided

2.The number of tire rotations depends on the distance traveled by the wheel and the circumference of the tire. If the wheel traveled a greater distance, the number of rotations would increase, and if it traveled a shorter distance, the number of rotations would decrease. Similarly, if the tire's circumference increased, the number of rotations would decrease, and if the circumference decreased, the number of rotations would increase.

3. Different tire sizes would change the circumference of the tire, and therefore the number of rotations of the wheel. A larger tire size would result in fewer rotations for the same distance traveled, while a smaller tire size would result in more rotations for the same distance traveled. Therefore, when changing tire sizes, it's important to consider the effect on speedometer readings and potential changes in vehicle handling

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El peso de Mariana en kilogramos es aproximadamente 79.378 kg. Debe conseguir 1.361 kg de pollo a la semana, 4.082 kg de frutas y 6.803 kg de verduras.

Para convertir el peso de Mariana de libras a kilogramos, debemos recordar que 1 libra equivale a aproximadamente 0.4536 kilogramos. Por lo tanto:

Peso de Mariana en kilogramos = 175 libras * 0.4536 kg/libra ≈ 79.3792 kg

Entonces, el peso de Mariana es aproximadamente 79.3792 kilogramos.

En cuanto a la cantidad de pollo que Mariana debe conseguir a la semana, la dieta establece que debe consumir 3 libras de pollo. Para convertirlo a kilogramos:

Cantidad de pollo a la semana = 3 libras * 0.4536 kg/libra ≈ 1.3618 kg

Por lo tanto, Mariana debe conseguir aproximadamente 1.3618 kilogramos de pollo a la semana.

De manera similar, para las frutas, la dieta establece 9 libras. Convertimos a kilogramos:

Cantidad de frutas a la semana = 9 libras * 0.4536 kg/libra ≈ 4.0824 kg

Por lo tanto, Mariana debe conseguir aproximadamente 4.0824 kilogramos de frutas a la semana.

Para las verduras, la dieta establece 15 libras. Convertimos a kilogramos:

Cantidad de verduras a la semana = 15 libras * 0.4536 kg/libra ≈ 6.804 kg

Por lo tanto, Mariana debe consumir aproximadamente 6.804 kilogramos de verduras (cocinadas o crudas) a la semana.

En resumen, el peso de Mariana es de aproximadamente 79.3792 kilogramos. Debe conseguir alrededor de 1.3618 kilogramos de pollo, 4.0824 kilogramos de frutas y 6.804 kilogramos de verduras a la semana.

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The probability of someone getting the mac and cheese or fries, with a burger and a chocolate cupcake is 1/6.

To determine the probability of someone getting the mac and cheese or fries, with a burger and a chocolate cupcake, we need to look at the possible combinations and find the ones that meet these criteria.

There are 3 side options, 2 sandwich options, and 2 dessert options, making a total of 3 x 2 x 2 = 12 possible combinations.

Now let's find the combinations that fit the desired meal:
1. Mac and cheese, burger, chocolate cupcake
2. Fries, burger, chocolate cupcake

There are 2 favorable combinations. Therefore, the probability is:

2 (favorable combinations) / 12 (total combinations) = 1/6

So, the probability of someone getting the mac and cheese or fries, with a burger and a chocolate cupcake is 1/6.

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The approximate APR for James' cabinet purchase can be calculated using the formula Approximate APR = (Finance Charge ÷ #Months) (12) ÷ Amount Financed. Plugging in the given values, we get (49 ÷ 18) (12) ÷ 438 = 0.0397 or 3.97%. Rounded to the nearest tenth, the approximate APR is 4%.

APR, or Annual Percentage Rate, is the annual interest rate charged by a lender for borrowing money. It includes not only the interest rate but also any additional fees or charges associated with the loan. The APR helps borrowers compare different loan offers and understand the true cost of borrowing.

It is important to note that the APR is an approximation and may differ from the actual interest rate charged over the life of the loan, especially if the loan has variable rates or fees. When considering a loan, it is important to compare not just the APR but also the terms and conditions of the loan, such as the repayment period, monthly payments, and any penalties for early repayment.

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The number of prizes Sam able to buy = 5

Given that;

Sam bought 1 prize for each 5 tickets

Which means he can buy 1 prize for 1 ticket

Since number of ticket Sam has = 5

Therefore he can buy

1 prize for 1 ticket

2 prizes for 2 tickets

3 prizes for 3 tickets

4 prizes for 4 tickets

5 prize4s for 5 tickets

Hence Sam can buy maximum 5 prizes.

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The current drawn by each resistor is: R1: 8 A R2: 9.25 A R3: 14.67 A And the power dissipated by each resistor is: R1: 192 W R2: 222 W R3: 352 W

To calculate the current drawn by each resistor and the power dissipated by each, we will use Ohm's Law and the Power formula.

Ohm's Law is V = IR, and the Power formula is P = IV.

Given: Resistor 1 (R1) = 192 W Resistor 2 (R2) = 222 W Resistor 3 (R3) = 352 W Voltage (V) = 24 V

Step 1: Calculate the current (I) drawn by each resistor using the Power formula (P = IV):

For R1: I1 = P1 / V = 192 W / 24 V = 8 A

For R2: I2 = P2 / V = 222 W / 24 V = 9.25 A

For R3: I3 = P3 / V = 352 W / 24 V = 14.67 A

Step 2: Calculate the power (P) dissipated by each resistor using the Power formula (P = IV):

For R1: P1 = I1 × V = 8 A × 24 V = 192 W

For R2: P2 = I2 × V = 9.25 A × 24 V = 222 W

For R3: P3 = I3 × V = 14.67 A × 24 V = 352 W

So, the current drawn by each resistor is: R1: 8 A R2: 9.25 A R3: 14.67 A And the power dissipated by each resistor is: R1: 192 W R2: 222 W R3: 352 W

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The polar coordinates (r, θ) for point B with rectangular coordinates (-5, 12) are (13, 112.62°).

The polar coordinates (r, θ) for point B with rectangular coordinates (-5, 12) can be determined as follows.

1. Calculate the radius r:

r = √(x² + y²) = √((-5)² + 12²) = √(25 + 144) = √169 = 13.

2. Calculate the angle θ in radians:

θ = arctan(y/x) = arctan(12/-5) ≈ -1.176 radians.

3. Convert θ from radians to degrees:

θ = (-1.176 * 180) / π ≈ -67.38 degrees.

4. Adjust the angle to the proper quadrant (since point B is in the second quadrant):

θ = 180 - 67.38 = 112.62 degrees.

So, the polar coordinates (r, θ) for point B are (13, 112.62°).

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The lateral surface area of a cylinder is the area of the sides of the cylinder, not including the top or bottom. In the case of a can of beans, the label that wraps around the can represents this lateral surface area.

To find the lateral surface area of the can, we need to use the formula for the lateral surface area of a cylinder: LSA = 2πr*h, where r is the radius of the base of the cylinder and h is the height of the cylinder.

Since we are given the diameter of the can (7 cm), we need to divide it by 2 to get the radius: r = 7/2 = 3.5 cm. The height of the can is given as 11 cm.

Now we can plug these values into the formula to find the lateral surface area of the can: LSA = 2π(3.5)(11) ≈ 242.95 cm².

So the lateral surface area of the can of beans is approximately 242.95 cm². This is the area of the sides of the can that the label would wrap around.

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Answer:

g(x) = -2f(x)

Step-by-step explanation:

From the graph, we can see that g(x) is a reflection of f(x) about the x-axis, followed by a vertical stretch by a factor of 2. This is equivalent to multiplying f(x) by -2, which gives us the transformation:

g(x) = -2f(x)

To conduct a hypothesis test comparing the mean voltages of the two types of batteries (K and Q), you'll need to state the null and alternative hypotheses. The null hypothesis (H₀) is that there is no difference between the mean voltages, while the alternative hypothesis (H₁) is that there is a difference between the mean voltages. In this case:

Step 1 of 5: State the null and alternative hypotheses for the test.

H₀: μ1 - μ2 = 0 (The true mean voltage for type K batteries is equal to the true mean voltage for type Q batteries.)

H₁: μ1 - μ2 ≠ 0 (The true mean voltage for type K batteries is not equal to the true mean voltage for type Q batteries.)

In the next steps, you would calculate the test statistic, determine the critical value, make a decision to reject or fail to reject the null hypothesis, and finally interpret the results based on the 0.02 level of significance.

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The perimeter of the triangle is 6 + 4√13

Let's denote the length of the congruent sides of the isosceles triangle as x.

The formula for the area of a triangle is A = (1/2)bh, where b is the base and h is the height.

So, we have

A = (1/2)bh

12 = (1/2)(6)(h)

h = 4

Now, using the Pythagorean theorem, we can solve for the length of the congruent sides:

x^2 = 6^2 + 4^2

x^2 = 52

x = √52

The perimeter of the triangle is the sum of the lengths of its sides:

P = 6 + √52 + √52

P = 6 + 2√52

So, we have

P = 6 + 4√13

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(a) y(x) = c1 e^(-4x/3) cos(2x) + c2 e^(-4x/3) sin(2x), stable node at the origin;

(b) y(x) = c1 e^(2x) + c2 e^(-4x), unstable node at the origin;

(c) y(x) = c1 e^(-x/22) cos(sqrt(119)x/22) + c2 e^(-x/22) sin(sqrt(119)x/22), stable node at the origin;

(d) y(x) = c1 e^(sqrt(3)x/2) + c2 e^(-sqrt(3)x/2), unstable saddle at the origin;

(e) y(x) = c1 e^x cos(2x) + c2 e^x sin(2x), stable spiral at the origin;

(f) y(x) = c1 cos(3x/2) + c2 sin(3x/2), stable limit cycle around the origin;

(g) y(x) = c1 e^(-x/3) + c2 e^(-x), stable node at the origin.

(a) The characteristic equation is 2r^2 + 9r + 4 = 0, with roots r1 = -4/3 and r2 = -1/2. The general solution is y(x) = c1 e^(-4x/3) cos(2x) + c2 e^(-4x/3) sin(2x). The equilibrium at the origin is a stable node since both eigenvalues have negative real parts.

(b) The characteristic equation is r^2 + 2r - 8 = 0, with roots r1 = 2 and r2 = -4. The general solution is y(x) = c1 e^(2x) + c2 e^(-4x). The equilibrium at the origin is an unstable node since both eigenvalues have positive real parts.

(c) The characteristic equation is 44r^2 - 12r + 5 = 0, with roots r1 = (3 + sqrt(119))/22 and r2 = (3 - sqrt(119))/22. The general solution is y(x) = c1 e^(-x/22) cos(sqrt(119)x/22) + c2 e^(-x/22) sin(sqrt(119)x/22). The equilibrium at the origin is a stable node since both eigenvalues have negative real parts.

(d) The characteristic equation is 2r^2 - 3 = 0, with roots r1 = sqrt(3)/2 and r2 = -sqrt(3)/2. The general solution is y(x) = c1 e^(sqrt(3)x/2) + c2 e^(-sqrt(3)x/2). The equilibrium at the origin is an unstable saddle since the eigenvalues have opposite signs.

(e) The characteristic equation is r^2 - 2r + 5 = 0, with roots r1 = 1 + 2i and r2 = 1 - 2i. The general solution is y(x) = c1 e^x cos(2x) + c2 e^x sin(2x). The equilibrium at the origin is a stable spiral since both eigenvalues have negative real parts and non-zero imaginary parts.

(f) The characteristic equation is 4r^2 + 9 = 0, with roots r1 = 3i/2 and r2 = -3i/2. The general solution y(x) = c1 cos(3x/2) + c2 sin(3x/2), stable limit cycle around the origin.

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The interquartile range for the data 18, 16, 7, 5, 8, 6, 4, 3, 2, 12, 17, 18, 20, 4, 22 is 14.

1. Arrange the data in ascending order (order the data set from smallest to largest): 2, 3, 4, 4, 5, 6, 7, 8, 12, 16, 17, 18, 18, 20, 22

2. Determine the median (Q2):

The IQR is a measure of variability that represents the range of the middle 50% of the data. To find it, we need to first calculate the median of the entire data set. Since we have an even number of data points, we take the average of the two middle values:

Median = (8 + 12) / 2 = 10

Next, we need to find the median of the lower half of the data set (also called the first quartile, or Q1). To do this, we take the median of the values below the overall median:

Q1 = (4 + 4) / 2 = 4

Finally, we find the median of the upper half of the data set (also called the third quartile, or Q3). To do this, we take the median of the values above the overall median:

Q3 = (18 + 18) / 2 = 18

3. Find the lower quartile (Q1):

The lower half of the data has 7 points, so the median of the lower half is Q1. Q1 is the 4th value, which is 4.

4. Find the upper quartile (Q3):

The upper half of the data also has 7 points, so the median of the upper half is Q3. Q3 is the 12th value, which is 18.

5. Calculate the interquartile range (IQR) by subtracting Q1 from Q3:

IQR = Q3 - Q1

= 18 - 4

= 14.

The interquartile range (IQR) for the given data is 14.

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Answer: 35 + 25 + 50 / 2 = 85

Step-by-step explanation: You would have to add them all together and then divide them by 2.

Susan earns $9.50 per hour. This is found by dividing her earnings by the number of hours worked for each corresponding row in the table.

To find how much money Susan earned per hour, we need to divide the total earnings by the total number of hours worked. For finding the Total earnings we need to add the money earned in every hour,

Total earnings = $47.50 + $66.50 + $85.50 + $104.50 = $304

Total hours worked = 5 + 7 + 9 + 11 = 32

Money earned per hour = Total earnings / Total hours worked

= $304 / 32

= $9.50

Therefore, Susan earned money of $9.50 per hour.

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The missing measures are BC ≈ 23.77, angle BCA = 24 degrees, AB ≈ 56.77, and CD ≈ 56.77.

To solve the problem, we can use the properties of rectangles and trigonometry.  Since ABCD is a rectangle, we know that angle ABC is also 90 degrees.

Using the Pythagorean theorem, we can find the length of BC:

BC² = AB² - AC²

BC² = 9² + 22²

BC² = 565

BC ≈ 23.77

Using the fact that the sum of the angles in triangle ABC is 180 degrees, we can find the measure of angle BCA

m(BCA) = 180 - m(ABC) - m(CAB)

m(BCA) = 180 - 90 - 66

m(BCA) = 24 degrees

Using trigonometry, we can find the length of AB

sin(24) = AC/AB

AB = AC/sin(24)

AB ≈ 56.77

Finally, we can find the length of CD, which is equal to AB

CD = AB ≈ 56.77

Therefore, the measures of AB ≈ 56.77, and CD ≈ 56.77.

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The inverse statement is "If an isosceles triangle does not have a right angle, it does not have two 45° angles."

The given statement is:

"If an isosceles triangle has a right angle, it has two 45° angles."

The inverse of this statement can be found by negating both the hypothesis and the conclusion and then reversing their order. The negation of the hypothesis is "An isosceles triangle does not have a right angle," and the negation of the conclusion is "It does not have two 45° angles."

Thus, the inverse statement is:

"If an isosceles triangle does not have a right angle, it does not have two 45° angles."

This statement asserts that if an isosceles triangle does not have a right angle, then it cannot have two 45° angles. In other words, if an isosceles triangle has only one 45° angle, it cannot have a right angle.

The inverse statement is logically equivalent to the original statement, and they are both true because they are both examples of the contrapositive of the conditional statement "If an isosceles triangle has two 45° angles, then it has a right angle."

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Answer:

------------------------------

The two smaller right triangles are similar by AA property.

Use ratios of corresponding sides to get:

Simplify and solve for y:

To minimize cost, we need to determine whether it's cheaper to lay the power line underground from A to S and then underwater from S to B, or to lay it underwater directly from A to B.

Let CS = x miles. Then AS = 6 - x miles and SB = 8 + x miles.

The cost of laying the power line underground from A to S is $2000 per mile for a distance of AS, or 2000(6-x) dollars. The cost of laying the power line underwater from S to B is $3000 per mile for a distance of SB, or 3000(8+x) dollars. So the total cost C(x) is:

C(x) = 2000(6-x) + 3000(8+x)
C(x) = 18000 - 2000x + 24000 + 3000x
C(x) = 42000 + 1000x

The power line should come to the shore at point S that is 5 miles downshore from A to minimize cost.

To minimize cost, we need to find the value of x that minimizes C(x). To do this, we take the derivative of C(x) with respect to x and set it equal to zero:

C'(x) = 1000
0 = 1000
x = -42

This doesn't make sense since x represents a distance and cannot be negative. So we know that this is not the minimum.

Alternatively, we can check the endpoints of our interval (0 ≤ x ≤ 6) to see which one gives the minimum cost. When x = 0, the cost is:

C(0) = 42000

When x = 6, the cost is:

C(6) = 44000

When x = 5, the cost is:

C(5) = 43000

To minimize the cost of constructing the power line, we need to find the point S on the shore where the combined cost of laying the underground line from A to S and the underwater line from S to B is minimized.

Let x be the distance from A to S, then the distance from S to B is (6 - x) miles.

Using the Pythagorean theorem, the underwater line's length from S to C is √((6 - x)^2 + 2^2) = √(x^2 - 12x + 40).

The cost of the underground line from A to S is 2000x, and the cost of the underwater line from S to C is 3000√(x^2 - 12x + 40). The total cost is:

Cost = 2000x + 3000√(x^2 - 12x + 40)

To minimize this cost, we can find the derivative of the cost function with respect to x and set it to zero, then solve for x. The optimal x value will give us the point S downshore from A that minimizes the cost.

After calculating the derivative and solving for x, we find that the optimal value of x is approximately 4.24 miles. Therefore, the point S should be approximately 4.24 miles downshore from A to minimize the cost of constructing the power line.

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The range of values for x in the triangle is 0 < x < 8

From the question, we have the following parameters that can be used in our computation:

AC = 3x + 32

BC = 7x + 16

Also, we know that

ADC is greater than BDC

This means that

AC > BC

So, we have

3x + 32 > 7x + 16

Evaluate the like terms

-4x > -32

Divide both sides by -4

x < 8

Also, the smallest value of x is greater than 0

So, we have

0 < x < 8

Hence, the range of values for x is 0 < x < 8

The steps to calculate the range is gotten from the theorem that implies that

The greater the angle opposite the side length of a triangle, the greater the side length itself

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The surface area of the storage bin is 34.8ft²². Storage capacity will the storage bin have 13.5ft³.

The area of a square is composed of (Side) (Side) square units. The area of a square equals d22 square units when the diagonal, d, is known. For instance, a square with sides that are each 8 feet long is 8 8 or 64 square feet in area. (ft2).

a=2*5-2>.5

b = 2 .

c = 2.1 ft

S = 2(3 * 2 * 2) + 3 * 2 + 2 * 1/v * 1/v

x 2+ 1 2 *3+3*1*3

= 2 deg + 6 + 1 + 1.5 + 6 * 3

= 34.8ft²

V = V Triangle prism + Vandrangular prism.

= 3×2×2 + 2 x = x2x2

= 12+ 1.5

= 13.5ft³

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Question:

Dave wants to know the amount of material he needs

to buy to make the bin. What is the surface area of the

storage bin?

Part B

How much storage capacity will the storage bin have?

Answer:

Step-by-step explanation:

as we alderdy have value of y,we can substuite it in the place of y

4x+8(2)=3x+7(2)+14

4x+16=3x+14+14

4x-3x=28-16

x=12

Answer:

E,F,H

Step-by-step explanation:

Answer:

B = 2 (could be 4, like with this font)

E = 4

F = 3

H = 4

P = 0 (could be 3, like this this font)

R = 0 (could be 3, like with this font)

X = (could be 4)

Other right angles:

D = 0 (could be 2, like with this font)

L = 1

T = 2

Y = (could be 1)

The area of the region enclosed by x + y² = 2 and x + y = 0 is 4/3 + 4√2/3 square units.

To find the limits of integration, we need to solve for the intersection points of the two curves.

Substituting x = -y from the second equation into the first equation, we get:

Using the quadratic formula, we get:

Since we're dealing with a real-valued area, we can discard the complex solution. The two intersection points are:

We can see from the graph below that the region we're interested in is the one enclosed by the curves, which lies to the left of the y-axis.

The limits of integration for the area are y = 0 (the x-axis) and y = 1 + √2.

Since the curves intersect at right angles, we can integrate with respect to either x or y. However, since the region is easier to express in terms of y, we'll integrate with respect to y.

The equation for the curve x + y² = 2 can be rearranged as:

The area of the region is given by:

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Answer:

False.

Inflation occurs in an economy when there is an increase in the overall price level of goods and services over time. It is usually caused by factors such as an increase in the money supply, higher demand for goods and services, or a decrease in the supply of goods and services. Therefore, a reduction in the total amount of money in an economy would generally lead to deflation, which is the opposite of inflation.

To maximize Q = xy with the constraint x + y = 332, and given x = 4, we need to express the objective function in terms of y.

Since x = 4, we can rewrite the constraint as: 4 + y = 332

Now, solve for y:
y = 332 - 4
y = 328

Now, substitute the value of x into the objective function:
Q = (4)(y)

So, the objective function in terms of y is:
Q = 4y

To write the objective function in terms of y, we can solve for x in the constraint equation:

x + 332 = 4

x = 4 - 332

x = -328

Now we can substitute this value of x into the equation for Q:

Q = xy

Q = (-328)y

Q = -328y

Therefore, the objective function in terms of y is Q = -328y.

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The system of equations has one solution.

To determine whether the system of equations has one solution, no solution, or infinite solutions, we will compare the slopes and y-intercepts of the given equations:

Equation 1: [tex]y = (\frac{2}{3})-1[/tex]
Equation 2: y = -x + 4

Step 1: Identify the slopes and y-intercepts of each equation.
For Equation 1, the slope is 2/3, and the y-intercept is -1.
For Equation 2, the slope is -1, and the y-intercept is 4.

Step 2: Compare the slopes and y-intercepts.
The slopes are different (2/3 ≠ -1), and the y-intercepts are also different [tex](\frac{2}{3} ) ≠ 4[/tex].

Your answer: Since the slopes and y-intercepts are different, the system of equations has one solution.

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