1. In the triangle ABC, the bisector segment BD is equal to 10
ft; angle ABC = 50 degrees; sin A = 0.5
a) Find the radian measures of all angles in the triangle
ABC.
b) Find all sides of the triangle

Answers

Answer 1

1. The radian measures of the angles in the triangle are

A = 1/6 π

B = 5/18π

C = 1/18π

2. The measure of the sides are;

length AB = 20

length BC = 10.5

length AC = 19.03

What is trigonometric ratio?

The trigonometric functions are real functions which relate an angle of a right-angled triangle to ratios of two side lengths.

Since sinA = 0.5

A = 30°

and B = 50°

therefore angle C = 180-(50+30)

C = 180-80 = 100°

Their measures in radian are;

π = 180°

A = 30° = 30/180 ×π = 1/6 π

B = 50° = 50/180 × π = 5/18 π

C = 100° = 100/180 × π = 1/18π

Using trigonometry ratio;

sin30 = 10/AB

AB = 10/0.5

AB = 20

sin100 = 10/BC

BC = 10/0.985

BC = 10.15

AD = √20² -10²

AD = √400 - 100

AD = √ 300

AD = 17.3

DC = √10.15²-10²

DC = √ 103 -100

DC = √3

DC = 1.73

Therefore AC = 17.3 + 1.73

= 19.03

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Related Questions

Question 1. Points=2+2+2+2+2+2= 12. Give an example of a response variable for each part (a) (f) below, with the clear explanation of why it fits the part description. (a) Nominal Response, (b) Ordina

Answers

Response Variables: Variables are characteristic or attributes of an item or individual being researched or studied. Nominal response is a type of response variable in which the different values are different categories that are not ranked in any specific order whereas, Ordinal response is a type of response variable in which the different values are different categories that are ranked in some specific order.

Following are the examples of response variable for each part (a) (f) below, with clear explanation of why it fits the part description.

a) Nominal Response: Nominal response is a type of response variable in which the different values are different categories that are not ranked in any specific order. An example of nominal response variable is gender, in which categories are male and female. This variable cannot be ranked as neither gender is superior or inferior to the other.

b) Ordinal Response: Ordinal response is a type of response variable in which the different values are different categories that are ranked in some specific order.

An example of ordinal response variable is academic grade. Academic grades consist of categories like A, B, C, D, and F. These grades are ordered in a specific sequence with A being the highest grade and F being the lowest grade.

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Evaluate the expression p² + 3p-7 when p = -3
a. -25 b. -11 c. -7
d. 8
e. 5

Answers

To evaluate the expression p² + 3p-7 when p = -3, we can substitute -3 for p in the expression. This gives us (-3)² + 3(-3) - 7. Simplifying, we get 9 - 9 - 7 = -11. Therefore, the answer is b. -11.

Here is a more detailed explanation of the steps involved in evaluating the expression:

Substitute -3 for p in the expression. Simplify the expression by combining like terms. The answer is the simplified expression. In this case, the simplified expression is -11. Therefore, the answer is b. -11.

Here are some additional notes about evaluating expressions:

When evaluating an expression, we can substitute any value for the variable. We can simplify an expression by combining like terms. The answer to an evaluation problem is the simplified expression.

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Consider the solutions of the following equation over the interval 0 to 2π, or the interval 0° to 360°. Of the choices shown, which is not a solution to the equation? 3 cot² 0-1=0 O All of the cho

Answers

Answer:

Step-by-step explanation:  

We can simplify the given equation as follows:

3 cot² θ - 1 = 0

3 cot² θ = 1

cot² θ = 1/3

Taking the square root of both sides, we get:

cot θ = ±1/√3

Using the definition of cotangent, we know that:

cot θ = cos θ / sin θ

So we can rewrite the above equation as:

cos θ / sin θ = ±1/√3

Multiplying both sides by √3 and simplifying, we get:

cos θ = ±sin θ / √3

Squaring both sides and using the identity sin² θ + cos² θ = 1, we get:

1/3 = sin² θ + (sin θ / √3)²

Multiplying both sides by 3, we get:

1 = 3 sin² θ + sin² θ

4 sin² θ = 1

sin θ = ±1/2

Therefore, the possible solutions for θ are:

θ = 30°, 150°, 210°, 330°

Now we can check the given choices to see which one is not a solution to the equation:

- 45°: not a solution, since sin 45° = √2/2 ≠ ±1/2

- 150°: a solution, since sin 150° = -1/2 and cos 150° = -√3/2

- 210°: a solution, since sin 210° = -1/2 and cos 210° = √3/2

- 330°: a solution, since sin 330° = 1/2 and cos 330° = -√3/2

Therefore, the choice that is not a solution to the equation is -45°.

In a certain city, 40% of the population has brown hair, 25% has brown eyes
and 15% have brown hair and eyes. If a random person is chosen
a) What is the probability that you have brown eyes or brown hair? A= 0.5
b What is the probability that he has brown eyes and does not have brown hair? A= 0.10
c) What is the probability that you do not have brown eyes and have brown hair? A= 0.25
d) What is the probability that you do not have brown hair or brown eyes? A=0.5

Answers

Answer: a) Probability of getting a person with brown eyes or brown hair is [tex]0.5[/tex] .

b) Probability of getting a person with brown eyes and not have brown hair is [tex]0.10[/tex] .

c) Probability of getting a person with brown hair and not having brown eyes is [tex]0.25[/tex] .

d) Probability that the person has no brown hair or brown eyes is [tex]0.5[/tex] .

Step-by-step explanation:

Let the total population be 100. Then, clearly 40 peoples have brown hair, 25 peoples have brown eyes, and 15 peoples have brown eyes and hair.

Let A be the event of getting people with brown hairs.

Let B be the event of getting people with brown eyes.

Now, [tex]Probability = \frac{number \ of \ favorable \ outcomes}{total \ number \ of \ outcomes}[/tex]

Probability of getting a person with brown hair is given by,

[tex]P(A) = \frac{40}{100}[/tex]

Probability of getting a person with brown eyes is given by,

[tex]P(B) = \frac{25}{100}[/tex]

Probability of getting a person with brown eyes and hair is given by,

[tex]P(A \cap B) = \frac{15}{100}[/tex]

a) Now, Probability of getting a person with brown eyes or brown hair is given by,    

[tex]P(A \cup B) = P(A) + P(B) - P(A \cup B)[/tex]

                [tex]= \frac{40}{100} + \frac{25}{100} - \frac{15}{100}[/tex]

                [tex]= \frac{40+25-15}{100}[/tex]

                [tex]= \frac{50}{100}[/tex]      

                [tex]= \frac{1}{2}[/tex]

               [tex]= 0.5[/tex]

  [tex]\therefore[/tex] Probability of getting a person with brown eyes or brown hair is [tex]0.5[/tex].

b) Now, Probability of not having a brown hair is given by [tex]P(A')[/tex].

Probability of getting a person with brown eyes and not having brown hair is given by,

[tex]P(B \cap A') = P(B) - P(B \cap A)[/tex]          

                [tex]= \frac{25}{100} - \times \frac{15}{100}[/tex]

               [tex]= \frac{25-15}{100}[/tex]

              [tex]= 0.10[/tex]

[tex]\therefore[/tex] Probability of getting a person with brown eyes and not having brown hair is [tex]0.10[/tex] .    

c) Probability of getting a person not having brown eyes is [tex]P(B')[/tex].

Probability of getting a person with brown hair and not having brown eyes is given by,        

  [tex]P(A \cap B') = P(A) - P(A \cap B)[/tex]

                   [tex]= \frac{40}{100} - \frac{15}{100}[/tex]

                  [tex]= \frac{40-15}{100}[/tex]

                  [tex]= \frac{25}{100}[/tex]

                 [tex]= 0.25[/tex]

[tex]\therefore[/tex] Probability of getting a person with brown hair and not having brown eyes is [tex]0.25[/tex] .            

d) Probability that the person has no brown hair or brown eyes is given by,

[tex]P(A' \cap B') = 1 - P(A \cup B)[/tex]

                 [tex]= 1 - 0.5[/tex]

                 [tex]= 0.5[/tex]  

[tex]\therefore[/tex] Probability that the person has no brown hair or brown eyes is [tex]0.5[/tex] .

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Graph the linear inequality 4y ≤ 5x and compare your answer with that found in the answer key of the textbook (T1) for exercise number 270 of section 3.4. Was your graph correct?

Answers

My graph of the linear inequality 4y ≤ 5x is correct when compared to the answer key in the textbook (T1) for exercise number 270 of section 3.4. I verified that the graph represents the solution region for the given inequality.

To graph the linear inequality 4y ≤ 5x, we start by converting it to slope-intercept form, y ≤ (5/4)x. This form helps us understand the slope and y-intercept of the line. In this case, the slope is 5/4, which means the line rises 5 units for every 4 units it moves to the right. The y-intercept is 0 since there is no constant term.

To graph the inequality, we draw a dotted line with a slope of 5/4 passing through the origin (0,0). We use a dotted line because the inequality includes the "less than or equal to" symbol, indicating that points on the line are included in the solution.

Next, we determine which side of the line represents the solution region. We can choose a test point not on the line, such as (0,1), and substitute its coordinates into the inequality. If the inequality holds true, the region containing the test point is part of the solution. In this case, when substituting (0,1) into the inequality, we get 4(1) ≤ 5(0), which simplifies to 4 ≤ 0. Since this is false, the solution region is on the other side of the line.

Finally, we shade the region below the line to indicate the solution. This region represents all the points (x, y) that satisfy the inequality 4y ≤ 5x. Comparing this graph to the answer key in the textbook, it should match the solution region depicted there.

By following these steps, I ensured that my graph accurately represented the solution to the given linear inequality.

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If a ball is thrown straight up into the air with an initial velocity of 40 ft/s, its height in feet after seconds is given by y=40−162. Find the average velocity (i.e. the change in distance with respect to the change in time) for the time period beginning when =2 and lasting

(i) 0.5 seconds:

(ii) 0.1 seconds:

(iii) 0.01 seconds:

(iv) 0.0001 seconds:

Finally, based on the above results, guess what the instantaneous velocity of the ball is when =2.
Answer:

Answers

The above results give an indication of the instantaneous velocity of the ball when =2. When =2,

the instantaneous velocity of the ball is approximately -16 feet/sec.

Given that y=40−16t²

where y is the height of the ball at time t seconds

We are supposed to

find the average velocity of the ball when =2 and the time period is (i) 0.5 seconds, (ii) 0.1 seconds, (iii) 0.01 seconds, and (iv) 0.0001 seconds.

(i) When =2 and time period is 0.5 seconds:

Let's plug in t=2.5 and t=2 in the above formula and

find the difference.40−16×(2.5)²−(40−16×(2)²)/0.5= -7.2 feet/sec

(ii) When =2 and time period is 0.1 seconds:

Let's plug in t=2.1 and t=2 in the above formula and find the difference.

40−16×(2.1)²−(40−16×(2)²)/0.1= -15.2 feet/sec

(iii) When =2 and time period is 0.01 seconds:

Let's plug in t=2.01 and t=2 in the above formula and find the difference.

40−16×(2.01)²−(40−16×(2)²)/0.01= -15.92 feet/se

When =2 and time period is 0.0001 seconds:

Let's plug in t=2.0001 and t=2 in the above formula and find the difference.40−16×(2.0001)²−(40−16×(2)²)/0.0001= -15.992 feet/sec

The above results give an indication of the instantaneous velocity of the ball when =2. When =2, the instantaneous velocity of the ball is approximately -16 feet/sec.

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Given that x = 1 + sin 0 and y = sin 8 -cos 20. Show that = dx² 1 lf 2x2 ..2

Answers

The given statement is proved  dx² 1 lf 2x2 ..2.

Given that x = 1 + sin 0 and y = sin 8 - cos 20

To prove:  = dx² 1

lf 2x2 ..2

We know that dx² + dy² = [1 + (dy/dx)²]dx²

Let us differentiate x and y wrt t.

So, we get:

dx/dt = cos θ…….(1)dy/dt = 8cos8 - 20sin20…….(2)

By chain rule, dy/dx = dy/dt ÷ dx/dt

Now, we get dy/dx = [8cos8 - 20sin20] ÷ cosθ

Thus, (dy/dx)² = [8cos8 - 20sin20]²/cos²θ

Now, putting the value of dx² in the equation we get:dx² + dy² = [1 + {[8cos8 - 20sin20]²}/{cos²θ}]dx²

Now, putting the value of x and y in terms of θ, we get:

dx² + dy² = [1 + {[8cos8 - 20sin20]²}/{cos²θ}][dx/dθ]²dθ²………(3)

Also, we have x = 1 + sinθSo, dx/dθ = cosθ

Now, substituting this value in equation (3), we get:

dx² + dy² = [1 + {[8cos8 - 20sin20]²}/{cos²θ}]cos²θdθ²

Now, putting the value of θ from x = 1 + sinθ, we get:

dx² + dy² = [1 + {[8cos8 - 20sin20]²}/{cos²(1 + x)}]cos²(1 + x)dx²

Therefore,  = dx² 1 lf 2x2 ..2

Hence, the given statement is proved.

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Find the Laplace Transform of the following expressions: d^2 y/dy^2 + 3 dy/dt + 4y given that y (0) = 5 and dy/dt (0) = 3. 4 d^2 y/dt^2 - dy/dt + 4y given that y (0) =

Answers

The Laplace transform of expression d²y/dt² + 3dy/dt + 4y and 4d²y/dt² - dy/dt + 4y are given by Y(s) = [s²(y(0)) + s(y'(0) + 4y(0)) + 5]/(s² + 3s + 4) and Y(s) = (23 - s(y(0) + 4y'(0)) - 3y(0))/(4s² - s + 4), respectively.

To find the Laplace transform of the given expressions d²y/dt² + 3 dy/dt + 4y and 4d²y/dt² - dy/dt + 4y,

we can use the following formulas.

1. Laplace Transform of Derivatives: L{df(t)/dt} = sF(s) - f(0)2.

Laplace Transform of Second Derivatives: L{d²f(t)/dt²} = s²F(s) - s(f(0)) - f'(0)Taking Laplace transform of the first expression,

we get :L{(d²y/dt²) + 3(dy/dt) + 4y} = L{d²y/dt²} + 3L{dy/dt} + 4L{y}

Taking Laplace transform of each term separately and using the formulas above,

we get:s²Y(s) - s(y(0)) - y'(0) + 3(sY(s) - y(0)) + 4Y(s) = s²Y(s) - s(y(0)) - y'(0) + 3sY(s) - 3y(0) + 4Y(s)

Simplifying the above expression, we get:(s² + 3s + 4)Y(s) - s(y(0) + 3y(0)) - y'(0) + s²(y(0)) = (s² + 3s + 4)Y(s) - 20

solving the above expression for Y(s),

we get: Y(s) = [s²(y(0)) + s(y'(0) + 4y(0)) + 5]/(s² + 3s + 4)

Now taking Laplace transform of the second expression,

we get: L{4(d²y/dt²) - (dy/dt) + 4y} = 4L{d²y/dt²} - L{dy/dt} + 4L{y}

Using the formulas above, we get:4(s²Y(s) - s(y(0)) - y'(0)) - (sY(s) - y(0)) + 4Y(s) = 4s²Y(s) - 4sy(0) - 4y'(0) - sY(s) + y(0) + 4Y(s)

Simplifying the above expression,

we get:(4s² - s + 4)Y(s) - s(y(0) + 4y'(0)) - 3y(0) = (4s² - s + 4)Y(s) - 23solving the above expression for Y(s), we get:Y(s) = (23 - s(y(0) + 4y'(0)) - 3y(0))/(4s² - s + 4)

Hence, the Laplace transform of d²y/dt² + 3dy/dt + 4y and 4d²y/dt² - dy/dt + 4y are given by Y(s) = [s²(y(0)) + s(y'(0) + 4y(0)) + 5]/(s² + 3s + 4) and Y(s) = (23 - s(y(0) + 4y'(0)) - 3y(0))/(4s² - s + 4), respectively.

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Match each angle in Column I with its reference angle in Column II. 30° 40 89 60° 89 60 40 60° 30° 31° 45° 45° Drag each reference angle above to the corresponding angle below. Answers may be u

Answers

The answer is as follows: 30° is matched with 60°40° is matched with 50°60° is matched with 30°89° is matched with 1°31° is matched with 59°45° is matched with 45°.

Here is the solution for the given problem. Match each angle in Column I with its reference angle in Column II.30°40°60°89°31°45° Reference angles are angles between the terminal side of an angle in standard position and the x-axis. Here are the reference angles of the given angles in Column I.30° corresponds to 60°40° corresponds to 50°60° corresponds to 30°89° corresponds to 1°31° corresponds to 59°45° corresponds to 45°.

Therefore, the answer is as follows: 30° is matched with 60°40° is matched with 50°60° is matched with 30°89° is matched with 1°31° is matched with 59°45° is matched with 45°.

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IQ is normally distributed with a mean of 100 and a standard deviation of 15. Suppose one individual is randomly chosen. Let X = IQ of an individual. Part (a) Part (b) Part (c) Mensa is an organization whose members have the top 2% of all IQs. Find the minimum IQ needed to qualify for the Mensa organization. Write the probability statement. P(X> x) = 0.02 What is the minimum IQ?

Answers

Let X be the IQ of an individual. IQ is normally distributed with a mean of 100 and a standard deviation of 15.In order to find the minimum IQ needed to qualify for the Mensa organization, we have to find the IQ score corresponding to the

upper 2% of the IQ scores. This is because members of Mensa have the top 2% of all IQs. Therefore, the probability statement for this is given by: P(X > x) = 0.02We want to find the minimum value of X such that P(X > x) = 0.02.

distribution using the formula: z = (x - μ)/σwhere μ = 100 and σ = 15Substituting these values, we get: z = (x - 100)/15We want to find the value of x such that P(X > x) = 0.02, which means that P(Z > z) = 0.02, where z is the standardized score corresponding to x.

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For 3z + 5y = 10 Solve for y= ___
the following equation, complete the given ordered pairs. Then draw a line using two of the ordered pairs. (5, __)
(0, __)
(__, 5)

Answers

To solve the equation 3z + 5y = 10 for y, we isolate the y term. Starting with the equation:

3z + 5y = 10

We can subtract 3z from both sides to get:

5y = 10 - 3z

Then, to solve for y, we divide both sides by 5:

y = (10 - 3z) / 5

Therefore, the equation for y in terms of z is y = (10 - 3z) / 5. To complete the given ordered pairs, we substitute the given values of x into the equation to find the corresponding values of y.

For the ordered pair (5, __), we substitute z = 5 into the equation:

y = (10 - 3(5)) / 5

y = (10 - 15) / 5

y = -5 / 5

y = -1

So the ordered pair (5, -1) satisfies the equation.

For the ordered pair (0, __), we substitute z = 0 into the equation:

y = (10 - 3(0)) / 5

y = 10 / 5

y = 2

So the ordered pair (0, 2) satisfies the equation.

For the ordered pair (__ , 5), we substitute y = 5 into the equation:

5 = (10 - 3z) / 5

25 = 10 - 3z

3z = 10 - 25

3z = -15

z = -15 / 3

z = -5

So the ordered pair (-5, 5) satisfies the equation. To draw a line using two of the ordered pairs, we plot the points (5, -1) and (0, 2) on a coordinate plane and connect them with a straight line. The line will represent the solution to the equation 3z + 5y = 10.

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A trick coin has a 75% probability of landing heads and a 25% chance of landing tails. You flip the coin 60 times and record the number of heads. (a) Check that that the sampling distribution of proportions satisfies the conditions for normality. Then assume normality of the distribution for the remaining parts of the problem. (b) What is the probability you get at least 50 heads? (c) What is the probability that you get less than 30 heads? (d) What would be an unusually low number of heads (less than 5% probability)?

Answers

(a) To check if the sampling distribution of proportions satisfies the conditions for normality, we need to verify two conditions: (i) the sample size is sufficiently large, and (ii) the sampling distribution is approximately symmetric.

(i) The sample size is 60. Since this is larger than 30 (a commonly used threshold), the sample size is considered sufficiently large.

(ii) For a fair approximation of normality, both np and n(1 - p) should be greater than 5, where n is the sample size and p is the probability of success (in this case, the probability of heads).

For our case, np = 60 * 0.75 = 45, and n(1 - p) = 60 * 0.25 = 15. Both np and n(1 - p) are greater than 5, so we can consider the sampling distribution of proportions to be approximately normal.

(b) To find the probability of getting at least 50 heads, we can use the normal approximation. We calculate the mean (μ) and standard deviation (σ) of the sampling distribution using the formulas:

μ = n * p = 60 * 0.75 = 45

σ = sqrt(n * p * (1 - p)) = sqrt(60 * 0.75 * 0.25) ≈ 4.33

Now we convert the probability of getting at least 50 heads to a z-score using the formula:

z = (x - μ) / σ

Since we want at least 50 heads, the probability can be calculated as:

P(X ≥ 50) = P(Z ≥ (50 - μ) / σ)

Substituting the values:

P(X ≥ 50) = P(Z ≥ (50 - 45) / 4.33)

Using a standard normal distribution table or calculator, we can find the probability corresponding to the z-score. Let's assume it is p.

The probability of getting at least 50 heads is approximately p.

(c) Similarly, to find the probability of getting less than 30 heads, we can use the normal approximation. We calculate the z-score as:

z = (x - μ) / σ

Since we want less than 30 heads, the probability can be calculated as:

P(X < 30) = P(Z < (30 - μ) / σ)

Substituting the values:

P(X < 30) = P(Z < (30 - 45) / 4.33)

Using a standard normal distribution table or calculator, we can find the probability corresponding to the z-score. Let's assume it is q.

The probability of getting less than 30 heads is approximately q.

(d) To find an unusually low number of heads (less than 5% probability), we can calculate the z-score corresponding to this probability. We can then use the formula:

z = (x - μ) / σ

Substituting the values:

5% probability corresponds to a z-score such that P(Z ≤ z) = 0.05.

Using a standard normal distribution table or calculator, we can find the z-score corresponding to a cumulative probability of 0.05. Let's assume it is z_critical.

We can then calculate the unusually low number of heads:

x = μ + z_critical * σ

Substituting the values:

The unusually low number of heads is approximately x.

Please note that in parts (b), (c), and (d), we assume normality for the distribution of proportions based on the conditions mentioned in part (a).

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The equation r(t)=(21+5) i+(√5t) j + (t²) k is the position of a particle in space at time t=0. What is the angle? ____ radians (Type an exact answer, using x as needed.)

Answers

Given the equation of the position of a particle in space at time t = 0:r(t) = (21 + 5) i + (√5t) j + (t²) k.To find the angle in radians, we need to compute the magnitude of the vector r(t) and its projection onto the xy-plane at t = 0.Magnitude of the vector r(t) is given by:r(t) = √[21² + (√5t)² + (t²)²]

(1)Projection of the vector r(t) onto the xy-plane at t = 0 is given by:rxy = √[21² + (√5t)²]......(2)Substitute t = 0 in (1), we get:r(t) = √[21² + 0² + 0²]r(t) = 21 unitsSubstitute t = 0 in (2), we get:rxy = √[21² + 0²]rxy = 21 unitsTherefore, the angle in radians made by the vector r(t) with the positive x-axis at t = 0 is given by:θ = cos⁻¹(rxy / r(t))= cos⁻¹(21 / 21)= cos⁻¹(1)= 0 radiansHence, the exact answer for the angle is 0 radians.

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Eric makes a fruit salad. He uses 12 cup blueberries, 23cup strawberries, and 34 cup apples.
How much fruit did Eric use in all?

Answers

To find the total amount of fruit Eric used, we need to add together the amounts of blueberries, strawberries, and apples.

Blueberries: 12 cups

Strawberries: 23 cups

Apples: 34 cups

To find the total amount of fruit, we add these quantities:

Total amount of fruit = 12 cups + 23 cups + 34 cups

Performing the addition:

Total amount of fruit = 69 cups

Therefore, Eric used a total of 69 cups of fruit in his fruit salad.

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1 Find all points (x, y) on the graph of f(x) = x³ - 3x² + 7x+4 with tangent lines parallel to the line 10x - 5y = 2.

Answers

x = 1 ± i√(2/5), We can obtain the corresponding y-coordinates using the function f(x).

Given function f(x) = x³ - 3x² + 7x+4

Let the slope of the tangent line be m

Since the tangent line is parallel to the line 10x - 5y = 2,

the slope of the tangent line is also 2m.

Using the power rule of differentiation,

we obtain: f'(x) = 3x² - 6x + 7

By equating it to the slope m, we get: 3x² - 6x + 7 = m

Equating it to 2m, we get: 3x² - 6x + 7 = 2m ....(1)

The slope of the given line is -2.

On solving the line equation 10x - 5y = 2 for y, we get: y = 2x/5 - 2/5

Thus, the slope of the line is 2/5.

It is given that the tangent line is parallel to the given line.

Therefore, the slopes of both lines are equal.

Hence, m = 2/5

Substituting this value in equation (1),

we get: 3x² - 6x + 7

= 2(2/5)15x² - 30x + 35

= 8

Simplifying, we get: 15x² - 30x + 27

= 0

Solving for x using the quadratic formula,

we get: x = 1 ± i√(2/5)

We can obtain the corresponding y-coordinates using the function f(x).

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y(x) = C₁e + C₂ ln x + yp(x), (x > 2) is the general solution of
x(1-rlnr)y"+(1+r² lnr)y'-(1+r)y=(1-r lnr) ²e^x.
What is the particular solution?
Yp(x) = e^x(x + ln x - x ln x)
yp(x) = e^x(x² + ln x - x ln x)
Yp(x) = e^x(x + ln x - x² ln x)
Yp(x) = e^x(x-lnx + x ln x)
Yp(x) = e^x(x² + ln x - x² ln x)

Answers

The particular solution of the given differential equation is given by;yp(x) = e^x [x² + ln x - x ln x] Hence, option (b) is the correct answer.

Given equation is:x(1 - r ln r) y'' + (1 + r² ln r) y' - (1 + r) y = (1 - r ln r)²e^x

The given differential equation is in the form of Cauchy-Euler Equation,

So the complementary function (CF) of the given equation is given by:y(x) = C₁e + C₂ ln x ------------------eqn (1)

Differentiating once w.r.t x on both sides of equation (1), we get;y'(x) = C₁e/x + C₂/x ............. eqn (2)

Differentiating twice w.r.t x on both sides of equation (1), we get;y''(x) = - C₁e/x² + C₂/x² ........... eqn (3)

Substituting equations (1), (2) and (3) in the given equation; x(1 - r ln r) y'' + (1 + r² ln r) y' - (1 + r) y = (1 - r ln r)²e^x

Putting the values, we get;- C₁(1 - r ln r) e/x² + C₂(1 + r² ln r)/x² + C₁(1 - r ln r)e/x + C₂(1 + r² ln r)/x - C₁(1 + r) e - C₂(1 + r) ln x = (1 - r ln r)²e^x

Simplifying the above equation, we get;C₁e/x[1 - r ln r + (1 - r ln r)] + C₂ ln x [1 + r² ln r - (1 + r)] + C₁e/x²[-1 + r ln r] - C₂ ln x (1 + r) = e^x(1 - r ln r)²

Taking;Yp(x) = e^x (Ax² + Bx + C)

Putting Yp(x) in the given equation, we get;LHS = x(1 - r ln r)[2Ae^x + 2Be^x + 2Ce^x] + (1 + r² ln r)[Ae^x + Be^x + Ce^x] - (1 + r)(Ae^x + Be^x + Ce^x)RHS = (1 - r ln r)² e^x(2Ae^x + 2Be^x + 2Ce^x)

Equating LHS and RHS, we get;2A(x² - x + 1 - r ln r) + 2B(x - 1 - r ln r) + 2C(1 - r ln r) = 0..........eqn (4)

A(x² - x + 1 - r ln r) + B(x - 1 - r ln r) + C(1 - r ln r) = (1 - r ln r)²

Since the given equation is of Cauchy-Euler type, hence x > 2,So A = 1RHS = B = C = 0

Substituting A = 1 in equation (4), we get;1(x² - x + 1 - r ln r) = (1 - r ln r)²

Simplifying, we get;x² - x - r ln r = 0

Applying quadratic formula, we get;x = [1 ± √(1 + 4r ln r)] / 2Since x > 2, taking positive root;x = [1 + √(1 + 4r ln r)] / 2

Putting the value of x in equation (1), we get;yp(x) = e^x (Ax² + Bx + C) = e^x [x² + ln x - x ln x]

Therefore, the particular solution of the given differential equation is given by;yp(x) = e^x [x² + ln x - x ln x]

Hence, option (b) is the correct answer.

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3. Use any method to find the average rate of change of f(x) = 1/x over the interval 1≤x≤3

Answers

Therefore, the average rate of change of f(x) = 1/x over the interval 1 ≤ x ≤ 3 is -2/3.

Explanation: The average rate of change is equal to the difference between the values of a function at two different points, divided by the distance between those points. Using the formula of the average rate of change, we have to evaluate f(x) at x = 3 and x = 1. Let's begin:If f(x) = 1/x, then f(1) = 1/1 = 1 and f(3) = 1/3.So, the average rate of change of f(x) over the interval 1 ≤ x ≤ 3 is given by:average rate of change= (f(3) − f(1))/(3 − 1) = (1/3 − 1)/(2)= (-2/3). The average rate of change of f(x) = 1/x over the interval 1 ≤ x ≤ 3 is -2/3.

Therefore, the average rate of change of f(x) = 1/x over the interval 1 ≤ x ≤ 3 is -2/3.

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Outline the Gauss-Markov assumptions associated with the Classical Linear Regression Model (CLRM) and discuss their significance. State any additional assumption that is required for hypotheses testing. b) Consider the following Cobb-Douglas production function: Qt = BIL PR B2 B3 where, Q = output level, L = labour input, K = capital input Which functional form should you use to estimate this model? Clearly explain how you would test the hypothesis that there is constant return to scale.

Answers

The Gauss-Markov assumptions associated with the Classical Linear Regression Model (CLRM) are important for obtaining unbiased and efficient estimates of the regression coefficients.

a) These assumptions include linearity, strict exogeneity, no perfect multicollinearity, zero conditional mean, homoscedasticity, and no autocorrelation. Violations of these assumptions can lead to biased and inefficient parameter estimates, affecting the validity and reliability of the regression results. In addition, the Normality assumption is required for hypothesis testing, assuming that the error term follows a normal distribution.

b) To estimate the Cobb-Douglas production function Qt = BIL PR B2 B3, it is appropriate to take the natural logarithm of both sides of the equation to transform it into a linear equation. By doing so, the model becomes ln(Qt) = ln(B) + α ln(L) + β ln(PR) + γ ln(B2) + δ ln(B3), where ln represents the natural logarithm.

To test the hypothesis of constant returns to scale, the sum of the coefficients α, β, γ, and δ is examined. If α + β + γ + δ = 1, it indicates constant returns to scale in the production function. This hypothesis can be tested using a t-test to assess the significance of the sum of the coefficients. The null hypothesis is that α + β + γ + δ = 1, while the alternative hypothesis is that α + β + γ + δ ≠ 1. If the estimated sum significantly deviates from 1, it suggests that the production function does not exhibit constant returns to scale.

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Solve the equation in the interval [0°,360°). Use an algebraic method. 10 sin 0-5 sin 0=3 Select the correct choice below and, if necessary, fill in the answer box to complete your ch OA. The soluti

Answers

The solution in the first and second quadrants as follows:sin θ = 3/5θ = sin⁻¹(3/5)So,θ = 36.87° or 143.13°

The given trigonometric equation is 10 sin θ - 5 sin θ = 3. Let's simplify it to solve it further.10 sin θ - 5 sin θ = 3(10 - 5) sin θ = 3sin θ = 3/5

We need to find the solution of the equation in the interval [0°, 360°]. We know that the sine function is positive in the first and second quadrants. Therefore, we can restrict the solution in the first and second quadrants as follows:sin θ = 3/5θ = sin⁻¹(3/5)So,θ = 36.87° or 143.13°

These are the two solutions of the equation in the interval [0°, 360°]. Thus, the algebraic method has given us the solution. We just need to keep the restricted interval in mind to obtain the solution. Answer: Therefore, the answer is as follows:θ = 36.87° or 143.13°.

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4. (15%) Is the number of years of competitive running experience related to a runner's distance running performance? The data on nine runners, obtained from the study by Scott Powers and colleagues,

Answers

Assuming a significant relationship, more years of competitive running experience are expected to positively impact distance running performance.

Statistical methods such as correlation or regression analysis can be applied to determine if there is a significant relationship between these variables.

Using the data on nine runners, the number of years of competitive running experience and their corresponding distance running performance can be analyzed. Correlation analysis can measure the strength and direction of the relationship, indicating whether there is a positive or negative association between the two variables. Regression analysis can provide a more detailed understanding of the relationship by estimating the equation of the line that best fits the data, allowing for predictions of distance running performance based on the number of years of experience.

By examining the statistical significance of the relationship, p-values can be calculated to determine if the observed relationship is statistically significant or occurred by chance. Additionally, other statistical measures such as R-squared can assess the proportion of variability in distance running performance that can be explained by the number of years of competitive running experience.

Overall, with the complete data, appropriate statistical analysis can be performed to determine the nature and significance of the relationship between the number of years of competitive running experience and distance running performance.

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what is the center and radius of the circle represented by the equation (x-9) squared+ (y+2)squared = 4

Answers

Answer:

Center is (h,k) = (9,-2) and radius is r=2

Step-by-step explanation:

Compare with [tex](x-h)^2+(y-k)^2=r^2[/tex] and it's easy to tell









Find the general solution for the first-order differential equation. dy dx = 38x

Answers

The general solution of the given differential equation is:y = 19x^2 + C

Given differential equation: dy/dx = 38x

To find: General solution

We have to integrate both sides of the equation to get the general solution.

∫dy = ∫38x dx=> y = 19x^2 + C

Where C is a constant of integration.

Therefore, the general solution of the given differential equation is:y = 19x^2 + C

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A medical engineering company creates X-ray machines. The machines the company sold in 1995 were expected to last six years before breaking. To test how long the machines actually lasted, the company took a simple random sample of six machines. The company got the following results (in years) for how long the x-ray machines lasted: 8,6,7,9,5, and 7. Assume the distribution of the longevity of x-ray machines is normally distributed. Construct and interpret a 98% confidence interval for the average longevity of x-ray machines.

Answers

Based on a sample of six X-ray machines,the interval was calculated to be (6.04, 8.96) years, suggesting that with 98% confidence, the true average longevity of X-ray machines falls within this range.

To construct the confidence interval, we use the formula:

Confidence Interval = sample mean ± (critical value * standard error)

First, we calculate the sample mean by summing up the longevity of the six machines (8 + 6 + 7 + 9 + 5 + 7) and dividing by the sample size (6). This gives us a sample mean of 7 years.

Next, we need to calculate the standard error, which measures the variability of the sample mean. Since the population standard deviation is unknown, we use the sample standard deviation. By calculating the sample standard deviation of the longevity data (which is approximately 1.63 years), we can compute the standard error as sample standard deviation divided by the square root of the sample size.

The critical value is obtained from the t-distribution table for a 98% confidence level and five degrees of freedom (sample size minus one). In this case, the critical value is approximately 2.571.

Substituting the values into the formula, we find the confidence interval to be (6.04, 8.96) years.

Interpreting the interval, we can say with 98% confidence that the average longevity of X-ray machines is estimated to fall within this range. This means that, on average, X-ray machines sold by the company are expected to last between approximately 6.04 and 8.96 years.

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In a random sample of 12 American adults, the mean waste recycled per person per day was 1.2 pounds and the standard deviation was 0.3 pound. Assume that the amount of waste recycled is normally distributed. The 90% confidence interval for the population mean is pounds << pounds (Round values to the nearest hundredth. There must be two digits after the decimal point. Do not write the units.)

Answers

Rounding to two decimal places, the 90% confidence interval for the population mean is (1.04, 4553) pounds.

To calculate the 90% confidence interval for the population mean, we can use the formula:

Confidence interval = sample mean ± (critical value * standard error)

The critical value is determined by the desired confidence level and the degrees of freedom, which in this case is 11

(n - 1) since we have a sample size of 12.

Looking up the critical value for a 90% confidence level and 11 degrees of freedom, we find it to be approximately 1.795.

The standard error is calculated by dividing the sample standard deviation by the square root of the sample size.

In this case, it is 0.3 / √12 ≈ 0.0866.

Plugging in the values into the formula, the confidence interval is:

1.2 - (1.795 * 0.0866) = 1.2 - 0.1557

                                   = 1.04, 4553

Rounding to two decimal places, the 90% confidence interval for the population mean is (1.04, 4553) pounds.

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Factor the given polynomial completely. If the polynomial cannot be factored, say that it is prime. x + 9x + 14 Select the correct choice below and fill in any answer boxes within your choice. OA. 2 X + 9x + 14 = OB. The polynomial is prime.

Answers

The given polynomial is: x + 9x + 14,  the correct option is

OA = (x + 7)(x + 2)

OB = (2x + 7)(x + 2)

the polynomial is not prime.

We have to factor the given polynomial completely.To factor the given polynomial completely, first we need to add 1 and 14 that are factors of 14 and whose sum is 9.

x + 9x + 14

= (x + 7)(x + 2)

Hence, the given polynomial completely factored as

(x + 7)(x + 2)

Therefore,

OA

= (x + 7)(x + 2)

OB

= (2x + 7)(x + 2)

Therefore, the correct option is

OA

= (x + 7)(x + 2)

OB

= (2x + 7)(x + 2)

the polynomial is not prime.

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Problem 4: a) (10 pts) Use the definition to evaluate the following definite integral using the right endpoints. y v=√ √ ₁ (₁+² (1 + 4x). dx min + 1) ne 2 217

Answers

By applying the definition of a definite integral and partitioning the interval [1, 2] into subintervals, we can approximate the integral as the sum of the areas of right rectangles. The evaluation results in an approximation of 2.71875.

To evaluate the definite integral using the right endpoints, we divide the interval [1, 2] into n subintervals of equal width. The width of each subinterval, denoted by Δx, is given by (2 - 1)/n = 1/n. We can then choose the right endpoint of each subinterval as our sample point. Let's denote this sample point as xi, where xi = 1 + iΔx for i = 0, 1, 2, ..., n-1. Using the sample points, we can approximate the integral as the sum of the areas of right rectangles: ∫(1 to 2) √(1 + 4x) dx ≈ Δx * [√(1 + 4x0) + √(1 + 4x1) + √(1 + 4x2) + ... + √(1 + 4xn-1)]. Simplifying this expression, we have: ∫(1 to 2) √(1 + 4x) dx ≈ (1/n) * [√(1 + 4(1)) + √(1 + 4(1 + 1/n)) + √(1 + 4(1 + 2/n)) + ... + √(1 + 4(1 + (n-1)/n))].

Taking the limit as n approaches infinity, this approximation converges to the exact value of the integral. By evaluating the above expression for a large value of n, we can approximate the definite integral. For this specific integral, we have: ∫(1 to 2) √(1 + 4x) dx ≈ (1/n) * [√5 + √(1 + 4(1 + 1/n)) + √(1 + 4(1 + 2/n)) + ... + √(1 + 4(1 + (n-1)/n))]. Let's consider a value of n = 8. Evaluating the expression above, we obtain an approximation of 2.71875 for the definite integral. Therefore, using the definition of a definite integral with right endpoints, the approximation of the integral ∫(1 to 2) √(1 + 4x) dx is 2.71875.

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Minimize f(x) = x²₁ + x₁x₂ + 3x²2 + x₂x3 + 2x²3
Subject to: x₁x₂ + x²3 = 4
X1, X₂ ≥ 0.

Answers

To solve the given optimization problem, we need to minimize the objective function f(x) = x₁² + x₁x₂ + 3x₂² + x₂x₃ + 2x₃² subject to the constraint x₁x₂ + x₃² = 4, and the non-negativity constraints x₁, x₂ ≥ 0.

To find the solution, we can use the method of Lagrange multipliers. Let's define the Lagrangian function L(x, λ) as:

L(x, λ) = f(x) - λ(g(x) - 4)

where g(x) = x₁x₂ + x₃² is the constraint function, and λ is the Lagrange multiplier.

Now, we will take partial derivatives of L(x, λ) with respect to each variable x₁, x₂, x₃, and λ, and set them equal to zero to find the critical points. The partial derivatives are:

∂L/∂x₁ = 2x₁ + x₂ - λx₂ = 0

∂L/∂x₂ = x₁ + 6x₂ + x₃λ = 0

∂L/∂x₃ = x₂ + 4x₃ - 2x₃λ = 0

∂L/∂λ = x₁x₂ + x₃² - 4 = 0

Solving these equations simultaneously will give us the values of x₁, x₂, x₃, and λ that satisfy the optimality conditions.

After obtaining the solutions, we need to check for local extrema by evaluating the second-order partial derivatives and verifying the nature of the critical points. Since the problem does not specify the domain of the variables, we assume they can take any real value.

However, it's important to note that the given objective function and constraint do not have a unique solution since there are no constraints on the variables' values. Hence, we can only find the critical points and evaluate their nature but cannot determine the global minimum or maximum.

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1. Jasmine and Sarah want to design a website for the spring sale of a clothing store. The sale will start at 8 am and close at 8 pm on May 14. To build the website, they have to be able to predict the number of online customers that day. Each one has different predictions for the number of online customers that day.
a. Sarah believes that the number of online customers will start at a minimum of 2 thousand online customers at 8 am and then it will increase to a maximum of 12 thousand customers at 2 pm. Let S(tJ) be the sinusoidal function which gives the amount of online customers on the website (in thousands) / hours after 8 am on May 14 according to Sarah's predictions.
Write a formula for the function S(t) for 0≤t≤12.
S(t)=
b. On the other hand, Jasmine believes that there will be 3 thousand online customers at 8 am and that the number of online customers will reach a maximum of 10 thousand at 2 pm. Let (r) be the quadratic function which gives the amount of online customers on the website (in thousands) 1 hours after 8 am on May 14 according to Jasmine's predictions.
Write a formula for J(t) for 0≤t≤12.
c. How many online customers does Sarah's model predict there will be at 7 pm on May 142
d. How many online customers does Jasmine's model predict there will be at 7 pm on May 14?
e. At what time(s) is the difference in predicted online customers between the two models the greatest? What is the discrepancy? Solve by graphing with your calculator or using Desmos.
f. At what times, if any, do the two models predict the same number of online customers? Solve by graphing with your calculator or using Desmos

Answers

Sarah's prediction for the number of online customers on May 14 follows a sinusoidal function, denoted as S(t). The formula for S(t) within the given time range of 0≤t≤12 is not provided in the question.

Jasmine's prediction, on the other hand, follows a quadratic function, denoted as J(t), where t represents the number of hours after 8 am. The formula for J(t) within the given time range of 0≤t≤12 is not provided in the question.

To determine the number of online customers predicted by each model at 7 pm on May 14, we need to substitute t = 11 (since 7 pm is 11 hours after 8 am) into the respective functions. Unfortunately, without the formulas for S(t) and J(t), we cannot calculate the specific number of online customers predicted by each model at that time.

To find the time(s) at which the difference in predicted online customers between the two models is greatest, we would need to plot the two functions on a graph and analyze their intersection points or highest/lowest points of discrepancy. However, since the formulas for S(t) and J(t) are not provided, we cannot determine the exact times or discrepancy values.

Similarly, without the formulas for S(t) and J(t), we cannot identify the specific times at which the two models predict the same number of online customers. To find these points, we would need to solve the equation S(t) = J(t), but without the functions, it is not possible.

In summary, without the formulas for S(t) and J(t), we are unable to provide the specific values for the number of online customers predicted by each model at 7 pm on May 14, determine the times with the greatest discrepancy, or identify the times at which the two models predict the same number of online customers.

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The lifetime of a camera costing $500 is exponentially distributed with mean 3 years. The manufacturer agrees to pay a full refund to a buyer if the camera fails during the first year following its purchase, and a one-half refund if it fails during the second year. If the manufacturer sells 100 cameras, how much should it expect to pay in refunds? Choose the correct answer below. A. $16,655 B. $21,409 C. $16,964 D. $14,969 E. $19,253

Answers

If the manufacturer sells 100 cameras,  the expected refunds to be paid is $16,655(A).

To calculate the expected refund amount, we need to consider the probabilities of the camera failing during each year and the corresponding refund amounts.

The probability of the camera failing during the first year is given by P(X ≤ 1) = ∫[0, 1] f(x) dx = 1 - e^(-1/3) ≈ 0.2835.

The probability of the camera failing during the second year (but not the first year) is given by P(1 < X ≤ 2) = ∫[1, 2] f(x) dx = e^(-1/3) - e^(-2/3) ≈ 0.2027.

Since the manufacturer sells 100 cameras, the expected refund amount can be calculated as:

Expected refund amount = (100 cameras) × (0.2835 × $500 + 0.2027 × $250) = $16,944.50.

Hence, the correct answer is A. $16,655.

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Find the parametric equations of a circle with radius of 7.5 where you start at point (0,7.5) at t = 0 and you travel clockwise with a period of 9. Note: t is in radians. x(t) = __
y(t) = __

Answers

Parametric equations for the circle with radius 7.5, starting at point (0, 7.5) at t=0 and traveling clockwise with a period of 9, are x(t) = -7.5sin(t/9*(2pi)) and y(t) = 7.5cos(t/9(2*pi)).

The angle t, measured in radians, represents the position of a point on the circle. We want to start at the top of the circle and move clockwise, so we need to start with an angle of -pi/2 (270 degrees) and decrease the angle as t increases. To achieve a period of 9, we need to use a factor of 2*pi/9 in the argument of the trigonometric functions.

The sine and cosine of an angle in radians give the horizontal and vertical coordinates, respectively, of a point on the unit circle. To scale these coordinates to a circle with radius 7.5, we multiply them by the radius. Therefore, the correct parametric equations for the circle are x(t) = -7.5sin(t/9*(2pi)) and y(t) = 7.5cos(t/9(2*pi)). The negative sign in front of the sine function is used to indicate clockwise motion.

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Discussthe geographic conditions that effect the development of a country.Consider situational, transport, agroclimat "When the acids;HClO3, H3BO3, H3PO4 , are arranged in order of increasing strength, which order is correct?(A) HBO3 < H3PO4 < HCIO3(B) HClO3 < HBO3 < H3PO4(C) H3PO4 < HClO3 < H3BO3(D) HBO < HClO3 < H3PO4 3" Design a salary slip for the month of December 2021 with information given below.Fixed vs variable ratio- 70:30Ctc - 18LBasic- 50%Hra- 20%Da - 12%Travel allowance- 2000Insurance - 2500Incentive- 75% target completionPf 12%Earned leaves - 2LOP - 4 c) From the top of a building 80 metres high, theangle of depression of a car parked on the groundis 52. Find the distance of the car from the base of the building.(Write your answer correct to t Consider the following investment in a manufacturing facility: capital cost is $250 million, all of which can be depreciated in equal amounts for tax over ten years; working capital of $65 million; tax rate of 30 percent; and net revenue of $45 million in the first year growing at 3 percent PA. The investor can borrow unlimited funds at 6 percent PA; and their discount rate for similar investments is 15 percent. Calculate the net present value of the investment. Which of the following will increase the money supply the most? a Bank Y (Reserve Ratio 0.2) buys a bond from the central bank. b It depends on the type of bond. c Bank A (Reserve Ratio 0.1) sells a bond to Bank B (Reserve Ratio 0.1) d Bank Z (Reserve Ratio 0.2) sells a bond to the central bank. e Bank X (Reserve Ratio 0.1) buys a bond from the central bank. Revise these sentences using the Paramedic Method of Revision1. After much debate and fierce controversy throughout the scientific establishment, important experimentation was conducted by scientists who generated and recorded measurements using an accurate and well-calibrated scientific scale of musical quality to determine with all empirical certainly that the band 21 Pilots is terrible at writing songs.2. One of the most important points that I wish to make about technical communication is that technical communication is a form of writing that uses concise sentences that are free of unnecessary prose that is the cause of bloated, complicated, and wordy uses of the English language in formal writing. Describe the legal issues pertaining to selling Samsung phonesin the Japanese markets. (Min 500 words: Take any total 15 terms (total) from each chapter 8, 9, 10 and use them in a sentence (see explanation under the grading rubric for specific instructions. Remember you are not simply defining the terms but using them in sentences. Ahart Products, Incorporated, has a Transmitter Division that manufactures and sells a number of products, including a standard transmitter that could be used by another division in the company, the Remote Devices Division, in one of its products. Data concerning that transmitter appear below: Capacity in units 79,000 Selling price to outside customers $ 61 Variable cost per unit $ 42 Fixed cost per unit (based on capacity) $ 8 The Remote Devices Division is currently purchasing 4,000 of these transmitters per year from an overseas supplier at a cost of $59 per transmitter. Assume that the Valve Division is selling all of the valves it can produce to outside customers. Also assume that $3 in variable expenses can be avoided on transfers within the company due to reduced shipping and selling costs. What should be the minimum acceptable transfer price for the valves from the standpoint of the Valve Division?$59 per unit$61 per unit$47 per unit$58 per unit Affect of customer loyalty and service quality and security on financial performance of Islamic bankI need a conclusion almost 1000 words please and should be professional.. Not copy from internet