Find the t value that forms the boundary of the critical region in the right-hand tail for a one-tailded test with o=. 01 for each of the folling sample size n=10

The photo takes up 30% of the framed area.

To calculate the percentage of the frame that is taken up by the photo, we first need to calculate the dimensions of the framed photo. If the photo measures 4 inches by 6 inches, the dimensions of the framed photo will be 8 inches by 10 inches (adding 2 inches to each side).

To calculate the area of the frame, we need to subtract the area of the photo from the area of the framed photo. The area of the photo is 4 inches x 6 inches = 24 square inches. The area of the framed photo is 8 inches x 10 inches = 80 square inches. So, the area of the frame is 80 square inches - 24 square inches = 56 square inches.

To calculate the percentage of the frame that is taken up by the photo, we divide the area of the photo by the area of the framed photo and multiply by 100.

24 square inches / 80 square inches x 100 = 30%

Therefore, the photo takes up 30% of the framed area.

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Answer:

that is really hard but im pretty sure one of the answers to the first one is -16? for the second x

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

2.17 > 2.017

because

2.017 = 2 + 17/1000

while

2.17 = 2 + 17/100 = 2 + 170/1000

170/1000 is larger than 17/1000.

for that reason D is wrong, of course.

2.17 is NOT equal to 2.017. 17/1000 is NOT equal to 170/1000.

2.018 = 2 + 18/1000

2.17 = 2 + 17/100 = 2 + 170/1000

also 18/1000 is NOT larger than 170/1000.

2.16 = 2 + 16/100 = 2 + 160/1000

2.017 = 2 + 17/1000

17/1000 are NOT larger than 160/1000.

A triangle with side lengths 6 cm, 7 cm, and √13 cm is right triangle and the side lengths form a Pythagorean triple.

To determine if the triangle with side lengths 6 cm, 7 cm, and √13 cm is a right triangle and if these side lengths form a Pythagorean triple, we'll use the Pythagorean theorem. The theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

Identify the longest side. In this case, it's the side with length 7 cm.

Check if the Pythagorean theorem holds true for these side lengths:
(6 cm)² + (√13 cm)² = (7 cm)²

Calculate the squares of the side lengths:
(6 cm)² = 36 cm²
(√13 cm)² = 13 cm²
(7 cm)² = 49 cm²

Check if the sum of the squares of the two shorter sides equals the square of the longest side:
36 cm² + 13 cm² = 49 cm²

Compare the results:
49 cm² = 49 cm²

Since the equation holds true, the triangle is indeed a right triangle, and the side lengths 6 cm, 7 cm, and √13 cm form a Pythagorean triple.

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Answer:

38/93

Step-by-step explanation:

11/31 x 38/33

11 x 38 = 418

31 x 33 = 1023

= 418/1023

Simplifying

The simplified form of 418/1023 is 38/93.

38/93 is your final answer.

In right triangle RST, the value of tan (s) is 12/5.

To find tan(s), we first need to determine which side is opposite angle S and which side is adjacent to angle S.

In this case, RT is the side opposite angle S, and ST is the side adjacent to angle S. Since tangent (x) or tan(x) is defined as the ratio of the length of the opposite side to the length of the adjacent side, we can write the formula for tan(s) as follows:

tan(s) = (opposite side) / (adjacent side)

Now we can plug in the given side lengths to calculate the value of tan(s):

tan(s) = RT / ST
tan(s) = 12 / 5

Thus, tan(s) = 12 / 5.

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Manuel can type 68 words in two minutes at a rate of 34 words per minute.

Given that; Manuel types at a rate of 34 words per minute.

To determine how many words Manuel can type in two minutes, we simply need to multiply his typing rate by the number of minutes he is typing.

Since Manuel is typing for two minutes

Hence;

Number of words = Typing rate × Time

Plugging in the values we have from the problem.

Number of words = 34 words/minute × 2 minutes

Simplifying

Number of words = 34 words × 2

Number of words = 68 words

Therefore, he can type 68 words in two minutes.

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The inequalities in the given table are "t > 0" and "3 < a."

To identify the inequalities from the provided options, we need to understand the meaning of the symbols and check if they represent a comparison between two values.

-3 = y: This is not an inequality symbol but rather an equality symbol. It represents that -3 is equal to y, not greater or less than.

t > 0: This is an inequality symbol. The symbol ">" represents "greater than." Therefore, t is greater than 0.

-4. 3 < a: This is another inequality symbol. The symbol "<" represents "less than." Hence, 3 is less than a.

g = 5 and one-half: This is an equality symbol. The symbol "=" denotes equality, indicating that g is equal to 5 and one-half, not greater or less than.

k less-than Negative Start Fraction 5 Over 7 End Fraction: This is also an inequality symbol. The phrase "less than" indicates a comparison. The fraction "Negative Start Fraction 5 Over 7 End Fraction" represents -5/7. Therefore, k is less than -5/7.

x = 1: This is an equality symbol. The symbol "=" indicates that x is equal to 1, not greater or less than.

In summary, the inequalities in the table are "t > 0" and "3 < a."

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Answer:

91%

Step-by-step explanation:

Answer:

a_48000cm^3

b_48000000mm^3

Step-by-step explanation:

first of all, let's find the base area:

Ab=((b+B)h)/2=((10cm+30cm)20cm)/2=400cm^2

then, to find the volume, we need to multiplicate the base area to the height of the prism:

V=Ab*H=400cm^2*120cm=48000cm^3=48000000mm^3

The distance from P to the airplane is y = x + 100 ≈ 628.38 m.

A triangle is a three-sided polygon with three angles. It is a fundamental geometric shape and is often used in geometry and trigonometry.

From a certain point Q on a straight road, which forms an angle of 22° with the horizontal, the angle of elevation of an airplane at point A is 57°. At the same instant from another point Q, 100 meters ahead of the first point, the angle of elevation of the airplane is 63°. The points P, Q, and A are in the same vertical plane. Find the distance from P to the airplane.

To solve the problem, we can use the concept of similar triangles. Let's call H the height of the airplane and x the distance from Q to the airplane. Then, the distance from P to the airplane is given by y = x + 100.

From triangle QA1H, we have:

tan(57°) = H / x

From triangle QA2H, we have:

tan(63°) = H / (x + 100)

Dividing these two equations, we get:

tan(57°) / tan(63°) = x / (x + 100)

Solving for x, we get:

x = 100 * tan(63°) / (tan(63°) - tan(57°)) ≈ 528.38 m

Therefore, the distance from P to the airplane is:

y = x + 100 ≈ 628.38 m.

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Answer:

Step-by-step explanation:

The probability of drawing 2 red cards from a standard 52-card deck can be calculated as follows:

There are 26 red cards in the deck, so the probability of drawing a red card on the first draw is 26/52.

After the first card is drawn, there are 25 red cards remaining in the deck out of 51 total cards, so the probability of drawing a red card on the second draw is 25/51.

To find the probability of both events happening together (drawing 2 red cards), we multiply the probabilities of each event:

(26/52) * (25/51) = 0.245 or approximately 24.5%

Therefore, the probability of drawing 2 red cards in a standard 52 card deck is approximately 24.5%.

The area of garage is 36,504 square inches.

The width of Scott's garage is 156 inches (since it is 1.5 times shorter than the length of 234 inches).

so width = 234/1.5

=> 156

To find the area, we multiply the length by the width:

=> 234 inches x 156 inches

=> 36,504 square inches.

To explain, the formula for finding the area of a rectangle is length x width. In this problem, we are given the length of the garage as 234 inches and are told that the width is 1.5 times shorter than the length.

To find the width, we can multiply the length by 1.5 to get 351 inches (which is longer than the length, so we know it must be incorrect). Instead, we need to divide the length by 1.5 to find the width, which gives us 156 inches. Then, we can multiply the length by the width to find the area of the garage, which is 36,504 square inches.

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The measure of the angle is 50.7° and the measure of its complementary angle is 39.3°.

Let x be the measure of the angle and y be the measure of its complementary angle.

Then we have:

x = y + 11.4 (since the angle measures 11.4° more than its complementary angle)

x + y = 90 (since the two angles are complementary)

Substituting the first equation into the second equation, we get:

(y + 11.4) + y = 90

2y + 11.4 = 90

2y = 78.6

y = 39.3

Substituting y = 39.3 into the first equation, we get:

x = y + 11.4 = 50.7

So, we have

x = 50.7

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The area of a horizontal cross-section of the cylinder whose diameter is 2.75 inches and height is 6 inches is 5.9 inch².

Diameter of the base of the container = 2.75 inch

Height of the cylinder = 6 inch

Area of a horizontal cross-section of the cylinder = πr²

Here, r = radius of the container

Radius = Diameter/2

Radius = 2.75/2

Radius = 1.375

Area of the horizontal cross-section of the cylinder = 3.14 × 1.375 × 1.375

Area = 5.9365625

Area of the horizontal cross- section of the cylinder to the nearest tenth is 5.9

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The value of x such that fg(x) = 20 is 6.5.

To find the composite function fg(x), we need to substitute the expression for g(x) into f(x), as follows:

fg(x) = f(g(x)) = f(x + 4) = 2(x + 4) - 1 = 2x + 7

So, fg(x) = 2x + 7

ii) To find the value of x such that fg(x) = 20, we can substitute fg(x) into the equation and solve for x, as follows:

fg(x) = 2x + 7 = 20

2x = 13

x = 6.5

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The sum of the series Σ (2k² - 4) from k = 1 to n can be found using the following formula:

Σ (2k² - 4) = [2(1²) - 4] + [2(2²) - 4] + [2(3²) - 4] + ... + [2(n²) - 4]

= 2(1² + 2² + 3² + ... + n²) - 4n

The sum of squares of the first n natural numbers can be calculated using the formula:

1² + 2² + 3² + ... + n² = [n(n + 1)(2n + 1)] / 6

Substituting this value in the above equation, we get:

Σ (2k² - 4) = 2[(n(n + 1)(2n + 1)) / 6] - 4n

= (n(n + 1)(2n + 1)) / 3 - 4n

Therefore, the sum of the series Σ (2k² - 4) from k = 1 to n is (n(n + 1)(2n + 1)) / 3 - 4n.

Answer:

mail

Step-by-step explanation:

skating Dinero broke 1p revision yahoo d10

The probability of the next elk caught in the park being unmarked can be calculated as follows:

The probability of capturing an unmarked elk in a nature reserve park can be calculated by dividing the number of unmarked elks by the total number of elks.

In this case, the number of unmarked elks is 5,400 out of a total of 5,625 elks. This gives a probability of 96% or 0.96 in decimal form. Marking and tracking animals is a common method used by scientists to study animal populations in nature reserves.

This data is crucial for designing conservation strategies that promote the survival of endangered species. Nature reserves play a crucial role in preserving and protecting wildlife and their habitats, given the significant threats they face from habitat loss, poaching, and climate change.

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Therefore, we need 3/4 of a quart of grape juice to mix with 3 3/4 quarts of sparkling water.

In mathematics, a fraction represents a part of a whole or a ratio between two numbers. It consists of a numerator and a denominator, separated by a horizontal or diagonal line. The numerator is the number above the line and the denominator is the number below the line. The numerator and denominator can be any real numbers, including integers, decimals, or even other fractions.

Here,

The punch recipe requires a ratio of 1 1/2 quarts of sparkling water to 3/4 of a quart of grape juice. To determine how much grape juice is needed to mix with 3 3/4 quarts of sparkling water, we can set up a proportion:

1 1/2 quarts of sparkling water : 3/4 quart of grape juice = 3 3/4 quarts of sparkling water : x

To solve for x, we can cross-multiply and simplify:

(1 1/2) / (3/4) = (15/4) / (3/4)

= 15/3

= 5

3 3/4 * 1 / 5 = 15/20

= 3/4

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The velocity with which a ball reaches the ground when it is dropped

from a height of 64 m is 35.44m/sec

From the information given, we have that the equation representing the velocity of the ball is expressed as;

V = 4.43√h

Given that the parameters of the formula are;

Since the height of the ball from the ground is 64m, we have to substitute the value, we have;

V = 4.43√64

Find the square root of the value

V= 4.43(8)

Now, multiply both the values to determine the velocity, we get;

V = 35.44m/sec

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By using the method of undetermined coefficients, The general solution is y = ae^(4x)cos(3x) + be^(4x)sin(3x) + (7/2cos(3t) + 5/2sin(3t))e^(4t). The solution to the initial value problem is y = 3e^(2x) + 14e^(4x) - 3e^(3x).

By using the method of undetermined coefficients, the associated homogeneous equation is y''-8y'+297=0, which has the characteristic equation r^2-8r+297=0. The roots of this equation are r=4+3i and r=4-3i, so the homogeneous solution is yh=a*e^(4x)cos(3x)+be^(4x)*sin(3x).

To find the particular solution, we make the ansatz yp = (Acos(3t) + Bsin(3t))e^(4t), where A and B are constants to be determined. Substituting this into the differential equation, we get

y" - 8y' + 297 = (16A - 18B)e^(4t)cos(3t) + (16B + 18A)e^(4t)sin(3t)

On the right-hand side, we have 48e^4tcos(3t) + 80e^4tsin(3t), which suggests setting

16A - 18B = 48, and

16B + 18A = 80

Solving these equations simultaneously, we get A = 7/2 and B = 5/2. Therefore, the particular solution is

yp = (7/2cos(3t) + 5/2sin(3t))e^(4t)

And the general solution is

y = yh + yp = ae^(4x)cos(3x) + be^(4x)sin(3x) + (7/2cos(3t) + 5/2sin(3t))e^(4t)

For the second problem, the associated homogeneous equation is y''-6y'+8y=0, which has the characteristic equation r^2-6r+8=0. The roots of this equation are r=2 and r=4, so the homogeneous solution is yh=ae^(2x)+be^(4x).

To find the particular solution, we make the ansatz yp = Ce^3x, where C is a constant to be determined. Substituting this into the differential equation, we get

y" - 6y' + 8y = 9Ce^3x - 18Ce^3x + 8Ce^3x = (8C - 9C)e^3x = -C*e^3x

On the right-hand side, we have 3e^x, which suggests setting -C = 3. Therefore, the particular solution is

yp = -3e^(3x)

And the general solution is

y = yh + yp = ae^(2x) + be^(4x) - 3e^(3x)

To find the values of a and b, we use the initial conditions

y(0) = a + b - 3 = 14

y'(0) = 2a + 4b - 9 = 29

y''(0) = 2a + 8b = 25

Solving these equations simultaneously, we get a = 3 and b = 14. Therefore, the solution to the initial value problem is

y = 3e^(2x) + 14e^(4x) - 3e^(3x)

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--The given question is incomplete, the complete question is given

"  (1 point) Use the method of undetermined coefficients to find a solution of a y" – 8y' + 297 = 48e4t cos(3t) + 80e4t sin(3t) + 3 - Use a and b for the constants of integration associated with the homogeneous solution. Use a as the constant in front of the cosine term. y = yh + yp = - = (1 point) Find y as a function of x if ' y" – 6y" + 8y' = 3e", - - = y(0) = 14, y'(0) = 29, y"(0) = 25."--

Answer:

Subtract the smaller amount of [tex]x[/tex] → [tex]2x+6 > 15[/tex]

Then subtract 6 from 15 as it is a plus you do the opposite → [tex]2x > 9[/tex]

Now divide 9 by 2 to isolate [tex]x[/tex] → [tex]x > 4.5[/tex]

According to the given condition the two-digit number is 66.

To find the two-digit number that is 11 times its units digit and has a sum of digits equal to 12, we can use the following steps:

1. Let's represent the two-digit number as XY, where X is the tens digit and Y is the units digit.
2. The number is 11 times its units digit, so we can write the equation: 10X + Y = 11Y.
3. The sum of the digits is 12, which means X + Y = 12.
4. Now, we have two equations with two variables:
   - 10X + Y = 11Y
   - X + Y = 12
5. We can solve for X from the second equation: X = 12 - Y.
6. Substitute the value of X in the first equation: 10(12 - Y) + Y = 11Y.
7. Simplify and solve for Y: 120 - 10Y + Y = 11Y.
8. Combine the Y terms: 120 - 9Y = 11Y.
9. Move all the Y terms to one side: 120 = 20Y.
10. Divide by 20 to get Y: Y = 6.
11. Now, substitute the value of Y back into the X equation: X = 12 - 6.
12. Solve for X: X = 6.

So, the two-digit number is 66.

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As a result, it will take roughly 10.24 years for the account to reach $20,000 in value.

As a quarter of 100, a number can be expressed as a percentage. It is frequently used to describe distinctions or express changes in numbers. The symbol for percentages is %, and they are frequently utilized to describe ratios, rates, and certain other numerical connections. An 80 percent score on a test, for instance, indicates that the student correctly answered 80 of the 100 questions. Similar to this, if a retailer were offering a 20% discount on a $100 item, the sale price would be $80.

given

With P = 10000, r = 0.08 (8% stated as a decimal), n = 12 (compound monthly), and t to be found when A = 20000, the situation is as follows.

When these values are added to the formula, we obtain:

[tex]20000 = 10000(1 + 0.08/12)^(12t) (12t)[/tex]

By multiplying both sides by 1000, we obtain:

[tex]2 = (1 + 0.08/12)^(12t) (12t)[/tex]

When we take the natural logarithm of both sides, we obtain:

ln(2) = 12t ln(1 + 0.08/12)

When we multiply both sides by 12 ln(1 + 0.08/12), we obtain:

t = ln(2) / (12 ln(1 + 0.08/12))

Calculating the answer, we discover:

10.24 years is t.

As a result, it will take roughly 10.24 years for the account to reach $20,000 in value.

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When rt is a diameter of circle p, it divides the circle into two equal halves. Since the sum of angles in a circle is 360 degrees, each half of circle p measures 180 degrees.

Thus, each arc of circle p that is intersected by diameter rt measures half of the circle or 90 degrees.

Therefore, each arc of circle p measures 90 degrees when rt is a diameter.

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The maximum height the golf ball reached before landing back on the ground is 3.75 yards.

To find the maximum height the golf ball reached before landing back on the ground, we need to find the vertex of the quadratic function[tex]h(t) = -0.6t^2 + 3t.[/tex] The vertex of a quadratic function in the form of[tex]f(x) = ax^2 + bx + c[/tex] is given by the formula x = -b/(2a).

In this case, a = -0.6 and b = 3. Plugging these values into the formula:

t = -3 / (2 * -0.6) = 3 / 1.2 = 2.5

Now that we have the time at which the ball reaches its maximum height, we can plug this value back into the height function to find the maximum height:

[tex]h(2.5) = -0.6(2.5)^2 + 3(2.5) = -0.6(6.25) + 7.5 = -3.75 + 7.5 = 3.75[/tex]

So, the maximum height the golf ball reached before landing back on the ground is 3.75 yards.

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This tells him that his salary is significantly below the average salary of quality management professionals surveyed by the ASQ, and that he is in the bottom percentile of salaries in this group.

The z-score is a statistical measure that indicates the number of standard deviations that a data point is from the mean of a distribution. A negative z-score indicates that the data point is below the mean.

In this case, the quality control specialist's z-score of -2.50 indicates that his salary is 2.50 standard deviations below the mean salary of the quality management professionals surveyed by the ASQ.

Without knowing the specific mean and standard deviation provided by the survey, it is difficult to determine the exact value of the specialist's salary. However, we can use the z-score to estimate the percentile rank of his salary compared to the rest of the survey respondents.

Using a standard normal distribution table, we can see that a z-score of -2.50 corresponds to a percentile rank of approximately 0.0062 or 0.62%. This means that only about 0.62% of quality management professionals surveyed by the ASQ earn a salary lower than that of the quality control specialist.

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