1. What is the supreme law of the United States?

Answer:

B. It's nucleus releases energy

Explanation:

Answer:

option C : they push apart

Explanation:

If you hold two magnets the wrong way around, they push apart - they repel! In other words, if you hold two magnets together so that like-poles are close together (two norths OR two souths), they repel

Answer:

the magnet push apart

Explanation:

that is the two magnet are facing each other with the same pole...

that is to say like pole push apart and unlike pole attract

Answer:

a

Explanation:

worng worng

Answer:

F = 5.39 x 10¹⁰ N

Explanation:

The electrical force between q₁ and q₂ can be calculated by Coulomb's Law:

[tex]F = \frac{kq_1q_2}{r^2}\\\\[/tex]

where,

F = electrical force = ?

k = Coulomb Constant = 8.99 x 10⁹ Nm²/C²

q₁ = first charge = +6 C = 6 C

q₂ = -4 C = 4 C

r = distance between charges = 2 m

Therefore,

[tex]F = \frac{(8.99\ x\ 10^9\ N.m^2/C^2)(6\ C)(4\ C)}{(2\ m)^2}\\\\[/tex]

F = 5.39 x 10¹⁰ N

Answer:

C on edge

Edge2021

Answer:

2081.65 m

Explanation:

We'll begin by calculating the time taken for the load to get to the target. This can be obtained as follow:

Height (h) = 3000 m

Acceleration due to gravity (g) = 10 m/s²

Time (t) =?

h = ½gt²

3000 = ½ × 10 × t²

3000 = 5 × t²

Divide both side by 5

t² = 3000 / 5

t² = 600

Take the square root of both side

t = √600

t = 24.49 s

Finally, we shall determine the distance from the target at which the load should be released. This can be obtained as follow:

Horizontal velocity (u) = 85 m/s

Time (t) = 24.49 s

Horizontal distance (s) =?

s = ut

s = 85 × 24.49

s = 2081.65 m

Thus, the load should be released from 2081.65 m.

The region of a longitudinal wave that is represented by an arrow is known as rarefaction. Thus, the correct option for this question is A.

A longitudinal wave may be defined as a type of wave where the displacement of the medium is in the same direction as the direction of the traveling wave. The distance between the centers of two consecutive regions of compression or the rarefaction is defined by wavelength, λ.

Longitudinal waves express areas of compression and rarefaction: compressions are regions of high pressure due to particles being close together. Rarefactions are regions of low pressure due to particles being spread further apart.

Therefore, the region of a longitudinal wave that is represented by an arrow is known as rarefaction. Thus, the correct option for this question is A.

To learn more about Longitudinal waves, refer to the link:

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Answer:

what could be rhe answer

Answer:

Also will be doubled

Explanation:

because potential energy is directly proportional to mass which means when mass or height increases the potential energy will also increases

Answer:

5 km

Explanation:

displacement is the straight line distance from a particular point. since north and south are in opposite directions, it means that he has taken a u-turn

thus, 10 - 5 = 5km displacement

Answer:

They rearrange themselves and join together differently to make new substances called products. The number of atoms of each type is the same before and after a reaction. This means that the total mass of the products is the same as the total mass of the starting substances. In other words, mass is conserved.

Answer:

where are the answers

Explanation:

Answer:

4.8 km/hr ;

0

Explanation:

Based on information plotted on the graph :

Distance traveled by swimmer C = 2400 m

Travel time of swimmer C = 30 minutes

Converting distance to km:

2400 m = 2400 / 1000 = 2.4 km

Converting time to hour :

30 minutes = 30 / 60 = 0.5 hour

Average speed = Distance traveled / time taken

Average speed = 2.4 km / 0.5 hour = 4.8 km/hr

2.)

Swimmer A's average speed during the period 10 to 20 minutes ;

Change in distance /change in time

(400 - 400) / (20 - 10) = 0

Hence, distance traveled is 0

ita called hematopoiesis

Answer:

F = 144 units

Explanation:

For this exercise we use coulomb's law, for the initial conditions

           F₀ = [tex]k \frac{q_1q_2}{r_o^2}[/tex]

indicate that the force F₀ = 36.0 units and the distance is reduced to r = r₀/2 which is the new force

          F = [tex]k \frac{ q_1q_2 }{(r_o/2)^2}[/tex]

we substitute

          F = 4 [tex]k \frac{q_1q_2}{r_o^2}[/tex]

          F = 4 F₀

we calculate

          F = 4 36

          F = 144 units

Answer:

answer D. all of the above

Answer:

Distance = 150 meters

Explanation:

Given the following data;

Work done = 6,000 Joules

Force = 40 Newton

To find the total distance covered by the wheelbarrow;

Workdone = force * distance

Substituting into the formula, we have;

6000 = 40 * distance

Distance = 6000/40

Distance = 150 meters

Therefore, the total distance the wheelbarrow was pushed is 150 meters.

Answer:

More heat is required for the change of state.

Explanation:

Applied heat works at critical temperatures because at this point more heat is needed by the substance in order to change the state of substance. At critical temperatures, the substance can't melt if no more heat energy is given to the substance. A refrigerator works to cool down warm objects by absorbing heat from the inside portion of the fridge and provides cool air which cools the inner side of the fridge. The point at which a solid changes into a liquid state is called melting point while on the other hand, the point at which a liquid changes into a gaseous state is known as boiling point of a substance.

Answer:

OPTION D (The waves will sometimes get very high and very low) is the answer.

Explanation:

Wavelength = velocity ÷ frequency

As the frequency which measures the number of waves per unit of time is inversely proportional to the wavelength, point X which lies between two sources, and one source is shorter than another, the wave heights at point x will vary as the distances from point X vary too. This means that waves at point X depending on the wave type and source will get very high at times and very low.

Answer:

The length traveled by an object moving in any direction or even changing direction is called distance. The location of an object in a frame of reference is called position. For straight line motion, positions can be shown using a number line. The separation between original and final position is called displacement

Explanation:

good luck

The equation of GPE is mgH, where m is mass, g is gravitational acceleration, and H is the height.

If we're solving for the change in GPE, then:

∆[tex]U_{g}[/tex] = mg∆H

Input our given values for m and g:

∆[tex]U_{g}[/tex] = 0.25 * 9.80 * ∆H

The book falls from 2 meters high to 0.5 meters high, so:

∆[tex]U_{g}[/tex] = 0.25 * 9.80 * (2.0 - 0.5)

∆[tex]U_{g}[/tex] = 0.25 * 9.80 * 1.5

∆[tex]U_{g}[/tex] = 3.675 (J)

Adjust for significant figures:

∆[tex]U_{g}[/tex] = 3.7 (J)

The change in gravitational potential energy was 3.7 (J)

If you have any questions on anything I did to get to the answer, just ask!

- breezyツ

Answer:

When the rock has fallen 12.0 m;

The kinetic energy of the rock is approximately 3,531.6 J

The potential energy of the rock is approximately 6,768.9 J

Explanation:

The question relates to the characteristic constant total mechanical energy of a body

The mass of the rock that falls, m = 30.0 kg

The height of the cliff from which the rock falls, h₁ = 35.0 m

The required information = The kinetic and potential energy when the rock has falling 12.0 m

The kinetic energy is given by the formula, K.E. = 1/2×m×v²

The potential energy is given by the formula, P.E. = m·g·h

Where;

g = The acceleration due to gravity ≈ 9.81 m/s²

The velocity of the rock after falling through a given height, h is given by the formula, v² = 2·g·Δh

The total mechanical energy of the rock, M.E. = K.E. + P.E. = Constant

At the height of the cliff before falling, Δh =0, therefore v₁ = 0, therefore, K.E. = 1/2×m×v₁² = 0 J

The potential energy at the cliff before the rock begins to fall, P.E. is goven as follows;

P.E. = 30.0 kg × 35.0 m × 9.81 m/s² = 10,300.5 J

At the top of the cliff, M.E. = K.E. + P.E. = 0 J+ 10,300.5 J = 10,300.5 J

∴ M.E. = 10,300.5 J

When the rock has fallen, 12.0 m, Δh = 12.0 m, the speed of the rock, v₂, is given as follows;

v₂² = 2 × 9.81 m/s² × 12.0 m = 235.44 m²/s²

v₂ = √(235.44 m²/s²) ≈ 15.344 m/s

∴ When the rock has fallen 12.0 m, K.E., is given as follows;

K.E. = 1/2×m×v₂²

K.E. = 1/2 × 30.0 kg × 235.44 m²/s² = 3,531.6 J

When the rock has fallen 12.0 m the kinetic energy, K.E. = 3,531.6 J

When the rock has fallen 12.0 m, M.E. = P.E. + K.E.

M.E. = Constant = 10,300.5 J

K.E. = 3,531.6 J

∴ 10,300.5 J = P.E. + 3,531.6 J

P.E. = 10,300.5 J - 3,531.6 J = 6,768.9 J

∴ When the rock has fallen 12.0 m, the potential energy, P.E. = 6,768.9 J.

Answer:

A) The time taken by the coin to reach the ground will be 0.4 seconds

B) Range of the motion of the coin will be 2m

Explanation:

This is a case of horizontal projectile motion as there's no initial vertical velocity given to the coin and has only horizontal velocity initially.

According to the equations of Horizontal projectile

Given :

Vertical distance to be traveled  ([tex]Sy[/tex])= 0.8m

Initial horizontal velocity ([tex]Vx[/tex])= 5m/s

For calculations, we will take acceleration due to gravity ([tex]g[/tex]) to be [tex]10 m/s^2[/tex]

A) Putting values in equation [tex]Sy=\frac{1}{2} *g*t^2[/tex]

   ⇒ [tex]0.8=\frac{1}{2} *10*t^2[/tex]

   ⇒[tex]\frac{1.6}{10} =t^2[/tex]

   ⇒ [tex]\sqrt{0.16} =t[/tex]

    ⇒  [tex]0.4=t[/tex]

Therefore, time taken by the coin to reach the ground is 0.4 seconds

B) Now using t= 0.4s putting values in equation [tex]Sx= Vx*t[/tex]

⇒[tex]Sx=5*0.4[/tex]

⇒[tex]Sx=2[/tex]

Hence , Range of the coin is 2m

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Answer:

A = L^3 T^-3  ,  B = L^3 T

Explanation:

Given: volume ( V )  = At^3 + B/t  ------ ( 1 )

dimension of volume = L^3

and the Dimension of time = T

back to equation ( 1 )

L^3 = A * T^3   ------- ( 2 )

also L^3 = B/T ------- ( 3 )

from equation ( 2 )

A = L^3 T^-3

from equation ( 3 )

B = L^3 T

The dimensions of the constants A and B

A = L^3 T^-3  ,  B = L^3 T

Answer:

Ben os ok. the moment of the bus and the worm are conserved

Explanation:

System formed by the bus and the worm, therefore the forces during the collision are internal and therefore the moment is conserved

initial instant. Airs of shock

        p₀ = My v₀

final instant. After the shock

        p_f = (M + m) v

the moment is preserved

        p₀ = p_f

        M v₀o = (M + m) v

       v = [tex]\frac{ M}{ M+m}[/tex]  v₀

       v = [tex]\frac{1}{1 +\frac{m}{M} }[/tex]  v₀

Let's analyze these equations the moment of the bus and the worm are conserved, therefore Ben is the one who is right. Let us propose the solution of the problem.

The person that I agree with based on their stance about the physics of the situation is; Ben Travlun

I will agree with Ben Travlun. The reason is that;

From the question, we see that the bug and the bus experience the same force, the same impulse, and the same momentum change.

Now, the concept of sameness above is not portrayed by Miles' statement because miles claims that the momentum change of the bug is much greater than the bus.

Now, though the bug has less mass and therefore more acceleration, the occupants of the very big bus will not feel the unusually small acceleration.

Finally, the bug is composed of a less strong material and as a result it will be scattered all over the windshield. However, this high level of the bug being scattered and the greater acceleration it possesses does not translate to greater force, impulse, or momentum change.

Read more about conservation of momentum at; https://brainly.com/question/7538238

Answer:

Following are the responses to the given question:

Explanation:

Please find the attached table.

[tex]\to t= 10\ /sec\\\\ \to v = 15\ m /sec\\\\ \to a= ?\\\\\to a=\frac{v}{t}\\\\[/tex]

       [tex]=\frac{15}{10}\\\\=1.5[/tex]

Answer:

No.

Explicación:

No, una corriente eléctrica sin resistencia no puede fluir constantemente sin ninguna fuente de energía porque la fuente de energía proporciona electrones para el flujo continuo de corriente en el circuito. Si fluye corriente por el cable, debe haber resistencia en el circuito. La fuente de energía proporciona corriente eléctrica continua al cable para que fluya y el cable tiene resistencia, por lo que parte de la corriente eléctrica se pierde durante su flujo debido a esta resistencia. Entonces podemos decir que la fuente de energía es necesaria para el flujo constante de corriente eléctrica.

Answer:

The distance from sphere A to sphere C on the right such that the original small sphere remains at rest is a/2

Explanation:

The force of a charge at a point is given as follows;

From an online source, we have;

E₁ + E₂ = 0

The electric field due to the sphere B of charge +8q = E₁

[tex]E_1 = \dfrac{k \cdot (8 \cdot Q)}{a^2}[/tex]

The position of the sphere B = A distance 'a' to the left of 'A'

The electric field due to the sphere C of charge +2q = E₂

The position of the sphere C = A distance to the right of 'A'

Therefore, for the electric field strength of sphere 'B' at 'A', we have;

[tex]E_1 = \dfrac{k \cdot (8 \cdot Q)}{a^2} = 4 \times \dfrac{k \cdot (2 \cdot Q)}{a^2}[/tex]

Let 'x' be the distance of the +2q charge to the right of 'A', we have;

[tex]E_2 = \dfrac{k \cdot (2 \cdot Q)}{x^2}[/tex]

Therefore, for the force of the +2q charge to balance the +8q charge at C, we have;

[tex]\dfrac{k \cdot (2 \cdot Q)}{x^2} = \dfrac{k \cdot (8 \cdot Q)}{a^2} = 4 \times \dfrac{k \cdot (2 \cdot Q)}{a^2}[/tex]

[tex]\therefore \ \dfrac{1}{x^2} = \dfrac{4}{a^2}[/tex]

[tex]\therefore \ \sqrt{ \dfrac{1}{x^2} }= \sqrt{\dfrac{4}{a^2}}[/tex]

[tex]\dfrac{1}{x} = \dfrac{2}{a}[/tex]

[tex]x= \dfrac{a}{2}[/tex]

Therefore, the distance, 'x', from sphere A to sphere C on the right such that the original small sphere remains at rest is x = a/2.

Answer:

humoidity

Explanation: