1.

What is the boiling point of a solution prepared by dissolving 2. 50 g of biphenyl (C12 H10)

in 85. 0 g of benzene. The molecular weight of biphenyl is 154 g. ​

Based on the scenario described, it is likely that the student spilled a solution containing a flammable compound such as ethanol or methanol. These compounds are commonly used in chemistry labs and can easily catch fire if not handled properly. The bright red color of the flames is likely due to the presence of a metal salt in the solution, which can produce colored flames when heated. It is important to always follow safety rules in a lab setting to prevent accidents like this from happening.

How does burn ethanol?

Ethanol can be burned in the presence of oxygen to produce carbon dioxide (CO2) and water (H2O) in a process known as combustion. The chemical formula for ethanol combustion is:

C2H5OH + 3O2 → 2CO2 + 3H2O

In this reaction, the ethanol (C2H5OH) reacts with oxygen (O2) to produce carbon dioxide (CO2) and water (H2O). The reaction releases heat, which can be used as a source of energy.

To burn ethanol, it is typically mixed with air or oxygen and then ignited. The combustion process can be controlled by adjusting the amount of ethanol and oxygen that is mixed together, as well as the temperature and pressure of the reaction.

In some cases, ethanol is burned in internal combustion engines, such as those used in cars and other vehicles. In these engines, the combustion of ethanol is used to power the engine and generate mechanical energy.

It's important to note that the combustion of ethanol releases carbon dioxide, a greenhouse gas that contributes to climate change. As such, efforts are being made to reduce the amount of greenhouse gas emissions from burning ethanol and other fuels, through the use of renewable energy sources and more efficient combustion processes.

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B. Zn (s) + H2SO4 (aq) ZnSO4 (aq) + H2 (l) of the following chemical reactions is a single replacement reaction

A single-displacement reaction occurs when a more reactive ingredient in a compound replaces a less reactive member. Metal displacement, hydrogen displacement, and halogen displacement are the three different categories of displacement processes.

Chlorine takes the place of bromine when it is introduced to a solution of sodium bromide in gaseous form (or as a gas dissolved in water). Chlorine, which is more reactive than bromine, causes sodium bromide to lose bromine, which causes the solutions to become blue.

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The volume/concentration of the above questions are as follows:

The amount of volume or concentration of a substance can be calculated using the following expression;

CaVa = CbVb

Where;

1. 10 × 250 = 0.5 × Vb

2500 = 0.5Vb

Vb = 5000mL

2. 0.400 × 15 = 2 × Cb

6 = 2Cb

Cb = 3M

3. 50 × 20 = 1000 × Cb

1000 = 1000Cb

Cb = 1M

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The question does not provide a specific nuclear chemical equation to work with, so it is difficult to provide a direct answer. However, I can provide some general information about nuclear chemical equations.

Nuclear chemical equations are used to represent nuclear reactions. These reactions involve changes in the nucleus of an atom, typically involving the addition or removal of protons and/or neutrons. Unlike chemical reactions, which involve the sharing or transfer of electrons, nuclear reactions involve changes in the core of the atom.

A typical nuclear chemical equation includes a reactant on the left side of the equation and a product on the right side. The reactant and product are both represented by chemical symbols, such as H for hydrogen or O for oxygen. The number of protons and neutrons in the reactant and product may differ, indicating a change in the nucleus.

In some cases, the nuclear chemical equation may be missing a symbol. This could indicate that the product is unknown or has not been determined. It is also possible that the missing symbol represents a hypothetical or theoretical product, rather than an actual substance.

In summary, nuclear chemical equations are used to represent nuclear reactions, which involve changes in the nucleus of an atom. The equations include reactants and products represented by chemical symbols, and may occasionally include missing symbols indicating an unknown or theoretical product.

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Answer:D

Explanation: Lions depend on grass to keep zebras well fed, since lions are carnivores, lions eat zebras. Thus, lions depend on the non living environmental food to nourish the zebras

The work done by Henry can be calculated by multiplying the weight of the box (500 N) with the distance it was lifted (0.75 m). Thus, the work done is 375 J (Joules).(D)

In physics, work is defined as the energy transferred when a force is applied to move an object through a distance. The unit of work is Joule, which is the same as Newton-meter. In this question, Henry lifted the box with a force equal to its weight, and the box was lifted through a distance of 0.75 m.

Therefore, Henry did work on the box by transferring 375 J of energy to it. This work is equal to the potential energy gained by the box due to its vertical displacement. The time taken (1.5 seconds) is not relevant to the calculation of work.

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The cell potential for the given unbalanced reaction is 2.334 V.

To calculate the cell potential, we first need to balance the reaction:
Mg(s) + 2Fe³⁺(aq) → Mg²⁺(aq) + 2Fe(s)

Next, we find the difference in standard reduction potentials:
E°(Mg²⁺/Mg) = -2.37 V
E°(Fe³⁺/Fe) = -0.036 V
E°cell = E°(Mg²⁺/Mg) - E°(Fe³⁺/Fe) = -2.37 - (-0.036) = -2.334 V

Now, we apply the Nernst equation to account for non-standard conditions:
E = E° - (RT/nF)ln(Q)
where R = 8.314 J/mol·K, T = 298 K, n = 2 moles of electrons, F = 96485 C/mol, and Q is the reaction quotient.

Q = [Mg²⁺]/[Fe³⁺]² = (0.000612)/(1.29)²

E = -2.334 - (8.314 * 298)/(2 * 96485) * ln(0.000612/1.29²)
E ≈ 2.334 V

Thus, the cell potential for the given reaction is 2.334 V.

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The rate of effusion of a gas is inversely proportional to the square root of its molar mass. This means that if the rate of effusion of one gas is 2.76 times faster than another gas, then the ratio of their effusion rates is:

Rate of unknown gas / Rate of CCl4 = √(Molar mass of CCl4 / Molar mass of unknown gas)

Since we are trying to find the identity of the unknown gas, we can assign it the variable X. We can then rewrite the equation as:

Rate of X / Rate of CCl4 = √(Molar mass of CCl4 / Molar mass of X)

We know that the rate of X is 2.76 times faster than the rate of CCl4. Therefore:

Rate of X = 2.76 x Rate of CCl4

Substituting this into the equation above, we get:

2.76 x Rate of CCl4 / Rate of CCl4 = √(Molar mass of CCl4 / Molar mass of X)

Simplifying this equation, we get:

2.76 = √(Molar mass of CCl4 / Molar mass of X)

Squaring both sides of the equation, we get:

7.6176 = Molar mass of CCl4 / Molar mass of X

Multiplying both sides by the molar mass of X, we get:

Molar mass of X = Molar mass of CCl4 / 7.6176

The molar mass of CCl4 is 153.82 g/mol, so:

Molar mass of X = 153.82 g/mol / 7.6176 = 20.18 g/mol

Therefore, the unknown gas has a molar mass of 20.18 g/mol. To determine its identity, we would need to compare this value to the molar masses of known gases.

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Yes, elements that make up polyatomic ions share their electrons.

Polyatomic ions are ions that are composed of more than two atoms.

Atoms are covalently bonded to each other  and in the entire structure non-neutral charge is present .The bonding electrons are distributed throughout the polyatomic ions and they are not localized between two atoms. A polyatomic ion is a molecule that can be ionized by either gaining or losing of electrons. The group of covalently bonded atoms altogether carries a net charge, this is because the total number of electrons in a molecule is not equal to the total number of protons present in the molecule.

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To expand a flattened plastic bag, one can increase the number of particles inside the bag, increase the temperature or speed of particles, increase the pressure or number of collisions of particles inside the bag, or increase the available volume or space inside the bag.

When the number of particles inside the bag is increased, the bag expands due to the increased amount of matter pushing against the inner surface of the bag. As temperature or speed of particles increases, their kinetic energy increases, causing them to collide with the inner surface of the bag with greater force and frequency, which leads to the expansion of the bag.

When the number of particles or their pressure inside the bag is increased, they collide with the inner surface of the bag with greater force, leading to the expansion of the bag. Increasing volume can be achieved by stretching the bag or pulling on it in different directions, which increases the distance between the particles inside the bag and allows them to occupy a greater volume of space.

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If 7.34 mol of O₂ reacts completely, the grams of CO₂ produced is  161.44 grams.

To calculate the grams of CO₂ produced when 7.34 mol of O₂ reacts completely, you'll need to use stoichiometry.

Step 1: Write the balanced chemical equation for the reaction. For the combustion of a hydrocarbon, the general equation is:

C_xH_y + O₂ -> CO₂ + H₂O

However, you need to know the specific hydrocarbon in order to balance the equation and proceed. Assuming the hydrocarbon is methane (CH4) for the sake of demonstration, the balanced equation is:

CH₄ + 2O₂ -> CO₂ + 2H₂O

Step 2: Identify the mole-to-mole ratio between O₂ and CO₂ in the balanced equation. In this case, the ratio is 2:1.

Step 3: Use the mole-to-mole ratio to find the moles of CO₂ produced when 7.34 mol of O₂ reacts completely:

(1 mol CO₂ / 2 mol O₂) × 7.34 mol O₂ = 3.67 mol CO₂

Step 4: Convert moles of CO₂ to grams by using the molar mass of CO₂ (12.01 g/mol for C and 16.00 g/mol for O):

3.67 mol CO₂ × (12.01 g/mol C + 2 × 16.00 g/mol O) = 3.67 mol CO₂ × 44.01 g/mol CO₂ = 161.44 g CO₂

So, when 7.34 mol of O₂ reacts completely, 161.44 grams of CO₂ are produced.

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If there is a container with a volume of 6.2 liters and a pressure of 1.5 atmospheres, the number of moles present in the container is approximately 0.28 moles. Therefore, the correct answer is option b) 0.28.

To calculate the number of moles present in the container, we can use the ideal gas law equation:

PV = nRT

Where:

P = pressure in atm

V = volume in liters

n = number of moles

R = ideal gas constant (0.0821 L atm / (mol K))

T = temperature in Kelvin

First, we need to convert the temperature from Celsius to Kelvin:

T(K) = T(°C) + 273.15

T(K) = 38 °C + 273.15 = 311.15 K

Now we can rearrange the equation to solve for the number of moles (n):

n = PV / RT

Substituting the given values:

P = 1.5 atm

V = 6.2 L

R = 0.0821 L atm / (mol K)

T = 311.15 K

n = [tex](1.5 \text{ atm} \times 6.2 \text{ L}) / (0.0821 \text{ L atm/(mol K)} \times 311.15 \text{ K})[/tex]

n ≈ 0.28 moles

Therefore, the number of moles present in the container is approximately 0.28 moles.

The correct answer is option b) 0.28.

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Approximately 0.35175 moles of C₁₂H₂₆ were reacted to produce 4.2105 moles of CO₂.

To find the moles of C₁₂H₂₆ that reacted to produce 4.2105 moles of CO₂, you can use the stoichiometry of the balanced chemical equation: 2 C₁₂H₂₆ + 37 O₂ → 24 CO₂ + 26 H₂O.

Step 1: Identify the mole-to-mole ratio between C₁₂H₂₆ and CO₂ in the balanced equation.
In this case, the ratio is 2 moles of C₁₂H₂₆ to 24 moles of CO₂.

Step 2: Set up a proportion to find the moles of C₁₂H₂₆.
(2 moles C₁₂H₂₆) / (24 moles CO₂) = (x moles C₁₂H₂₆) / (4.2105 moles CO₂)

Step 3: Solve for x, which represents the moles of C₁₂H₂₆.
x moles C₁₂H₂₆  = (2 moles C₁₂H₂₆) * (4.2105 moles CO₂) / (24 moles CO₂)

Step 4: Calculate the value of x.
x = (2 * 4.2105) / 24
x ≈ 0.35175

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The percent by mass of hydrogen in CH3COOH is 6.7%. (C)

To calculate the percent by mass of hydrogen in a compound, you need to determine the mass of hydrogen present in relation to the total mass of the compound.

The molecular formula of acetic acid (CH3COOH) indicates that it contains two hydrogen atoms. To calculate the percent by mass of hydrogen, we need to consider the molar mass of hydrogen and the molar mass of acetic acid.

The molar mass of hydrogen (H) is approximately 1.00784 grams per mole, and the molar mass of acetic acid (CH3COOH) can be calculated as follows:

Molar mass of CH3COOH = (molar mass of carbon × 2) + (molar mass of hydrogen × 4) + molar mass of oxygen

= (12.01 g/mol × 2) + (1.00784 g/mol × 4) + 16.00 g/mol

= 24.02 g/mol + 4.03136 g/mol + 16.00 g/mol

= 44.05 g/mol

Now, to calculate the percent by mass of hydrogen, we can use the following formula:

Percent by mass of hydrogen = (mass of hydrogen / total mass of acetic acid) × 100

Since there are two hydrogen atoms in one molecule of acetic acid, the mass of hydrogen is (2 × 1.00784 g/mol) = 2.01568 g/mol.

Plugging the values into the formula, we get:

Percent by mass of hydrogen = (2.01568 g/mol / 44.05 g/mol) × 100= 6.7%

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Copper (Cu) is oxidized, and Nitrogen (N) is reduced.

The element that is oxidized or reduced is calculated as follows;

Cu + HNO3 → Cu(NO3)2 + NO + H2O

Oxidation is the loss of electrons, whereas reduction is the gain of electrons.

In the given reaction, copper (Cu) is oxidized as it loses two electrons, going from an oxidation state of 0 to +2 in Cu(NO3)2.

On the other hand, nitrogen in HNO3 undergoes a change in oxidation state from +5 to +2, indicating that it has gained three electrons and hence, is reduced to NO.

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The pH of the resulting solution is calculated to be 1.40.

To determine the pH of the resulting solution, we need to first calculate the moles of each acid present.

Moles of HCl = (0.50 mol/L) x (0.050 L) = 0.025 mol
Moles of HNO3 = (0.10 mol/L) x (0.150 L) = 0.015 mol

Since the two acids are both strong acids, they will completely dissociate in solution. This means that the resulting solution will contain 0.025 mol of H+ ions from HCl and 0.015 mol of H+ ions from HNO3.

To calculate the pH of this solution, we can use the equation:

pH = -log[H+]

[H+] = (0.025 mol + 0.015 mol) / (0.050 L + 0.150 L) = 0.040 mol/L

pH = -log(0.040) = 1.40

Therefore, the pH of the resulting solution is 1.40.

In summary, when 50.0 ml of 0.50 M HCl is added to 150.0 ml of 0.10 M HNO3, the resulting solution contains 0.025 mol of H+ ions from HCl and 0.015 mol of H+ ions from HNO3. The pH of the resulting solution is calculated to be 1.40.

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The color of methyl orange in a 1.2 M solution of KOH would be yellow.

Methyl orange is a pH indicator that is often used in titration due to its distinct and visible color variation at various pH levels.

At pH 5 or higher, methyl orange turns yellow. Strong bases totally dissolve into K+ and OH- ions in solution while KOH at 1.2 M will do the same. Since KOH is a powerful base, its solution pH will be higher than 7 (neutral).

Therefore, the color of methyl orange in a 1.2 M solution of KOH would be yellow.

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0.21 dm³ of 0.1 mol/dm³ hydrochloric acid is required to neutralize 20 cm³ of 2.0 mol/dm³ sodium hydroxide.

The volume of 0.1 mol/dm³ hydrochloric acid required to neutralize 20 cm³ of 2.0 mol/dm³ sodium hydroxide can be calculated using the formula:

Volume of acid = (Volume of alkali x Concentration of alkali x Molar mass of acid) / (Molar mass of alkali x Concentration of acid)

Firstly, we need to convert the volume of alkali from cm³ to dm³, which gives us 0.02 dm³. The molar mass of hydrochloric acid (HCl) is 36.5 g/mol, and the molar mass of sodium hydroxide (NaOH) is 40 g/mol.

Substituting these values and the given concentrations into the formula, we get:

Volume of acid = (0.02 x 2.0 x 40) / (36.5 x 0.1) = 0.21 dm³

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The activation energy (Ea) is the minimum energy required for a reaction to occur, and it is defined as the energy difference between the reactants and the activated complex or transition state. In an exothermic reaction, the products have lower energy than the reactants, so the change in energy (∆E) is negative.

The activation energy of the forward reaction is given as 20 kJ/mol. This means that 20 kJ/mol of energy must be provided to the reactants to reach the activated complex and initiate the forward reaction.

To find the activation energy of the reverse reaction (Ea′), we can use the equation:

Ea′ = Ea + ∆E

where Ea is the activation energy of the forward reaction and ∆E is the change in energy of the reaction. Since we are given ∆E as -33 kJ/mol, which represents the change in energy for the forward reaction, we can substitute the values and solve for Ea′.

Plugging in the given values, we get:

Ea′ = 20 kJ/mol + (-33 kJ/mol)

Ea′ = -13 kJ/mol

Therefore, the activation energy of the reverse reaction (Ea′) is -13 kJ/mol. This negative value means that the reverse reaction has a lower activation energy than the forward reaction, which is consistent with the fact that the reaction is exothermic. A lower activation energy for the reverse reaction means that it is easier for the products to convert back to the reactants, which is why exothermic reactions tend to be more favorable in the forward direction.

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The calories of heat transferred by the sample were 1526.06.

The amount of heat transferred by the sample can be calculated using the equation
Q = m x c x ΔT

where:
Q = heat transferred (in calories)
m = mass of the sample (in grams)
c = specific heat capacity of antimony (in cal/(g·°C))
ΔT = temperature change of the sample (in °C)

Substituting the values:
Q = 983.6 g x 0.049 cal/(g·°C) x 31.51 °C
Q = 1526.06 calories

So, the heat transferred by the 983.6 g sample of antimony with a temperature change of +31.51 °C is approximately 1526.06 calories. Specific heat capacity is a property of a material that describes the amount of heat required to raise the temperature of one gram of the material by one degree Celsius. This property can be used to calculate the amount of heat transferred during temperature changes.

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An endothermic reaction is one that absorbs heat from its surroundings, resulting in an increase in the system's internal energy.

Therefore, the enthalpy change associated with an endothermic reaction is positive. The energy required to break the bonds in the reactants is greater than the energy released when new bonds are formed in the products, resulting in a net absorption of energy.

The enthalpy change is a measure of the heat energy released or absorbed during a chemical reaction, and it is often used to determine whether a reaction is exothermic or endothermic.

In the case of an endothermic reaction, the products have more internal energy than the reactants, and the enthalpy change is positive.

Some examples of endothermic reactions include melting ice, evaporating water, and photosynthesis. In all of these reactions, heat is absorbed from the surroundings, resulting in a positive enthalpy change.

Understanding the enthalpy change associated with a reaction is important in fields such as thermodynamics, chemical engineering, and materials science.

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The pinacol rearrangement more often use the sulfuric acid, H₂SO₄ , as the acid catalyst rather than the hydrochloric acid, HCl is because H₂SO₄ have the more proton than that of the HCl.

The pinacol rearrangement process will takes place through 1,2-rearrangement. This rearrangement will involves the shift of the two adjacent atoms. Pinacol is the compound which has the two hydroxyl groups, each of the attached to the vicinal carbon atom. It is the solid organic compound which is the white.

The H₂SO₄ have the more proton than that of the HCl. This will makes the pinacol rearrangement more often use the sulfuric acid H₂SO₄ , as the acid catalyst and rather than the hydrochloric acid, HCl.

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It is likely that the jewels are hidden in the tank with salt residue on their sides.

The presence of the electric wires in both tanks suggests that the thief has set up a security system to protect the treasure chests.

The purpose of the salt in the right tank is likely to act as a conductor, completing an electric circuit if someone were to touch the chest or the wires. This would trigger an electric shock and serve as a deterrent to potential thieves.

Since the thief is unlikely to have set up the security system in the tank without the jewels, the lack of salt in the left tank suggests that it is a decoy, intended to mislead potential thieves.

Therefore, the tank with the salt residue is the more likely hiding place for the jewels.

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A 35. 3 g of element M is reacted with nitrogen to produce 43. 5 g of compo und M₃N₂ (i) The molar mass of element M is 24.0 g/mol. (ii) The name of the element is magnesium (Mg).

(i) To find the molar mass of element M, we need to use stoichiometry to relate the mass of M to the mass of M₃N₂. We can start by calculating the moles of M3N2 produced:

43.5 g M₃N₂ × 1 mol M₃N₂/100.9 g M₃N₂ = 0.43 mol M₃N₂

Since the molar ratio between M and M₃N₂ is 1:3, we can calculate the moles of M:

0.43 mol M₃N₂ × 1 mol M/3 mol M₃N₂ = 0.14 mol M

Finally, we can calculate the molar mass of M by dividing its mass (35.3 g) by the number of moles (0.14 mol):

molar mass of M = 35.3 g/0.14 mol = 253 g/mol

However, this value is much higher than the molar mass of any known element. We can recognize that the formula M₃N₂ implies that element M is a metal with a +2 charge, since each M atom forms 3 bonds with N atoms, and each N atom forms 2 bonds with M atoms.

(ii) Based on this information, we can identify element M as magnesium (Mg), which has a molar mass of 24.0 g/mol.

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The chemical equation is Na₂CO₃(aq) + CoCl₂(aq) -> 2NaCl(aq) + CoCO₃ (s), which represents the reaction between sodium carbonate and cobalt chloride to form sodium chloride and cobalt carbonate precipitate.

The balanced chemical equation for the reaction between Na₂CO₃ (sodium carbonate) and CoCl₂ (cobalt chloride) is:

Na₂CO₃ (aq) + CoCl₂ (aq) → CoCO₃ (s) + 2NaCl (aq)

In this reaction, the sodium carbonate reacts with cobalt chloride to produce cobalt carbonate and sodium chloride. This is an example of a double displacement reaction, where the positive and negative ions of two compounds exchange places to form two new compounds.

In this case, the carbonate ion (CO₃²⁻) from sodium carbonate combines with the cobalt ion (Co⁺) from cobalt chloride to form cobalt carbonate (CoCO₃), which is a solid precipitate.

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Yes, we have enough information to calculate the amount of energy transferred in this situation. We can use the equation Q = mCΔT.

Q is the amount of energy transferred, m is the mass, C is the specific heat capacity, and ΔT is the change in temperature. We know the mass and specific heat capacity of the aluminum and water, as well as the change in temperature of the water.

Using this information, we can calculate the amount of energy transferred from the aluminum to the water.

To be specific, we can use the equation Q(aluminum) = m(aluminum) x C(aluminum) x ΔT(water) to find the amount of energy transferred from the aluminum to the water.

Since the aluminum starts at a higher temperature than the water, it will lose energy and transfer it to the water until both reach thermal equilibrium.

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In the balanced equation for the reaction of Pb with N2, 3 moles of Pb would react with 2 moles of N2 to form 6 moles of Pb3N2. Since 1 mole of a substance is equal to 6.02x1023 particles, 3 moles of Pb would be equal to 1.81x1024 particles of Pb.

Similarly, 2 moles of N2 would be equal to 1.21x1024 particles of N2. When these two react to form Pb3N2, 6 moles of Pb3N2 would be formed, which is equal to 3.63x1024 particles of Pb3N2. Thus, if there are 3 moles of Pb, then there are 3.63x1024 particles of Pb3N2.

Molecules and atoms are the building blocks of all matter in the universe. A mole is a unit of measurement used to quantify the amount of a substance present in a given sample. It is defined as the amount of substance that contains the same number of particles as 12 grams of Carbon-12.

Moles are used to calculate the number of particles present in a given amount of a substance, as the number of particles in a mole of a substance is always the same. This allows us to easily calculate the number of particles present in any given amount of a substance.

In chemistry, the balanced equation of a reaction is used to calculate the amount of each reactant and product present in the reaction. Knowing the number of moles of each substance present in the reaction allows us to calculate the number of particles present in each substance as well.

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1.  Balanced equation for the combustion of propane: [tex]C_3H_8 + 5O_2\ - > 3CO_2 + 4H_2O.[/tex]

2. Balanced equation for the reaction between hydrochloric acid and sodium hydroxide:[tex]HCl + NaOH\ - > NaCl + H_2O.[/tex]

3. 3. Balanced equation for the decomposition of calcium carbonate upon heating: [tex]CaCO_3\ - > CaO + CO_2.[/tex]

1. [tex]C_3H_8 + 5O_2\ - > 3CO_2 + 4H_2O.[/tex]

This reaction shows that propane[tex](C_3H_8)[/tex] reacts with oxygen[tex](O_2)[/tex] from the air to produce carbon dioxide[tex](CO_2)[/tex] and water[tex](H_2O)[/tex] in a balanced chemical equation.

2. [tex]HCl + NaOH\ - > NaCl + H_2O.[/tex]

This reaction demonstrates that hydrochloric acid (HCl) reacts with sodium hydroxide (NaOH) to produce sodium chloride (NaCl) and water [tex](H_2O)[/tex] in a balanced chemical equation.

3. [tex]CaCO_3\ - > CaO + CO_2[/tex].

This reaction illustrates that when calcium carbonate[tex](CaCO_3)[/tex] is heated, it decomposes to produce calcium oxide (CaO) and carbon dioxide [tex](CO_2)[/tex] in a balanced chemical equation.

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--The complete Question is, Write balanced equations for each of the processes described below:

1. Combustion of propane (C3H8) in air to produce carbon dioxide and water.

2. Reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) to produce sodium chloride (NaCl) and water (H2O).

3. Decomposition of calcium carbonate (CaCO3) upon heating to produce calcium oxide (CaO) and carbon dioxide (CO2). --

Answer:

15717.124

Explanation:

124 moles of FeCl2.

The molar mass of FeCl2 is 126.751 g/mol.

To find grams of FeCl2, multiply the number of moles by its molar mass.

124 moles * 126.751 g/mol  = 15717.124 grams.

You can check the ending unit. moles * grams / moles leaves just grams, which is the answer you're looking for.

The only plate with all margins as convergent boundaries is the Pacific Plate. Convergent boundaries occur when two tectonic plates move toward each other and collide, resulting in the formation of various geological features such as mountains, volcanic arcs, and deep-sea trenches.

The Pacific Plate is the largest tectonic plate on Earth, covering an area of around 103 million square kilometers. It is surrounded by convergent boundaries along its entire perimeter. To the west, it converges with the Eurasian,

Philippine Sea, and Australian Plates, forming the Japan, Kuril-Kamchatka, and Izu-Bonin-Mariana Trenches, as well as the Indonesia and Philippine Trenches. To the east, it converges with the North American and Cocos Plates, resulting in the deep-sea trenches along the western coast of North and Central America, and the formation of the Andes mountain range in South America.

To the south, the Pacific Plate converges with the Antarctic Plate, forming the Pacific-Antarctic Ridge. To the north, it converges with the North American Plate, resulting in the formation of the Aleutian Trench and volcanic arc.

The continuous movement of the Pacific Plate and its surrounding convergent boundaries are responsible for much of the seismic and volcanic activity in the Pacific Ring of Fire, which is home to about 75% of the world's active and dormant volcanoes.

To know more about tectonic plates refer here

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