1150 kg car is on a 8.70 degree hill. What’s the x component of the normal force

1150 Kg Car Is On A 8.70 Degree Hill. Whats The X Component Of The Normal Force

Answers

Answer 1

Answer:

The x - component of the normal force is equal to 1706.45 N.

Explanation:

To solve the problem, and since there is no additional information, we can safely assume that the x-axis is parallalel to the hill surface and the y-axis is perpendicular to the x-axis. Knowing that, we can calculate the components of the normal force (or weight for this case), using the following formulas:

[tex]N

x

=W∗Sin(α)=mg∗Sin(α)[/tex]

[tex]N

y

=W∗Cos(α)=mg∗Cos(α)[/tex]

Now, using the given information, we have:

[tex]mass=m=1150Kg[/tex]

[tex]a=8.70[/tex]

[tex]g=9.81 \frac{m}{ {s}^{2} } [/tex]

Calculating, we have:

[tex]N_{x}=mg*Sin(\alpha)[/tex]

[tex] \: \: \: \: \: \: \: \: \: N_{x}=1150Kg*9.81\frac{m}{s^{2}}*Sin(8.70\°)[/tex]

[tex]N

x =11281.5

s

2

Kg.m

∗Sin(8.70\°) = \\ \\ 1706.45

s

2

Kg.m

=1706.45.23N[/tex]

Hence, we have that the x-component of the normal force is equal to 1706.45 N.

Answer 2

Answer:

zero

Explanation:

fx=


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Answer:

The amplitude of a wave is the height of a wave as measured from the highest point on the wave (peak or crest) to the lowest point on the wave (trough). Wavelength refers to the length of a wave from one peak to the next.

Explanation:

Jay has a small object that is very dense.
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A square loop of wire lies in the plane of the page. A decreasing magnetic field is directed into the page. The induced current in the loop is maximum and clockwise.

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Thus, the induced current in the loop is maximum and clockwise.

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Relative to the movement of the building, a mass damper on the roof of an earthquake resistant building move in the opposite direction.

Thus, the correct option is C.

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A 35-mf capacitor is connected to an ac source with a frequency of 400 hz and a maximum emf of 20 v. The maximum current, in s. I. Units, is:

Answers

The value of maximum current for A 35-mf capacitor which is connected to an ac source with a frequency of 400 hz and a maximum emf of 20 v is 1.76 ampere.

What is capacitance of capacitor?

The capacitance of a capacitor is the ratio of the electric charge stored inside the capacitance to the potential difference.  The value of capacitive reactance can be calculated as,

[tex]X_c=\dfrac{1}{2\pi fC}[/tex]

Here, C is capacity and (f) is the frequency.

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[tex]X_c=\dfrac{1}{2\pi fC}\\X_c=\dfrac{1}{2\pi (35\times10^{-6})(400)}\\\X_c=11.37\rm\; ohm[/tex]

The maximum current flowing is the ratio of maximum emf to the capacitive reactance. Thus, the maximum current is,

[tex]I_{\text{RMS}}=\dfrac{V_{\text{RMS}}}{X_C}\\I_{\text{RMS}}=\dfrac{20}{11.37}\\I_{\text{RMS}}=1.76\rm\; Amp[/tex]

Thus, the value of maximum current for A 35-mf capacitor which is connected to an ac source with a frequency of 400 hz and a maximum emf of 20 v is 1.76 ampere.

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A weight lifter lifts a mass m at constant speed to a height h in time t. How much work is done by the weight lifter?

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The total work is done by the weight lifter who lifts a mass m at constant speed to a height h in time t, is (mgh)/t.

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The amount of energy which is required to lift a object at a height is known as the work done of lifting an object.

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[tex]W=\dfrac{mgh}{t}[/tex]

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[tex]W=\dfrac{mgh}{t}[/tex]

Hence, the total work is done by the weight lifter who lifts a mass m at constant speed to a height h in time t, is (mgh)/t.

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28. use the first equation in section iv for this problem. k = - u_{g} , g=6.67*10^ -11 .m^ 3 kg^-1 s^-2 and m = 3.2 * 10 ^ 23 * kg . find y in terms of r.

Answers

When, the mass and gravitational constant is provided, the  velocity v in terms of r is 6.534 x 10⁶ r^(-1/2) m/s.

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The force of attraction felt by a person which is directed at the center of a planet or Earth is called as the gravity.

The gravitational potential energy is directly proportional to the negative of product of masses of the object and inversely proportional to the distance between them.

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Thus, the value of velocity v in terms of r is 6.534 x 10⁶ r^(-1/2) m/s.

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on the graph below, what is the total distance traveled during the recorded time interval? what is the displacement?

Answers

5m is the total distance

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Displacement is a vector quantity. This indicates that it has both a direction and a magnitude and that it is visually represented as an arrow that points from the starting position to the ending position.

As given in the problem we have to find out the total distance and the displacement of the object from the graph shown in the problem,

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                                                     =6 - 1

                                                     = 5 meters

Thus, The total distance traveled during the recorded time interval would be 5 meters and the displacement of the object would be 5 meters.

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Graph the following data on the graph, then use the graph to determine the half-life of this isotope.
Time (years): 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10.
Mass Remaining (grams): 100, 75, 56, 42, 32, 24, 18, 13, 10, 8, 6.

Answers

Answer:

4, 56

Explanation:

Hope this helped!

Answer:

4, 56

Ex................................................................................

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Digital information can be sent through the vacuum if space, but the information must be converted to wave pulses. The correct option is B.

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Answers

Answer:

15 N

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Answer:

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The average speed of a moving body can be calculated by dividing the distance moved by the time taken.

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bem ²4.23=1.4m/s
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Answers

1.4 x 1/1000 x 60
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Answers

Explanation:

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91 is the missing number because an alpha particle with a charge of 2 was emitted.

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Answers

Answer:

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Two conducting spheres have net charges of +3.0 uC and -9.0 uC and attract each
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Answers

The force between the two charges will be 16,000 N. It is the force exerted by one charge on another charge.

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The electric force between the two charges is directly proportional to the product of the charge and inversely proportional to the square of the distance between them.

The given data in the problem is;

The magnitude of charge of sphere q₁  = +3.0 μC=-3.0×10⁻⁶ C

The magnitude of charge of sphere q₂ =  -9.0 μC=9.0×10⁻⁶ C

k is the proportionality constant = 9 × 10⁹ Nm²

r is the separated distance to be found;

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The electric force is found as;

[tex]\rm F = \frac{K q_1q_2}{r^2} \\\\ \rm 0.20 \times 10^{-3} = \frac{9 \times 10^9 \times 3.0 \times 10^{-6}\times 3.0 \times 10^{-6} }{r^2} \\\\\ R^ 2 =4.04\times 10^{-4} \\\\ R= 0.020 \ m[/tex]

Hence, the force between the two charges will be 16,000 N.

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give an example of how the law of inertia is demonstrated (a) for moving objects and (b) for objects at rest

Answers

Answer:

Both

Explanation:

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How do the amplitudes of a 120 decibel sound and a 100-decibel sound compare?​

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The 120 decibel sound has more amplitude than the 100 decibel sound.

In Physics, the relation between amplitude and intensity is that the intensity of the wave is directly proportional to the square of its amplitude.

When light of wavelength 160 nm falls on a gold surface, electrons having a maximum kinetic energy of 2. 66 ev are emitted. Find values for the following

Answers

When the light of wavelength is falling on gold surface, the electrons begin to exchange energies.

a)The work function in eV is Φ =5.097 eV.

b) The cut-off wavelength is λ₀ = 243.71 nm

c) The frequency is ν₀  =1.231 × 10¹⁵ Hz

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The energy needed for a particle to escape and break through the surface.

The kinetic energy of the light emitted is 2.66 eV and wavelength of the light is 160 nm = 160 × 10⁻⁹ m.

a) The work function of the gold for given maximum kinetic energy is

Φ = hc / λ  - K.Emax

Substituting 6.626 × 10⁻³⁴ J.s for h, 3 × 10⁸ m/s for c and 2.66 eV for K.Emax, work function will be

Φ =8.16 × 10⁻¹⁹ J

1 eV = 1.6 × 10⁻¹⁹

The work function in eV is Φ =5.097 eV.

b) The cutoff wavelength is related to work function as

λ₀ = hc / Φ

Substitute the corresponding values into the equation, we get the cut off wavelength

λ₀ = 243.71 nm

c) The frequency corresponding to the cut-off wavelength is

ν₀ = c / λ₀

Substitute the corresponding values into the equation, we get the frequency,

ν₀  =1.231 × 10¹⁵ Hz

Therefore, the values for the following are

a)The work function in eV is Φ =5.097 eV.

b) The cut-off wavelength is λ₀ = 243.71 nm

c) The frequency is ν₀  =1.231 × 10¹⁵ Hz

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The cluster of galaxies that our own galaxy belongs to is called the.

Answers

Answer:

The Local Group/ Virgo Cluster

Explanation:

Our solar system is part of a galaxy called the Milky Way galaxy. The Milky Way galaxy is part of a small cluster of just over 30 galaxies known as the "Local Group." This cluster resides in a larger cluster of galaxies called the "Virgo Cluster" (sometimes called the Virgo Supercluster). The Virgo cluster contains just about 2000 galaxies.

The amount of energy that would be needed to accelerate a large spaceship to half the speed of light is:.

Answers

At a known mass of the spaceship, the amount of energy that would be needed to accelerate the spaceship to half the speed of light is 1.5 x 10⁸  x m (J).

Energy needed

The amount of energy that would be needed to accelerate a large spaceship to half the speed of light is calculated as folllows;

E = mc²

where;

m is mass of the spaceshipc is speed of light = 3 x 10⁸ m/s

half the speed of light = 1.5 x 10⁸ m/s

E = 1.5 x 10⁸  x m

Thus, at a known mass of the spaceship, the amount of energy that would be needed to accelerate the spaceship to half the speed of light is 1.5 x 10⁸  x m (J).

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The magnitude of the average braking force on the car is most nearly

Answers

Braking force is applied to brakes to stop the car. The average braking force is 2kN.

What is force?

Force is the product of mass of the object and acceleration.

The braking force is the force applied on the brakes to stop the car at a distance.

Suppose, the mass of the car is m=1000kg

The initial velocity of the car is u=10m/s

The time is t=5s

The final velocity of the car is v = 0 m/s

Applying the first equation of motion, to calculate the acceleration,

v=u + at

a=(v−u) / t

a =0−10 / 5

a =−2m/s²

Then, apply Newton's Second Law of Motion to calculate the braking force

F = ma = 1000 x 2= 2000 N or 2kN

Thus, the magnitude of the average braking force on the car is most nearly 2kN.

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I need a detailed explanation on What is nuclear fusion is and what company’s are using it

Answers

Answer: here are some of the places that use nuclear fusion

Commonwealth Fusion Systems (CFS)

TAE Technologies.

General Fusion (Canada)

Helion Energy.

Tokamak Energy (U.K.)

First Light (U.K.)

Explanation: nuclear fusion is a nuclear reaction in which atomic nuclei of low atomic number fuse to form a heavier nucleus with the release of energy.

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Answer:

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Explanation:

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