Correct the error in finding the area of sector XZY when the area of ⊙Z is 255 square feet.



n/360=115/225



n=162. 35



Round to the nearest tenth.


The area should equal ______ft2.

No, 2352 is not a perfect square.

To find the smallest number by which 2352 must be multiplied so that the product is a perfect square, we need to factorize 2352 into its prime factors.

2352 = 2^4 x 3 x 7^2

To make it a perfect square, we need to multiply it by 2^2 and 7, which gives us:

2352 x 2^2 x 7 = 9408

Now, we can take the square root of 9408:

√9408 = √(2^8 x 3 x 7) = 2^4 x √(3 x 7) = 16√21

Therefore, the smallest number by which 2352 must be multiplied so that the product is a perfect square is 2^2 x 7, which gives us the square root of 9408 as 16√21.

Answer:

The smallest number by which 2352 must be multiplied so that the product is a perfect  square = 3

The square root of the new number = 84

Step-by-step explanation:

√2352 ≈ 48.5 so not a perfect square

Prime factorization of 2352 yields

2352 = 2 x 2 x 2 x 2 x 7 x 7 x 3

In exponential form this is
2⁴ x  7² x 3¹

So
[tex]\sqrt{2352} = \sqrt{2^4 \cdot 7^2 \cdot 3}\\\\= \sqrt{2^4} \cdot \sqrt{7^2} \cdot \sqrt{3}\\\\= 2^2 \cdot 7 \cdot \sqrt{3}\\\\= 28 \sqrt{3}[/tex]

To get rid of the radical in the square root and get a whole number, all you have to do is multiply [tex]\sqrt{2352}[/tex]  by √3

[tex]28 \sqrt{3} \cdot \sqrt{3} = 28\cdot 3 = 84\\\\84^2 = 7056 = 2352 \cdot 3\\[/tex]

This means that if you multiply 2352 by 3 it will become a perfect square

Check:
[tex]2352 \cdot 3 = 7056\\\\\sqrt{7056} = 84[/tex]

The integral evaluates to (16/3)s³/² + C.

The power rule of integration is a method for finding the indefinite integral of a function of the form f(x) = x^n, where n is any real number except for -1. The rule states that the indefinite integral of f(x) is (x^(n+1))/(n+1) + C, where C is an arbitrary constant of integration.

To evaluate the integral 8√(s) ds, follow these steps:

1. Rewrite the integral with a rational exponent: ∫8s¹/² ds
2. Apply the power rule for integration: ∫sⁿ ds = (sⁿ⁺¹/(n+1) + C, where n ≠ -1
3. Substitute n=1/2: (s³/²)/(3/2) + C
4. Multiply by 8: 8*(s³/²)/(3/2) + C
5. Simplify the expression: (16/3)s³/² + C

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Step-by-step explanation:

Finding the square root of a number is simply jist dividing the given number by 2 till you get to the last number which should be 1 then you pair up the number of two's and multiply. For example you have 6 two's when you pair them in two's you get 3 two's left then you multiply the remaining two's which would then be 2×2×2 which is 6

Answer:

Step-by-step explanation:

so basically, a square root is just the number that is multipled together to equal that, so sq rt of 64 is 8. This is because 8x8= 64. If you were to take a weird number like sq rt of 112, it would be a little bit more difficult, however its pretty easy to do this through thinking of your multiplication charts. if you think about it 11x10 but thats 110, it would have to be a number around there. 11x11 is too high but 10x10 is too low. SO it would have to be a number around there. if you did 10.5x10.5 it would give 110.25. so if you try to do 10.6x10.6 it would equal 112.36. (The actual answer is 10.58300524425836)  So that is how you determine how close you can get. It is very tedious to do this process and very time consuming. However, i would just advise you try to use a calculator (??)

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The velocity of the truck after the collision would be 24 m/s east.

The law of conservation of momentum states that the momentum of a closed system remains constant if no external forces act on it. In this case, we can assume that the car and the truck form a closed system.

The momentum of an object is given by its mass multiplied by its velocity, p = mv. Initially, the momentum of the system is:

p_initial = m_car * v_car + m_truck * v_truck

where m_car and v_car are the mass and velocity of the car, and m_truck and v_truck are the mass and velocity of the truck.

After the collision, the car is stopped, so its velocity is 0. The momentum of the system after the collision is:

p_final = m_car * 0 + m_truck * v'_truck

where v'_truck is the velocity of the truck after the collision.

Since momentum is conserved, we can set p_initial equal to p_final:

m_car * v_car + m_truck * v_truck = m_truck * v'_truck

Solving for v'_truck, we get:

v'_truck = (m_car * v_car + m_truck * v_truck) / m_truck

Substituting the given values, we have:

v'_truck = (1200 kg * 40 m/s + 2000 kg * 0 m/s) / 2000 kg

v'_truck = 24 m/s east

Therefore, the velocity of the truck after the collision would be 24 m/s east.

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Answer:

1

Step-by-step explanation:

USE PEMDAS OR ORDER OF OPERATIONS

1. Evaluate parenthesis.

-2/27 - 2/51 = - 52/459.

2. Add

15/51 + 16/27 = 407/459

3. Subtract to get the final answer

407/459 - -52/459 = 407/459 + 52/459 = 1

So, 15/51+16/27-(-2/27-2/51) = 1

Based on the data, we can infer that Kallie needs 6 teaspoons of water conditioner for the 12 fish tanks.

To calculate how many teaspoons of water conditioner we must take into account the information on the capacity of each tank:

In accordance with the above, we do the following logical procedure.

We multiply the capacity of each tank by the number of tanks.

So we need 60 gallons of water to fill the tanks, and we divide by 10 to find how many teaspoons we need to fill all 12 tanks.

Based on the above, we need 6 teaspoons to condition the water in the 12 tanks.

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The equation of the circle graphed below is (x - 1)² + (y - 1)² = 4.

To determine the equation of a circle, we need to know the coordinates of its center and the radius. The general equation of a circle with center (h, k) and radius r is given by:

(x - h)² + (y - k)² = r²

where (x,y) are the coordinates of any point on the circle. The equation shows that the distance between any point (x,y) on the circle and the center (h,k) is always equal to the radius r.

To determine the equation of the circle graphed below, we need to identify the coordinates of its center and the radius. One way to do this is to use the distance formula between two points. We can choose any two points on the circle and use their coordinates to find the distance between them, which is equal to the diameter of the circle. Then, we can divide the diameter by 2 to find the radius.

To find the radius, we can choose any point on the circle and use the distance formula to find the distance between that point and the center. We can use the point (5,1), which is on the right side of the circle. The distance between (5,1) and (1,1) is 4 units, which means that the radius is 2 units.

Substituting the values of (h,k) and r in the general equation of the circle, we get:

(x - 1)² + (y - 1)² = 4

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We would expect 9 pumpkin cupcakes to be sold in the next 21 cupcakes. The probability of a chocolate cupcake being sold is approximately 14%.

The question asks to determine how many of the next 21 cupcakes sold would be expected to be pumpkin cupcakes, and also to find the probability of a chocolate cupcake being sold.

First, let's analyze the given data:
- Chocolate cupcakes: 2
- Pistachio cupcakes: 1
- Banana cupcakes: 5
- Pumpkin cupcakes: 6

Total cupcakes sold: 2 + 1 + 5 + 6 = 14

To find the expected number of pumpkin cupcakes in the next 21 sold, calculate the proportion of pumpkin cupcakes in the original data, and then multiply by 21:

(6 pumpkin cupcakes / 14 total cupcakes) * 21 = 9 (rounded)

So, we would expect 9 pumpkin cupcakes to be sold in the next 21 cupcakes (Answer A).

For Part B, we need to find the probability of a chocolate cupcake being sold. To do this, divide the number of chocolate cupcakes by the total number of cupcakes:

Probability (chocolate cupcakes) = (2 chocolate cupcakes / 14 total cupcakes) = 0.142857

Now, convert this probability to a percentage and round to the nearest whole number:

0.142857 * 100 = 14.29% ≈ 14%

So, the probability of a chocolate cupcake being sold is approximately 14%.

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The expected value of X is 2.33.

To find the expected value of the random variable X, we need to use the given probability function f(x) and the formula for expected value: E(X) = Σ[x * f(x)]. Here's a step-by-step explanation:

1. Identify the possible values of x: 1, 2, and 3.
2. Calculate f(x) for each x value using the given probability function f(x) = x/6:
  f(1) = 1/6
  f(2) = 2/6 = 1/3
  f(3) = 3/6 = 1/2
3. Apply the expected value formula by multiplying each x value by its corresponding f(x) and summing the results:
  E(X) = (1 * 1/6) + (2 * 1/3) + (3 * 1/2) = 1/6 + 2/3 + 3/2
4. Simplify the expression to find the expected value:
  E(X) = 1/6 + 4/6 + 9/6 = (1 + 4 + 9)/6 = 14/6 = 7/3

The expected value of the random variable X is 7/3 or 2.33.

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The area of the shaded region of the circle is 89.75 mi².

The area of a sector of a circle, you can use the formula:

A = (θ/360) × π × r²

Where A is the area of the sector, θ is the central angle of the sector, r is the radius of the circle, and π is a constant approximately equal to 3.14.

From the diagram, angle of the unshaded sector equals 150 degree.

Angle of the shaded region = 360 - 150 = 210 degree

Radius r = 7 miles.

We can substitute these values into the formula and solve for the area A.

A = (θ/360) × π × r²

A = ( 210/360 ) × 3.14 × 7²

A = ( 210/360 ) × 3.14 × 49

A = 89.75 mi²

Therefore, the area of the sector is approximately 89.75 mi².

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To find the probability of Sarah cleaning her room or doing her homework, we can use the addition rule for probabilities. However, we need to be careful not to count the probability of Sarah cleaning her room and doing her homework twice. Therefore, we need to subtract the probability of Sarah cleaning her room and doing her homework from the sum of the probabilities of Sarah cleaning her room and doing her homework separately.

Let C be the event that Sarah cleans her room, and let H be the event that Sarah does her homework. Then we know:

P(C) = 0.40 (the probability that Sarah cleans her room)

P(H) = 0.70 (the probability that Sarah does her homework)

P(C and H) = 0.24 (the probability that Sarah cleans her room and does her homework)

Using the addition rule, we can find the probability of Sarah cleaning her room or doing her homework as follows:

P(C or H) = P(C) + P(H) - P(C and H)

          = 0.40 + 0.70 - 0.24

          = 0.86

Therefore, the probability of Sarah cleaning her room or doing her homework is 0.86, or 86%.

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There are 225 possible outcomes in the sample space if the spinner is spun twice

From the question, we have the following parameters that can be used in our computation:

Spinner

The number of sections in the spinner is

n = 15

If the spinner shown is spun twice, then we have

Outcomes = n²

Substitute the known values in the above equation, so, we have the following representation

Outcomes = 15²

Evaluate

Outcomes = 225

Hence, the possible outcomes are in the sample space are 225

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To compute the integral JSS, udv, where U is the part of the ball of radius 3, centered at 0,0,0), that lies in the 1st octant, we can use spherical coordinates. Since the region is defined as having all three coordinates nonnegative, we can set our limits of integration as follows: 0 ≤ ρ ≤ 3, 0 ≤ θ ≤ π/2, and 0 ≤ φ ≤ π/2.

Using the Jacobian transformation, we have:

JSS, udv = ∫∫∫U ρ²sinφ dρdθdφ

Substituting in our limits of integration, we get:

JSS, udv = ∫0^π/2 ∫0^π/2 ∫0³ ρ²sinφ dρdθdφ

Evaluating the integral, we get:

JSS, udv = (3³/3) [(sin(π/2) - sin(0))] [(1/2) (π/2 - 0)]

JSS, udv = 9/2 π

Therefore, the value of the integral JSS, udv, over the part of the ball of radius 3 that lies in the 1st octant is 9/2π.
To compute the integral JSS, udv, over the region U, which is the part of the ball of radius 3 centered at (0,0,0) and lies in the first octant, we will use spherical coordinates for this computation as it's more preferable.

In spherical coordinates, the volume element is given by dv = ρ² * sin(φ) * dρ * dφ * dθ, where ρ is the radial distance, φ is the polar angle (between 0 and π/2 for the first octant), and θ is the azimuthal angle (between 0 and π/2 for the first octant).

Now, we need to set up the integral for the volume of the region U:
JSS, udv = ∫∫∫ (ρ² * sin(φ) * dρ * dφ * dθ), with limits of integration as follows:
ρ: 0 to 3 (radius of the ball),
φ: 0 to π/2 (for the first octant),
θ: 0 to π/2 (for the first octant).

So, the integral becomes:
JSS, udv = ∫(0 to π/2) ∫(0 to π/2) ∫(0 to 3) (ρ² * sin(φ) * dρ * dφ * dθ)

By evaluating this integral, we will obtain the volume of the region U in the first octant.

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If Katie started with $40, the remaining balance after purchasing the supplies is $20.

To determine how much money Katie had left after purchasing the supplies, we'll consider the fraction "1/5" for the storybook and "3/10" for the calculator.

1: Calculate the amount spent on the storybook.

Katie spent 1/5 of her initial $40 on the storybook. To find this amount, multiply the fraction by the total amount:

(1/5) x $40 = $8

2: Calculate the amount spent on the calculator.

Katie spent 3/10 of her initial $40 on the calculator. To find this amount, multiply the fraction by the total amount:

(3/10) x $40 = $12

3: Add the amounts spent on both the storybook and calculator.

$8 (storybook) + $12 (calculator) = $20

4: Subtract the total amount spent from Katie's initial amount of money to find the remaining balance.

$40 (initial amount) - $20 (total spent) = $20

After purchasing the supplies, Katie had $20 left.

Note: The question is incomplete. The complete question probably is: Katie started with $40. He spent 1/5 of the money on a storybook and 3/10 on a calculator. how much money did she have left after purchases the supplies.

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Answer is: Probability of a student getting a lunch that does not include chips is 6/12 or 0.5.

1. To find the probability of a student getting a lunch that includes chips and apple juice, we need to first find the total number of possible lunch combinations. There are 3 options for sandwiches, 2 options for sides, and 2 options for drinks, so there are a total of 3 x 2 x 2 = 12 possible lunch combinations.

Out of those 12 combinations, there is only 1 combination that includes chips and apple juice: ham and cheese sandwich, chips, and apple juice.

Therefore, the probability of a student getting a lunch that includes chips and apple juice is 1/12 or approximately 0.083.

2. To find the probability of a student getting a lunch that does not include chips, we can count the number of possible lunch combinations that do not include chips and divide by the total number of lunch combinations.

There are 3 sandwich options and 2 drink options, so there are a total of 3 x 2 = 6 possible lunch combinations without chips.

Out of the total of 12 possible lunch combinations, 6 do not include chips, so the probability of a student getting a lunch that does not include chips is 6/12 or 0.5.

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The ratios are: surface area 9:121, volume 27:1331, width 3:11.

(a) The ratio of the surface area of the model to the surface area of the original can be found by using the scale factor to find the ratio of the corresponding side lengths. Since surface area is proportional to the square of the side length, we can use this ratio squared to find the ratio of the surface areas.
The ratio of the corresponding side lengths is 3:11, so the ratio of the surface areas is (3/11)^2, which simplifies to 9/121.
Therefore, the ratio of the surface area of the model to the surface area of the original is 9:121.
(b) The ratio of the volume of the model to the volume of the original can be found using the same method as above, but with volume instead of surface area. Since volume is proportional to the cube of the side length, we can use this ratio cubed to find the ratio of the volumes.
The ratio of the corresponding side lengths is 3:11, so the ratio of the volumes is (3/11)^3, which simplifies to 27/1331.
Therefore, the ratio of the volume of the model to the volume of the original is 27:1331.
(c) The ratio of the width of the model to the width of the original can be found directly from the scale factor, since width is one of the corresponding side lengths.
The ratio of the corresponding side lengths is 3:11, so the ratio of the widths is 3:11.
Therefore, the ratio of the width of the model to the width of the original is 3:11.
Overall, the ratios are: surface area  9:121, volume  27:1331, width 3:11.

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The approximate length of the base of the triangle is 5 units.

Given that, the area of a hexagon is about 65 square units. You decompose the figure into 6 triangles.

A regular hexagon can be decomposed into 6 equal triangles,

So, the area of each triangle is 65/6 = 10.8 square units

The height of one triangle is about 4.3 units.

We know that, the area of a triangle is 1/2 ×Base×Hieght

Now, 10.8=1/2 ×Base×4.3

21.6=Base×4.3

Base=21.6/4.3

Base=5.02

Therefore, the approximate length of the base of the triangle is 5 units.

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Using the composition of functions, if the two functions are inverses of each other, therefore, we cannot conclude if f(x) and g(x) are inverses of each other.

To check if the two functions f(x) and g(x) are inverses of each other, we need to verify if their composition f(g(x)) and g(f(x)) results in the identity function f(x) = x.

Let's first find the composition f(g(x)):

f(g(x)) = f(x^2 - 4)

= sqrt(x^2 - 4) + 4

Now, let's find the composition g(f(x)):

g(f(x)) = g(sqrt(x) + 4)

= (sqrt(x) + 4)^2 - 4

= x + 16 + 8sqrt(x)

To check if f(x) and g(x) are inverses of each other, we need to check if f(g(x)) = x and g(f(x)) = x for all x in the domain of the functions.

For f(g(x)):

f(g(x)) = sqrt(x^2 - 4) + 4

This function is only defined for x > 2, since the square root of a negative number is not real. Therefore, the domain of f(g(x)) is (2, infinity).

For g(f(x)):

g(f(x)) = x + 16 + 8sqrt(x)

This function is only defined for x >= 0, since the square root of a negative number is not real. Therefore, the domain of g(f(x)) is [0, infinity).

Since the domains of f(g(x)) and g(f(x)) do not overlap, we cannot check if they are inverses of each other. Therefore, we cannot conclude if f(x) and g(x) are inverses of each other.

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About $786 billion will be spent at restaurants in 2017 if the trend continues.

We can use the formula for compound interest:

A = P(1 + r)^n

where:

A is the final amount

P is the initial amount

r is the annual interest rate

n is the number of years

In this instance, we're looking to determine how much will be spent at restaurants in 2017, which is 12 years from now, in 2005. The initial amount was $410 billion in 2005, and the yearly interest rate is 6%. We thus have:

A = 410(1 + 0.06)^12

A ≈ 786.34

Therefore, about $786 billion will be spent at restaurants in 2017 if the trend continues.

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The final values is (fog)(x) = f(g(x)) = f(0) = -8.

In the given problem, we are given two functions, f(x) and g(x). The function f(x) is a polynomial function, and g(x) is a constant function equal to 0. We are asked to find the composition of these two functions, that is, (fog)(x) and (gof)(x).

The composition of two functions f(x) and g(x) is denoted by (fog)(x) and is defined as follows:

(fog)(x) = f(g(x))

This means that we first evaluate g(x) and then use the output of g(x) as the input of f(x) to get the final output of (fog)(x).

In this case, since g(x) = 0, we have:

(fog)(x) = f(g(x)) = f(0)

To evaluate f(0), we substitute x = 0 in the expression for f(x):

[tex]f(x) = 2x^2 - 6x^2 + 4x - 8[/tex]

[tex]f(0) = 2(0)^2 - 6(0)^2 + 4(0) - 8[/tex]

f(0) = -8

Therefore, (fog)(x) = f(g(x)) = f(0) = -8.

Now, to find (gof)(x), we need to evaluate g(f(x)). Since f(x) is a polynomial function, we can find its value for any value of x. However, since g(x) is a constant function equal to 0, its output is always 0 for any input x. Therefore, g(f(x)) = 0 for all values of f(x).

This means that (gof)(x) = g(f(x)) = 0 for all x.

In summary, we found that (fog)(x) = -8 and (gof)(x) = 0.

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The quadratic function that models the number of cases of flu each year, where y is years since 2012 is y = -0.02x^2 + 0.5x + 10. The coefficient of x is 0.5.

Suppose the number of cases of flu each year initially increases rapidly, but then starts to level off and eventually decline. We can model this behavior with a quadratic function of the form:

y = ax^2 + bx + c

where y is the number of cases of flu, and x is the number of years since 2012. Estimate the coefficients a, b, and c.

Assume the number of cases of flu was initially very low in 2012, so the y-intercept c is small value, say 10.

Next, assume that the number of cases of flu initially increased rapidly, but then started to level off around 2018.

y = ax^2 + bx + 10

where a is negative and b is positive.

Suppose the coefficient of the linear term is small, since we expect the trend to level off rather than continue to increase at a constant rate.

So, a possible quadratic function that models the number of cases of flu each year is:

y = -0.02x^2 + 0.5x + 10

The coefficient of x in this function is 0.5, which represents the rate of change of the number of cases of flu each year after 2012.

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Mariah cycles a distance of 8.6 miles, which is more than 8 miles, hence more than 2/3 of the cycling portion of the triathlon.

A triathlon is  described as an endurance multisport race consisting of swimming, cycling, and running over various distances.

The coordinates are given as follows:

Suppose that we have two points,  and . The distance between them is given by:

distance = √(x2 - x1)² + (y2-y1)²

We substitute in the equation

Hence the distance between her house and the library is:

D = 8.6 miles.

She cycles a distance of 8.6 miles, which is more than 8 miles, hence more than 2/3 of the cycling portion of the triathlon.

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By increasing their recycling by 500 pounds per month, the school conserves 4,800 gallons of water in a year.

Determine the ratio of water conserved per pound of paper recycled:

8 gallons of water are saved for every 10 pounds of paper recycled.

Calculate the water saved for each pound of paper:

8 gallons/10 pounds = 0.8 gallons/pound.

Find the increase in paper recycled per month:

500 pounds/month.

Calculate the water saved per month:

[tex]500 $ pounds/month \times  0.8 $ gallons/pound = 400 $ gallons/month.[/tex]

Calculate the water saved in a year:

[tex]400 $ gallons/month \times  12 months = 4,800 $ gallons/year.[/tex]

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Answer:

For 10 sections you would need 60 rails

The rule for posts is to multiply the section by 3

the rule for rails is to multiply the post by 2

The volume of the frustum is 132.84 cubic units.

The lateral area of the frustum is 7π√17/4 square units.

To calculate the volume of the frustum, we can use the formula:

V = (1/3) × π × h × (r₁² + r₂² + (r₁ * r₂))

where:

V is the volume of the frustum,

h is the height of the frustum,

r₁ is the radius of the smaller base,

r₂ is the radius of the larger base, and

π is a mathematical constant approximately equal to 3.14159.

Plugging in the values given:

h = 2,

r₁ = 1, and

r₂ =[tex]2\frac{1}{2}[/tex] = 5/2,

V = (1/3)× π × 2 × (1² + (5/2)² + (1 × (5/2)))

V = (1/3) × π × 2 × (1 + 25/4 + 5/2)

V = 132.84

Therefore, the volume of the frustum is approximately 132.84 cubic units.

To calculate the lateral area of the frustum, we can use the formula:

A = π × (r₁ + r₂) × l

To find the slant height, we can use the Pythagorean theorem:

l = √(h² + (r₂ - r₁)²)

Plugging in the values given:

h = 2, r₁ = 1, and r₂ =5/2

l = √ 2² + ((5/2) - 1)²

l = √(4 + (5/2 - 2)²)

l = √(17/4)

l = √(17)/2

Now, plugging in the values into the lateral area formula:

A = π×(1 + 5/2)× √17/2

A = π × (7/2) × √(17)/2

A = 7π√17/4

Therefore, the lateral area of the frustum is 7π√17/4 square units.

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a) Approximately 79.38% of the phones have a battery life of at least 4 hours and 45 minutes.

b) Approximately 34.13% of the phones have a battery life between 4.5 hours and 5.25 hours.

c) Approximately 50% of the phones have a battery life less than 5 hours or greater than 5.5 hours.

a) What percentage battery life of 4 hours and 45 minutes?

a) For phones with a mean battery life of 5 hours and a standard deviation of 15 minutes, we can calculate the percentage of phones with a battery life of at least 4 hours and 45 minutes. By converting 4 hours and 45 minutes to minutes (4*60 + 45 = 285 minutes) and using the z-score formula, we find that the z-score is (285 - 300) / 15 = -1. Hence, the percentage is approximately 1 - 0.8359 = 0.1641, which is about 16.41%.

b) What percentage battery life between 4.5 hours and 5.25 hours?

b) To determine the percentage of phones with a battery life between 4.5 hours and 5.25 hours, we need to calculate the z-scores for both values. Converting the hours to minutes, we have 4.5 hours = 270 minutes and 5.25 hours = 315 minutes. The z-scores are (270 - 300) / 15 = -2 and (315 - 300) / 15 = 1. By referring to the standard normal distribution table, we find that the area between -2 and 1 is approximately 0.6141. Thus, the percentage is 0.6141 * 100 = 61.41%.

c) For the percentage of phones with a battery life less than 5 hours or greater than 5.5 hours, we need to calculate the z-score for both cases. The z-score for 5 hours is (300 - 300) / 15 = 0, and the z-score for 5.5 hours is (330 - 300) / 15 = 2. By referring to the standard normal distribution table, we find that the area to the left of 0 is 0.5 and the area to the right of 2 is 1 - 0.9772 = 0.0228. Adding these percentages, we get 0.5 + 0.0228 = 0.5228, which is approximately 52.28%.

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Hi! I'd be happy to help you with your question about transformations and congruence. When Triangle ABC is reflected over the x-axis, the algebraic rule applied to the figure is:

Your answer: (x, y) → (x, -y)

This rule states that the x-coordinate remains the same, while the y-coordinate is multiplied by -1, resulting in a reflection over the x-axis. This transformation preserves congruence, as the size and shape of Triangle ABC remain the same, only its position changes.

The algebraic rule applied to the figure when Triangle ABC is reflected over the x-axis is (x,y) → (x,-y), where x represents the x-coordinate and y represents the y-coordinate. This is because reflecting a figure over the x-axis involves keeping the x-coordinate the same while changing the sign of the y-coordinate. This preserves the congruence of the original and reflected triangles.

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