0
R
(r-12)
>R
-
(3r + 5)
+
P
S
Solve for x:
O
What is mZP?

The amount of a sample remaining after t days is given by the equation p(1) - al2 is: 74 days.

Using this formula

P(t)=A×(1/2)^t/h

Let plug in the formula

0.6x=x ×(1/2)^t/h

0.6=(1/2)^t/100

Hence:

Log0.6=Log(1/2)^t/100

Log 0.6=t/100× log0.5

Log 0.6/Log0.5×100=t

-0.2218487/-0.30102999×100=t

0.736×100=t

t=73.6

t=74 days (Approximately)

The amount of a sample remaining after t days is: 74 days.

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Answer:

74 DAYS

Step-by-step explanation:

I DID IT ON EDGE

Answer:

12 different rectangles.

Step-by-step explanation:

I just divided 24 and got 12

Answer: -4112

Step-by-step explanation:

The letters in full are given as L, C C, C C, L, L, A, L, L, O, and M. They are identified by either reflecting them or rotating them. See below which of the elements gives the result for each.

Rotation in mathematics is defined as the act of turning an element by one or more degrees about one fixed axis or central point such that the object faces different directions each time.

According to the rules of geometry, a reflection occurs when an object is flipped into its mirror image. See the attached as an example.

Both reflections and rotation are known as transformation.

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Answer:

1 pound of rice is $2.25. Counting up the graph, - 2, 4, 6, 8, 10.

Step-by-step explanation:

You didn't add the picture so this is how I explained it.

Answer:

Step-by-step explanation:

Answer:

  4.34 inches

Step-by-step explanation:

You want the diameter of a cylinder if the stroke length is 4.5 in, and 6 of them have a volume of 400 in³.

Filling the given values into the formula, we have ...

  400 = π/4(d²)(4.5)(6)

  d² = 400(4)/(4.5·6π) . . . . . . . . . divide by the coefficient of d²

  d = 40/(3√(3π)) ≈ 4.34 . . . . . . . take the square root

The diameter is about 4.34 inches.

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Answer:

Step-by-step explanation:

Sum of supplementary angles is 180°

Find the value of x

Find the measure of ∠B

Supplementary angles have sum 180°

<B

The probability that the cat lands on its feet both times it falls out of a tree is 0.85

The probability that the cat lands on its feet is given as:

P(Feet) = 0.92

The probability that it lands on its feet twice is calculated using:

P = P(Feet) * P(Feet)

So, we have:

P = 0.92 * 0.92

Evaluate

P = 0.85

Hence, the probability is 0.85

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There are more than one solution of the equation. The solution of the equation when solved for y are 5, 2.5-4.3301i, 2.5+4.3301i.

If the equation is given a unique and single value of variable after solving, then the equation is said one solution equation. Such equation gives exactly one solution.

The three solution of an equation are-

The expression for y is given as,

y³=125

Here, y is a real number. equate the equation to zero,

y³-125=0

y³-5³=0

Use the formula of difference of two perfect cube as,

(y-5)(y²+5y+25)=0

The values of y we get after solving the equation as,

y=5, 2.5-4.3301i, 2.5+4.3301i

Thus, there are more than one solution of the equation. The solution of the equation when solved for y are 5, 2.5-4.3301i, 2.5+4.3301i.

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Using separation of variables for the differential equation, it is found that:

a) The differential equation is: [tex]\frac{dP}{dt} = kP[/tex]

b) The solution is: [tex]P(t) = 5000e^{kt}[/tex]

c) In 6 months, the population is: [tex]P(6) = 5000e^{6k}[/tex]

Population of fishes in a pond is directly proportional to amount of fishes present in the bond, hence the differential equation is:

[tex]\frac{dP}{dt} = kP[/tex]

In which k is the growth rate.

In separation of variables, we place all the factors of y on one side of the equation with dy, all the factors of x on the other side with dx, and integrate both sides.

Hence, for the differential equation in this problem:

[tex]\frac{dP}{dt} = kP[/tex]

[tex]\frac{dP}{P} = k dt[/tex]

[tex]\int \frac{dP}{P} = \int k dt[/tex]

[tex]\ln{P} = kt + P(0)[/tex]

[tex]P(t) = P(0)e^{kt}[/tex]

In which P(0) = 5000 is the initial population, hence:

[tex]P(t) = 5000e^{kt}[/tex]

In 6 months, the population is:

[tex]P(6) = 5000e^{6k}[/tex]

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Check the picture below.

Answer: A, C

Step-by-step explanation:

The measure of an incsribed angle is half the measure of the arc it subtends.

The method that was used by Isabella to pay for the CD players is a credit card.

A credit card is a line of credit that is extended by a bank to the holder of the credit card. The bank extends credit to the credit cardholder based on the holder's credit worthiness.

The holder of the credit card is expected to make payments on debts owed at the end of every month until all the debt has been repaid.

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Answer:

Isabella bought a CD player at the store. She will receive the bill at the end of the month. She plans to pay $30 each month until the bill is paid in full. How did Isabella pay for the CD player?

❌ A) cash

❌ B) check

❌ D) debit card

I Took Question Test Have Nice Day.

Answer:

-h - 6

Step-by-step explanation:

(6h + 2) + (-7h - 8) <== remove parenthesis

6h + 2 - 7h - 8 <== combine like terms

6h - 7h + 2 - 8

-h - 6

Hope this helps!

Answer: Option A

Step-by-step explanation:

Replace F with 86 then solve

86 - 32 = 54

54 × 5/9 = 30

C =30

Answer:

Step-by-step explanation:

5/9(86-32)

5/9(54)

5(6)= 30

answer is A

Answer:

What Graph?

Step-by-step explanation:

Answer:

you have to put the image of the graph

Answer:

C. $26 is the closest estimate

Step-by-step explanation:

127.59 rounded is 128

128 x 0.2 = 25.6
25.6 is closest to 26 so C is the answer

so that is the closest estimate
this should be correct! :)

Answer:

Step-by-step explanation:

Area of shaded region

  When we subtract the area of the circle from the area of square, we get the area of the 4 corners. When we divide that by 2, we get the area of 2 corners(shaded).
[tex]\sf \boxed{\text{Area of the shaded region =$\dfrac{Area \ of \ square - area \ of \ circle}{2}$}}[/tex]

Area of square = side *side

                          = 8 * 8

                          = 64 square inches

     diameter of the circle = side of the square

                                     d = 8 in

                                      r = 8/2 = 4 in

   [tex]\sf \text{Area of circle = \pi r^2}[/tex]  Area of circle = πr²

                            = 3.14 * 4 * 4

                            = 50.24 square inches

[tex]\sf \text{Area of shade region = \dfrac{64 - 50.24 }{2}}[/tex]

[tex]\sf \text{Area of the shade region = $\dfrac{64 - 50.24}{2}$}[/tex]

                                       [tex]\sf = \dfrac{13.76}{2}\\\\= 6.88 \ square inches[/tex]

Answer:

check photo for detailed analysis

Answer:

119 copies

Step-by-step explanation:

Given that,

→ 1 minute = 28 copies

Copies made in 4 minutes & 15 seconds,

→ 28 × (4 + 15/60)

→ 28 × (4 + 1/4)

→ 28 × (16+1)/4

→ 28 × 17/4

→ 476/4

→ [ 119 copies ]

Hence, the machine made 119 copies.

Answer:

check the attachment for your answer

Step-by-step explanation:

Answer:

depends?

Step-by-step explanation:

(31/2)/(1/4) or (3 1/2)/(1/4) aka (7/2)/(1/4)?

Check the picture below.

[tex]\stackrel{\textit{\LARGE Areas}}{\stackrel{two~triangles}{2\left[\cfrac{1}{2}(15)(8) \right]}~~ + ~~\stackrel{rectangle}{(25)(15)}~~ + ~~\stackrel{rectangle}{(25)(17)}~~ + ~~\stackrel{rectangle}{(25)(8)}} \\\\\\ 120~~ + ~~375~~ + ~~425~~ + ~~200\implies 1120~yd^2[/tex]

Answer:

b

Step-by-step explanation:

Using it's concept, the event that has the highest probability is given as follows:

B. The bus is from route A and is on time.

A probability is given by the number of desired outcomes divided by the number of total outcomes.

We have that out of the 110 buses, 8 are delayed from route B, hence:

P(A) = 8/110.

28 are on time from route A, hence:

P(B) = 28/110.

24 are on time from route C, hence:

P(C) = 24/110.

6 are delayed from route C, hence:
P(D) = 6/110.

Hence option B gives the highest probability.

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Answer:

B.  The bus is from route A and is on time.

Step-by-step explanation:

[tex]\large \begin{array}{| c | c | c | c |}\cline{1-4} & \sf On-Time & \sf Delayed & \sf Total\\\cline{1-4} \sf Bus\:Route\:A & 28 & 7 & 35\\\cline{1-4} \sf Bus\:Route\:B & 37 & 8 & 45\\\cline{1-4} \sf Bus\:Route\:C & 24 & 6 & 30\\\cline{1-4} \sf Total & 89 & 21 & 110\\\cline{1-4}\end{array}[/tex]

[tex]\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}[/tex]

Therefore:

[tex]\textsf{P(Route B and delayed)}=\dfrac{8}{110}[/tex]

[tex]\textsf{P(Route A and on time)}=\dfrac{28}{110}[/tex]

[tex]\textsf{P(Route C and on time)}=\dfrac{24}{110}[/tex]

[tex]\textsf{P(Route C and delayed)}=\dfrac{6}{110}[/tex]

So the event that has the highest probability is:

B.  The bus is from route A and is on time.