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Joe and Tommy are playing a game of chicken. Tommy has a mass of 91 kg, Joe has a mass of 97 kg. Tommy is running towards Joe with a velocity of 5 m/s, Joe is running towards Tommy with a velocity of 6 m/s. Neither "chickens" out. After collision, Joe is standing still. How fast does Tommy bounce off Joe? Round to four decimal places

Answers

Answer 1

Tommy bounces off Joe at a speed of 5.9451 m/s after the collision.

We need to use the conservation of momentum, which states that the total momentum of a closed system remains constant. In this case, the closed system is the two players, Joe and Tommy.

We can start by calculating the initial momentum of the system, which is given by:

[tex]p_{initial} = m_{Tommy} * v_{Tommy} + m_{Joe} * v_{Joe}[/tex]

where m_Tommy and m_Joe are the masses of Tommy and Joe, respectively, and v_Tommy and v_Joe are their initial velocities.

Plugging in the given values, we get:

[tex]p_{initial} = 91 kg * 5 m/s + 97 kg * 6 m/s[/tex]

p_initial = 1123 kgm/s

After the collision, Joe is standing still, which means his velocity is zero. Let's call Tommy's velocity after the collision v_Tommy', which we need to find.

The final momentum of the system is given by:


[tex]p_{final} = m_{Tommy} * v_{Tommy'} + m_{Joe} * 0[/tex]

where we set Joe's velocity to zero since he's standing still.

Since the momentum is conserved, we can equate p_initial and p_final:

p_initial = p_final

[tex]m_Tommy * v_Tommy + m_Joe * v_Joe = m_Tommy * v_Tommy'[/tex][tex]m_{Tommy} * v_{Tommy} + m_{Joe} * v_{Joe} = m_{Tommy} * v_{Tommy'}[/tex]

91 kg * 5 m/s + 97 kg * 6 m/s = 91 kg * v_Tommy'

Solving for v_Tommy', we get:

[tex]v_{Tommy'} = (91 kg * 5 m/s + 97 kg * 6 m/s) / 91 kg[/tex]

v_Tommy' = 5.9451 m/s (rounded to four decimal places)


In summary, we used the conservation of momentum to calculate the velocity of Tommy after bouncing off Joe. We found that he bounces off Joe at a speed of 5.9451 m/s.

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Related Questions

Suppose we used a between subjects design to see if caffeine influenced levels of alertness. We had three groups of participants: participants who received 8 ounces of a caffeinated beverage, participants who received 24 ounces of a caffeinated beverage, and participants who received no caffeine. If this was a between subjects design with 30 total participants, how many participants would be in each condition

Answers

If we have 30 total participants in a between-subjects design with three groups, we can assign any number of participants to each group as long as the sum of participants in each group adds up to 30. The number of participants in each group is 10 in the 8-ounce group, 15 in the 24-ounce group, and 5 in the no-caffeine group.

If we have a total of 30 participants in a between-subjects design, we need to divide them into three groups according to the conditions.

Let x be the number of participants who received 8 ounces of a caffeinated beverage, y be the number of participants who received 24 ounces of a caffeinated beverage, and z be the number of participants who received no caffeine. Since we have a total of 30 participants, we can write

x + y + z = 30

We don't know the specific number of participants in each group, but we do know that they must add up to 30.

However, we also know that each participant can only be in one group, which means that we have mutually exclusive groups. Therefore, we can assume that there is no overlap between the groups, which means that the total number of participants in each group is

x + y + z = 30

z = 30 - (x + y)

So, we can assign any value to x and y, as long as the sum of x and y is less than or equal to 30. Then, we can find the value of z using the equation above.

For example, if we assign 10 participants to the 8-ounce group and 15 participants to the 24-ounce group, we would have

x = 10

y = 15

z = 30 - (10 + 15) = 5

So, there would be 10 participants in the 8-ounce group, 15 participants in the 24-ounce group, and 5 participants in the no-caffeine group.

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What is the exact circumference of a circle with a radius of 15 cm?
Responses

10π cm
10 pi, cm

15π cm
15 pi, cm

30π cm
30 pi, cm

60π cm

Answers

Answer:

30π cm

Step-by-step explanation:

if r = 15 cm

circumference = π2r

= π × 2 × 15

= 30π cm

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A ball is drawn randomly from a jar that contains 8 red balls, 7 white balls, and 3 yellow balls. Find the probability of the given event. Write your answers as reduced fractions or whole numbers. (a) P(A red ball is drawn) = (b) P(A white ball is drawn) = (c) P(A yellow ball is drawn) = (d) P(A green ball is drawn) =

Answers

(a) P(A red ball is drawn) = 4/9

(b) P(A white ball is drawn) = 7/18

(c) P(A yellow ball is drawn) = 1/6

(d) P(A green ball is drawn) = 0



(a) To find the probability that a red ball is drawn, we'll use the following formula:
P(A red ball is drawn) = (Number of red balls) / (Total number of balls)

There are 8 red balls and a total of 8+7+3 = 18 balls in the jar. So, the probability of drawing a red ball is:
P(A red ball is drawn) = 8/18 = 4/9

(b) To find the probability that a white ball is drawn:
P(A white ball is drawn) = (Number of white balls) / (Total number of balls)

There are 7 white balls, so the probability of drawing a white ball is:
P(A white ball is drawn) = 7/18

(c) To find the probability that a yellow ball is drawn:
P(A yellow ball is drawn) = (Number of yellow balls) / (Total number of balls)

There are 3 yellow balls, so the probability of drawing a yellow ball is:
P(A yellow ball is drawn) = 3/18 = 1/6

(d) To find the probability that a green ball is drawn:
P(A green ball is drawn) = (Number of green balls) / (Total number of balls)

There are no green balls in the jar, so the probability of drawing a green ball is:
P(A green ball is drawn) = 0/18 = 0

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Find an exponential function that passes through (2,8) and (4,128)

Answers

The final exponential function using the values of 'a' and 'b':
y = (1/2)(4^x)

To find an exponential function that passes through the points (2,8) and (4,128), follow these steps:

Step 1: Recall the general form of an exponential function: y = ab^x
Here, 'a' and 'b' are constants that need to be determined using the given points.

Step 2: Substitute the first point (2,8) into the equation:
8 = ab^2

Step 3: Substitute the second point (4,128) into the equation:
128 = ab^4

Step 4: Divide the second equation by the first equation to eliminate 'a':
(128 = ab^4) / (8 = ab^2)
16 = b^2

Step 5: Solve for 'b':
b = √16
b = 4

Step 6: Substitute the value of 'b' back into the first equation:
8 = a(4^2)

Step 7: Solve for 'a':
8 = 16a
a = 8/16
a = 1/2

Step 8: Write the final exponential function using the values of 'a' and 'b':
y = (1/2)(4^x)

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36 inches in 3 feet
rate=____ unit rate ___

Answers

Answer:

Rate: 36:3

Unit Rate: 12:1

Step-by-step explanation:

Solve 2x(x 0.5) = −(x+2.5)² + 5.5 by graphing. Round to the nearest thousandth.
x≈
and x

Answers

we find that the solutions to the equation are:x ≈ -1.283, x ≈ 4.283.

How to solve the equation ?

To solve the equation 2x(x+0.5) = -(x+2.5)² + 5.5 by graphing, we can first rearrange it to the standard form:

x² - 3x - 2 = 0.5(x+2.5)²

Then we can plot the two functions y = x² - 3x - 2 and y = 0.5(x+2.5)² - 5.5 on the same graph and find their intersection points, which represent the solutions to the equation.

Enter the two functions in separate equations:

[tex]y_1 = x^2 - 3x - 2[/tex]

[tex]y_2 = 0.5(x+2.5)^2 - 5.5[/tex]

Adjust the zoom level and position of the graph to see the intersection points.

Click on the intersection points to see their coordinates.

Round the coordinates to the nearest thousandth.

After following these steps, we find that the solutions to the equation are:

x ≈ -1.283

x ≈ 4.283

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Qué expresión es igual a 4.6?
a. 1.6 + (3 × 4) – 2 ÷ 2
b. 1.6 + 3 × 4 – 2 ÷ 2
c. [1.6 + (3 × 4)] – (2 ÷ 2)
d. (1.6 + 3) × (4 – 2) ÷ 2

Answers

The correct expression that is equal to 4.6 is option c. [1.6 + (3 × 4)] – (2 ÷ 2)

Let's evaluate each expressions using the BODMAS rule of mathematics,

a. 1.6 + (3 × 4) – 2 ÷ 2

= 1.6 + 12 - 1

= 12.6

b. 1.6 + 3 × 4 – 2 ÷ 2

= 1.6 + 12 - 1

= 12.6

c. [1.6 + (3 × 4)] – (2 ÷ 2)

= [1.6 + 12] - 1

= 12.6

d. (1.6 + 3) × (4 – 2) ÷ 2

= 4.6 × 2 ÷ 2

= 4.6

BODMAS is an acronym used to remember the order of operations in mathematics: Brackets, Orders, Division, Multiplication, Addition, Subtraction. It is used to perform calculations in the correct order to obtain the correct result. Therefore, the correct answer is (c).

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Complete question - Which expression is equal to 4.6?

a. 1.6 + (3 × 4) – 2 ÷ 2

b. 1.6 + 3 × 4 – 2 ÷ 2

c. [1.6 + (3 × 4)] – (2 ÷ 2)

d. (1.6 + 3) × (4 – 2) ÷ 2

A recipe for maroon paint says, "mix 5 ml of red paint with 3 ml of blue paint."
use snap cubes to represent the amounts of red and blue paint in the recipe. then, draw a sketch of your snap-cube representation of the maroon paint.what amount does each cube represent?

Answers

Assuming that one snap cube represents one milliliter (ml) of paint, we can use five red snap cubes to represent 5 ml of red paint and three blue snap cubes to represent 3 ml of blue paint. We can arrange these snap cubes in a row to represent the recipe:

RRRRR BBB

This indicates that we mix 5 ml of red paint with 3 ml of blue paint to create the maroon paint.

To draw a sketch of the snap-cube representation of the maroon paint, we can combine the red and blue snap cubes into a single row:

RRRRR BBB

This gives us a row of eight snap cubes, which represents the maroon paint. Visually, the maroon paint will appear as a blend of red and blue, with a darker, richer hue than either color alone.

Each snap cube represents one milliliter (ml) of paint. Therefore, in this representation, each snap cube represents a fixed amount of paint, regardless of the color. In other words, each cube represents a unit of volume, rather than a unit of color or pigment.

The altitude to the hypotenuse of a right angled triangle is 8 cm. If the hypotenuse is 20 cm long, find the lenghs of the two segments of the hypotenuse

Answers

Let the two segments of the hypotenuse be x and y.
Using the Pythagorean theorem, we know that:
x^2 + 8^2 = y^2
and
y^2 + 8^2 = 20^2
Simplifying the second equation:
y^2 = 20^2 - 8^2
y^2 = 336
y = sqrt(336) = 4sqrt(21)
Now we can use the first equation to solve for x:
x^2 + 8^2 = (4sqrt(21))^2
x^2 + 64 = 336
x^2 = 272
x = sqrt(272) = 4sqrt(17)
Therefore, the lengths of the two segments of the hypotenuse are 4sqrt(17) cm and 4sqrt(21) cm.

A rectangular prism has a square
base with edge length (x + 1). Its
volume is (x + 1)2(x – 3). What
does the expression (x + 1)(x – 3)
represent?
area of the base
area of one side
height of the prism
surface area of the prism

Answers

The expression (x + 1)(x - 3) represents the Area of base of the prism.

What is Prism?

a crystal is a polyhedron containing a n-sided polygon base, a respectable halfway point which is a deciphered duplicate of the first, and n different countenances, fundamentally all parallelograms, joining relating sides of the two bases. Translations of the bases exist in every cross-section that runs parallel to the bases.

According to question:

The volume of a rectangular prism is given by the formula V = Bh, where B is the area of the base and h is the height of the prism. In this case, the base is a square with edge length (x + 1), so its area is (x + 1)^2. The volume of the prism is given as (x + 1)^2(x - 3).

We can find the height of the prism by dividing the volume by the area of the base:

B = V/h = (x + 1)^2(x - 3)/(x + 1) = (x + 1)(x - 3)

Therefore, the expression (x + 1)(x - 3) represents the Area of base of the prism.

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Find the exact values of sin 2u, cos2u, and tan2u using the double-angle formulas cot u= square root 2, pi < u < 3pi/2

Answers

sin 2u = -1/2, cos 2u = -1/2, tan 2u = 1, because cot u = sqrt(2) and the range of u is between pi and 3pi/2.

How to find the trigonometric function?

Given cot u = sqrt(2) and the range of trigonometric of u, we can determine the values of sine, cosine, and tangent of 2u using the double-angle formulas. First, we can find the value of cot u by using the fact that cot u = 1/tan u, which gives us tan u = 1/sqrt(2). Since u is in the third quadrant (i.e., between pi and 3pi/2), sine is negative and cosine is negative.

Using the double-angle formulas, we can express sin 2u and cos 2u in terms of sin u and cos u as follows:

sin 2u = 2sin u cos u

cos 2u =[tex]cos^2[/tex] u - [tex]sin^2[/tex] u

Substituting the values of sine and cosine of u, we get:

sin 2u = 2*(-sqrt(2)/2)*(-sqrt(2)/2) = -1/2

cos 2u = (-sqrt(2)/2[tex])^2[/tex] - (-1/2[tex])^2[/tex] = -1/2

To find the value of tangent of 2u, we can use the identity:

tan 2u = (2tan u)/(1-[tex]tan^2[/tex] u)

Substituting the value of tan u, we get:

tan 2u = (2*(1/sqrt(2)))/(1 - (1/sqrt(2)[tex])^2[/tex]) = 1

Therefore, sin 2u = -1/2, cos 2u = -1/2, and tan 2u = 1.

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The money in Maya's college savings account earns 2 1/5% interest. Which value is less than 2 1/5%?


A. 0. 0215


B. 11/5


C. 0. 022


D. 11/500

Answers

A value that is less than 2 1/5% from the given data is 0. 0215. Option A is the correct answer.

A fraction represents a part of a number or any number of equal parts. There is a fraction, containing numerator and denominator.

To find a value that is less than 2 1/5% we need to find the decimal number of a given fraction. to convert the given fraction into decimal form we need to divide the given fraction by 100.

= 2 1/5% / 100

= (2 + (1/5)) / 100

= 0.022

A value that is less than 0.022 from the given data is 0. 0215.

Therefore, a value less than 2 1/5% is 0. 0215.

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The shopkeeper sold every day the number of eggs is recorded. At equal intervals group 42, 49, 61, 35, 27, 36, 50, 34, 31, 40

Answers

The shopkeeper sold an average of 40.5 eggs per day during the given interval.

How to find the avg number of eggs?

To calculate the average number of eggs sold per day, add up the total number of eggs sold and divide by the number of days.

Total number of eggs sold = 42 + 49 + 61 + 35 + 27 + 36 + 50 + 34 + 31 + 40 = 405

Number of days = 10

Average number of eggs sold per day = 405 / 10 = 40.5

The shopkeeper sold an average of 40.5 eggs per day during the given interval.

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The shopkeeper sold every day the number of eggs is recorded. At equal intervals group 42, 49, 61, 35, 27, 36, 50, 34, 31, 40

What is the average number of eggs sold per day by the shopkeeper over the given interval?

PLEASE HELP FAST!!!!


On Monday a group of students took a test and the average ( arithmetic mean ) score was exactly 80. 4. A student who was absent on Monday took the same test on Tuesday and scored 90. The average age test score was then exactly 81. How many students took the test on Monday?


A) 14


B) 15


C) 16


D) 17


E) 18


With steps please

Answers

The number of students who took the test on Monday is found to be 15, hence the correct option is B.

Let us assume that the number of student taking test on Monday is n. The total score for Monday's test is n times the average score of 80.4,

Monday's total score = 80.4n

When the student who missed the test on Monday took the test on Tuesday and scored 90, the total score became,

Total score = 80.4n + 90

The new average score of 81 can be expressed as,

81 = Total score / (n+1)

Substituting the value of the total score, we get,

81 = (80.4n + 90)/(n+1)

Multiplying both sides by n+1, we get,

81(n+1) = 80.4n + 90

Expanding the brackets,

81n + 81 = 80.4n + 90

Simplifying,

0.6n = 9

n = 15, so, the number of students who took the test on Monday is 15.

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to measure the length of a hiking trail, a worker uses a device with a 2-foot-diameter wheel that counts the number of revolutions the wheel makes. if the device reads 1,100.5 revolutions at the end of
the trail, how many miles long is the trail, to the nearest tenth of a mile?

Answers

The length of the trail is determined as 1.3 miles.

What is the length of the trail?

The length of the trail is calculated as follows;

The circumference of the circle is calculated as;

S = πd

where;

d is the diameter of the circle

S = π x 2 ft

S = 2π ft

I revolution = 1 circumference = 2π ft

1 rev = 2π ft

1,100.5 rev = ?

= 1,100.5 rev/rev x 2π ft

= 6,914.65 ft

5280 ft -------> 1 mile

6,914.65 ft ------> ?

= 1.3 miles

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Which are correct representations of the inequality –3(2x – 5) < 5(2 – x)? Select two options. x < 5 –6x – 5 < 10 – x –6x + 15 < 10 – 5x A number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right. A number line from negative 3 to 3 in increments of 1. An open circle is at negative 5 and a bold line starts at negative 5 and is pointing to the left.

Answers

To solve the inequality –3(2x – 5) < 5(2 – x), we can simplify the left and right sides separately and then solve for x:

–3(2x – 5) < 5(2 – x)

–6x + 15 < 10 – 5x

–6x + 5x < 10 – 15

–x < –5

x > 5

The correct representations of the inequality are:

- x > 5
- –6x + 15 < 10 – x

Option A, -6x - 5 < 10 - x, is not correct because it does not correctly simplify the inequality.

Option B, -6x + 15 < 10 - 5x, is correct as it simplifies to -x < -5 after combining like terms.

Option C is not correct because it is the same as option A.

Option D is not correct because it represents the opposite inequality, x < 5 instead of x > 5.

The correct number line representation is the first option: a number line from negative 3 to infinity, with an open circle at 5 and a bold line pointing to the right.

Element x decays radioactively with a half life of 15 minutes. if there are 960 grams of element x, how long, to the nearest tenth of a minute, would it take the element to decay to 295 grams?


y=a(.5)^(t/h)

Answers

It would take approximately 21.2 minutes for 960 grams of Element X to decay to 295 grams.

The time it takes for 960 grams of Element X with a half-life of 15 minutes to decay to 295 grams can be found using the formula y = a [tex](0.5)^\frac{t}{h}[/tex] .

1: Identify the variables.


a = initial amount = 960 grams
y = final amount = 295 grams
h = half-life = 15 minutes
t = time in minutes (this is what we want to find)

2: Plug the variables into the formula.
295 = 960 [tex](0.5)^\frac{t}{15}[/tex]

3: Solve for t.
Divide both sides by 960.
(295/960) =  [tex](0.5)^\frac{t}{15}[/tex]

4: Take the logarithm of both sides to remove the exponent.
log(295/960) = log  [tex](0.5)^\frac{t}{15}[/tex]

5: Use the logarithm property to move the exponent to the front.
log(295/960) = (t/15) * log(0.5)

6: Solve for t.
t = (15 * log(295/960)) / log(0.5)

7: Calculate t.
t ≈ 21.2 minutes

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On a certain hot​ summer's day,670 people used the public swimming pool. The daily prices are for children 1.25 and for adults.2.00 The receipts for admission totaled 1118.00 How many children and how many adults swam at the public pool that​ day

Answers

Based on simultaneous equations, the number of children and adults who swam at the public pool that hot summer's day is as follows:

Children = 296Adults = 374.

What are simultaneous equations?

Simultaneous equations are two or more equations solved concurrently.

Simultaneous equations are also referred to as a system of equations because the equations are solved at the same time.

The total number of people who used the public swimming pool = 670

The unit price for children = $1.25

The unit price for adults = $2.00

The total amount collected that day = $1,118

Let the number of children who swam at the public pool that day = x

Let the number of adults who swam at the pool that day = y

Equations:

x + y = 670 ... Equation 1

1.25x + 2y = 1,118 ... Equation 2

Multiply Equation 1 by 2:

2x + 2y = 1,340 Equation 3

Subtract Equation 2 from Equation 3:

2x + 2y = 1,340

-

1.25x + 2y = 1,118

0.75x = 222

x = 296

y = 670 - 296

= 374

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Andre owns a condominium with a value of $155,000. He has a stock portfolio worth $8,100. He owes $3,300 on his car, which is valued at $9,100. He has $7,600 in student loans to repay. He has a credit card balance of $4,327. He also has $2,600 in a bank account. Construct a net worth statement to find Andre's net worth.

Answers

Using  net worth statement, Andre's net worth is $159,573.

How to Construct a net worth statement to find Andre's net worth.

Andre's net worth can be calculated by subtracting his total liabilities from his total assets.

Total assets = $155,000 (condominium) + $8,100 (stock portfolio) + $9,100 (car value) + $2,600 (bank account) = $174,800

Total liabilities = $3,300 (car loan) + $7,600 (student loans) + $4,327 (credit card balance) = $15,227

Net worth = Total assets - Total liabilities = $174,800 - $15,227 = $159,573

Therefore, Andre's net worth is $159,573.

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Which expression is equivalent to 1/2(2n+6

1/2+2n+6
2 1/2 + 6 1/2
n + 6
n+ 3

Answers

n+3

You distribute the property of 1/2 to 2n and 6, which will equal (1)n+3. The one does not need to be added and is understood to be there even if not visible.

How do I solve for X with the base numbers on a right triangle. (Please give an explanation and an answer, I need to know how it works.)

Answers

Let's label the 3 points as A;B;C, where BC is the hypotenuse and AB is the shortest side, and x as AH.

We can see that triangle AHC is similar to triangle CAB, and triangle ACH is similar to triangle BCA, so therefore triangle AHC is similar to triangle CHA (i might've messed up the order but you get it)

Because they are similar, we get the ratio : x/12 = 40/x, or x^2 = 480.

So, x = [tex]\sqrt{480}[/tex], or 21.9 (1 d.p)

Answer:

21.9 units

-----------------------

According to the right triangle altitude theorem:

the altitude on the hypotenuse is equal to the geometric mean of line segments formed by altitude on the hypotenuse.

We see x is the altitude and 12 & 40 are the segments formed on the hypotenuse.

Applied to the given triangle, we get following equation:

[tex]x=\sqrt{12*40} =\sqrt{480} =21.9\ units[/tex]

Find the volume of the solid generated when the rectangle below is rotated about side
LO. Round your answer to the nearest tenth if necessary.

Answers

The volume of the obtained solid is 36 units³.

Given that a rectangle of dimension 9 units x 2 units, has been rotated to form a solid we need to find its volume,

So we know that a rectangle rotated to form a rectangular prism.

Volume of a rectangular prism = product of the dimensions.

The dimensions of the obtained solid will be 9 units x 2 units x 2 units,

So the volume = 9 x 2 x 2 = 36 units³

Hence the volume of the obtained solid is 36 units³.

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Obtain the equation of the line that passes through the point (4 , 6) and is parallel to the line y= -2x+4.

Answers

Answer:

y = -2x + 14

Step-by-step explanation:

OK so first u have to do y = -2x + b cuz its parallel

then u gotta just plug in the ordered pair so

6 = -2(4)+b

6 = -8 +b

14 = b

So now u have to do

y = -2x + 14

The ratio of Adults to Girls in a tennis club is 5:1
The ratio of Girls to Boys in the same club is 3:4
What is the ratio of adults to boys?

Answers

The ratio of adult to boys is 35:24

What is ratio?

A ratio is a comparison of two or more numbers that indicates their sizes in relation to each other. For example, if the ratio of boys to girls in a class is 4:1. This means that the for every 4 boys therefore is a girl.

Represent the total number of adult, boys and girls in the club by x

This means number of boys = 4/7× x

number of adult = 5/6 × x

Therefore the ratio of adults to boys will be

5x/6 : 4x/7

= 5/6 : 4/7

multiply through by 42

= 35 : 24

therefore the ratio of adult to boys is 35: 24

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The volume of a cylinder is twice the volume of a cone. The cone and the
cylinder have the same diameter. The height of the cylinder is 5 meters.
What is the height of the cone?

Answers

The height of the cone that the volume of a cylinder is twice the volume of a cone is 7.5 meters.

How to determine  the height of the cone

Let's first define some variables to represent the dimensions of the cone and cylinder. Let's use r for the radius of both shapes, h for the height of the cone, and 5 for the height of the cylinder.

The volume of a cone is given by V_cone = (1/3)πr^2h, and the volume of a cylinder is given by V_cylinder = πr^2h.

We are told that the volume of the cylinder is twice the volume of the cone:

V_cylinder = 2V_cone

Substituting the formulas for the volumes of the cone and cylinder, we get:

πr^2(5) = 2[(1/3)πr^2h]

Simplifying, we can cancel the π and the r^2 terms on both sides:

5 = (2/3)h

Multiplying both sides by 3/2, we get:

h = 7.5

Therefore, the height of the cone is 7.5 meters.

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A farmer of a large apple orchard would like to estimate the true mean number of suitable apples produced per tree. He selects a random sample of 40 trees from his large orchard and determines with 95% confidence that the true mean number of suitable apples produced per tree is between 375 and 520. Which of these statements is a correct interpretation of the confidence level?

Answers

The confidence level represents the degree of certainty that the interval contains the true population parameter.

The statement "determines with 95% confidence that the true mean number of suitable apples produced per tree is between 375 and 520" means that if the farmer were to repeat the sampling process many times and calculate the confidence interval each time, 95% of those intervals would contain the true mean number of suitable apples per tree.

Therefore, we can be 95% confident that the true mean number of suitable apples produced per tree is within the interval of 375 to 520 for this particular sample of 40 trees.

The confidence level represents the degree of certainty that the interval contains the true population parameter.

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Use the given facts about the functions to find the indicated limit.


lim x->3 f(x)=0, lim x->3 g(x)=4 lim x->3 h(x)=2


lim x->3 6h/ 4f+g (x)



*there are no answer choices. Its a prompt*

Answers

The value of [tex]\lim_{x \to 3} \frac{6h}{4f+g} (x)[/tex] is 3

Given, [tex]\lim_{x \to 3} f(x)=0[/tex]

[tex]\lim_{x \to 3} g(x)=4[/tex]

[tex]\lim_{x \to 3} h(x)=2[/tex]

We have to find the value of [tex]\lim_{x \to 3} \frac{6h}{4f+g} (x)[/tex]

[tex]\lim_{x \to 3} \frac{6h}{4f+g} (x)=\lim_{x \to 3} \frac{6h(x)}{4f(x)+g(x)}[/tex]

[tex]= \frac{\lim_{x \to 3}6h(x)}{\lim_{x \to 3}4f(x)+\lim_{x \to 3}g(x)}[/tex]

[tex]=\frac{6\times 2}{4\times0+4}[/tex]

= 12/4

= 3

Hence, the value of [tex]\lim_{x \to 3} \frac{6h}{4f+g} (x)[/tex] is 3

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A fair six-sided die will be rolled fifteen times, and the numbers that land face up will be recorded. Let x¯1 represent the average of the numbers that land face up for the first five rolls, and let x¯2 represent the average of the numbers landing face up for the remaining ten rolls. The mean μ and variance σ2 of a single roll are 3. 5 and 2. 92, respectively. What is the standard deviation σ(x¯1−x¯2) of the sampling distribution of the difference in sample means x¯1−x¯2?

Answers

The mean of a single roll is given as μ = 3.5, and the variance is given as [tex]σ^2[/tex] = 2.92.

The sample size for the first five rolls is n1 = 5, and the sample size for the remaining ten rolls is n2 = 10.

The mean of the sampling distribution of the difference in sample means x¯1−x¯2 is given as:

μ(x¯1−x¯2) = μ(x¯1) - μ(x¯2) = μ - μ = 0

The variance of the sampling distribution of the difference in sample means x¯1−x¯2 is given as:

σ^2(x¯1−x¯2) = (σ^2(x¯1)/n1) + (σ^2(x¯2)/n2)

where σ^2(x¯1) is the variance of the sample mean for the first five rolls and σ^2(x¯2) is the variance of the sample mean for the remaining ten rolls.

Since each roll of the die is independent, the variance of the sample mean for each sample is given as:

σ^2(x¯1) = σ^2/ n1 = 2.92/5 = 0.584

σ^2(x¯2) = σ^2/ n2 = 2.92/10 = 0.292

Substituting these values in the above equation, we get:

σ^2(x¯1−x¯2) = (0.584/5) + (0.292/10) = 0.1468

Therefore, the standard deviation of the sampling distribution of the difference in sample means x¯1−x¯2 is:

σ(x¯1−x¯2) = sqrt(σ^2(x¯1−x¯2)) = sqrt(0.1468) = 0.3835 (rounded to four decimal places)

Hence, the standard deviation of the sampling distribution of the difference in sample means x¯1−x¯2 is 0.3835.

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someone help pls!! giving brainlist to anyone who answers

Answers

Answer:  csc M =  [tex]\frac{\sqrt{86} }{8}[/tex]

Step-by-step explanation:

The csc is related to sin

csc x =  1/sin x

find sin M first  then flip it to find csc M

sin M= opposite/hypotenuse

sin M= [tex]\frac{8}{\sqrt{86} }[/tex]                >flip that

csc M =  1/sin M

csc M =  [tex]\frac{\sqrt{86} }{8}[/tex]              >root cannot be simplified it breaks down into 2 and 43

                                     which are 2 prime numbers

1. Un ciclista ha recorrido 145. 8 km en una etapa, 136. 65 km en otra etapa y 162. 62 km en una tercera etapa. ¿Cuántos kilómetros le quedan por recorrer si la carrera es de 1000 km?


Esta es una y la segunda es otra ayúdenme



2. Una clinica dental tiene una tarifa de $ 19,99 para las calzas de piezas dentales. Si en un mes se registraron 109 calzas realizadas, ¿ que cantidad de dinero ingreso a la clinica?

Answers

1) The distance left in the race is  554.93km

2) The total amount earned is $2,178.91

How many kilometers remain in the race?

We know that the total race is of 1000km, to find the distance missing, we need to take that total distance and subtract the amounts that the cyclist already traveled.

Then we will get:

distance left = 1000km - 145.8km - 136.65km - 162.62 km

distance left = 554.93km

That is the distance left in the race.

2) We know that each piece costs $19.99, and 109 pieces are sold, then the amount earned is the product between these two numbers.

Earnings = 109*$19.99  = $2,178.91

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