There are 90 children in year 6 at woodland junior school


they are split into three classes


class


number n class


27


6m


6p


33


6t


30


each child chose football or netball or hockey.


in 6m, 13 children chose hockey.


the rest of the class were split equally between football and netball.


in 6p, 9 children chose netball


twice as many children chose football as chose hockey


in 6t the ratio of children who chose


football to netball to hockey was 1:2:3


complete this table


class


number in class


football


netball


hockey


6м


27


13


6p


33


6t


30

To apply the pigeonhole principle, we need to determine the number of pigeonholes and the number of pigeons. The pigeonhole principle cannot be applied to this question.

In this case, the"  holes" are the high minidresses and the" lockers" are the ranges of  particular records. Let's assume that the range of  particular records is from 6  bases( 72  elevation) to 7  bases( 84  elevation).   The difference between the upper and lower bounds of the range is

84- 72 =  12  elevation.

We can divide this range into five subintervals of length2.4  elevation( 72,74.4),(74.4,76.8),(76.8,79.2),(79.2,81.6), and(81.6, 84).  

Since there are only five subintervals, but we've three high minidresses, it isn't  inescapably true that two of the  platoon members must have  particular records that are within four  elevation of each other. For  illustration, if the three high minidresses have  particular records of 6  bases 3  elevation( 75  elevation), 6  bases 7  elevation( 79  elevation), and 7  bases( 84  elevation),  also none of them have  particular records within four  elevation of each other.

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The equations that will find the distance between the lions and giraffes include the following:

B. 11² + 16² = c².

D. 11(2) + 16(2) = 2.

In Mathematics and Science, distance can be defined as the amount of ground that is travelled by a physical object or body over a particular period of time and speed, irrespective of its direction, starting point or ending point.

Mathematically, the distance traveled by both the lions and giraffes when they are positioned one (1) unit apart can be calculated by using this equation:

11² + 16² = c²

Additionally, the distance traveled by both the lions and giraffes when they are positioned two (2) unit apart can be calculated by using this equation:

11(2) + 16(2) = c

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Answer: attach an image

Step-by-step explanation:

To find the principal, we can use the formula for simple interest:

I = P*r*t

where I is the interest, P is the principal, r is the interest rate, and t is the time in years.

We need to convert 82 days to years by dividing it by 365 (the number of days in a year):

t = 82/365

t = 0.2247

Now we can plug in the values we know and solve for P:

67.14 = P*0.0625*0.2247

P = 67.14/(0.0625*0.2247)

P = 1900

Therefore, the principal is $1900.

The correct relationship which does not represent a direct proportion is,

⇒ A dog groomer charges $15 per hour.

Given that;

The graph is shown relation between number of minutes and Distance.

Take two points on the line are,

(2, 100) and (4, 150)

Hence, From graph we get;

The equation of line is,

⇒ y - 100 = (150 - 100)/ (4 - 2) (x - 2)

⇒ y - 100 = 25 (x - 2)

⇒ y - 100 = 25x - 50

⇒ y = 25x - 50 + 100

⇒ y = 25x + 50

Thus, The correct relationship which does not represent a direct proportion is,

⇒ A dog groomer charges $15 per hour.

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There are 30 zeros in the mass of the sun which is 1.9891 x 10³⁰ kg when it is written in standard notation. The correct answer is option B.

To determine how many zeros are in the mass of the sun (1.9891 x 10³⁰ kg) when it is written in standard notation, you first need to recognize that the provided mass is not written correctly. It should be written as 1.9891 x 10^n kg, where n is an integer representing the exponent.

The actual mass of the sun is 1.9891 x 10³⁰ kg. When written in standard notation, this number would be:

1,989,100,000,000,000,000,000,000,000,000 kg

There are 30 zeros in this number when written in standard notation.

So, the correct answer is B) 30.

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Answer:

Step-by-step explanation:

If the number of minutes used is less than 625 per month, it is more affordable to use International Links if not, you can go for World Connections.

Let us assume that the number of minutes used = x

Cost per minute =  18 cents

Total cost for International calls = 0.18x

Basci cahrge =  50 per month

If we use x number of minutes for calls for world connections then the total cost will be:

50 + 0.10x

To find the value of x where International Links cost is less than the total cost for World Connections

0.18x < 50 + 0.10x

0.08 < 50

8x < 50

x < 625

Therefore, we can infer that if the number of minutes used is less than 625 per month, it is cheaper to use International Links.

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The volume of the diamond is  609.3 cm³.

To find the volume of the diamond, we can use the formula:

Volume = Mass / Density

Given:

Mass = 2138.7 grams

Density = 3.51 g/cm³

Substituting these values into the formula:

Volume = 2138.7 g / 3.51 g/cm³

Calculating the division:

Volume ≈ 609.3 cm³

Therefore, the volume of the diamond is approximately 609.3 cm³.

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The value of the rate of change when we put a glass of water at room temperature is 1/3.

The pace at which one quantity changes in relation to another quantity is known as the rate of change function. Simply said, the rate of change is calculated by dividing the amount of change in one thing by the equal amount of change in another.

The connection defining how one quantity changes in response to the change in another quantity is given by the rate of change formula. The formula for calculating the rate of change from y coordinates to x coordinates is y/x = (y2 - y1)/. (x2 - x1 ).

Rate of change  = change in temperature / time

= 10-5/15

=5 / 15

= 1/3

Therefore, the Rate of change is 1/3.

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Complete question;

What is the value of the rate of change when we put a glass of water at room temperature in the freezer for 15 minutes, what is its temperature at 5 minutes and then at 10 minutes.

Answer:

12

Step-by-step explanation:

20-(5+(9-6)) = 20-(5+(3)) = 20-(8) = 12.

Alternatively, rewrite the question without parenthesis.

20-(5+(9-6)) = 20-(5+9-6) = 20-5-9+6 = 12.

Answer:

If they were both charged today, it would be on the sixth day that they were actually charging at the same time

If you do not replace the marble after the first draw, the probability calculation depends on whether you are dealing with a dependent or an independent event.

The possibility or chance of an event occurring is measured by probability. It is a number between 0 and 1 (inclusive), where 0 denotes an impossibility and 1 denotes a certainty. By dividing the number of favorable outcomes by the total number of potential outcomes, the probability of an occurrence is determined. The field of mathematics known as probability studies the possibility that a certain event will take place. It is a way to quantify the possibility or likelihood that something will really happen.

For an independent event, assuming that the first draw had no bearing on the outcome of the second draw, in the case of an isolated occurrence, the chance of drawing a specific marble on the second draw would be the same as the likelihood of drawing that same marble on the first draw. For a dependent event, the outcome of the first draw would determine the possibility of drawing a specific marble on the second draw.

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The value of dt/dN when N = 15 is -0.00509.

We are given the equation t = 7,286.9 - 1,252 ln(N/IV) which relates the number of years t that must pass before N grams of a radioactive element remain. We want to find the rate of change of t with respect to N, i.e., dt/dN when N = 15.

We can start by taking the derivative of both sides of the equation with respect to N:

dt/dN = -1252 / (N*ln(2))

Now we can substitute N = 15 into this equation to get:

dt/dN = -1252 / (15*ln(2))

Evaluating this expression, we get dt/dN ≈ -0.00509 (rounded to 2 decimal places). Therefore, the rate of change of t with respect to N when N = 15 is approximately -0.00509 years per gram.

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The ladder makes an angle of approximately 82 degrees with the ground when it is extended to a length of 18 feet and the bottom of the ladder is 4.5 feet from the base of the building.

To determine the angle that the ladder makes with the ground, we can use trigonometry. Let x be the height of the ladder when it is leaned against the building. Then, using the Pythagorean theorem, we have: [tex]x^{2}[/tex] + [tex]4.5^{2}[/tex] = [tex]18^{2}[/tex]

Solving for x, we get: x = sqrt([tex]18^{2}[/tex] - [tex]4.5^{2}[/tex]), x ≈ 17.29

Therefore, the ladder makes an angle θ with the ground such that: sin θ = opposite/hypotenuse = x/18, θ = arcsin(x/18)

Substituting x ≈ 17.29, we get: θ ≈ 81.99 degrees

Therefore, the ladder makes an angle of approximately 82 degrees with the ground when it is extended to a length of 18 feet and the bottom of the ladder is 4.5 feet from the base of the building.

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Answer:

B f(x)=1(8)^x

Step-by-step explanation:

1 is the 0 value, you can see it's exponential by the rapid growth and how it grows by a lot each time

Both Zola and Amir are correct in writing the area of the rectangle. They have simply used different ways of expressing the same value.

Zola and Amir have both written the area of a rectangle using different algebraic expressions.

Zola wrote the area of the rectangle as `2a + 3a + 4a`, which can be simplified using the distributive property of multiplication:

2a + 3a + 4a = (2 + 3 + 4)a

Therefore, Zola's expression simplifies to `(2 + 3 + 4)a`, which is the same as Amir's expression.

Amir wrote the area of the rectangle as `(2 + 3 + 4) a`, which can also be simplified:

(2 + 3 + 4) a = 9a

Therefore, Amir's expression simplifies to `9a`, which is the same as the sum of the terms in Zola's expression.

Therefore, both Zola and Amir are correct in writing the area of the rectangle. They have simply used different ways of expressing the same value.

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Answer:16/45 of his yarn

Step-by-step explanation:

8/9 x 2/5 = 16/45

Step-by-step explanation:

perimeter of triangle=22 cm

AB+BC+CA=22cm

AB+4+AB =22cm (given,AB=AC)

2AB+4cm=22cm

2AB=22-4cm

2AB=18

AB=18÷2

AB=9cm

The total amount of money Victoria will have in her bank account after x years can be modeled by the function f(x) = 200 * (1.05)ˣ.

To model the total amount of money Victoria will have in her bank account after depositing her $200 and accruing interest over time, we can combine the two functions h(x) and s(x).

We can use the following formula to represent the total amount of money Victoria will have in her bank account after x years:

f(x) = h(x) + h(x) * s(x)

where h(x) represents the $200 that Victoria has saved at home, and h(x) * s(x) represents the amount of interest accrued on that $200 in x years according to the function s(x).

The justification for this formula is that the total amount of money Victoria will have in her bank account after x years is the sum of the initial amount of $200 and the interest accrued on that amount over x years.

The interest accrued can be calculated by multiplying the initial amount by the interest rate function s(x).

For example, if Victoria leaves her $200 in the bank for 5 years, the total amount of money she will have in her account can be calculated using the formula:

f(5) = h(5) + h(5) * s(5) = 200 + 200 * (1.05)⁴ ≈ $273.04

Therefore, the total amount of money Victoria will have in her bank account after x years can be modeled using the function f(x) = h(x) + h(x) * s(x).

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The difference in the proportions of firstborn or only children for the two populations from which these samples were drawn is 0.16.The bound for the error of estimation is 95% confidence that the true difference in proportions of firstborn or only children for the two populations is between 0.058 and 0.262.

To estimate the difference in the proportions of firstborn or only children for the two populations, we can use the sample proportions and apply the formula:

p1 - p2 = (x1/n1) - (x2/n2)

where p1 and p2 are the true population proportions, x1 and x2 are the numbers of firstborn or only children in the samples, and n1 and n2 are the sample sizes.

The sample proportions,

p1 = x1/n1 = 0.7

p2 = x2/n2 = 0.54

Substituting these values into the formula,

p1 - p2 = (x1/n1) - (x2/n2) = 0.7 - 0.54 = 0.16

Therefore, we estimate that the difference in the proportions of firstborn or only children for the two populations is 0.16.

To find a bound for the error of estimation, we can use the formula:

E = z sqrt(p1*(1-p1)/n1 + p2*(1-p2)/n2)

where E is the margin of error, z is the critical value for the desired level of confidence (we'll use z = 1.96 for a 95% confidence interval), and p1 and p2 are the sample proportions.

Substituting the given values, we get:

E = 1.96sqrt(0.7(1-0.7)/180 + 0.54*(1-0.54)/100) ≈ 0.102

Therefore, we can say with 95% confidence that the true difference in proportions of firstborn or only children for the two populations is between 0.058 and 0.262

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The slope at the given points are -1/36 and -1/16 respectively.

Given is a function f(x) = 1/x+6 we need to find the slope of the function,

The slope of a function is given by dy/dx, therefore,
dy/dx = -1/(x+6)²

Therefore, at point (0, 1/6),

The slope = -1/(0+6)² = -1/36

At point (-2, 1/4),

The slope = -1/(-2+6)² = -1/16

Hence the slope at the given points are -1/36 and -1/16 respectively.

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An interest rate of approximately 2.40% per annum, compounded annually, is required to double an investment in 29 years.

Let "r" be the annual interest rate, then the investment will double after 29 years if (1 + r)^29 = 2. Solving this equation, we get r ≈ 0.0240 or 2.40% (rounded to two decimal places) as the required annual interest rate. This means that if the investment is compounded annually at this rate, it will double after 29 years.

Alternatively, we can use the formula for compound interest, A = P(1 + r/n)^(nt), where A is the future value, P is the present value, r is the annual interest rate, n is the number of times interest is compounded per year, and t is the number of years.

We want to find the interest rate, r, that will double the investment, so we can set A = 2P, t = 29, n = 1 (compounded annually), and solve for r. This gives us r ≈ 0.0240 or 2.40%.

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The data sets represent the answers of twenty students in Class A and twenty students in Class B regarding the number of hours they took to prepare for an exam. These data sets are important because they help us understand the study habits and time allocation of the students in each class.

To analyze the data sets, first, collect the data from each student in both classes. Record the number of hours they took to prepare for the exam, ensuring you have 20 responses from Class A and 20 from Class B. Then, you can compute the average, or mean, time spent for each class by summing up the hours reported by all students in each class and dividing by 20.

Next, compare the averages for Class A and Class B to determine if there is a significant difference in the time spent preparing for the exam. Additionally, you can calculate other statistical measures such as median and mode to gain further insight into the data sets.

Furthermore, analyzing the distribution of the data, such as the range, will provide information on the variability of the time spent studying in each class. This can help identify any trends or patterns in the students' preparation time.

In conclusion, the data sets representing the number of hours spent by students in Class A and Class B to prepare for an exam can provide valuable insights into their study habits, the effectiveness of their preparation, and any possible correlations between time spent studying and exam performance.

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We have found a value of b that makes y(t) = [tex]e^2t[/tex] [1; 4; -1/2] a solution of y′ = [4 1 3; 2 3 3; −2 −1 −1]y. To check if y(t) is a solution of y′ = Ay, we need to substitute it into the differential equation and see if it holds.

Let's start by finding y′:

y′(t) = [[tex]2e^2t, 8e^2t, 4be^2t[/tex]]

Now, let's find Ay:

Ay = [4 1 3; 2 3 3; −2 −1 −1] [1; 4; b] = [4+4b; 14; -5-b]

We want y(t) = e^2t [1; 4; b] to satisfy y′ = Ay, so we set them equal:

y′ = Ay

[[tex]2e^2t; 8e^2t; 4be^2t] = [4+4b; 14; -5-b] e^2t[/tex] [1; 4; b]

Expanding this equation, we get:

[tex]2e^2t[/tex]= (4+4b)[tex]e^2t[/tex]

[tex]8e^2t[/tex] = 14 [tex]e^2t[/tex]

[tex]4be^2t[/tex]= (-5-b) [tex]e^2t[/tex]

The second equation is always true, so we can ignore it. For the first equation, we can cancel out [tex]e^2t[/tex] on both sides to get:

2 = 4+4b

Solving for b, we get:

b = -1/2

Finally, we can substitute b = -1/2 back into the third equation to check if it holds:

4be^2t = (-5-b) [tex]e^2t[/tex]

-2e^2t = (-5 + 1/2)[tex]e^2t[/tex]

This equation is true, so we have found a value of b that makes y(t) = [tex]e^2t[/tex] [1; 4; -1/2] a solution of y′ = [4 1 3; 2 3 3; −2 −1 −1]y.

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Point estimate is 29.7%.

The confidence interval for the proportion of homeowners who support the ban on nonnatural lawn fertilizers is (26.6%, 32.8%).

A) The point estimate is the proportion of homeowners who support the ban on nonnatural lawn fertilizers.

In this case, 22 out of 74 homeowners support the ban. To find the point estimate, divide the number of supporters (22) by the total number of homeowners in the sample (74):
Point estimate = 22 / 74 ≈ 0.297 or 29.7%

B) To find the lower and upper limits, we need to consider the margin of error (±3.1%). Subtract the margin of error from the point estimate for the lower limit, and add the margin of error to the point estimate for the upper limit:
Lower limit = 29.7% - 3.1% = 26.6%
Upper limit = 29.7% + 3.1% = 32.8%

The confidence interval for the proportion of homeowners who support the ban on nonnatural lawn fertilizers is (26.6%, 32.8%).

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Answer:

Top

Step-by-step explanation:

The closer the data points come to forming a straight line when plotted, the higher the correlation between the two variables, or the stronger the relationship. Therefore, the top option has the most closest lines to a linear function.

(Ex. 1) Y=4x-2

This example shows the corresponding possibilities of a linear regression because of the way the line is represented as graphed, making a straight line as similar to the top option

(Ex. 2) f(x) = x^2-5+15

This example dialates to a similar option like the third option, which isnt linear regression because of it being a quadratic function.

In a nut shell, all data plotted on the graph that are formed closer together and corresponds to a linear equation is a linear regression

The force on a sail with an area of 250 f12 and a wind speed of 35 mph would be 108.72 pounds.

We are given that the wind force F on a sail varies jointly as the area A and the square of the wind speed W. We can represent this relationship mathematically using the equation:

F = k * A * W²

where k is a constant of proportionality.

We are also given that the force on a sail with an area of 500 p and wind speed of 18 mph is 64.8 pounds. We can use this information to solve for k:

64.8 = k * 500 * 18²

Solving for k, we get:

k = 64.8 / (500 * 18²)

k = 0.0000768

Now, we can use the equation to find the force for a sail with an area of 250 f12 and a wind speed of 35 mph:

F = 0.0000768 * 250 f12 * 35²

F = 108.72 pounds

Therefore, the force on a sail with an area of 250 f12 and a wind speed of 35 mph would be 108.72 pounds.

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The series given is (-1)^71n*n. To test for convergence or divergence, the alternating series test as the series alternates in sign. Also, the absolute value of the terms of the series is decreasing as n increases. In conclusion, the given series (-1)^71n * n diverges, and it does not have a finite sum.

According to the alternating series test, if a series alternates in sign, and the absolute value of its terms is decreasing as n increases, then the series converges.
Thus, the series converges.
To find the sum of the series, we use the formula for the sum of an alternating series:
Sum = (-1)^71*1 - (-1)^71*2 + (-1)^71*3 - (-1)^71*4 + ...
= (-1)^71*(1 - 2 + 3 - 4 + ...)
= (-1)^71*(n(n+1)/2)
= 0
Therefore, the sum of the series is 0.

I'd be happy to help you with your question. To determine the convergence or divergence of the series (-1)^71n * n, we can follow these steps:
(i) Since the series has terms that alternate in sign, we can use the Alternating Series Test to test for convergence.
(ii) To apply the Alternating Series Test, we must first verify that the sequence of positive terms is decreasing and has a limit of zero. In this case, the sequence of positive terms is given by "n". As "n" goes to infinity, the sequence increases, not decreases, and the limit is not zero. Therefore, the series (-1)^71n * n does not pass the Alternating Series Test, and it diverges.
(iii) Since the series diverges, it does not have a finite sum.
In conclusion, the given series (-1)^71n * n diverges, and it does not have a finite sum.

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Answer:

A = P(1 + r/n)^(nt)

Where:

A = the future balance

P = the present balance ($1430.00)

r = the annual interest rate (2% or 0.02)

n = the number of times the interest is compounded per year (since it's compounded annually, n = 1)

t = the number of years (8 years in this case)

Plugging in the values into the formula:

A = 1430(1 + 0.02/1)^(1*8)

Simplifying the equation:

A = 1430(1.02)^8

Using a calculator or performing the calculations manually:

A ≈ 1430(1.171661)

A ≈ 1674.02

the balance after 8 years will be approximately $1674.02.

Planting an additional 210 vines will maximize grape production.

To find the number of vines that should be planted to maximize grape production, we need to find the maximum value of the function A(n) = (800 + n)(10 - 0.01n), which represents the number of pounds of grapes produced per acre as a function of the number of additional vines planted. To find the maximum value, we can take the derivative of A(n) with respect to n and set it equal to zero.

A'(n) = -0.01n² + 2.1n + 800

Setting A'(n) = 0, we get

-0.01n²+ 2.1n + 800 = 0

Solving for n using the quadratic formula, we get

n ≈ 210

Therefore, planting an additional 210 vines will maximize grape production.

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