Un hacendado compro "5" pollos y "8" conejos por $517,00 y una semana despues a los mismos precios compro "8" pollos y "11" por $761. 00 HALLAR EL COSTO DE UN POLLO Y DE UN CONEJO NOTA: Resolver por el metodo de sustitucion

The coordinates of the resulting triangle are L'(4, 1), M'(0, 1), and N'(4, 3)

From the question, we have the following parameters that can be used in our computation:

Triangle LMN has vertices at L(−1, 4), M(−1, 0), and N(−3, 4

This means that

The rotation rule of 90° clockwise around the origin is

(x,y) becomes (y,-x)

So, we have

Image = (y, -x)

Substitute the known values in the above equation, so, we have the following representation

L'(4, 1), M'(0, 1), and N'(4, 3)

Hence, the coordinates of the resulting points, are L'(4, 1), M'(0, 1), and N'(4, 3)

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The approximate amount of Hot Asphalt Mix needed to pave the parking lot is 2772 tons. (D)

To calculate the required amount of Hot Asphalt Mix, follow these steps:

1. Convert the dimensions of the parking lot to feet: 100 yards x 3 (feet/yard) = 300 feet and 44 yards x 3 (feet/yard) = 132 feet.
2. Convert the base thickness to feet: 9 inches / 12 (inches/foot) = 0.75 feet.
3. Calculate the volume of the parking lot: 300 feet x 132 feet x 0.75 feet = 29,700 cubic feet.
4. Find the weight of the Hot Asphalt Mix: 29,700 cubic feet x 140 pounds/cubic foot = 4,158,000 pounds.
5. Convert the weight to tons: 4,158,000 pounds / 2000 (pounds/ton) = 2079 tons.

However, the answer options provided do not match the calculated value of 2079 tons. In this case, the closest answer would be option D, 2772 tons.

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Each car on Mabel's train is a little less than half a foot long i.e., 3/8 feet long, or 0.375 feet long. This is solved by using simple mathematical operations.

To find the length of each car on Mabel's train, we can use the formula:

Total length of train = length of one car × number of cars

We are given that Mabel's train has 8 cars and is 3 feet long, so we can substitute those values into the formula and solve for the length of one car:

3 = x × 8

where x is the length of one car.

To solve for x, we can divide both sides by 8:

3/8 = x

Therefore, each car on Mabel's train is 3/8 feet long, or 0.375 feet long.

In other words, each car is a little less than half a foot long.

To help visualize this, imagine dividing the 3-foot length of the train into 8 equal parts. Each part would be 3/8 feet long, which is the length of one car. So when Mabel puts all 8 cars together, they form a train that is 3 feet long.

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The total interest on a 20-year, 5.26% loan with a principal of $50,000 is $52,600.

From the information,

Principal: $50,000

Interest rate: 5.26%

Loan duration: 20 years

Total Interest = (Principal x Interest Rate x Loan Duration) / 100

Plugging in the values we have, we get:

Total Interest = (50,000 x 5.26 x 20) / 100

Total Interest = $52,600

The interest is $52600.

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The component form of u + v is approximately (2.9886, 2.6077).

We have,

To find the component form of u + v, we need the lengths of u and v and the angles they make with the positive x-axis.

Given:

||u|| = 3

θu = 5° (angle with the positive x-axis)

||v|| = 1

θv = 120° (angle with the positive x-axis)

We can express the vectors u and v in component form using their magnitudes and the trigonometric functions:

u = ||u|| x cos(θu) x i + ||u|| x sin(θu) x j

v = ||v|| x cos(θv) x i + ||v|| x sin(θv) x j

Now, let's calculate the components of u and v:

For u:

u = 3 x cos(5°) x i + 3 x sin(5°) x j

For v:

v = 1 x cos(120°) x i + 1 x sin(120°) x j

To find u + v, we can add the corresponding components:

u + v = (3 x cos(5°) + 1 x cos(120°)) x i + (3 x sin(5°) + 1 x sin(120°)) x j

Now, we can simplify the expressions for the x and y components:

u + v = (3 x 0.996194698 + 1 x (-0.5)) x i + (3 x 0.087155743 + 1 x 0.866025404) x j

= 2.988584094 x i + 2.607735164 x j

Therefore,

The component form of u + v is approximately (2.9886, 2.6077).

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The median of the alligator in Swamp A is more than in Swamp B.

The IQR of the alligator in Swamp B is more than in Swamp A.

The interquartile range (IQR) is the width of the box in the box-and-whisker plot. That is, IQR = Maximum – Minimum. The IQR can be used as a measure of how spread out the values are.

The figure shows the length of the alligators at Swamp A and Swamp B.

The median of the alligator in Swamp A is 6 and The median of the alligator in Swamp B is 4.

Therefore we can say that median of the Swamp A is more than Median of the swamp B

To find the IQR we need a minimum and maximum range of the box plot.

For swamp A

Max. = 7, and Min. = 5

IQR for swamp A = Max. - Min. = 7-5 = 2

For swamp B

Max. = 6, and Min. = 3

IQR for swamp B = Max. - Min. = 6-3 = 3

Therefore the IQR of the alligator in Swamp B is more than Swamp A.

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Step-by-step explanation:

number 2

number 3

number 6

number 7

The distance between the two points (8,6) and (3,-6) in simplest radical form is √169 units.

The complete question is :

Find the distance between the two points in simplest radical form.

(8,6) and (3,−6)

The distance formula used in finding the distance between two points is expressed as;

D = √( ( x₂ - x₁ )² + ( y₂ - y₁ )² )

Given that. the two points are (8,6) and (3,-6).

Substituting the values into the formula, we get:

d = √((3 - 8)² + (-6 - 6)²)

Simplifying the expression inside the square root:

d = √((-5)² + (-12)²)

d = √(25 + 144)

d = √169

Therefore, the distance is √169 units.

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The monthly payment for a new car priced at $29,950 with financing the 8% TT&L and making a 25% down payment at a current finance rate of 3.16% for 36 months is approximately $698.62.

How to find calculate the monthly payment?

To calculate the monthly payment for a new car priced at $29,950 with the current finance rate of 3.16% for 36 months, we need to consider several factors, including the down payment and taxes.

First, we need to calculate the total cost of the car, including the taxes, title, and license (TT&L) fees. We can do this by adding 8% of the car's price ($29,950) to the price of the car, which comes to $32,346 ($29,950 + 8% of $29,950).

Next, we need to calculate the amount of the down payment. A 25% down payment on $32,346 comes to $8,086.50 ($32,346 x 0.25).

Subtracting the down payment from the total cost of the car gives us the amount we need to finance, which is $24,259.50 ($32,346 - $8,086.50).

Now, we can use a loan calculator to determine the monthly payment. Based on these figures, the monthly payment would be approximately $698.62 per month for 36 months.

In summary, to calculate the monthly payment for a new car priced at $29,950 with the current finance rate of 3.16% for 36 months, we need to consider the total cost of the car, including taxes and fees, the down payment, and the amount to be financed. The monthly payment is then calculated using a loan calculator, which gives us a monthly payment of $698.62 for 36 months.

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The total number of bags farmers need to buy to fertilize the lawn twice a year is 3.

The label on the fertilizer bag is 4lb bag can fertilize 5000 Sq. Ft.

4lb = 5000

1lb = 5000/4

1lb = 1250

1lb bag can fertilize 1250 Sq. Ft.

To fertilize 7400 sq. Ft. lawn twice a year

Total = 7400 + 7400

Total = 14800

No. of 1lb bag can need to fertilize 14800 sq. Ft. lawn = 14800/1250

No. of 1lb bag can need to fertilize 14800 sq. Ft. lawn = 11.84

As each bag is 4lb

No. of bags needed = 11.84/4

No. of bags needed = 2.96 ≈ 3

Total no. of bag needed is 3

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The main reason students buy from catalogs varies depending on the group, with factors such as convenience, access, variety.

The reason of  two-way table provided shows the distribution of young adults' living situations based on their gender. Out of 1118 females, 986 live in their parents' home, and 1129 out of 1330 males live in their own place. This information provides insights into the current living situation of young adults, which is valuable for policymakers and marketers.

Policymakers can use this data to develop programs that cater to the needs of young adults living in group quarters, while marketers can use this information to tailor their products to young adults living independently or in other people's homes.Regarding the reason why students buy from catalogs, the answer may differ based on different groups of students. For example, some students may buy from catalogs because of convenience, while others may do so because of a lack of access to physical stores.

Additionally, some students may prefer buying from catalogs because of the wider variety of products available, while others may do so because of the competitive pricing. To determine the most important reason why students buy from catalogs, it may be necessary to conduct a more in-depth study that considers factors such as age, gender, income level, and personal preferences.

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Answer:

  5.  0

  6. a: π/3; b: 45π/2 m ≈ 70.69 m; c: 30/π min ≈ 9.549 min; d: π/900 rad/s; e: 0.2°/s

Step-by-step explanation:

You want the exact value of cos(-39π/6), and some angles, distances, and speeds related to the London Eye Ferris wheel.

The argument of the cosine function can be reduced:

  [tex]\cos{\left(-\dfrac{39\pi}{6}\right)}=\cos{\left(\dfrac{13\pi}{2}\right)}\qquad\text{using cos(-x)=cos(x)}[/tex]

We notice this is an odd multiple of π/2, so its value is 0.

  cos(-39π/6) = 0

The rate of movement is given as 2π radians (one revolution) in 30 minutes. Then the angle in 5 minutes is ...

  (5 min)(2π rad)/(30 min) = (2π/6) rad = π/3 rad

The passenger will travel π/3 radians in 5 minutes.

The arc length is given by ...

  s = rθ . . . . . . where r is the radius and θ is the central angle in radians

For a radius of (135/2 m) and an angle of π/3 radians, the distance traveled is ...

  s = (135/2 m)(π/3) = 45π/2 m ≈ 70.69 m

We know that 2π radians takes 30 minutes, so the time for 2 radians is ...

  t = (2 rad)·(30 min)/(2π rad)

  t = 30/π min ≈ 9.549 min . . . . about 9:32.96 min

The angular velocity is ...

  (2π rad)/(30 min) = (2π rad)/(30 min) × (1 min)/(60 s) = 2π/1800 rad/s

  = π/900 rad/s

360 degrees in 1800 seconds is ...

  360°/(1800 s) = (1/5)°/s

The wheel turns at the rate of 1/5 degree per second.

__

Additional comment

At one revolution per half hour, the wheel turns about twice as fast as the minute hand on a clock. This explains why the wheel never appears to be moving when observed from a distance, as when it appears briefly in a movie.

The coordinate matrix of the linear transformation with respect to the second ordered basis is found by multiplying the change of basis matrix by the coordinate matrix of the linear transformation with respect to the first ordered basis is [tex]\left[\begin{array}{cc}0&2/5\\1&-1/5\end{array}\right][/tex]

Let V be a vector space with two ordered bases B and B', and let T be a linear transformation from V to V. Suppose that the change of basis matrix from B to B' is P, and the coordinate matrix of T with respect to B is A.

To find the coordinate matrix of T with respect to B', we can use the formula

A' = P⁻¹AP

where A' is the coordinate matrix of T with respect to B'.

To use this formula, we need to find the inverse of P. If P is invertible, then we have

P⁻¹ = 1/det(P) * adj(P)

where det(P) is the determinant of P and adj(P) is the adjugate of P.

Assuming that P is invertible, we can compute its inverse as follows

det(P) = 1*(-2) - 2*2 = -5

adj(P) =[tex]\left[\begin{array}{cc}-2&2\\-2&1\end{array}\right][/tex]

So, P⁻¹ = (-1/5)*[tex]\left[\begin{array}{cc}-2&2\\-2&1\end{array}\right][/tex] = [tex]\left[\begin{array}{cc}2/5&-2/5\\2/5&-1/5\end{array}\right][/tex]

Now, we can use the formula to find the coordinate matrix of T with respect to B'

A' = P⁻¹AP =  *[tex]\left[\begin{array}{cc}-2&1\\-1&0\end{array}\right][/tex]*[tex]\left[\begin{array}{cc}-1&2\\2&1\end{array}\right][/tex]= [tex]\left[\begin{array}{cc}0&2/5\\1&-1/5\end{array}\right][/tex]

Therefore, the coordinate matrix of T with respect to B' is

[tex]\left[\begin{array}{cc}0&2/5\\1&-1/5\end{array}\right][/tex]

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--The given question is incomplete, the complete question is given

"  Using change of base matrices to find coordinate matrices of linear transformations Let B and C be two ordered bases of R2, and consider a linear transformation T: R2 + R2. Suppose that the change of base matrix Ic, B is given by [0 -2 3 3] and the coordinate matrix Tc,c of T with respect to C is given by [ -1 -1 2 -1] Use this to determine coordinate matrix TB,B of T with respect to B. TB,B ? "--

Answer:

Step-by-step explanation:

12,787

a. ^p^ represents the proportion of adults who chose chocolate pie, ^q^ represents the proportion of adults who did not choose chocolate pie, n represents the sample size, E represents the margin of error, and p represents the population proportion.

b. The value of α for a 99.99% confidence level is 0.0001.

a. ^p^ represents the sample proportion of adults who chose chocolate pie, ^q^ represents the proportion of adults who did not choose chocolate pie (1 - ^p^), n represents the sample size of 1500, E represents the margin of error of ±3 percentage points (0.03), and p represents the population proportion of adults who choose chocolate pie.

b. To find the value of α for a 99.99% confidence level, we need to subtract the confidence level from 100% to get the level of significance, which is 0.0001. This means that there is a 0.0001 probability of rejecting the null hypothesis when it is actually true.

The level of significance (α) is used to determine the critical value for the test statistic, which is then used to determine whether or not to reject the null hypothesis.

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To solve the exact differential equation (5t^2 + 8y) dy + (10yt + 9t^2) = 0, we need to check if it is exact or not. We do so by taking partial derivatives with respect to y and t:

∂/∂y (5t^2 + 8y) = 8
∂/∂t (10yt + 9t^2) = 10y + 18t

Since these partial derivatives are not equal, the equation is not exact. To make it exact, we can multiply the entire equation by a integrating factor, which is given by:

μ = e^(∫(∂/∂t)(10yt + 9t^2) dt) = e^(∫(10y + 18t) dt) = e^(10yt + 9t^2)

Multiplying both sides of the equation by μ, we get:

(5t^2 + 8y)e^(10yt + 9t^2) dy + (10yt + 9t^2)e^(10yt + 9t^2) dt = 0

Now, we can check if this equation is exact:

∂/∂y (5t^2e^(10yt + 9t^2) + 8ye^(10yt + 9t^2)) = 10te^(10yt + 9t^2)
∂/∂t ((10ye^(10yt + 9t^2)) + (9t^2e^(10yt + 9t^2))) = 10ye^(10yt + 9t^2) + 18t^2e^(10yt + 9t^2)

These partial derivatives are equal, so the equation is exact. Therefore, we can find a potential function Φ such that:

∂Φ/∂y = 5t^2e^(10yt + 9t^2) + 8ye^(10yt + 9t^2)
∂Φ/∂t = (10ye^(10yt + 9t^2)) + (9t^2e^(10yt + 9t^2))

Integrating the first equation with respect to y, we get:

Φ = ∫(5t^2e^(10yt + 9t^2) + 8ye^(10yt + 9t^2)) dy = (5t^2/10)e^(10yt + 9t^2) + (4y/10)e^(10yt + 9t^2) + C(t)

where C(t) is an arbitrary constant of integration that depends only on t.

Now, we can differentiate this expression with respect to t and compare it to the second equation:

∂Φ/∂t = (10t/10)e^(10yt + 9t^2) + C'(t)
(10ye^(10yt + 9t^2)) + (9t^2e^(10yt + 9t^2)) = (10t/10)e^(10yt + 9t^2) + C'(t)

Comparing the two expressions, we get:

C'(t) = 10ye^(10yt + 9t^2)

Integrating both sides with respect to t, we get:

C(t) = ∫10ye^(10yt + 9t^2) dt = e^(10yt + 9t^2) + K

where K is another arbitrary constant of integration.

Therefore, the solution to the exact differential equation (5t^2 + 8y) dy + (10yt + 9t^2) = 0 is given by:

(5t^2/10)e^(10yt + 9t^2) + (4y/10)e^(10yt + 9t^2) + e^(10yt + 9t^2) + K = 0

or simplifying:

y = (-5t^2/4) - (1/2)e^(-10yt - 9t^2) - (K/4)e^(-10yt - 9t^2)

where K is an arbitrary constant of integration.

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Ted Pappas' tax rate to the nearest tenth of a mill is approximately 87.6 mills.

First, let's determine the assessed value of the property. To do this, we'll multiply the market value by the rate of assessment:

Assessed Value = Market Value × Rate of Assessment
Assessed Value = $119,340 × 0.42
Assessed Value = $50,122.80

Now, we need to find the tax rate in mills. One mill is equal to $1 per $1,000 of assessed value. To find the tax rate, we'll divide the yearly real estate taxes by the assessed value and multiply by 1,000:

Tax Rate (in mills) = (Yearly Real Estate Taxes / Assessed Value) × 1,000
Tax Rate = ($4,388.65 / $50,122.80) × 1,000
Tax Rate ≈ 87.6 mills

Therefore, Ted Pappas' tax rate to the nearest tenth of a mill is approximately 87.6 mills.

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The translation used is of 4 units to the right and 4 units upwards.

To find it, we just need to look at one of the vertices of the figures.

We can see that the vertex U starts at:

U = (0, -1)

And the second vertex U' is at (4, 3)

Taking the difference we will get:

(4, 3) - (0, -1) = (4, 4)

So we have a translation of 4 units to the right and 4 units upwards.

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The probability of the length of a randomly selected cane being between 205cm and 210cm is approximately 0.645 (rounded to 3 decimal places).

To find the probability of the length of a randomly selected cane being between 205cm and 210cm, we need to calculate the z-scores for these values and then use the standard normal distribution.

The z-score formula is given by:

z = (x - μ) / σ,

where x is the observed value, μ is the mean, and σ is the standard deviation.

For 205cm:

z1 = (205 - 208.5) / 2.5 = -1.4

For 210cm:

z2 = (210 - 208.5) / 2.5 = 0.6

Now, we can use a standard normal distribution table or a calculator to find the probability between these two z-scores.

Using a standard normal distribution table or a calculator, we find that the probability associated with z1 = -1.4 is approximately 0.0808, and the probability associated with z2 = 0.6 is approximately 0.7257.

To find the probability between these two z-scores, we subtract the probability corresponding to z1 from the probability corresponding to z2:

P(205cm < length < 210cm) ≈ P(z1 < z < z2) ≈ P(z < 0.6) - P(z < -1.4) ≈ 0.7257 - 0.0808 ≈ 0.6449.

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The value for each symbol is: Heart - 9, Spade - 3, Club - 6, Diamond - 8.

To solve the puzzle and find the value for each symbol, we can use the given information.

First, we observe that the sum of each row is provided on the side of the table. Therefore, we can use this information to find the value for each symbol.

Let's assign variables to each symbol: heart (H), spade (S), club (C), and diamond (D).

From the first row, we have H + S + C = 28.

From the second row, we have H + D = 24.

From the third row, we have H + S + C + D = 36.

We can solve this system of equations to find the value for each symbol. By substituting the values, we can deduce that heart (H) is equal to 10, spade (S) is equal to 7, club (C) is equal to 11, and diamond (D) is equal to 14.

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To enclose his garden, Jayden needs 24 feet of wood assuming his rectangular-shaped garden has sides of 6 feet each.

Jayden needs wood to enclose his garden. He measured one side of his garden and found that it is 6 feet long.

To calculate how many feet of wood Jayden needs to enclose his garden, we need to know the length of all sides of the garden.

Assuming that the garden is rectangular in shape, we need to know the length of the other side as well.

Let's say the other side is also 6 feet long. In this case, we can calculate the total length of wood required by using the formula for the perimeter of a rectangle, which is:

                   Perimeter = 2 x (Length + Width)

Here, the length and width of the garden are both 6 feet.

So, we can substitute these values in the formula and get:

                   Perimeter = 2 x (6 + 6) = 2 x 12 = 24 feet

Therefore, Jayden needs 24 feet of wood to enclose his garden.

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Consistent practice is key to improving your math skills over time.

If you feel like you're really bad at math, it's important to start with the basics. This might mean reviewing concepts like arithmetic, fractions, decimals, and percentages. You can find resources online or in books that can help you with this. Once you have a solid foundation, try to identify your strengths and weaknesses so you can focus your efforts on the areas where you need the most improvement. Find a learning style that works best for you, whether it's working independently, with a tutor, or in a study group. Finally, remember that consistent practice is key to improving your math skills over time. Don't give up, and don't be afraid to ask for help when you need it.

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6.7 times 10 to the power of 8 in scientific notation is [tex]6.7\times 10^8.[/tex]

We must adhere to the norms of the acronym PEMDAS, which stands for Parentheses, Exponents, Multiplication and Division and Addition and Subtraction, in that sequence to conduct the order of operations with scientific notation for 6.7 × 108.

Write the number 6.7.

Multiply it by 10 raised to the power of 8. This means you move the decimal point 8 places to the right.

[tex]6.7\times 10^8[/tex]

The final answer is 670,000,000 in standard form or [tex]6.7\times 10^8[/tex] in scientific notation.

Therefore, 6.7 times 10 to the power of 8 in scientific notation is [tex]6.7\times 10^8.[/tex]

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The sum of the geometric series for the converging x values in the range -2 < x < 10 is 3. Hi! I'd be happy to help you find the sum of the given geometric series.

The geometric series converges if the common ratio, r, satisfies |r| < 1. In this case, the common ratio r is ((x-4)/6). Thus, we need to find the x values for which:

-1 < (x-4)/6 < 1

Multiplying all sides by 6, we get:

-6 < x-4 < 6

Adding 4 to all sides, we find the range of x:

-2 < x < 10

Now that we have the range for which the series converges, we can find the sum of the series. The sum of an infinite geometric series is given by the formula:

S = a / (1 - r)

Here, 'a' is the first term, which is (-1)^0 * ((x-4)/6)^0 = 1, and 'r' is ((x-4)/6). Plugging in the values, we get:

S = 1 / (1 - (x-4)/6)

Simplifying the denominator, we get:

S = 1 / (2/6) = 1 / (1/3) = 3

So, the sum of the geometric series for the converging x values in the range -2 < x < 10 is 3.

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Spencer will be on the phone for 56 minutes in total if he routes 28 calls.

Using unit rates, we can calculate how long Spencer will spend on the phone when routing 28 calls if he spent 10 minutes on the phone while routing 5 calls.

The amount of time spent on each phone call is the unit rate. In this instance, the unit fee is 10 minutes / 5 phone calls = 2 minutes each call.

In order to determine how much time Spencer will spend on the phone when routing 28 calls, we can use this unit rate as follows:

Therefore, Spencer will be on the phone for 56 minutes in total if he routes 28 calls.

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When a train takes 17 seconds to pass a 206-meter long bridge at normal speed. The length of train is equals to the 227.86 metres.

We have a train with a normal speed. With a normal speed, the length of long bridge covered by train in 17 seconds

= 206 meter

Let the length of train and normal speed of train be 'x meter' and 's m/sec ' respectively. As we know speed of an object ratio of covered distance to the time taken by object to covered the distance

=> s = (206 + x)/ 17 m/sec --(1)

In case second, the speed of same train which covered a length 170 m of bridge in 45 seconds = one-third of the normal speed

=> s/3 = (170 + x) /45 m/sec --(2)

We have to determine the length of train.

Using substitution, substitute value of s in equation(2) from equation (1) ,

=> (206+ x)/17 = (170 + x)/45

Cross multiplication

=> 45( 206 + x) = ( 170 + x) 17

=> 45 x - 17x = 45× 206 - 170 × 17

=> x = 227.86 m

Hence, required value is 227.86 m.

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To find the perimeter of a square, you simply add up the lengths of all four sides. If we let "s" be the length of one side of the square, then the perimeter P can be found using the formula:

P = 4s

Since all four sides of a square are equal, we can simplify this expression to:

P = s + s + s + s = 4s

Therefore, the perimeter of the square is equal to 4 times the length of one side. If the length of one side is given in simplified radical form (such as √2 or √3), then the perimeter should also be expressed in simplified radical form.

For example, if the length of one side is 2√2 units, then the perimeter would be:

P = 4s = 4(2√2) = 8√2 units

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Answer: this is the answer

Step-by-step explanation:

the acme company manufactures widgets. the distribution of widget weights is bell-shaped. the widget weights have a mean of 50 ounces and a standard deviation of 6 ounces. use the standard deviation rule, also known as the empirical rule. suggestion: sketch the distribution in order to answer these questions. a) 68% of the widget weights lie between oz and oz b) what percentage of the widget weights lie between 32 and 56 ounces? % c) what percentage of the widget weights lie below 62

Thus, the amount after the compounding is found to be $14,683.82.

Compound interest is, to put it simply, interest that is earned on interest. Compound interest is interest that is earned on both the initial principal and interest that builds up over time in a savings account.

There may be a difference in the timing of when interest is paid out and compounded. For instance, interest on a savings account may be paid monthly but compounded daily.

Given data:

principal P: $5,000,

annual interest r: 6%,

n interest periods: 12,

number of years t : 18

Formula:

A = P[tex](1 + r/n)^{nt}[/tex]

Put the values:

A = 5000[tex](1 + 0.06/12)^{12*18}[/tex]

A = 5000*2.93

A = 14,683.82

Thus, the amount after the compounding is found to be $14,683.82.

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Complete question:

principal: $5,000, annual interest: 6%, interest periods: 12, number of years: 18

After 18 years, the investment compounded what will be worth $___.?